\section{Rigidity of lattice-supported modular distributions and the localization obstruction} \label{sec:rigidity} Expanding the spectrum of an admissible partition function to finite order about points of circle lattices produces a distribution on momentum space with discrete support. This section determines the distributions of this kind that are invariant under $\mathbb S$ and $\mathcal C$, and derives a quantitative consequence. The results are of three kinds. \begin{enumerate}[(a)] \item A tempered distribution that is supported on a finite union of circle lattices and invariant under $\mathbb S$ and $\mathcal C$ is a finite sum of polynomials in the boost generator $\mathcal K$ applied to circle combs (Theorems~\ref{thm:grid-rigidity}, \ref{thm:circle-union} and~\ref{thm:circle-jets}). In particular its local expansion at the origin is a multiple of $\delta_0$, and in the even sector it is a combination of radius derivatives of the circle Fock measures $\rhoF_r$. \item The statement about the origin has a finite quantitative form: finitely many Gaussian-mixture test functions bound every derivative coefficient at the origin of a $\mathcal C$-invariant distribution by its $\mathbb S$-defect (Theorem~\ref{thm:origin-certificate}), with at most a finite-power loss when one radius moves (Proposition~\ref{prop:moving-certificate}). \item The shifted vacuum of an admissible partition function contributes $-\frac a4(\partial_P^2+\partial_Q^2)\delta_0$ at the origin. Consequently the low spectrum cannot be localized, with a power-law error in a logarithmic window, on a fixed finite union of circle lattices together with one moving pair (Theorems~\ref{thm:fixed-localization} and~\ref{thm:moving-localization}). \end{enumerate} \subsection{Distributions with discrete support} \label{subsec:rig-conventions} In this section $T$ denotes a distribution on $\RR^2$. Multi-indices refer to the momentum coordinates, $\partial^\alpha=\partial_P^{\alpha_1}\partial_Q^{\alpha_2}$, and $\mathcal A_q=\{\alpha\in\NN^2:|\alpha|\leq q\}$. \paragraph{Local coefficients.} Let $S\subset\RR^2$ be closed and discrete. A distribution $T$ with $\supp T\subset S$ has a unique expansion \begin{equation}\label{eq:rig-local-form} T=\sum_{x\in S}\sum_{\alpha}c_\alpha(x)\,\partial^\alpha\delta_x , \end{equation} in which, for each $x$, only finitely many $c_\alpha(x)$ are nonzero; conversely every such array of complex numbers defines a distribution, the sum being locally finite. We say that $T$ has \emph{local order at most $q$} if $c_\alpha(x)=0$ whenever $|\alpha|>q$. The numbers $c_\alpha(0)$ with $|\alpha|\geq1$ are the \emph{positive-order origin coefficients} of $T$. A tempered distribution has finite order, so a tempered distribution with support in $S$ has local order at most $q$ for some $q<\infty$. A function \emph{vanishes to order at least $q+1$} at a point if all its derivatives of order at most $q$ vanish there. \begin{lemma}\label{lem:rig-local-pairing} Let $T$ be a tempered distribution with support in a closed discrete set $S$ and of local order at most $q$, with coefficients as in \eqref{eq:rig-local-form}. \begin{enumerate}[(i)] \item Let $F_0\subset S$ be finite and let $\psi$ be a Schwartz function that vanishes to order at least $q+1$ at every point of $S\setminus F_0$. Then \[ \langle T,\psi\rangle=\sum_{x\in F_0}\sum_{|\alpha|\leq q} (-1)^{|\alpha|}c_\alpha(x)\,\partial^\alpha\psi(x). \] \item Let $\omega$ be a smooth function, all of whose derivatives are polynomially bounded, that vanishes to order at least $q+1$ at every point of $S$. Then $\omega T=0$. \end{enumerate} \end{lemma} \begin{proof} (i) Let $\chi\in C_c^\infty(\RR^2)$ equal one near the origin and put $\chi_\varrho(X)=\chi(X/\varrho)$. Then $\chi_\varrho\psi\to\psi$ in the Schwartz space as $\varrho\to\infty$, so $\langle T,\psi\rangle=\lim_\varrho\langle T,\chi_\varrho\psi\rangle$. The support of $\chi_\varrho\psi$ meets finitely many points of $S$, and by \eqref{eq:rig-local-form} \[ \langle T,\chi_\varrho\psi\rangle=\sum_{x\in S}\sum_{|\alpha|\leq q} (-1)^{|\alpha|}c_\alpha(x)\,\partial^\alpha(\chi_\varrho\psi)(x). \] By the Leibniz rule the derivatives of order at most $q$ of $\chi_\varrho\psi$ vanish at every $x\in S\setminus F_0$, and for large $\varrho$ they agree with those of $\psi$ at the points of $F_0$. (ii) For a Schwartz function $f$, the function $\omega f$ is a Schwartz function vanishing to order at least $q+1$ on $S$, so $\langle\omega T,f\rangle=\langle T,\omega f\rangle=0$ by (i) with $F_0=\emptyset$. \end{proof} \paragraph{Translations, characters, reflections.} For $w\in\RR^2$ let $(\tau_wf)(X)=f(X+w)$ and $\chi_w(X)=e^{2\pi iB(w,X)}$; on distributions, $\langle\tau_wT,f\rangle=\langle T,\tau_{-w}f\rangle$, so that $\tau_w\delta_x=\delta_{x-w}$. From \eqref{eq:S-transform}, $\mathbb S(\chi_wf)=\tau_w\mathbb Sf$ and $\mathbb S(\tau_{-w}f)=\chi_w\mathbb Sf$ for Schwartz functions, and by duality $\mathbb S(\chi_wT)=\tau_w\mathbb ST$ for tempered $T$. Hence, for vectors $w_i$ and integers $m_i\geq0$, \begin{equation}\label{eq:rig-intertwine} \prod_i(\tau_{w_i}-I)^{m_i} =\mathbb S\circ\Bigl(\prod_i(\chi_{w_i}-1)^{m_i}\Bigr)\circ\mathbb S^{-1} \end{equation} on tempered distributions, the middle factor acting by multiplication. Let $\check T$ denote the image of $T$ under $X\mapsto-X$. Since $\mathbb S^2f=\check f$, the distribution $\mathbb S^{-1}T$ is the reflection of $\mathbb ST$; it has the same local orders as $\mathbb ST$, and its support is the reflection of that of $\mathbb ST$. If $T$ is even, then $\mathbb S^{-1}T=\mathbb ST$, and $\langle T,f\rangle=\langle T,f^{\rm ev}\rangle$ for every test function $f$. \paragraph{Lattices, grids and combs.} For a full-rank lattice $\Gamma\subset\RR^2$ the dual lattice with respect to the Lorentzian pairing is \[ \Gamma^\vee=\{w\in\RR^2:B(w,\lambda)\in\ZZ\text{ for all } \lambda\in\Gamma\},\qquad(\Gamma^\vee)^\vee=\Gamma . \] If $w\in\Gamma^\vee$ then $\chi_w-1$ vanishes on $\Gamma$. We call $\Gamma$ a \emph{grid} if $\Gamma^\vee\subset\Gamma$. The quotient $\Gamma/\Gamma^\vee$ is then finite, and for $\gamma\in\Gamma/\Gamma^\vee$ we define the \emph{coset comb} and the space of comb measures \[ e_\gamma=\sum_{\lambda\in\gamma+\Gamma^\vee}\delta_\lambda,\qquad \mathcal E(\Gamma)=\operatorname{span} \{e_\gamma:\gamma\in\Gamma/\Gamma^\vee\}. \] Two families of grids occur. The \emph{rational momentum grid} $(2k)^{-1}\ZZ^2$, in the coordinates $(P,Q)$ and for an integer $k\geq1$, has dual $k\ZZ^2$. The \emph{hyperbolic grid} \[ d^{-1}\Lambda_r=\Bigl\{(u,v)=\Bigl(\frac{mr}d,\frac n{dr}\Bigr): m,n\in\ZZ\Bigr\},\qquad d\geq1\text{ an integer},\ r>0, \] has dual $d\Lambda_r$, which consists of the points with $m,n\in d^2\ZZ$; its spin function is $s=mn/d^2$. For $d=1$ the grid is the self-dual lattice $\Lambda_r$ and its only comb is $e_r$. Poisson summation takes the following form. Let $(\mathsf b_1,\mathsf b_2)$ be a basis of $\Gamma^\vee$ and $(\mathsf b_1^*,\mathsf b_2^*)$ the basis of $\Gamma$ with $B(\mathsf b_i,\mathsf b_k^*)=\one_{i=k}$. For a Schwartz function $f$ and $\gamma\in\Gamma$ put $\phi(x)=f(x_1\mathsf b_1^*+x_2\mathsf b_2^*)\, e^{2\pi iB(\gamma,x_1\mathsf b_1^*+x_2\mathsf b_2^*)}$, $x\in\RR^2$. The substitution $X'=x_1\mathsf b_1^*+x_2\mathsf b_2^*$ in \eqref{eq:S-transform} gives $\mathbb Sf(\gamma+n_1\mathsf b_1+n_2\mathsf b_2) =c_\Gamma\int\phi(x)e^{2\pi in\cdot x}\dd x$, where $c_\Gamma$ is the absolute value of the determinant of $(\mathsf b_1^*,\mathsf b_2^*)$ in light-cone coordinates, and the classical Poisson formula $\sum_{n\in\ZZ^2}\int\phi(x)e^{2\pi in\cdot x}\dd x =\sum_{n\in\ZZ^2}\phi(n)$ yields $\langle\mathbb Se_\gamma,f\rangle =c_\Gamma\sum_{\mu\in\Gamma}e^{2\pi iB(\gamma,\mu)}f(\mu)$. The phase depends only on the classes of $\gamma$ and $\mu$ modulo $\Gamma^\vee$, so \begin{equation}\label{eq:rig-poisson} \mathbb Se_\gamma=c_\Gamma\sum_{\delta\in\Gamma/\Gamma^\vee} e^{2\pi iB(\gamma,\delta)}\,e_\delta,\qquad c_\Gamma=[\Gamma:\Gamma^\vee]^{-1/2}. \end{equation} The value of $c_\Gamma$ follows because the matrix of $B$ in light-cone coordinates has determinant $-1$, so that the covolumes of $\Gamma$ and $\Gamma^\vee$ are reciprocal. For $\Gamma=d^{-1}\Lambda_r$ one has $c_\Gamma=d^{-2}$, and \eqref{eq:rig-poisson} with $d=1$ is the first identity in \eqref{eq:circle-invariance}. In particular $\mathcal E(\Gamma)$ is mapped into itself by $\mathbb S$, and by $\mathbb S^{-1}$ because $\check e_\gamma=e_{-\gamma}$. \paragraph{Polynomial differential operators.