\documentclass[11pt]{amsart} \usepackage[T1]{fontenc} \usepackage[utf8]{inputenc} \usepackage{lmodern} \usepackage[margin=1in]{geometry} \usepackage{amsmath,amssymb,amsthm} \usepackage[colorlinks=true,linkcolor=blue,citecolor=blue,urlcolor=blue]{hyperref} \usepackage{bookmark} \hypersetup{pdftitle={The Benson--Etingof--Ostrik conjecture}} \newtheorem{theorem}{Theorem}[section] \newtheorem{proposition}[theorem]{Proposition} \newtheorem{lemma}[theorem]{Lemma} \newtheorem{corollary}[theorem]{Corollary} \theoremstyle{definition} \newtheorem{definition}[theorem]{Definition} \theoremstyle{remark} \newtheorem{remark}[theorem]{Remark} \newtheorem{example}[theorem]{Example} \newcommand{\one}{\mathbf1} \newcommand{\C}{\mathcal C} \newcommand{\D}{\mathcal D} \newcommand{\Q}{\mathcal Q} \newcommand{\T}{\mathcal T} \newcommand{\V}{\mathcal V} \DeclareMathOperator{\Ind}{Ind} \DeclareMathOperator{\Hom}{Hom} \DeclareMathOperator{\End}{End} \DeclareMathOperator{\Ext}{Ext} \DeclareMathOperator{\Sym}{Sym} \DeclareMathOperator{\Rep}{Rep} \DeclareMathOperator{\Ver}{Ver} \renewcommand{\Vec}{\operatorname{Vec}} \DeclareMathOperator{\sVec}{sVec} \DeclareMathOperator{\Mod}{Mod} \DeclareMathOperator{\ad}{ad} \DeclareMathOperator{\im}{im} \DeclareMathOperator{\id}{id} \DeclareMathOperator{\ev}{ev} \DeclareMathOperator{\coev}{coev} \DeclareMathOperator{\coker}{coker} \DeclareMathOperator{\gr}{gr} \numberwithin{equation}{section} \title[The Benson--Etingof--Ostrik conjecture] {The Benson--Etingof--Ostrik conjecture} \date{10 November 2026} \begin{document} \begin{abstract} We prove the conjecture of Benson--Etingof--Ostrik (2023): every symmetric tensor category of moderate growth over an algebraically closed field of positive characteristic admits a symmetric tensor functor to a higher Verlinde category, possibly of infinite height. Using maximal nilpotence and geometric reductivity, we reduce the problem to proving that finitely generated maximally nilpotent tensor categories are finite. The main ingredients are the construction of generic points using alternating norms and a Frobenius reduction of the fundamental coend to an ordinary Hopf subalgebra. \end{abstract} \maketitle \part{All positive characteristics} \label{part:all} \section{Main theorem and preliminaries}\label{sec:inputs} We follow \cite{EGNO} for the basic conventions on tensor categories, duality, ind-completions, Deligne products, and extension groups. All tensor categories are symmetric, with \(\End(\one)=k\); tensor functors are exact, symmetric, and linear over the indicated ground field. Unless a different hypothesis is stated, the ground field \(k\) is algebraically closed of characteristic \(p>0\). The main theorem resolves the conjecture of Benson, Etingof, and Ostrik \cite[Conjecture 1.4]{BEO} in full generality. \begin{theorem}[Benson--Etingof--Ostrik conjecture]\label{thm:main} Let \(k\) be an algebraically closed field of characteristic \(p>0\). For every symmetric tensor category \(\C\) over \(k\) of moderate growth, there exists an exact faithful \(k\)-linear symmetric monoidal functor \[ F:\C\longrightarrow\Ver_{p^\infty,k}. \] If \(\C\) is finitely generated, \(F\) factors through \(\Ver_{p^r,k}\) for some finite \(r\ge1\); in particular, \(\C\) fibres over a finite tensor category. \end{theorem} Here \(\Ver_{p^r,k}\) is the finite higher Verlinde category of height \(r\) \cite{BEO}. We omit \(k\) when it is fixed, and put \(\Ver_{p^\infty,k}=\bigcup_{r\ge1}\Ver_{p^r,k}\) under the standard tensor embeddings. A fibre functor with target \(\D\) means a tensor functor to \(\D\). Theorem~\ref{thm:mn-finite} proves the intermediate assertion that finitely generated maximally nilpotent (MN) categories are finite. Moderate growth is automatic for MN categories by Lemma~\ref{lem:mn-consequences}(4). The finiteness proof uses the ordinary-coend results established in Parts~\ref{part:odd} and~\ref{part:two}. Proposition~\ref{prop:mn-embedding} then passes from finite MN categories to arbitrary MN categories by constructing a countable cofinal chain and gluing its embeddings. Section~\ref{sec:extensions} also proves that every tensor subcategory of an MN category in odd characteristic is Serre. \subsection*{Notation specific to this paper} A tensor subcategory is full and closed under subquotients, finite sums, tensor products, and duals; it need not be closed under extensions. Write \(\langle G\rangle\) for the tensor subcategory generated by \(G\). Thus \emph{finitely generated} means \(\C=\langle G\rangle\), whereas \emph{finite} has the usual meaning of \cite[Section 1.8]{EGNO}: equivalence as an abelian category to finite-dimensional modules over a finite-dimensional algebra. Write \(\ell(X)\) for composition length. Moderate growth means that for every \(X\) some \(b_X>0\) satisfies \(\ell(X^{\otimes n})\le b_X^n\) for all \(n\ge1\). We use \(\one\), \(X^*\), \(\ev_X\), \(\coev_X\), and \(c_{X,Y}\) for the unit, dual, evaluation, coevaluation, and symmetry. An invertible object is also called a \emph{line}; it is \emph{even} if its self-symmetry is the identity. The categories of vector spaces and super vector spaces are denoted by \(\Vec_k\) and \(\sVec_k\). An \emph{ordinary} ind-object is a direct sum of copies of \(\one\). A \emph{finite object} is an object of \(\C\), as opposed to an arbitrary object of \(\Ind\C\). Algebras are commutative and unital ind-algebras unless stated otherwise. We write \(\Sym^nX=(X^{\otimes n})_{S_n}\) for ordinary symmetric powers and \(\Sym X=\bigoplus_{n\ge0}\Sym^nX\). An algebra is finitely generated if it is a quotient of \(\Sym X\) for a finite \(X\); an \(A\)-module is finitely generated if it is a quotient of \(A\otimes X\) for such an \(X\). We write \(\Mod_A(\Ind\C)\) for all \(A\)-modules in \(\Ind\C\), with relative tensor product \(\otimes_A\). \subsection*{Alternating norms} For the action of \(S_n\) through the symmetry, put \[ a_n^X=\sum_{\sigma\in S_n}\operatorname{sgn}(\sigma)\sigma, \qquad A_n(X)=\im a_n^X,\qquad \ad(X)=\sup\{n\ge0:A_n(X)\ne0\}. \] We call \(a_n^X\) the antisymmetrizer or alternating norm, and \(\ad(X)\) its top nonzero degree. We use \(A_0(X)=\one\) and \(\ad(0)=0\). There is no factorial division; in characteristic two all the signs are \(1\). In positive characteristic, over any field, moderate growth is equivalent to finiteness of these degrees, and \[ \ell(X)\le\ad(X),\qquad \ad(X\otimes Y)\le\ad(X)\ad(Y) \] \cite[Proposition 4.7(4), Lemma 4.8, and Corollary 4.11]{FE}. The top nonzero norm image is an even line (Lemma~\ref{lem:top-line}). \subsection*{Existence and descent} A category is \emph{incompressible} if every outgoing tensor functor embeds it as a tensor subcategory. A tensor functor is \emph{surjective} if every target object is a subquotient