\section{Orthogonal descent and its local parameter} \label{fl:sec:orthogonal-descent} The residual representation of Proposition~\ref{fl:lem:residual-analytic} lives on a special orthogonal group, or on the corresponding general spin group $\operatorname{GSpin}$ (an extension of the special orthogonal group by $\mathbb G_m$), about twice as large as the group we want. The descent is a Fourier coefficient of it along a unipotent subgroup $U_{\rm desc}$, for a character $\psi_{\rm desc}$ whose stabilizer $H$ in the Levi subgroup is the target group. This section does three things. It computes the twisted Jacquet module of the local components for $(U_{\rm desc},\psi_{\rm desc})$ (Proposition~\ref{fl:prop:uniform-b-jacquet}), which gives the Hecke eigenvalues of the descent if it is nonzero. It proves two lemmas on rearranging Fourier coefficients (Lemmas~\ref{fl:lem:uniform-row-separation} and~\ref{fl:lem:uniform-interleave}). And it proves that the descent to an odd orthogonal group is nonzero, with a nonzero Whittaker coefficient, in every characteristic (Proposition~\ref{fl:prop:uniform-b-nonzero}). The descent to an even orthogonal group is treated in Sections~\ref{fl:sec:odd-symplectic} and~\ref{fl:sec:char2-d}. Two features of the local computation are used later. In the even orthogonal case the Jacquet module has two summands, exchanged by the outer automorphism. And it vanishes when the stabilizer is not split, so that the stabilizer of a nonzero global descent is split at every unramified place. \subsection{The descent datum} Write a split even quadratic space as \[ V=\bigoplus_{i=1}^m(Fe_i\oplus Ff_i),\qquad Q\Bigl(\sum x_ie_i+y_if_i\Bigr)=\sum x_iy_i, \] with root vectors \[ E_{e_i-e_j}=E_{ij}-E_{f_jf_i},\qquad E_{e_i+e_j}=E_{if_j}-E_{jf_i},\qquad F_\alpha=E_\alpha^t. \] In odd dimension there is an additional basis vector $u$, orthogonal to the others; its norm is $1$ in characteristic two, and a convenient nonzero constant otherwise. Orthogonal groups are the smooth special orthogonal groups. In even dimension this is the kernel of the Dickson invariant on the orthogonal group of the quadratic form; outside characteristic two it is the kernel of the determinant. In odd dimension it is the kernel of the determinant $\mathrm O(Q)\to\mu_2$ in every characteristic; in characteristic two the bilinear form of an odd-dimensional space has the line of $u$ as radical, and the quadratic form is not zero on it. The rank of $g-1$ modulo two, which is the Dickson invariant in even dimension, cannot be used in odd dimension: in characteristic two a short root element of the odd orthogonal group differs from the identity by a matrix of rank one. All unipotent groups below are the same for the orthogonal group and for $\operatorname{GSpin}$. In both configurations $r\ge1$, and $U_{\rm desc}$ is the unipotent radical of the parabolic subgroup fixing the flag $\langle e_1\rangle\subset\cdots\subset\langle e_1,\ldots,e_r\rangle$, whose Levi subgroup is the product of a torus of rank $r$ and the orthogonal group of the space spanned by the remaining basis vectors. The character $\psi_{\rm desc}$ is $\psi$ of the sum of the coordinates on the simple roots $e_i-e_{i+1}$, $ir$ and by $u$ in odd dimension, so that $M=\mathbb G_m^r\times G_W$ with $G_W$ the special orthogonal group of $W$, or its inverse image in $\operatorname{GSpin}$. The elements of the last row are the $n(y)$, $y\in W$, with $n(y)f_r\equiv f_r+y$ modulo $e_r$; on them $\psi_{\rm desc}(n(y))=\psi(\lambda(y))$, and the root subgroups are \[ x_{e_r-e_h}(t)=n(-tf_h),\qquad x_{e_r+e_h}(t)=n(-te_h), \] and in odd dimension the short root subgroup $U_{e_r}$ consists of the $n(tu)$. Let $\gamma$ be an element of $M$, with components $(a_1,\ldots,a_r)$ and $g\in G_W$. Put $\psi^\gamma(n)=\psi_{\rm desc}(\gamma^{-1}n\gamma)$. Since $\gamma^{-1}n(y)\gamma=n(a_r^{-1}g^{-1}y)$, this is the character of $U_{\rm desc}$ of the same kind as $\psi_{\rm desc}$ in which the coefficients on the simple roots $e_i-e_{i+1}$, $ir}(x_he_h+y_hf_h)+zu$, the coefficients of $\psi^\gamma$ on $U_{e_r-e_h}$ and $U_{e_r+e_h}$ are $-x_h$ and $-y_h$, and $Q(v')=\sum_hx_hy_h+Q(u)z^2$. \item[(b)] In the second configuration in characteristic two, $\lambda'(u)\ne0$: the line of $u$ is the radical of the bilinear form of $W$ and $Q(u)\ne0$, so $g$ fixes $u$, and $\lambda'(u)=a_r^{-1}\lambda(u)$. \end{enumerate} The condition of Lemma~\ref{fl:lem:odd-averaging} at the point $\gamma$ of the double coset of $w$ is that $\psi^\gamma$ be trivial on $U_w=U_{\rm desc}\cap w^{-1}P'w$. This group is the product of the root subgroups $U_\alpha$, $\alpha$ in \eqref{rw:eq:descent-roots}, for which $w\alpha$ is a root of $P'$, that is, a positive root or a root $\pm(e_{2c-1}-e_{2c})$ of a block. So the condition is: \begin{equation}\label{rw:eq:jacquet-criterion} \text{if }w\alpha\text{ is a root of }P',\text{ the coefficient of } \psi^\gamma\text{ on }U_\alpha\text{ is zero.} \end{equation} This is a condition on root subgroups and on the values of $\psi$ at their points, and the arguments below are the same in every characteristic. The inducing character is trivial on all unipotent elements of $P'$, including those of the blocks, so the $\mu_j$ do not enter the condition. \begin{lemma}[The contributing double coset] \label{rw:lem:jacquet-double-coset} Let $w$ be a signed permutation, and suppose that \eqref{rw:eq:jacquet-criterion} holds at some point $\gamma$ of $M$. Then $w$ lies in the double coset of the element $w_0$ with \[ w_0(e_i)=f_{2i-1},\qquad w_0(e_{r+k})=e_{2k}\quad(1\le i,k\le r), \] extended to the $f_i$ by duality. In the first configuration $w_0$ fixes $e_{m-1}$, and it exchanges $e_m$ and $f_m$ exactly when $r$ is odd; in the second configuration $w_0(u)=(-1)^ru$. \end{lemma} \begin{proof} For $i\le r$ write \[ w(e_i)=e_{j_i}\ (\text{sign }+)\quad\text{or}\quad w(e_i)=f_{j_i}\ (\text{sign }-),\qquad A_i=\lceil j_i/2\rceil, \] so that $A_i$ is the block of $P'$ containing the image. \step{1}{the sign of $e_r$ is negative} Suppose $w(e_r)=e_j$. Let $h>r$. If $w(e_h)=e_l$, then $w(e_r+e_h)=e_j+e_l$ is a positive root, so $y_h=0$. If $w(e_h)=f_l$, then $w(e_r-e_h)=e_j+e_l$, so $x_h=0$. Hence $x_hy_h=0$ for all $h$. In even dimension this gives $Q(v')=0$, which contradicts (a). In odd dimension $w(e_r)=e_j$ is a positive short root, so $\lambda'(u)=0$. In odd characteristic $\lambda'(u)=2Q(u)z$, hence $z=0$ and again $Q(v')=0$. In characteristic two $\lambda'(u)\ne0$ by (b), a contradiction. \step{2}{all signs are negative} If the signs of $e_i$ and $e_{i+1}$ are $(+,-)$, then $w(e_i-e_{i+1})=e_{j_i}+e_{j_{i+1}}$ is a positive root, while the coefficient of $\psi^\gamma$ on the simple root $e_i-e_{i+1}$ is not zero. So a positive sign cannot be followed by a negative one; since the last sign is negative, all