} Let $\mathcal W$ be the algebra of linear differential operators on $\RR^2$ with polynomial coefficients. It acts on distributions and preserves temperedness. Every $\mathsf A\in\mathcal W$ has a unique \emph{normal form} $\mathsf A=\sum_\alpha\partial^\alpha\circ p_\alpha$ with polynomials $p_\alpha$, almost all zero, and for a closed discrete set $S$ \begin{equation}\label{eq:rig-normal-action} \mathsf A\sum_{\lambda\in S}\delta_\lambda =\sum_\alpha\sum_{\lambda\in S}p_\alpha(\lambda)\, \partial^\alpha\delta_\lambda . \end{equation} We use the generators \begin{equation}\label{eq:rig-generators} \mathsf x_1=P,\qquad\mathsf x_2=Q,\qquad \mathsf y_1=\frac{\partial_P}{4\pi i},\qquad \mathsf y_2=-\frac{\partial_Q}{4\pi i}, \end{equation} whose only nonzero commutators are \begin{equation}\label{eq:rig-commutators} [\mathsf y_1,\mathsf x_1]=\frac1{4\pi i},\qquad [\mathsf y_2,\mathsf x_2]=-\frac1{4\pi i}. \end{equation} For $\mathsf A\in\mathcal W$ and an integer $\nu$ put $\sigma(\mathsf A)=\mathbb S\mathsf A\mathbb S^{-1}$ and $\kappa_\nu(\mathsf A)=\mathcal C^\nu\mathsf A\mathcal C^{-\nu}$. Differentiating \eqref{eq:S-transform} under the integral sign and integrating by parts gives, for Schwartz functions, $\mathbb S(Pf)=(4\pi i)^{-1}\partial_P\mathbb Sf$, $\mathbb S(\partial_Pf)=-4\pi iP\,\mathbb Sf$, $\mathbb S(Qf)=-(4\pi i)^{-1}\partial_Q\mathbb Sf$ and $\mathbb S(\partial_Qf)=4\pi iQ\,\mathbb Sf$; these identities extend to tempered distributions by duality. Together with $\mathcal C^\nu\partial_P\mathcal C^{-\nu}=\partial_P-4\pi i\nu P$ and $\mathcal C^\nu\partial_Q\mathcal C^{-\nu}=\partial_Q+4\pi i\nu Q$ they show that $\sigma$ and $\kappa_\nu$ are automorphisms of $\mathcal W$, given on the generators by \begin{equation}\label{eq:rig-sigma-kappa} \sigma:(\mathsf x_j,\mathsf y_j)\mapsto(\mathsf y_j,-\mathsf x_j), \qquad \kappa_\nu:(\mathsf x_j,\mathsf y_j)\mapsto (\mathsf x_j,\,\mathsf y_j-\nu\mathsf x_j),\qquad j=1,2 . \end{equation} The boost generator \eqref{eq:boost} is $\mathcal K=-4\pi i\,(\mathsf x_1\mathsf y_2-\mathsf x_2\mathsf y_1)$. Since $\mathsf x_1,\mathsf y_1$ commute with $\mathsf x_2,\mathsf y_2$, the element $\mathsf x_1\mathsf y_2-\mathsf x_2\mathsf y_1$ is fixed by both substitutions in \eqref{eq:rig-sigma-kappa}. Therefore \begin{equation}\label{eq:rig-K-facts} \mathbb S\mathcal K=\mathcal K\mathbb S,\qquad \mathcal C\mathcal K=\mathcal K\mathcal C,\qquad \mathcal K\delta_0=0 , \end{equation} the last identity because $P\partial_Q\delta_0=\partial_Q(P\delta_0)=0$ and likewise for $Q\partial_P\delta_0$. Thus $p(\mathcal K)\delta_0=p(0)\delta_0$ for every polynomial $p$. Away from the origin the opposite holds. For $x=(P_x,Q_x)$ the identity $f\,\partial^\alpha\delta_x=\sum_{\beta\leq\alpha}(-1)^{|\alpha-\beta|} \binom\alpha\beta(\partial^{\alpha-\beta}f)(x)\,\partial^\beta\delta_x$ shows that $\mathcal K\partial^\alpha\delta_x =(Q_x\partial_P+P_x\partial_Q)\partial^\alpha\delta_x$ plus terms of order at most $|\alpha|$, and by induction \begin{equation}\label{eq:rig-K-nonzero} p(\mathcal K)\delta_x=\hat p\,(Q_x\partial_P+P_x\partial_Q)^j\delta_x +(\text{terms of order}m$, with $c_\alpha(\lambda)=p_{j,\gamma,\alpha}(\lambda)$ for all but finitely many $\lambda\in\gamma+\Gamma_j^\vee$. Carry this out for every $j$, put $\mathsf A_{j,\gamma}=\sum_\alpha\partial^\alpha\circ p_{j,\gamma,\alpha}$ and $F=T-\sum_{j,\gamma}\mathsf A_{j,\gamma}e_{j,\gamma}$. By \eqref{eq:rig-normal-action} and the previous paragraph, $F$ has finite support. Each $\mathsf A_{j,\gamma}e_{j,\gamma}$ is tempered, and $\mathbb S(\mathsf A_{j,\gamma}e_{j,\gamma}) =\sigma(\mathsf A_{j,\gamma})\,\mathbb Se_{j,\gamma}$ is supported in $\Gamma_j$ by \eqref{eq:rig-poisson}. Hence $\mathbb SF$ is supported in the closed discrete set $S$. But $F$ is a finite combination of derivatives of point masses, so $\mathbb SF$ is a real-analytic function, a finite sum of polynomials times characters. A continuous function supported in a discrete set vanishes; hence $\mathbb SF=0$ and $F=0$. \end{proof} \begin{lemma}[Operators invariant under two shears] \label{lem:boost-invariants} Let $\mathsf A\in\mathcal W$ and let $\nu$ be a nonzero integer. If $\mathsf A$ is invariant under conjugation by $\mathcal C^\nu$ and by $\mathbb S\mathcal C^\nu\mathbb S^{-1}$, that is, \[ \kappa_\nu(\mathsf A)=\mathsf A\qquad\text{and}\qquad \sigma\kappa_\nu\sigma^{-1}(\mathsf A)=\mathsf A , \] then $\mathsf A=p(\mathcal K)$ for a polynomial $p$. \end{lemma} \begin{proof} For a matrix $\mathsf g=\bigl(\begin{smallmatrix}\mathsf g_{11}&\mathsf g_{12}\\ \mathsf g_{21}&\mathsf g_{22}\end{smallmatrix}\bigr) \in\mathrm{SL}_2(\CC)$ the substitution \[ \Phi_{\mathsf g}:\ (\mathsf x_j,\mathsf y_j)\mapsto (\mathsf g_{11}\mathsf x_j+\mathsf g_{12}\mathsf y_j,\ \mathsf g_{21}\mathsf x_j+\mathsf g_{22}\mathsf y_j),\qquad j=1,2, \] preserves the relations \eqref{eq:rig-commutators}, because $[\mathsf g_{21}\mathsf x_j+\mathsf g_{22}\mathsf y_j,\, \mathsf g_{11}\mathsf x_j+\mathsf g_{12}\mathsf y_j] =\det\mathsf g\,[\mathsf y_j,\mathsf x_j]$ and the generators with different indices commute. Hence $\Phi_{\mathsf g}$ is an automorphism of $\mathcal W$, and $\Phi_{\mathsf g}\Phi_{\mathsf g'}=\Phi_{\mathsf g'\mathsf g}$. By \eqref{eq:rig-sigma-kappa}, \[ \kappa_\nu=\Phi_{\mathsf g}\ \text{with}\ \mathsf g=\begin{pmatrix}1&0\\-\nu&1\end{pmatrix},\qquad \sigma\kappa_\nu\sigma^{-1}=\Phi_{\mathsf g}\ \text{with}\ \mathsf g=\begin{pmatrix}1&\nu\\0&1\end{pmatrix}; \] for the second, $\sigma^{-1}$ maps $(\mathsf x_j,\mathsf y_j)$ to $(-\mathsf y_j,\mathsf x_j)$, so $\sigma\kappa_\nu\sigma^{-1}(\mathsf x_j) =\sigma(-\mathsf y_j+\nu\mathsf x_j)=\mathsf x_j+\nu\mathsf y_j$ and $\sigma\kappa_\nu\sigma^{-1}(\mathsf y_j)=\sigma(\mathsf x_j) =\mathsf y_j$. Let $\mathcal W_n\subset\mathcal W$ be the finite-dimensional span of all products of at most $n$ generators; every $\Phi_{\mathsf g}$ preserves $\mathcal W_n$. Choose $n$ with $\mathsf A\in\mathcal W_n$. For $z\in\CC$ let $\alpha_z=\Phi_{\mathsf g}$ with $\mathsf g=\bigl(\begin{smallmatrix}1&0\\z&1\end{smallmatrix}\bigr)$. Then $\alpha_z\alpha_{z'}=\alpha_{z+z'}$, and $z\mapsto\alpha_z(\mathsf A)$ is a polynomial map from $\CC$ to $\mathcal W_n$. By hypothesis $\alpha_{-\nu}(\mathsf A)=\mathsf A$, hence $\alpha_{k\nu}(\mathsf A)=\mathsf A$ for all $k\in\ZZ$, and the polynomial $\alpha_z(\mathsf A)-\mathsf A$ has infinitely many zeros. Thus $\alpha_z(\mathsf A)=\mathsf A$ for all $z\in\CC$. Likewise, with $\beta_z=\Phi_{\mathsf g}$ for $\mathsf g=\bigl(\begin{smallmatrix}1&z\\0&1\end{smallmatrix}\bigr)$, the hypothesis $\beta_\nu(\mathsf A)=\mathsf A$ and the polynomial dependence on $z$ give $\beta_z(\mathsf A)=\mathsf A$ for all $z\in\CC$. The set of $\mathsf g$ with $\Phi_{\mathsf g}(\mathsf A)=\mathsf A$ is a subgroup of $\mathrm{SL}_2(\CC)$ that contains all elementary matrices, which generate $\mathrm{SL}_2(\CC)$. Therefore $\Phi_{\mathsf g}(\mathsf A)=\mathsf A$ for every $\mathsf g\in\mathrm{SL}_2(\CC)$. We conclude by induction on $n$; the case $n=0$ is trivial since $\mathcal W_0=\CC$. By \eqref{eq:rig-commutators} the associated graded algebra of the filtration $(\mathcal W_n)$ is the polynomial ring $\CC[\mathsf x_1,\mathsf y_1,\mathsf x_2,\mathsf y_2]$, and $\Phi_{\mathsf g}$ acts on it by the same linear substitution. Let $\mathsf a^{\rm top}$ be the class of $\mathsf A$ in $\mathcal W_n/\mathcal W_{n-1}$, a homogeneous