of an image, as in \cite[Definition 3.1.4]{CEO}. We use the following established results. \begin{enumerate} \item Every category of moderate growth over an algebraically closed field admits a surjective tensor functor to an incompressible category of moderate growth \cite[Theorem 5.2.1]{CEO}. Its target is finitely generated if the source is. \item Every finite tensor category over \(k\) admits a tensor functor to a finite higher Verlinde category \cite[Theorem B]{CF}, the finite Benson--Etingof--Ostrik theorem. The Verlinde categories are defined over the prime field \cite[Section 4.9]{BEO}; their scalar extension is made explicit in the proof of Theorem~\ref{thm:main}. \item If \(\V\) is MN and geometrically reductive, then an exact \(k\)-linear symmetric monoidal functor \(\C\to\Mod_R(\Ind\V)\), for a nonzero commutative ind-algebra \(R\), implies the existence of a tensor functor \(\C\to\V\) \cite[Appendix B, Theorem B.1]{AF}. \end{enumerate} MN is defined in Section~\ref{sec:mn}. Geometric reductivity (GR) means that every epimorphism \(X\twoheadrightarrow\one\) has a split positive symmetric power. We prove MN implies GR in Section~\ref{sec:gr}. The Frobenius reduction used for finiteness is stated at its point of use in Section~\ref{sec:coends}. We also use Gabriel localization: quotienting a Grothendieck category by a Serre subcategory closed under coproducts gives an exact quotient functor with a fully faithful right adjoint \cite[Section 1.2]{Gabriel}. The next two sections establish the tensor structure and finiteness properties of our particular quotient. \section{A highest-norm identity and flatness} This section and Section~\ref{sec:generic} allow an arbitrary ground field of positive characteristic, except where stated otherwise. \begin{lemma}[Parametrized inner inverse]\label{lem:inner-inverse} Let \(\mathcal M\) be an additive symmetric monoidal category with additive tensor product. Let \(P,Q\) be dualizable, and \(0\ne f:P\to Q\). Suppose either \(a_n^P=0\) for all sufficiently large \(n\), or \(a_n^Q=0\) for all sufficiently large \(n\). There are a dualizable object \(T\), a nonzero map \(t:T\to\one\), and \(g:T\otimes Q\to P\) such that \begin{equation}\label{eq:inner-inverse} fg(\id_T\otimes f)=f(t\otimes\id_P). \end{equation} If \(\mathcal M\) is abelian with simple unit, \(t\) is epic. \end{lemma} \begin{proof} Choose the largest \(n\ge1\) for which \[ F_n=a_n^Q f^{\otimes n}=f^{\otimes n}a_n^P\ne0. \] Put \(T=(Q^{\otimes n})^*\otimes P^{\otimes n}\), and define \[ t=\ev_{Q^{\otimes n}}(\id\otimes F_n):T\longrightarrow\one. \] The duality bijection \(\Hom(P^{\otimes n},Q^{\otimes n}) \simeq\Hom(T,\one)\) makes \(t\ne0\). This is a matrix-coefficient map, not a trace. The coset decomposition of \(S_{n+1}\) gives the following integral identity, with object superscripts suppressed and \((i,n+1)\) denoting the transposition of positions \(i\) and \(n+1\): \begin{equation}\label{eq:cosets} a_{n+1}=(a_n\otimes\id) \left(\id-\sum_{i=1}^n(i,n+1)\right). \end{equation} Apply it to \(f^{\otimes(n+1)}\) and evaluate its first \(n\) outputs against \((Q^{\otimes n})^*\). Its left side is zero. The identity term on the right is \(f(t\otimes\id_P)\). Here is an explicit factorization of the other terms. Let \[ b_i:P^{\otimes n}\otimes Q\longrightarrow Q^{\otimes n}\otimes P \] interchange the \(i\)-th parameter and the last input, apply \(f\) to the other \(n-1\) parameter factors, and leave the last output factor unchanged. Define \[ g_i=(\ev_{Q^{\otimes n}}\otimes\id_P) (\id\otimes a_n^Q\otimes\id_P) (\id\otimes b_i). \] Naturality of the symmetry gives the explicit identification \[ (\ev_{Q^{\otimes n}}\otimes\id_Q) \bigl(\id\otimes[(a_n^Q\otimes\id_Q) f^{\otimes(n+1)}(i,n+1)_P]\bigr) =fg_i(\id_T\otimes f). \] Thus \(g=\sum_i g_i\) gives \eqref{eq:inner-inverse}. The construction uses neither scalar points nor factorial division; all signs come from the symmetry. If the unit is simple, every nonzero map to it is epic. \end{proof} In an abelian monoidal category with right exact tensor product, an object \(M\) is \emph{flat} if \(M\otimes-\) is exact. A monomorphism is \emph{pure} if it stays monic after tensoring with any object. \begin{lemma}[Purity of an image]\label{lem:purity} Suppose \(\mathcal M\) is abelian symmetric monoidal, tensor product is right exact, and the unit is simple. Let \(f:P\to Q\) satisfy Lemma~\ref{lem:inner-inverse}. Then \(\im(f)\hookrightarrow Q\) remains monic after tensoring with any object. If \(Q\) is flat, \(\coker f\) is flat. \end{lemma} \begin{proof} Write \(f=j\pi\), where \(\pi:P\twoheadrightarrow I=\im f\) and \(j:I\hookrightarrow Q\). Set \(r=\pi g\). Cancel \(j\) in \eqref{eq:inner-inverse}, and descend along the epimorphism \(\id_T\otimes\pi\). This gives \begin{equation}\label{eq:purity} r(\id_T\otimes j)=t\otimes\id_I. \end{equation} For any \(M\), let \(J=\ker(j\otimes\id_M)\). Restrict \eqref{eq:purity}, tensored with \(M\), to \(T\otimes J\). It says that the composite \[ T\otimes J\xrightarrow{\,t\otimes\id_J\,}J \hookrightarrow I\otimes M \] is zero. The first arrow is epic by right exactness, so \(J=0\). This proves purity without assuming that \(M\) is flat. For completeness, let \(M'\hookrightarrow M\) have cokernel \(M''\). Purity gives exact rows \[ 0\longrightarrow I\otimes M'\longrightarrow Q\otimes M' \longrightarrow(\coker f)\otimes M'\longrightarrow0 \] and the analogous row for \(M\). Flatness of \(Q\), together with the monomorphisms from \(I\), makes both left vertical arrows monic. The snake lemma identifies the possible kernel on the right with the kernel of \(I\otimes M''\to Q\otimes M''\). This is zero by purity. Hence \(\coker f\) is flat. \end{proof} \begin{remark}\label{rem:presentations} For an ind-algebra \(A\) in a tensor category, call \(A\otimes X\), with \(X\) finite, \emph{finite free}. Such objects need not be projective. Nevertheless every \(A\)-module is a filtered colimit of cokernels of maps between finite free modules. Indeed, take a free cover \(P=\bigoplus_{\alpha}(A\otimes X_\alpha)\twoheadrightarrow M\). For each finite subsum \(P_J\), its relation module \(\ker(P_J\to M)\) is the union of images of finite free modules. Take the cokernels of all finite sets of these relations in all such \(P_J\). These form a filtered system with colimit \(M\). Each is a cokernel of a map \(A\otimes X\to A\otimes Y\). The relevant compactness is just \[ \Hom_A(A\otimes X,-)=\Hom_{\Ind\C}(X,-), \] which commutes with filtered colimits. It does not assert projectivity; on the right, the module's \(A\)-action is forgotten. \end{remark} \section{The generic category of a domain}\label{sec:generic} For subobjects \(E,F\subset A\), their product is the image of \(E\otimes F\to A\); similarly, \(E^n\) denotes