are. \step{3}{the blocks} For $ir$, $w(e_h)=e_l$ or $f_l$. Then $l\ne j_r$ and $\lceil l/2\rceil\le r+1=A_r$, so $e_l-e_{j_r}$ is a root of $P'$: a positive root if $l$ lies in an earlier block than $j_r$, a root of the last block otherwise. It is the image of $e_r+e_h$ if $w(e_h)=e_l$ and of $e_r-e_h$ if $w(e_h)=f_l$. So again $x_hy_h=0$ for every $h$ and $Q(v')=0$, a contradiction. Therefore $A_i=i$ for all $i$ in both configurations. \step{4}{the representative} Multiplying $w$ on the left by the Weyl group of the Levi subgroup of $P'$, which exchanges the two indices of a block, we may assume $j_i=2i-1$. The images of the $e_h$, $h>r$, are then, up to signs, the $e_{2k}$ with $k\le r$ and, in the first configuration, $e_{m-1}$ and $e_m$. Multiplying on the right by the Weyl group of $G_W$, which consists of the signed permutations of the indices $h>r$, with an even number of sign changes when $W$ has even dimension, we arrive at $w(e_i)=f_{2i-1}$ and $w(e_{r+k})=e_{2k}$ for $1\le i,k\le r$. In the first configuration we arrive in addition at $w(e_{m-1})=e_{m-1}$, and then $w$ exchanges $e_m$ and $f_m$ exactly when $r$ is odd, since the number of sign changes of an element of the Weyl group of type $D_m$ is even. In the second configuration $w(u)=(-1)^ru$, the determinant being one. This is $w_0$. \end{proof} \begin{lemma}[The intersection] \label{rw:lem:jacquet-intersection} For $w=w_0$ the group $U_w=U_{\rm desc}\cap w^{-1}P'w$ is \[ U_{\rm int}=\prod_{1\le k\le i\le r}U_{e_i+e_{r+k}} , \] a product of commuting root subgroups. \end{lemma} \begin{proof} We apply $w_0$ to the list \eqref{rw:eq:descent-roots}. In the following table $1\le i\le r$, $ii$ & $e_{2k}-e_{2i-1}$ & no\\ $e_i\pm e_{m-1}$, $e_i\pm e_m$ (type $D$) & $-e_{2i-1}\pm e_{m-1}$, $-e_{2i-1}\pm e_m$ & no\\ $e_i$ (type $B$) & $-e_{2i-1}$ & no\\ \bottomrule \end{tabular} \end{center} The roots marked ``no'' are negative, and none of them is a root $\pm(e_{2c-1}-e_{2c})$ of a block: in $e_{2j-1}-e_{2i-1}$ both indices are odd, in $e_{2k}-e_{2i-1}$ with $k>i$ the indices lie in different blocks, and in type $D$ we have $2i-1i-d),\qquad B_j-A_i\ (i\ge2,\ ji-d$, and the root $B_j-A_h$ has been added, at the step $(h-1,j)$, exactly when $h\ge2$ and $ji$ or as $(A_i-B_h)+(B_h-B_j)$ with $hi$ was removed at an earlier value of $i$, and $A_i-B_h$ with $hi$ earlier; the sum is a nonadjacent root of the first chain. In the second row $h>i+1$, and the sum was added at the step $(h-1,j)$. In the third row $hi+1-d\ge j+1$, and the sum is a nonadjacent root of the second chain. In all cases the sum belongs to the common subgroup and the character is trivial on it. \emph{Conjugation by $X_{ij}$.} The possible sums are $A_i-B_h$ with $h>j$, $A_h-B_j$ with $hm+2$, whereas the Siegel--Whittaker coefficient is along the group of all positive roots. We pass from the second to the first; Figure~\ref{rw:fig:siegel-exchange} shows the case $m=6$. For $i=m-2,\ldots,2$ in decreasing order: if $i\ge n$, first remove the root $e_{i+1}+e_{i+2}$, on which the character is trivial; then, for $j=m,\ldots,\max(i+2,m+2-i)$ in decreasing order, exchange \[ U_{e_i+e_j}\quad\hbox{for}\quad U_{-e_{i+1}-e_j}. \] At the step $(i,j)$ the positive roots $e_k+e_l$ present are those with $ki$ and $k+lm+2$, or $k=i+1$ and $l>j$; in both lists $ki$ with $k+lj$, raising $k$ gives two indices which are at least $i+2$, with sum larger than $m+2$ because $l>m+2-i$. This gives the sums of a root $e_a-e_b$ with a root of $\mathsf N$. \item \emph{A root of $\mathsf P$ plus a root of $\mathsf N$.