Superlinear complexity of the steering word
Version 1 / Oct 20, 2026/ arXiv: 2607.11648 / CC0 1.0
Abstract
Write with the nearest integer and
, and let , , be the
resulting \emph{steering word}: the step-by-step record of the map
on the orbit of 1, coded by nearest-integer rounding.
We prove that the subword complexity of is superlinear,
. A pigeonhole argument reduces this to exponential pair
repulsion of the orbit modulo one, which we establish by two applications of
the -adic Subspace Theorem: once in three variables, which handles all gaps
between the two orbit points at once, and once in two variables (Ridout's
theorem) for the single degenerate family of constant gap. The argument is
completely formalized in Lean~4, together with the Subspace Theorem it uses.
Provenance statement
Formalizations
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Version history
- v1 · 20 pagesSubmitted by Ralf StephanInitial depositCurrentOct 20, 2026