the image of \(E^{\otimes n}\to A\) under multiplication. An ideal of \(A\) is an \(A\)-submodule of its regular module. A nonzero algebra is \emph{simple} if its only ideals are zero and itself. The ideal generated by \(E\) is \(AE=\im(A\otimes E\to A)\). It is \emph{finitely generated} when \(E\) can be chosen finite. For an ideal \(I\) and an \(A\)-module \(M\), write \(IM=\im(I\otimes_A M\to M)\); \(I\) annihilates \(M\) if \(IM=0\). We call \(A\ne0\) a \emph{domain} if the product of any two nonzero ideals is nonzero. This definition is internal to the tensor category. \begin{lemma}[Torsion localization]\label{lem:torsion} Let \(A\) be a domain in \(\Ind\C\). Let \(\T_A\) consist of the modules that are unions of submodules annihilated by nonzero finitely generated ideals of \(A\). These are called \emph{torsion} modules; \emph{torsion free} means having no nonzero torsion submodule. Then \(\T_A\) is a localizing Serre tensor ideal, where tensor ideal means closed under tensoring with arbitrary \(A\)-modules. The Gabriel quotient \[ \Q_A=\Mod_A(\Ind\C)/\T_A,\qquad q:\Mod_A(\Ind\C)\longrightarrow\Q_A \] is a nonzero Grothendieck category with a right exact symmetric tensor product that is cocontinuous, meaning colimit-preserving, in each variable. The functor \(q\) is exact and strong symmetric monoidal, and \(qA\) is its simple tensor unit. The tensor product on \(\Q_A\) is induced by \(\otimes_A\); we write it simply as \(\otimes\). \end{lemma} \begin{proof} Products of nonzero finitely generated ideals are again nonzero and finitely generated. A finite sum of annihilated submodules is therefore annihilated by one such ideal. Closure under subobjects, quotients, and sums follows. For extension closure, take an extension with torsion endpoints and a finitely generated submodule \(E\) of its middle term. Its image in the quotient is killed by a nonzero finitely generated ideal \(I\). Hence \(IE\) lies in the torsion submodule. The module \(IE\) is finitely generated: tensor finite free covers of \(I\) and \(E\), and use right exactness. Thus \(JIE=0\) for another nonzero finitely generated ideal \(J\). Since every module is the union of its finitely generated submodules, extension closure follows. Tensoring an \(I\)-annihilated module with any module preserves annihilation; colimits give the tensor-ideal assertion. Tensor descent requires checking kernels, not just cokernels. Suppose \(j:M'\hookrightarrow M\) has cokernel killed by a nonzero ideal \(I\). The action \(I\otimes_A M\to M\) factors through \(M'\). Its restriction to \(I\otimes_A M'\) agrees with the action on \(M'\): compose with \(j\) and cancel that monomorphism \emph{before} tensoring further. For an arbitrary module \(N\), the action on \(M'\otimes_A N\) therefore factors as \[ I\otimes_A M'\otimes_A N \longrightarrow I\otimes_A M\otimes_A N \longrightarrow M'\otimes_A N. \] It kills \(\ker(j\otimes_A\id_N)\). The cokernel after tensoring is killed by \(I\) as well. If \(M/M'\) is only locally torsion, write it as a filtered union of annihilated submodules and take their inverse images in \(M\). Exactness of filtered colimits expresses the kernel after tensoring as a union of the just-considered kernels. For an epimorphism with torsion kernel, right exactness suffices. Thus tensoring preserves every morphism with torsion kernel and cokernel, and descends to the Gabriel quotient. The usual localization theorem gives the Grothendieck category, the exact quotient functor, and its fully faithful right adjoint \(q_*\). Tensor preserves colimits in the quotient: lift a diagram by \(q_*\), compute its colimit before applying \(q\), and use that both \(q\) and the original relative tensor product preserve colimits. The symmetry and associativity constraints descend. There is no nonzero torsion ideal in \(A\): a nonzero finite subobject of such an ideal would generate a nonzero ideal whose product with another nonzero ideal is zero. Consequently \(qA\ne0\). For every nonzero ideal \(I\), choose a nonzero finitely generated ideal inside \(I\); it kills \(A/I\). Thus \(qI\simeq qA\). Every subobject \(U\subset qA\) is the image of an ideal of \(A\). Explicitly, pull back \(q_*U\subset q_*qA\) along \(A\to q_*qA\), and apply the exact functor \(q\). Hence \(qA\) is simple. \end{proof} \begin{theorem}[The generic tensor category]\label{thm:generic} Suppose every object of \(\C\) has finite alternating norm degree. For a domain \(A\), tensor product in \(\Q_A\) is exact. Every object of \(\Q_A\) is a union of finite-length subobjects. The full finite-length subcategory \(\D_A\) is a tensor category over the field \[ K_A=\End_{\Q_A}(qA). \] Scalars on the nonzero unit give an embedding \(k\hookrightarrow K_A\). The functor \[ F_A:\C\longrightarrow\D_A,\qquad X\longmapsto P_X=q(A\otimes X) \] is \(k\)-linear, exact, faithful, and strong symmetric monoidal, with \begin{equation}\label{eq:length-bound} \ell(P_X)\le\ad(X). \end{equation} Every object of \(\D_A\) is a quotient of some \(P_X\). If \(\C\) has moderate growth in positive characteristic, then so does \(\D_A\). The field \(K_A\) need not equal \(k\); equality is proved under the additional hypotheses of Lemma~\ref{lem:point}. \end{theorem} \begin{proof} The \(P_X\) are dualizable, with dual \(P_{X^*}\), and generate \(\Q_A\) under sums and quotients. Tensoring by a dualizable object has both adjoints, so the \(P_X\) are flat. They inherit vanishing of high alternating norms. For every nonzero map \(f:P_X\to P_Y\), Lemmas~\ref{lem:inner-inverse} and \ref{lem:purity} show that \(\coker f\) is flat; this is also true when \(f=0\). Apply \(q\) to the filtered presentations in Remark~\ref{rem:presentations}. Every object of \(\Q_A\) is a filtered colimit of these flat cokernels. Filtered colimits are exact and commute with tensor product, so every object is flat. Tensor product is therefore exact. Tensor products of nonzero objects are nonzero. A nonzero map \(P_X\to M\) transposes to a nonzero map \(qA\to M\otimes P_{X^*}\), which is monic because \(qA\) is simple. Tensoring it with \(N\ne0\) proves \(M\otimes N\ne0\). We adapt the filtration argument of \cite[Lemma 4.9]{FE} to this setting, where finite length is not yet known. Suppose an object \(P\) has a strict finite filtration with \(d\) nonzero factors \(Q_1,\ldots,Q_d\). Exact tensor product gives the usual tensor filtration, whose associated graded is \((\bigoplus_iQ_i)^{\otimes d}\), compatibly with permutations. On the ordered summand \(Q_1\otimes\cdots\otimes Q_d\), the composite of the alternating norm and projection back to that summand is the identity: every other permutation lands in a different ordered summand. This summand is nonzero. Thus \(a_d^P\ne0\). Applied to \(P_X\), this proves \eqref{eq:length-bound}, without assuming finite length in advance. Images of finite sums of the \(P_X\) exhaust every object. They have finite length, proving local finite length. A finite-length object \(M\) is a quotient of one \(P_Y\); its kernel is again finite-length and is covered by a \(P_X\). Hence \[ P_X\longrightarrow P_Y\longrightarrow M \longrightarrow0. \] The category is closed monoidal: cocontinuous tensor functors on a Grothendieck category have right adjoints. The internal Hom \(\underline{\Hom}(M,N)\) is characterized by \[ \Hom(U,\underline{\Hom}(M,N))\simeq\Hom(U\otimes M,N). \] Set \(M^\vee=\underline{\Hom}(M,qA) =\ker(P_{Y^*}\to P_{X^*})\), a finite-length object. For \(P=P_X,P_Y\), dualizability makes the canonical map \[ \underline{\Hom}(P,qA)\otimes N \longrightarrow\underline{\Hom}(P,N) \] an isomorphism. Left exactness of internal Hom in its first variable and exactness of \(-\otimes N\) identify the corresponding map for \(M\) with the isomorphism \[ M^\vee\otimes N \xrightarrow{\sim}\ker(P_{Y^*}\otimes N\to P_{X^*}\otimes N) =\underline{\Hom}(M,N). \] Invertibility of this canonical map for every \(N\) is equivalent to dualizability of \(M\): its adjunction unit and counit give coevaluation and evaluation, with the duality identities. Thus \(M\) is dualizable with dual \(M^\vee\). Tensor products of finite-length objects are finite-length, since they are quotients of objects \(P_X\otimes P_Y=P_{X\otimes Y}\). The endomorphism ring of the simple unit is a division ring, and is commutative by the monoidal unit axioms. It is the field \(K_A\). Independent maps \(qA\to V\) give a monomorphism from the corresponding finite sum of units. Consequently \[ \dim_{K_A}\Hom(qA,V)\le\ell(V),\qquad \dim_{K_A}\Hom(M,N)\le\ell(M^\vee\otimes N). \] This proves Hom-finiteness. Essential smallness follows because the \(P_X\) form a set and, up to isomorphism, the quotients of each object in a Grothendieck category form a set. These establish all the tensor-category axioms for \(\D_A\). For \(M\) a quotient of \(P_X\), the norm bounds give \[ \ell(M^{\otimes n})\le\ell(P_{X^{\otimes n}}) \le\ad(X^{\otimes n})\le\ad(X)^n. \] This proves moderate growth. Finally \(F_A\) is exact because free modules and \(q\) are exact. For \(X\ne0\), coevaluation is monic \(\one\hookrightarrow X\otimes X^*\); its image under \(F_A\) prevents \(F_A(X)\) from vanishing. An exact functor that detects nonzero objects is faithful. In particular it preserves alternating norm degree exactly. \end{proof} \begin{corollary}[Simple commutative algebras]\label{cor:simple-flat} Let \(\C\) have moderate growth over a field of positive characteristic. Every simple commutative ind-algebra \(A\) is \emph{absolutely flat}: tensor product \(\otimes_A\) is exact on \(\Mod_A(\Ind\C)\). Moreover, \[ \ell_A(A\otimes X)\le\ad(X)\qquad(X\in\C), \] where \(\ell_A\) denotes length in the module category. Thus \(A\) is \emph{artinian} in the terminology of \cite{AF}: every finite free \(A\)-module has finite length. \end{corollary} \begin{proof} A simple algebra is a domain, and its only nonzero ideal is \(A\). Consequently \(\T_A=0\), so Theorem~\ref{thm:generic} applies directly to \(\Q_A=\Mod_A(\Ind\C)\). \end{proof} This answers \cite[Questions 3.27--3.28]{AF} for moderate-growth categories in positive characteristic. \begin{corollary}[Scalar extension]\label{cor:scalar-extension} Let \(\C\) have moderate growth in positive characteristic over a field \(k\), and let \(L/k\) be a field extension. The finite-length \(L\)-modules in \(\Ind\C\) form a moderate-growth tensor category \(\C_L\) over \(L\). The functor \(X\mapsto L\otimes_kX\) is exact, faithful, strong symmetric monoidal, and surjective. It preserves finite tensor generation. For \(X,Y\in\C\), \begin{equation}\label{eq:base-change-hom} \Hom_{\C_L}(L\otimes X,L\otimes Y) =L\otimes_k\Hom_\C(X,Y). \end{equation} \end{corollary} \begin{proof} Regard \(L\) as an ordinary commutative ind-algebra. Every subobject of a sum of units is again a sum of units, so its internal ideals are precisely its ordinary ideals. Thus \(L\) is simple and its torsion subcategory is zero. Apply Theorem~\ref{thm:generic} with \(A=L\). Since \(\End_L(L)=\Hom(\one,L)=L\), it gives the tensor category \(\C_L\) over \(L\), its moderate growth, and all the stated properties of free extension. In particular, every finite-length \(L\)-module is a quotient of some \(L\otimes X\); this gives surjectivity and preservation of finite generation. Finally, free-module adjunction and compactness of \(X\) give \eqref{eq:base-change-hom}. \end{proof} \begin{lemma}[A generic point over the original field]\label{lem:point} Let \(k\) be uncountable and algebraically closed of positive characteristic, and let \(\C\) have moderate growth. Let \(B\) be a finitely generated commutative ind-algebra, and let \(E\subset B\) be finite with \(E^n\ne0\) for all \(n\ge1\). There are a moderate-growth tensor category \(\D\) over \(k\), a tensor functor \(F:\C\to\D\), and a unital algebra morphism \[ \epsilon:F(B)\longrightarrow\one \] whose restriction to \(F(E)\) is nonzero. Here \(F\) on ind-objects means its colimit extension. \end{lemma} \begin{proof} Choose an ideal \(P\) maximal among those containing none of the \(E^n\). A chain union still avoids them, since each \(E^n\) is finite, so Zorn's lemma applies. If ideals \(I,J\) are not contained in \(P\), maximality gives \(E^a\subset P+I\) and \(E^b\subset P+J\) for some \(a,b\). Then \(E^{a+b}\subset P+IJ\), so \(IJ\not\subset P\). Therefore \(A=B/P\) is a domain. Write \(\overline E\) for the image of \(E\) in \(A\). Every nonzero ideal of \(A\) contains some \(\overline E^n\), again by maximality. Thus the nonzero ideals \[ J_n=A\overline E^n \] are a decreasing cofinal family among all nonzero ideals. The module \(A\) is torsion free. The morphism formula for a Serre quotient therefore gives \[ K_A=\varinjlim_{0\ne I\subset A}\Hom_A(I,A) =\varinjlim_n\Hom_A(J_n,A). \] The transition maps are restriction along smaller ideals. Restriction to generators gives an injection \[ \Hom_A(J_n,A)\hookrightarrow\Hom_{\Ind\C}(\overline E^n,A). \] Because \(B\), and hence \(A\), is finitely generated, it is a countable union of finite objects. Each of these Hom spaces is consequently countable-dimensional, and so is \(K_A\) over \(k\). If \(t\in K_A\) were transcendental, the elements \((t-c)^{-1}\), \(c\in k\), would be linearly independent: clear denominators in a finite relation and evaluate at each distinct \(c\). This contradicts countable dimension. Thus \(K_A/k\) is algebraic and \(K_A=k\). Use \(\D=\D_A\) and \(F=F_A\) from Theorem~\ref{thm:generic}. The map \(A\otimes B\to A\), induced by multiplication and \(B\to A\), gives \(\epsilon\) after applying \(q\). Its