} If $e_a+e_b\in\mathsf P$ and $-e_b-e_c\in\mathsf N$ with $a\ne c$, the sum is $e_a-e_c$, and we must show $ai$, then $a+bm+2$ we get $c>m+2-b>a$. When $b=i+1$ and $c>j$ we get $aj$ does not occur, since it would give $am+2$ exclude each other, and for $k=i+1$ the conditions $lj$ do. \end{itemize} The same verification applies with the root $e_i+e_j$ removed, so the common subgroup of the two groups of an exchange is a group. The only commutator on which the character is nontrivial is the root $e_i-e_{i+1}$, with coefficient $\pm1$: it is the commutator of the two exchanged root subgroups. The other sums of an exchanged root with a present root which could be simple roots do not occur, because $e_{i+1}+e_{j-1}\notin\mathsf P$, as $i+j\ge m+2$, and because no root of $\mathsf N$ involves the index $i$. Consider the root removed at the beginning of the step for $i\ge n$. Among the positive roots which are sums and are still present, $e_{i+1}+e_{i+2}$ is the only one with both indices greater than $i$; lowering one of its indices gives a root which is still present, and the removed root is not obtained by lowering an index of a root which is kept. Among the negative roots which are sums, none involves the index $i+1$, and with a root $-e_{i+2}-e_l$ one obtains $e_{i+1}-e_l$ with $l\ge i+3$, on which the character is trivial. So the root subgroup which is removed normalizes the subgroup which is kept, and its character. The coefficient before a removal is an integral of the coefficient after it, so nonvanishing is preserved, and each exchange is an equivalence by Lemma~\ref{fl:lem:odd-exchange}. At the end the roots are those of positive degree for $D_{\rm SW}$. \step{5}{conclusion} If the Siegel--Whittaker coefficient is not identically zero on $\mathcal V$, then by step~4 neither is the coefficient for $(D_{\rm SW},f_{\rm SW})$, and conjugating by $P_{t_*}\in G(F)$ neither is the coefficient for $(D,f_{t_*})$. The latter is a Fourier coefficient, along the root subgroup of $e_n-e_1$, of the coefficient on $\{\delta=0\}$ of step~2, which is therefore not identically zero. By steps~2 and~1 the Whittaker coefficient of the descent is not identically zero. \end{proof} \begin{remark}\label{rw:rem:odd-descent-computer} Of the two values $t=0,-1$ exactly one gives an isometry in the identity component of the orthogonal group; which one depends on the parity of $n$. The argument works in characteristic two because it uses the quadratic form and not only its bilinear form: the latter does not see the component or the action of the short root subgroup. The identities of step~3, the determinant of $P_t$ and the dimensions of the intersections have been verified by computer for $n\le5$. The sequences of exchanges in steps~1, 2 and~4 and in Lemma~\ref{fl:lem:uniform-interleave}, and the statements of Lemmas~\ref{rw:lem:jacquet-double-coset} and~\ref{rw:lem:jacquet-intersection}, have been verified in small rank by a program. At each exchange it checks the conditions of Lemma~\ref{fl:lem:odd-exchange} on the sets of roots and on the supports of the characters, in the form in which the program encodes them. The same was done for Lemmas~\ref{fl:lem:even-period-to-generic} and~\ref{fl:lem:descent-vanishing-and-period}. \end{remark}