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math.CO — Combinatorics

A linear gap for the maximal cp-rank

Contributed by Yair Lavi

We prove that the maximal cp-rank pnp_n satisfies pn≥n(n−3)/2p_n\ge n(n-3)/2 for odd n≥5n\ge5 and pn≥n(n−3)/2−1p_n\ge n(n-3)/2-1 for even n≥6n\ge6. Together with the known upper bound pn≤(n+12)−4p_n\le\binom{n+1}{2}-4, this gives pn=n2/2+O(n)p_n=n^2/2+O(n).

A mix of human-written and AI-generated textHuman understanding: all partsCompletely positive matrixCopositive matrixCyclic incidence matrixExposed facecp-rank
Nov 11, 20268 pages
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