image on \(A\otimes E\) is \(J_1\). Since \(qJ_1\simeq qA\), the restriction to \(F(E)\) is even epic. \end{proof} \section{Maximal nilpotence from generic points}\label{sec:mn} Throughout this section the ground field is algebraically closed. For \(X\in\C\), let \[ \widetilde X=\ker\bigl(X\longrightarrow \Hom(X,\one)^*\otimes\one\bigr). \] The displayed map is the maximal quotient that is a sum of units; it is epic. A \emph{nilpotent subobject} \(E\subset B\) means that the multiplication map \(E^{\otimes n}\to B\) vanishes for some \(n\ge1\). \begin{definition}\label{def:mn} A category is \emph{maximally nilpotent}, abbreviated MN, if \(\widetilde X\), in degree one of \(\Sym(X)\), is nilpotent for every \(X\). Equivalently the image of \(\Sym(\widetilde X)\to\Sym(X)\) is finite. This is the maximal-unit-quotient formulation of MN \cite[Theorem 7.2.2]{CEO}. \end{definition} Finite MN categories are incompressible by \cite[Theorem 7.2.3(2)]{CEO}. The next proposition proves a converse over an uncountable field without assuming finiteness. \begin{proposition}\label{prop:incompressible-mn} Over an uncountable algebraically closed field of positive characteristic, every incompressible tensor category of moderate growth is MN. \end{proposition} \begin{proof} If \(\widetilde X\) were nonnilpotent in \(B=\Sym(X)\), Lemma~\ref{lem:point} would give \(F\) and an algebra map \(F(B)\to\one\) nonzero on \(F(\widetilde X)\). Its degree-one restriction is a map \(F(X)\to\one\). Incompressibility makes \(F\) full, so this map is \(F(v)\) for some \(v:X\to\one\). Every such \(v\) vanishes on \(\widetilde X\), a contradiction. \end{proof} \begin{lemma}[Consequences of maximal nilpotence]\label{lem:mn-consequences} In an MN category: \begin{enumerate} \item If \(\Hom(X,\one)=0\), then \(\Sym(X)\) is finite. \item Every tensor functor over the ground field out of the category is full. \item Every even invertible object is the unit. \item The category has moderate growth. \end{enumerate} MN passes to tensor subcategories. \end{lemma} \begin{proof} For (1), \(\widetilde X=X\). For (2), as in \cite[Theorem 7.2.3(1)]{CEO}, let \(F:\C\to\D\) be a tensor functor and \(\varphi:F(X)\to\one\). The induced algebra map \(F(\Sym X)\to\one\) shows that the restriction \(\psi:F(\widetilde X)\to\one\) has a zero tensor power. A nonzero map to the simple unit is epic and has epic tensor powers, so \(\psi=0\). Thus \(\varphi\) factors through \(F(X/\widetilde X)\), a finite sum of units, and lifts to \(X\to\one\). Duality now gives fullness on all morphism spaces. For (3), an invertible object is simple. If it is even, every ordinary symmetric power is its nonzero tensor power. A nonunit even invertible would contradict (1). For (4), part (1) gives \(\Sym^nL=0\) for some \(n\) whenever \(L\) is a nonunit simple. The symmetrizer \(\sum_{\sigma\in S_n}\sigma\), a nonzero element of \(kS_n\), then acts by zero on \(L^{\otimes n}\): its action factors through \(\Sym^nL\). Thus \(kS_n\to\End(L^{\otimes n})\) is not injective, and the same holds in every larger degree. By \cite[Proposition 4.7(6)]{FE}, we have \(\ad(L)<\infty\). Also \(\ad(\one)=1\). If \(L_1,\ldots,L_m\) are the composition factors of \(X\), exact tensor product gives a filtration of \(X^{\otimes n}\) with factors \(L_{i_1}\otimes\cdots\otimes L_{i_n}\). The norm bounds recalled in Section~\ref{sec:inputs} imply \[ \ell(X^{\otimes n}) \le\left(\sum_{i=1}^m\ad(L_i)\right)^n. \] This proves moderate growth directly, as in \cite[Lemma 5.4]{AF}, without assuming GR or finiteness. Inheritance is immediate from fullness of a tensor-subcategory inclusion and the definition of \(\widetilde X\). \end{proof} \begin{theorem}[Maximal nilpotence of higher Verlinde categories] \label{thm:verlinde-mn} Over any algebraically closed field of positive characteristic, \(\Ver_{p^r}\) is MN for every \(1\le r\le\infty\). \end{theorem} \begin{proof} First let \(r<\infty\), and choose an uncountable algebraically closed extension \(L/k\). The finite category \(\Ver_{p^r,L}\) has moderate growth and is incompressible by \cite[Theorem 4.71(ii)]{BEO}. Proposition~\ref{prop:incompressible-mn} therefore makes it MN. The scalar-extension functor \(F:\Ver_{p^r,k}\to\Ver_{p^r,L}\) is exact and faithful. Here the scalar extension agrees with the higher Verlinde category over \(L\), since its construction is defined over the prime field \cite[Section 4.9]{BEO}. Formula~\eqref{eq:base-change-hom} gives \[ \Hom(FX,\one)=L\otimes_k\Hom(X,\one), \qquad F(\widetilde X)=\widetilde{FX}. \] Moreover \(F\) commutes with symmetric powers. For every \(X\), MN over \(L\) makes the multiplication \(F(\widetilde X)^{\otimes n}\to\Sym^n(FX)\) zero for some \(n\). Faithfulness makes \(\widetilde X^{\otimes n}\to\Sym^nX\) zero, proving MN over \(k\). Finally, every object of \(\Ver_{p^\infty}\) belongs to a finite level. The full tensor inclusions preserve the maximal unit quotient and symmetric powers, so MN passes to the union. \end{proof} This result is also contained in \cite[Theorem A, Proposition 4.1]{CFNO}. \begin{remark}[Finite incompressible categories] A finite tensor category is MN if and only if it is incompressible, as also recorded in \cite[Proposition 4.3]{CFNO}. The forward implication is \cite[Theorem 7.2.3(2)]{CEO}. For the converse, \cite[Theorem B]{CF} gives a functor to a finite higher Verlinde category; incompressibility makes it a tensor-subcategory embedding. Apply Theorem~\ref{thm:verlinde-mn} and inheritance of MN. \end{remark} \section{Nilpotent kernels and geometric reductivity}\label{sec:gr} The top alternating norm supplies the invertible object used in the determinant argument. We follow the graded Hopf-algebra argument of \cite[Section 5, Proposition 5.1]{CFNO}. \begin{lemma}[The top component of a connected graded Hopf algebra] \label{lem:hopf-top} Let \(H=\bigoplus_{i=0}^n H_i\) be a not necessarily commutative Hopf algebra in \(\C\), with all structure maps respecting the grading, \(H_0=\one\), \(Z=H_n\ne0\), and invertible antipode \(S\). Then \(Z\) is invertible. Moreover, for a scalar \(s\in k\) with \(s^2=1\), \[ S|_Z=s\id_Z, \qquad c_{Z,Z}=s\id_{Z\otimes Z}. \] \end{lemma} \begin{proof} Write \(\mu\) and \(\Delta\) for multiplication and comultiplication. The Frobenius theorem for finite Hopf algebras \cite[Corollary 4.5]{Tak} gives an invertible object \(L\) and a morphism \(\lambda:H\to L\) such that the multiplication pairing \(\lambda\mu:H\otimes H\to L\) is nondegenerate. Thus its adjoint is an isomorphism \(\phi:H\xrightarrow{\sim}H^*\otimes L\). Here ``finite'' means that \(H\) is an object of \(\C\); the ambient category need not be finite. Multiplication vanishes on \(H_i\otimes H_j\) when \(i+j>n\). Consequently, without assuming that \(\phi\) preserves