polynomial of degree $n$ in the two vectors $w_1=(\mathsf x_1,\mathsf y_1)$ and $w_2=(\mathsf x_2,\mathsf y_2)$ with $\mathsf a^{\rm top}(\mathsf gw_1,\mathsf gw_2) =\mathsf a^{\rm top}(w_1,w_2)$ for all $\mathsf g\in\mathrm{SL}_2(\CC)$. If the determinant $\mathsf k=\det(w_1,w_2)=\mathsf x_1\mathsf y_2-\mathsf x_2\mathsf y_1$ is nonzero, the matrix $\mathsf g$ with columns $w_1/\mathsf k$ and $w_2$ has determinant one and maps $(\mathsf k,0)$ to $w_1$ and $(0,1)$ to $w_2$; hence $\mathsf a^{\rm top}(w_1,w_2) =\mathsf a^{\rm top}\bigl((\mathsf k,0),(0,1)\bigr)$ is a polynomial in $\mathsf k$ on the dense set $\{\mathsf k\neq0\}$, and therefore everywhere. By homogeneity $\mathsf a^{\rm top}=\vartheta\, (\mathsf x_1\mathsf y_2-\mathsf x_2\mathsf y_1)^{n/2}$ for a constant $\vartheta$, with $\vartheta=0$ if $n$ is odd. The element $\mathsf x_1\mathsf y_2-\mathsf x_2\mathsf y_1=-\mathcal K/(4\pi i)$ of $\mathcal W$ is fixed by every $\Phi_{\mathsf g}$, since $\mathsf x_1,\mathsf y_1$ commute with $\mathsf x_2,\mathsf y_2$ and $\det\mathsf g=1$. Consequently $\mathsf A-\vartheta\bigl(-\mathcal K/(4\pi i)\bigr)^{n/2}$ lies in $\mathcal W_{n-1}$ and is fixed by every $\Phi_{\mathsf g}$. By the induction hypothesis it is a polynomial in $\mathcal K$, and so is $\mathsf A$. \end{proof} \begin{lemma}[Combs on one grid]\label{lem:grid-combs} Let $\Gamma$ be a grid. \begin{enumerate}[(i)] \item If $T$ is a tempered distribution such that $T$ and $\mathbb ST$ are supported in $\Gamma$, then $T=\sum_{\gamma\in\Gamma/\Gamma^\vee}\mathsf A_\gamma e_\gamma$ with uniquely determined operators $\mathsf A_\gamma\in\mathcal W$. \item There is an integer $\nu\geq1$ such that $\nu s(\lambda)\in\ZZ$ for all $\lambda\in\Gamma$, where $s=P^2-Q^2$; one may take $\nu=4k^2$ for $\Gamma=(2k)^{-1}\ZZ^2$ and $\nu=d^2$ for $\Gamma=d^{-1}\Lambda_r$. For every such $\nu$, both $\mathcal C^\nu$ and $\mathbb S\mathcal C^\nu\mathbb S^{-1}$ fix every element of $\mathcal E(\Gamma)$. \end{enumerate} \end{lemma} \begin{proof} Part (i) is Lemma~\ref{lem:transverse-combs} for a single grid. For (ii), let $n_0$ be the exponent of the finite group $\Gamma/\Gamma^\vee$. For $\lambda\in\Gamma$ we have $n_0\lambda\in\Gamma^\vee$, so $2n_0s(\lambda)=B(n_0\lambda,\lambda)\in\ZZ$, and $\nu=2n_0$ has the required property; the two special values are read off from $s=P^2-Q^2$ and $s=mn/d^2$. If $\nu s$ is integral on $\Gamma$, then $\mathcal C^\nu$ fixes every measure carried by $\Gamma$, in particular every element of $\mathcal E(\Gamma)$. Since $\mathbb S^{-1}$ maps $\mathcal E(\Gamma)$ into itself by \eqref{eq:rig-poisson}, $\mathbb S\mathcal C^\nu\mathbb S^{-1}e=\mathbb S\mathbb S^{-1}e=e$ for $e\in\mathcal E(\Gamma)$. \end{proof} \begin{theorem}[Rigidity on a grid]\label{thm:grid-rigidity} Let $\Gamma$ be a grid, for instance a rational momentum grid $(2k)^{-1}\ZZ^2$ or a hyperbolic grid $d^{-1}\Lambda_r$, and let $T$ be a tempered distribution with $\supp T\subset\Gamma$ and \[ \mathbb ST=T,\qquad\mathcal CT=T . \] Then there are unique polynomials $p_\gamma$, $\gamma\in\Gamma/\Gamma^\vee$, such that \begin{equation}\label{eq:rig-grid-form} T=\sum_{\gamma\in\Gamma/\Gamma^\vee}p_\gamma(\mathcal K)\,e_\gamma . \end{equation} In particular the local expansion of $T$ at the origin is $p_0(0)\,\delta_0$: all positive-order origin coefficients of $T$ vanish. \end{theorem} \begin{proof} By Lemma~\ref{lem:grid-combs}(i), $T=\sum_\gamma\mathsf A_\gamma e_\gamma$. Let $\nu$ be as in Lemma~\ref{lem:grid-combs}(ii). Since $\mathcal C^\nu T=T$ and $\mathcal C^\nu e_\gamma=e_\gamma$, \[ \sum_\gamma\mathsf A_\gamma e_\gamma=\mathcal C^\nu T =\sum_\gamma\kappa_\nu(\mathsf A_\gamma)\,\mathcal C^\nu e_\gamma =\sum_\gamma\kappa_\nu(\mathsf A_\gamma)\,e_\gamma , \] and the uniqueness in Lemma~\ref{lem:grid-combs}(i) gives $\kappa_\nu(\mathsf A_\gamma)=\mathsf A_\gamma$. The operator $\mathbb S\mathcal C^\nu\mathbb S^{-1}$ also fixes $T$ and every $e_\gamma$, and the same computation gives $\sigma\kappa_\nu\sigma^{-1}(\mathsf A_\gamma)=\mathsf A_\gamma$. By Lemma~\ref{lem:boost-invariants}, $\mathsf A_\gamma=p_\gamma(\mathcal K)$. The polynomials are unique by the uniqueness of the $\mathsf A_\gamma$ and the linear independence of the powers of $\mathcal K$. Only the coset $\gamma=0$ contains the origin, near which $e_0=\delta_0$, and $p_0(\mathcal K)\delta_0=p_0(0)\delta_0$ by \eqref{eq:rig-K-facts}. \end{proof} Neither positivity nor integrality of the coefficients of $T$, nor any bound on its local order, enters Theorem~\ref{thm:grid-rigidity}. \subsection{Finite unions of circle lattices} \label{subsec:rig-circles} Two radii $r,r'>0$ are \emph{commensurable} if $r/r'\in\QQ$. If they are not, then $\Lambda_r\cap\Lambda_{r'}=\{0\}$, and the same holds for $d^{-1}\Lambda_r$ and $d'^{-1}\Lambda_{r'}$: at a common point the light-cone coordinate $u$ lies in $\QQ r\cap\QQ r'=\{0\}$ and $v$ in $\QQ r^{-1}\cap\QQ r'^{-1}=\{0\}$. \begin{definition}\label{def:rig-transverse-family} A \emph{transverse family of hyperbolic grids} is a finite family $\Gamma_i=d_i^{-1}\Lambda_{r_i}$, $i\in\mathsf I$, with integers $d_i\geq1$ and pairwise incommensurable radii $r_i>0$. Its \emph{support} is $S=\bigcup_i\Gamma_i$, its \emph{phase exponent} is $\nu=\operatorname{lcm}\{d_i^2:i\in\mathsf I\}$, and its combs are the coset combs $e_{i,\gamma}$, $\gamma\in\Gamma_i/\Gamma_i^\vee$. The family is \emph{adapted} to a finite set $\mathcal R\subset(0,\infty)$ if $\bigcup_{r\in\mathcal R}\Lambda_r\subset S$. \end{definition} For such a family, \begin{equation}\label{eq:rig-classes} \Gamma_i^\vee=d_i\Lambda_{r_i}\subset\Gamma_i,\qquad \Gamma_i\cap\Gamma_{i'}=\{0\}\ \ (i\neq i'),\qquad \nu s(\lambda)\in\ZZ\ \ (\lambda\in S), \end{equation} so that Lemmas~\ref{lem:rig-transverse-differences} and~\ref{lem:transverse-combs} apply to it, and $\mathcal C^\nu$ fixes every comb $e_{i,\gamma}$. Every finite set $\mathcal R$ has an adapted family: choose one representative $r_i$ in each commensurability class of $\mathcal R$; if $r=(k/k')r_i$ with positive integers $k,k'$, then $\Lambda_r\subset(kk')^{-1}\Lambda_{r_i}$, and $d_i$ may be taken to be a common multiple of the products $kk'$ occurring in the class. \begin{theorem}[No origin jets on a finite union of circle lattices] \label{thm:circle-union} Let $(\Gamma_i)_{i\in\mathsf I}$ be a transverse family of hyperbolic grids with support $S$; for instance a family adapted to a finite set of radii $\mathcal R$, in which case $S\supset\bigcup_{r\in\mathcal R}\Lambda_r$. Let $T$ be a tempered distribution with $\supp T\subset S$ and \[ \mathbb ST=T,\qquad\mathcal CT=T . \] Then there are unique polynomials $p_{i,\gamma}$ with \begin{equation}\label{eq:rig-union-form} T=\sum_{i\in\mathsf I}\ \sum_{\gamma\in\Gamma_i/\Gamma_i^\vee} p_{i,\gamma}(\mathcal K)\,e_{i,\gamma}. \end{equation} In particular, a tempered distribution that is invariant under $\mathbb S$ and $\mathcal C$ and supported on a finite union of circle lattices has a local expansion at the origin equal to a multiple of $\delta_0$: all its positive-order origin coefficients vanish. \end{theorem} \begin{proof} By \eqref{eq:rig-classes} and Lemma~\ref{lem:transverse-combs}(ii), $T=\sum_{i,\gamma}\mathsf A_{i,\gamma}e_{i,\gamma}$. Let $\nu$ be the phase exponent. By Lemma~\ref{lem:grid-combs}(ii), applied to each $\Gamma_i$ with this common $\nu$, the operators $\mathcal C^\nu$ and $\mathbb S\mathcal C^\nu\mathbb S^{-1}$ fix every $e_{i,\gamma}$; they also fix $T$. As in the proof of Theorem~\ref{thm:grid-rigidity}, \[ \sum_{i,\gamma}\mathsf A_{i,\gamma}e_{i,\gamma} =\sum_{i,\gamma}\kappa_\nu(\mathsf A_{i,\gamma})\,e_{i,\gamma} =\sum_{i,\gamma}\sigma\kappa_\nu\sigma^{-1}(\mathsf A_{i,\gamma})\, e_{i,\gamma}, \] and the faithfulness statement of Lemma~\ref{lem:transverse-combs}(i) shows that each $\mathsf A_{i,\gamma}$ is fixed by $\kappa_\nu$ and by $\sigma\kappa_\nu\sigma^{-1}$. Lemma~\ref{lem:boost-invariants} gives $\mathsf A_{i,\gamma}=p_{i,\gamma}(\mathcal