degree, its restriction to \(H_i\) factors as a monomorphism \[ H_i\lhook\joinrel\longrightarrow \bigoplus_{j=0}^{n-i}H_j^*\otimes L. \] For \(i=n\), this is a nonzero monomorphism \(Z\hookrightarrow L\). Since an invertible object is simple, it is an isomorphism. Both \(Z\) and \(Z\otimes Z\) therefore have endomorphism ring \(k\); write \(S|_Z=s\id_Z\) and \(c_{Z,Z}=t\id_{Z\otimes Z}\), where \(t^2=1\). Let \(\iota:Z\hookrightarrow H\) be the inclusion. Multiplicativity of \(\Delta\) and the antipode identity give, as maps \(H\otimes H\to H\otimes H\), \begin{equation}\label{eq:hopf-top-identity} (\mu\otimes\id_H)(S\otimes(\Delta\mu))(\Delta\otimes\id_H) =(\id_H\otimes\mu)(c_{H,H}\otimes\id_H)(\id_H\otimes\Delta). \end{equation} Indeed, substitute \(\Delta\mu=(\mu\otimes\mu) (\id_H\otimes c_{H,H}\otimes\id_H)(\Delta\otimes\Delta)\) on the left and cancel the adjacent antipode and multiplication using \(\mu(S\otimes\id_H)\Delta=\eta\varepsilon\), where \(\eta\) and \(\varepsilon\) are the unit and counit. Precompose \eqref{eq:hopf-top-identity} with \(\iota\otimes\iota\). Products of a top-degree factor with a positive-degree factor vanish. Since \(H_0=\one\), the two sides reduce respectively to \((S\iota)\otimes\iota\) and \(c_{H,H}(\iota\otimes\iota)\). Naturality of the symmetry gives \[ (S\iota)\otimes\iota =(\iota\otimes\iota)c_{Z,Z}. \] Cancelling the monomorphism \(\iota\otimes\iota\) shows \(s=t\). \end{proof} \begin{lemma}[The top alternating norm is an even line]\label{lem:top-line} Let \(X\ne0\) have finite alternating norm degree \(d=\ad(X)\). Then \(A_d(X)\) is invertible and its self-symmetry is the identity. \end{lemma} \begin{proof} Work in the tensor category \(\C^{\mathrm{gr}}\) of \(\mathbb Z/2\mathbb Z\)-graded objects of \(\C\), with symmetry \[ c'_{V,W}=(-1)^{ab}c_{V,W} \quad\text{for homogeneous parities }a,b. \] Put \(U=X\) in odd parity. This construction also applies when \(p=2\), when all the displayed signs are \(1\). There are two graded Hopf structures on \(\bigoplus_{m\ge0}U^{\otimes m}\) in \(\Ind\C^{\mathrm{gr}}\). The tensor Hopf algebra \(T(U)\) has concatenation product and coproduct determined by making \(U\) primitive. The shuffle Hopf algebra \(T^{\mathrm{sh}}(U)\) has deconcatenation coproduct: its component of bidegree \((i,m-i)\) is the canonical identification \(U^{\otimes m}=U^{\otimes i}\otimes U^{\otimes(m-i)}\). Its product on degrees \(i,j\) sums over all permutations of \(i+j\) positions that preserve the order within each of the two input blocks, acting through \(c'\). Partitioning permutations into such shuffles verifies the bialgebra identities. The connected grading supplies the antipode. The shuffle product is commutative for \(c'\). The algebra map \(T(U)\to T^{\mathrm{sh}}(U)\) that is the identity on \(U\) is a Hopf map, since \(U\) is primitive on both sides. In degree \(m\) this map is \(\sum_{\sigma\in S_m}\sigma\), with the action through \(c'\). On the underlying object \(X^{\otimes m}\), it is exactly \(a_m^X\): each transposition contributes the additional sign from the odd parity of \(U\). Its image \(H\) is therefore a commutative graded Hopf algebra with \[ H_m=A_m(X)\text{ placed in parity }m\bmod2, \qquad H=\bigoplus_{m=0}^d H_m. \] In particular, \(H\) is a finite object, \(H_0=\one\), and \(H_d\ne0\). It is generated by the primitive object \(U\), so its antipode, an algebra map by commutativity, acts on \(H_m\) by \((-1)^m\). It is thus invertible. Lemma~\ref{lem:hopf-top} makes \(H_d\) invertible and gives \(c'_{H_d,H_d}=(-1)^d\id\). Forgetting the grading is strong monoidal, so \(A_d(X)\) is invertible in \(\C\). Comparing the two symmetries gives \[ (-1)^{d^2}c_{A_d(X),A_d(X)}=(-1)^d\id. \] Since \(d^2\equiv d\pmod2\), the self-symmetry is the identity. This conclusion does not require \(d\) to be even. \end{proof} \begin{lemma}[Divided derivatives across a nilpotent kernel] \label{lem:hasse} Let \(\alpha:X\twoheadrightarrow\one\) have kernel \(K\), and put \(B=\Sym X\). Suppose that the multiplication map \(K^{\otimes N}\to B\) vanishes. If \(q=p^e\ge N\), with \(e\ge0\), there is a canonical isomorphism \[ D_q:B_{2q-1}\xrightarrow{\ \sim\ }B_{q-1}, \qquad B_n=\Sym^nX. \] Here \(D_r\) is the coefficient of \(z^r\) in translation by \(\alpha\), that is, in the algebra map \[ \tau:B\longrightarrow B\otimes k[z],\qquad x\longmapsto x+\alpha(x)z. \] The formula for generators denotes the morphism \(X\to B_1\oplus B_0z\), so does not assume vector-space points of \(X\). \end{lemma} \begin{proof} Let \(J=(K)\subset B\). Then \(J^N=0\) and \(B/J=\Sym(X/K)=k[t]\), with \(t\) of degree one. Translation fixes \(K\), so every coefficient \(D_r\) preserves \(J^j\). Write \(M_j=J^j/J^{j+1}\), and \(R_j=(M_j)_j\). The graded \(k[t]\)-module \(M_j\) is generated in degree \(j\) by the image of \(K^{\otimes j}\). Hence multiplication gives epimorphisms \[ u_{j,n}:R_j\longrightarrow(M_j)_n, \qquad u_{j,n}(v)=t^{n-j}v\quad(n\ge j). \] These are isomorphisms: \(D_r(R_j)=0\) for \(r>0\), and translation on the quotient is \(t\mapsto t+z\); taking the coefficient of \(z^{n-j}\) gives \(D_{n-j}u_{j,n}=\id_{R_j}\). These calculations use the induced \(k[t]\)-action on \(M_j\), not a choice of a lift \(\one\to X\). More generally, \begin{equation}\label{eq:layer-derivative} D_r u_{j,n}=\binom{n-j}{r}u_{j,n-r} \quad\text{when }n-r\ge j. \end{equation} For \(0\le j2\), Proposition~\ref{prop:ordinary-odd} identifies \(\D\) with \(\Vec\) or \(\sVec\). If \(p=2\), Proposition~\ref{prop:ordinary-mn} makes \(\D\) finite. Lemma~\ref{lem:coend} makes \(K=H_\D\) finite. Since \(H\) is a finitely generated \(K\)-module, it is a quotient of \(K\otimes W\) for some finite \(W\in\C\), so it too is finite. Apply the same lemma to conclude that \(\C\) is finite. \end{proof} \begin{corollary}\label{cor:finite-mn-embedding} Every finitely generated MN tensor category embeds as a tensor subcategory of a finite higher Verlinde category. \end{corollary} \begin{proof} It is finite by Theorem~\ref{thm:mn-finite}, and hence incompressible by \cite[Theorem 7.2.3(2)]{CEO}. Its functor to a finite higher Verlinde category supplied by \cite[Theorem B]{CF} is therefore a tensor-subcategory embedding. \end{proof} A tensor category is \emph{subterminal} if any two tensor functors with the same source and that target are isomorphic as symmetric monoidal functors. \begin{corollary}[Subterminality]\label{cor:verlinde-subterminal} The categories \(\Ver_{p^r}\), for \(1\le r\le\infty\), are subterminal. \end{corollary} \begin{proof} They are MN by Theorem~\ref{thm:verlinde-mn} and GR by Theorem~\ref{thm:mn-gr}. Apply \cite[Theorem 7.3.1]{CEO}, which states that every MN and GR category is subterminal. \end{proof} This conclusion is also recorded in \cite[Proposition 4.2]{CFNO}. \begin{proposition}[Embedding an arbitrary MN category] \label{prop:mn-embedding} Every MN tensor category over \(k\) embeds as a tensor subcategory of \(\Ver_{p^\infty,k}\). \end{proposition} \begin{proof} Let \(\mathcal A\) be MN. Its finitely generated tensor subcategories are finite and embed in finite higher Verlinde categories by Corollary~\ref{cor:finite-mn-embedding}. The classification \cite[Corollary 4.61]{BEO} shows that these subcategories have only countably many possible equivalence types. Within \(\mathcal A\), two such subcategories of the same type actually coincide. Indeed, let \(\D_1,\D_2\subset\mathcal A\) have a tensor equivalence \(E:\D_1\to\D_2\). Their join is finitely generated and MN, so embeds in \(\Ver_{p^\infty}\). The two resulting functors from \(\D_1\), one by its inclusion and the other through \(E\), are isomorphic by subterminality. Their essential images therefore agree. Full faithfulness of the embedding of the join gives \(\D_1=\D_2\). Enumerate these subcategories as \(\D_1,\D_2,\ldots\), repeating the last one if there are only finitely many, and choose generators \(G_i\) for them. Then \[ \mathcal E_n=\langle G_1\oplus\cdots\oplus G_n\rangle, \qquad \mathcal A=\bigcup_{n\ge1}\mathcal E_n \] is a cofinal increasing sequence of finite MN subcategories. Choose embeddings \(F_n:\mathcal E_n\to\Ver_{p^\infty}\). Subterminality gives monoidal isomorphisms \(F_{n+1}|_{\mathcal E_n}\simeq F_n\). Choose these for adjacent terms and compose them for longer intervals; this gives coherent transition isomorphisms. The functors therefore glue to \(F:\mathcal A\to\Ver_{p^\infty}\). Every coherence diagram for the tensor structure and every short exact sequence is contained in one stage, so \(F\) is symmetric monoidal and exact. Every pair of objects lies in one \(\mathcal E_n\), so \(F\) is fully faithful. Every subquotient of an image object already lies in the image of that same \(\mathcal E_n\), so \(F\) is a tensor-subcategory embedding. \end{proof} \section{Proof of the main theorem} \begin{proof}[Proof of Theorem~\ref{thm:main}] First suppose \(k\) is uncountable. By \cite[Theorem 5.2.1]{CEO}, choose a surjective tensor functor \(F:\C\to\mathcal I\) to an incompressible category of moderate growth. Proposition~\ref{prop:incompressible-mn} makes \(\mathcal I\) MN, and Proposition~\ref{prop:mn-embedding} embeds it in \(\Ver_{p^\infty,k}\). Composition proves the assertion over \(k\). For a general algebraically closed \(k\), choose an uncountable algebraically closed extension \(L\). Corollary~\ref{cor:scalar-extension} shows that \(\C_L\) has moderate growth. The preceding paragraph gives \(\C_L\to\Ver_{p^\infty,L}\). For each finite \(r\), the construction over the prime field \cite[Section 4.9]{BEO} identifies \((\Ver_{p^r,k})_L\) with \(\Ver_{p^r,L}\). Concretely, a projective generator realizes the finite category as modules over a finite-dimensional \(k\)-algebra; scalar extension replaces this algebra by its tensor product with \(L\). Thus \(\Ver_{p^r,L}\) is the category of finite-length \(L\)-modules in \(\Ind\Ver_{p^r,k}\), compatibly with the standard embeddings as \(r\) varies. Restricting along \(\C\to\C_L\) yields an exact \(k\)-linear strong symmetric monoidal functor \[ \C\longrightarrow \Mod_L(\Ind\Ver_{p^\infty,k}). \] The category \(\Ver_{p^\infty,k}\) is MN by Theorem~\ref{thm:verlinde-mn}, and geometrically reductive by Theorem~\ref{thm:mn-gr}. The neutrality theorem \cite[Appendix B, Theorem B.1]{AF}, which does not require finite generation of the source or finiteness of the target, therefore gives \(\C\to\Ver_{p^\infty,k}\). Finally, if \(\C=\langle G\rangle\), the image of \(G\) belongs to some \(\Ver_{p^r,k}\) with finite \(r\). Since that category is closed under tensor products, duals, sums, and subquotients, the entire functor factors through it. \end{proof} \begin{remark}[Uniqueness] The resulting tensor functor \(\C\to\Ver_{p^\infty,k}\) is unique up to isomorphism: \(\Ver_{p^\infty,k}\) is subterminal by Corollary~\ref{cor:verlinde-subterminal}. The same result gives uniqueness for any fixed finite target \(\Ver_{p^r,k}\) whenever such a functor exists. \end{remark} \begin{remark}[Ground fields and height] The uncountability assumption in Lemma~\ref{lem:point} ensures \(K_A=k\). The scalar-extension and neutrality argument above removes this assumption from Theorem~\ref{thm:main}. The proof gives no explicit bound on the height \(r\) in terms of a tensor generator. \end{remark} \begin{remark}[The generic quotient] A domain need not be simple: the domain \(k[x,y]\) in \(\Rep(\mathrm{SL}_2)\) has the proper stable ideal \((x,y)\). Passing to \(\Q_A\) makes the unit simple; this is the property used in the highest-norm argument. \end{remark} \part{Odd characteristic}\label{part:odd} Throughout this part, \(k\) is algebraically closed and \(p>2\). \section{Ordinary coends}\label{sec:ordinary-odd} We use the theorem that the maximal Tannakian and super-Tannakian subcategories are Serre, together with its consequence for categories whose semisimple objects form an integral fusion category \cite[Appendix, Theorem 7.1 and Proposition 7.2]{EG}. Here Tannakian and super-Tannakian mean admitting a tensor functor to \(\Vec_k\) and \(\sVec_k\), respectively. \begin{proposition}\label{prop:ordinary-odd} An MN tensor category \(\mathcal U\) with ordinary fundamental coend is equivalent to \(\Vec_k\) or \(\sVec_k\). \end{proposition} \begin{proof} By Corollary~\ref{lem:simple-coefficient}, all simples are invertible. The self-symmetry of an invertible object is a scalar \(\pm1\), and Lemma~\ref{lem:mn-consequences} makes every even invertible the unit. The product of two odd invertibles is even. Consequently there is at most one nonunit simple \(\varepsilon\), and if it exists then \(\varepsilon^{\otimes2}\simeq\one\) and its self-symmetry is \(-1\). The semisimple objects therefore form a tensor subcategory with at most two invertible simples, hence an integral fusion category. The cited theorem makes \(\mathcal U\) super-Tannakian. Its tensor functor to \(\sVec\) is full by MN and faithful by exactness. All short exact sequences split after this functor, so their splittings lift. Thus \(\mathcal U\) is semisimple, and its fully faithful image in \(\sVec\) is \(\Vec\) or \(\sVec\). \end{proof} \begin{example}[Parity of the top norm] The parity assertion concerns the norm images \(A_n(X)\); evenness describes their self-symmetry, while the integer \(d\) can be odd. For instance, \(\ad(\one)=1\) and \(A_1(\one)=\one\) is even. For example, let \(\varepsilon\) be the one-dimensional odd object of \(\sVec_k\). Each permutation \(\sigma\in S_n\) acts on \(\varepsilon^{\otimes n}\) by \(\operatorname{sgn}(\sigma)\), so \[ a_n^\varepsilon=n!\,\id_{\varepsilon^{\otimes n}},\qquad A_n(\varepsilon)= \begin{cases} \varepsilon^{\otimes n},&0\le nn/2\) and \(e=e_{21}\). Indeed, \(d^2\otimes d^2\) must vanish below degree \(n\); in degree \(n\) a possible leading term \(w\otimes w\) would equal \(e+e_{21}\). The latter has zero diagonal in a homogeneous basis, forcing \(w=0\), and then \(e=e_{21}\). Since \(k\) is perfect, write \[ e=v\otimes v+h+h_{21}, \] where \(v\) lies in the degree-\(n/2\) piece of \(\gr B\), and \(v=0\) for odd \(n\). Take square roots of the diagonal entries to obtain \(v\), and use the remaining off-diagonal entries for \(h\). Both tensor factors of the error have positive degree, so choose lifts \(v\in\mathfrak m\) and \(h\in\mathfrak m\otimes\mathfrak m\). Twisting by \(1+h\) leaves the degree-\(n\) error \(v\otimes v\). If \(d=0\), replace it by \(v\). Otherwise twist further by \(1+d\otimes v\) and replace \(d\) by \(d+v\). More explicitly, modulo \(\mathcal F^{n+1}\), \[ \begin{aligned} &(1+v\otimes d)^{-1}(1+d\otimes d+v\otimes v)(1+d\otimes v)\\ &\hspace{3em}\equiv1+(d+v)\otimes(d+v). \end{aligned} \] Indeed, \(\deg(d^2)>n/2\) and \(\deg v\ge n/2>\deg d\) make all omitted products have degree greater than \(n\). For example, \((d\otimes d)(d\otimes v)=d^2\otimes dv\) has degree greater than \(n+\deg d\), and \((d\otimes v)(v\otimes d)\) has degree at least \(n+2\deg d\). The induction terminates because \(\mathfrak m\) is nilpotent; the product of its twists gives \(Q\). Finally \((1+d\otimes d)^2=1\) gives \(d^2\otimes d^2=0\), hence \(d^2=0\). \end{proof} \begin{proposition}\label{prop:ordinary-mn} Let \(k\) be algebraically closed of characteristic two. An MN tensor category \(\mathcal U\) with ordinary fundamental coend is finite. Its underlying abelian category is equivalent to \(\Vec_k\) or to finite-dimensional modules over \(k[d]/(d^2)\). \end{proposition} \begin{proof} Corollary~\ref{lem:simple-coefficient} and Lemma~\ref{lem:mn-consequences} show that the only simple of \(\mathcal U\) is \(\one\): every simple is invertible, and its self-symmetry is a scalar whose square is \(1\), hence is \(1\) in characteristic two. Thus length is multiplicative under tensor products, \(\mathcal U\) has moderate growth, and its Frobenius--Perron dimension is composition length. By \cite[Proposition 7.4]{EO}, \[ \mathcal U_{\mathrm{ex}} =\{X\in\mathcal U:\ell(\operatorname{Fr}X)=\ell(X)\} \] is a Frobenius-exact tensor subcategory. The cited proposition requires finitely many simples, not a finite category. It admits a tensor functor to \(\Vec\) by \cite[Theorem 1.1]{FE}. It inherits MN, so this functor is full. Consequently \(\mathcal U_{\mathrm{ex}}=\Vec\) inside \(\mathcal U\). \emph{Commutative reconstruction.} Extend the identity on \(\Vec\subset\mathcal U\) to an exact faithful quasi-tensor functor \(F:\mathcal U\to\Vec\), using \cite[Appendix, Proposition 7.5]{EG}. Exactness gives \(\dim F(X)=\ell(X)\). Coalgebra reconstruction identifies \(\mathcal U\) with the finite-dimensional continuous modules over the initially possibly noncommutative algebra \[ A=\operatorname{Nat}(F,F),\qquad J=\ker(A\longrightarrow\End(F(\one))=k). \] Use finite collections of objects containing \(\one\) to define the action topology. Then \(A\) is an inverse limit of finite-dimensional algebras. Elements of \(J\) lower composition filtrations, so these finite action quotients are local with residue field \(k\). Under reconstruction, \(F\) is the forgetful functor. Write \(\gamma_{X,Y}:F(X)\otimes F(Y)\to F(X\otimes Y)\) for its tensor isomorphisms and identify \(F(\one)=k\). The unit constraints identify \(\gamma_{\one,-}\) and \(\gamma_{-,\one}\) with units \(a,b\in A\) having the same value \(\lambda\in k^\times\) on \(\one\). Replacing \(\gamma_{X,Y}\) by \[ \lambda\,\gamma_{X,Y}(b_X^{-1}\otimes a_Y^{-1}) \] makes both unit isomorphisms the identity. We use this normalized quasi-tensor structure from now on. In fact \(A\) is commutative. The pairing \[ F(X^*)\otimes F(X)\xrightarrow{\gamma_{X^*,X}} F(X^*\otimes X)\xrightarrow{F(\ev_X)}k \] defines a natural map \(\delta_X:F(X^*)\to F(X)^*\). It is an isomorphism on \(\one\); both sides are exact contravariant functors, so induction on length makes it an isomorphism for every \(X\). This argument does not require associativity coherence for \(\gamma\). Thus, with \(H=H_{\mathcal U}\), \[ F(H)\simeq\int^{X\in\mathcal U}F(X)^*\otimes F(X). \] These vector-space identifications carry the natural map \[ \operatorname{Nat}(\id_{\mathcal U},\id_{\mathcal U}) \longrightarrow A,\qquad u\longmapsto F(u), \] to \(\Hom(H,\one)\to\Hom_k(F(H),k)\): the functional corresponding to \(u\) restricts on \(X^*\otimes X\) to \(\ev_X(\id_{X^*}\otimes u_X)\), and naturality of \(\gamma\) identifies its image with the functional for \(F(u_X)\). The map is bijective because \(H\) is ordinary. The map preserves composition, and natural endomorphisms of the identity commute. Hence \(A\) is commutative. \emph{Bounding each finite quotient.} Let \(B\) be a finite action quotient of \(A\), with maximal ideal \(\mathfrak m\). By reconstruction, its finite-dimensional modules are objects of \(\mathcal U\), via restriction of scalars. On pairs of \(B\)-modules, transport the symmetry through the quasi-tensor isomorphisms and remove the ordinary flip. This is a natural endomorphism of the ordinary tensor product of the two underlying vector spaces. Evaluating on regular modules identifies it with an element \(R_B\in B\otimes B\). The symmetry and unit axioms give \[ R_B\in1+\mathfrak m\otimes\mathfrak m,\qquad (R_B)_{21}R_B=1. \] Apply Lemma~\ref{lem:finite-r} to obtain \(Q_B,d_B\), and let \(X\in\mathcal U\) correspond to the cyclic module \(B/d_BB\). On \(F(X)\otimes F(X)\), the operator \(Q_{B,21}^{-1}R_BQ_B\) is the identity. Equivalently the transported symmetry \(\tau R_B\) is conjugate to the ordinary flip \(\tau\), since \[ \tau Q_{B,21}^{-1}R_BQ_B=Q_B^{-1}(\tau R_B)Q_B. \] The cohomology of \(1+\tau\) on \(V\otimes V\) has basis \([v_i\otimes v_i]\), for any basis \((v_i)\) of \(V\). Exactness of \(F\) and the Frobenius formula therefore give \(\ell(\operatorname{Fr}X)=\dim F(X)=\ell(X)\). Hence \(X\in\mathcal U_{\mathrm{ex}}=\Vec\). Thus \(B/d_BB\) is a nonzero cyclic trivial \(B\)-module, so is \(k\). Every \(b\in B\) is therefore \(\lambda+d_Bb'\). Since \(d_B^2=0\), this gives \(d_BB=kd_B\) and \(\dim_kB\le2\). Their duals form a directed union equal to the reconstruction coalgebra, so it too has dimension at most two, as does \(A\). The local algebra \(A\) is consequently \(k\) or \(k[d]/(d^2)\), and reconstruction proves the assertion. Only the action of \(R_B\) on the displayed module was used. 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