K)$. The polynomials are unique by Lemma~\ref{lem:transverse-combs}(i) and the linear independence of the powers of $\mathcal K$. Near the origin only the combs $e_{i,0}$ contribute, each equal to $\delta_0$ there, and $p_{i,0}(\mathcal K)\delta_0=p_{i,0}(0)\delta_0$ by \eqref{eq:rig-K-facts}. \end{proof} The finite-dimensional problem that remains is to find the invariant elements of $\mathcal E(\Gamma)$ for a hyperbolic grid. The next lemma is the special case, for such a grid, of the finite Fourier analysis in \cite[Section~3.5]{EL}; we include the proof because the coefficients are arbitrary complex numbers here. \begin{lemma}[Invariant comb measures on a hyperbolic grid] \label{lem:grid-invariants} Let $\Gamma=d^{-1}\Lambda_r$ with an integer $d\geq1$ and $r>0$. The elements of $\mathcal E(\Gamma)$ that are invariant under both $\mathbb S$ and $\mathcal C$ are exactly the complex linear combinations of the circle combs \[ e_{rk/d},\qquad k\ \text{a positive divisor of}\ d^2 , \] and these combs are linearly independent. \end{lemma} \begin{proof} Index the cosets of $\Gamma^\vee$ by $(m,n)\in(\ZZ/d^2\ZZ)^2$, the coset $e_{m,n}$ containing the point $(u,v)=(mr/d,\,n/(dr))$. On $\Gamma$ the spin is $mn/d^2$ and the pairing is $B=(mn'+nm')/d^2$. By \eqref{eq:rig-poisson} and $c_\Gamma=d^{-2}$, \[ \mathbb Se_{m,n}=\frac1{d^2}\sum_{m',n'} e^{2\pi i(mn'+nm')/d^2}\,e_{m',n'},\qquad \mathcal Ce_{m,n}=e^{2\pi imn/d^2}\,e_{m,n}. \] A measure $\sum\phi(m,n)e_{m,n}$ is therefore invariant if and only if \begin{equation}\label{eq:rig-finite-invariance} \phi(m,n)=\frac1{d^2}\sum_{m',n'}\phi(m',n')\, e^{2\pi i(m'n+n'm)/d^2}, \qquad\bigl(e^{2\pi imn/d^2}-1\bigr)\phi(m,n)=0 . \end{equation} Let $\widehat\phi(m,n)=\sum_{n'}\phi(m,n')e^{2\pi inn'/d^2}$ be the Fourier transform in the second variable, which determines $\phi$. The second condition in \eqref{eq:rig-finite-invariance} holds if and only if $\widehat\phi(m,n+m)=\widehat\phi(m,n)$ for all $m,n$. The right side of the first condition equals $d^{-2}\sum_{m'}e^{2\pi im'n/d^2}\widehat\phi(m',m)$, whose transform in $n$ at the point $(m,n)$ is $\widehat\phi(-n,m)$; so the first condition holds if and only if $\widehat\phi(m,n)=\widehat\phi(-n,m)$ for all $m,n$. The maps $(m,n)\mapsto(m,n+m)$ and $(m,n)\mapsto(-n,m)$ are right multiplication of the row vector $(m,n)$ by $\bigl(\begin{smallmatrix}1&1\\0&1\end{smallmatrix}\bigr)$ and $\bigl(\begin{smallmatrix}0&1\\-1&0\end{smallmatrix}\bigr)$, which generate $\mathrm{SL}_2(\ZZ)$. Hence $\phi$ is invariant if and only if $\widehat\phi$ is constant on the orbits of $\mathrm{SL}_2(\ZZ)$ on $(\ZZ/d^2\ZZ)^2$. These orbits are the level sets of $k=\gcd(m,n,d^2)$. Indeed, the ideal of $\ZZ$ generated by $m,n,d^2$ is unchanged by the action. Conversely, let $\gcd(m,n,d^2)=k$ and write $(m,n)=k(m_1,n_1)$ with integers satisfying $\gcd(m_1,n_1,d^2/k)=1$. We may take $1\leq n_1\leq d^2/k$. By the Chinese remainder theorem there is an integer $k'$ such that $m_2=m_1+k'd^2/k$ is not divisible by any prime that divides $n_1$ but not $d^2/k$; the primes dividing both $n_1$ and $d^2/k$ do not divide $m_1$, hence not $m_2$. Thus $\gcd(m_2,n_1)=1$, and there is a matrix in $\mathrm{SL}_2(\ZZ)$ with first row $(m_2,n_1)$. It maps $(k,0)$ to $(km_2,kn_1)\equiv(m,n)$ modulo $d^2$, so $(m,n)$ lies in the orbit of $(k,0)$. Consequently the invariant $\widehat\phi$ are the functions of $\gcd(m,n,d^2)$. A basis of this space is given by the functions $\one_{k\mid m}\one_{k\mid n}$, $k\mid d^2$, since these are obtained from the indicators of the level sets by a triangular change of basis with respect to divisibility. Inverting the transform, \[ \widehat\phi=\one_{k\mid m}\one_{k\mid n}\quad\Longleftrightarrow\quad \phi(m,n)=\frac1{d^2}\sum_{n':\,k\mid n'}\one_{k\mid m}\, e^{-2\pi inn'/d^2}=\frac1k\,\one_{k\mid m}\,\one_{(d^2/k)\mid n}. \] The corresponding measure is $k^{-1}$ times the comb of the lattice of points $(u,v)=(m_1kr/d,\,n_1d/(kr))$, $m_1,n_1\in\ZZ$, which is $\Lambda_{rk/d}$. \end{proof} \begin{theorem}[Classification of the invariant distributions] \label{thm:circle-jets} Let $\mathcal R\subset(0,\infty)$ be finite, let $F\subset\Lambda_1$ be finite, and let $T$ be a tempered distribution with \[ \mathbb ST=T,\qquad\mathcal CT=T,\qquad \supp T\subset\bigcup_{r\in\mathcal R}\Lambda_r\cup F . \] \begin{enumerate}[(i)] \item There are polynomials $p_r$, $r\in\mathcal R$, such that \begin{equation}\label{eq:rig-circle-jets} T=\sum_{r\in\mathcal R}p_r(\mathcal K)\,e_r . \end{equation} \item The polynomials $p_r$ are uniquely determined by $T$, and $\deg p_r\leq q$ if $T$ has local order at most $q$. Conversely, every distribution of the form \eqref{eq:rig-circle-jets} is tempered and invariant under $\mathbb S$ and $\mathcal C$. \item Suppose that $\mathcal R$ is closed under $r\mapsto1/r$. Then $T$ is even if and only if $p_{1/r}(z)=p_r(-z)$ for all $r\in\mathcal R$, and if and only if $T$ is a finite linear combination of the radius derivatives \begin{equation}\label{eq:rig-radius-derivative} (r\partial_r)^j\rhoF_r =\frac{(-1)^j}2\,\mathcal K^j\bigl(e_r+(-1)^je_{1/r}\bigr), \qquad r\in\mathcal R,\ r\geq1,\ j\geq0 . \end{equation} Here $(r\partial_r)^j\rhoF_r$ denotes the tempered distribution $f\mapsto(t\partial_t)^j\langle\rhoF_t,f\rangle\big|_{t=r}$. For $r=1$ the derivatives of odd order vanish. The coefficients of the combination are unique if only even $j$ are used at $r=1$, and only orders $j\leq q$ occur if $T$ has local order at most $q$. \end{enumerate} \end{theorem} \begin{proof} \emph{Private points.} We first record a fact about circle lattices. Let $\mathcal R'\subset(0,\infty)$ be finite, $r\in\mathcal R'$, and let $\varpi$ be a prime with $\varpi>r/r'$ for all $r'\in\mathcal R'$. The point $x_\varpi$ with light-cone coordinates $(u,v)=(r,\varpi/r)$ lies in $\Lambda_r$. If it lies in $\Lambda_{r'}$, say $(r,\varpi/r)=(m'r',n'/r')$, then $m',n'$ are positive integers with $m'n'=\varpi$, so $m'=1$ and $r'=r$, or $m'=\varpi$ and $r'=r/\varpi$. The second case is excluded for $r'\in\mathcal R'$ by the choice of $\varpi$. Thus $x_\varpi$ belongs to $\Lambda_{r'}$ for no $r'\in\mathcal R'\setminus\{r\}$; we call it a \emph{private point} of $r$ relative to $\mathcal R'$. There are infinitely many of them, and they are different from the origin. \emph{Uniqueness and degrees.} Suppose \eqref{eq:rig-circle-jets} holds, and let $x$ be a private point of $r$ relative to $\mathcal R$. Near $x$ we have $T=p_r(\mathcal K)\delta_x$. By \eqref{eq:rig-K-nonzero} this determines $p_r$, and its local order is $\deg p_r$. This proves the first two assertions of (ii). The converse follows from \eqref{eq:circle-invariance} and \eqref{eq:rig-K-facts}. \emph{Existence.} Let $(\Gamma_i)_{i\in\mathsf I}$, with $\Gamma_i=d_i^{-1}\Lambda_{r_i}$, be a transverse family adapted to $\mathcal R\cup\{1\}$. Its support contains $\supp T$, and Theorem~\ref{thm:circle-union} gives $T=\sum_{i,\gamma}p_{i,\gamma}(\mathcal K)e_{i,\gamma}$. Collecting powers of $\mathcal K$, write \[ T=\sum_{j\geq0}\mathcal K^j\eta_j,\qquad \eta_j=\sum_i\eta_{j,i},\quad \eta_{j,i}\in\mathcal E(\Gamma_i), \] with only finitely many $\eta_j\neq0$. Each $\mathcal E(\Gamma_i)$ is mapped into itself by $\mathbb S$, by \eqref{eq:rig-poisson}, and by $\mathcal C$, which multiplies $e_{i,\gamma}$ by the constant $e^{2\pi is(\gamma)}$. Since $\mathcal K$ commutes with $\mathbb S$ and $\mathcal C$, \[ 0=\mathbb ST-T=\sum_j\mathcal K^j(\mathbb S\eta_j-\eta_j),\qquad 0=\mathcal CT-T=\sum_j\mathcal K^j(\mathcal C\eta_j-\eta_j). \] Expanding $\mathbb S\eta_{j,i}-\eta_{j,i}$ in the combs $e_{i,\gamma}$, the first identity has the form $\sum_{i,\gamma}\bigl(\sum_j\vartheta_{i,\gamma,j}\mathcal K^j\bigr) e_{i,\gamma}=0$ with complex numbers $\vartheta_{i,\gamma,j}$. By Lemma~\ref{lem:transverse-combs}(i) each operator $\sum_j\vartheta_{i,\gamma,j}\mathcal K^j$ vanishes, and by the linear independence of the powers of $\mathcal K$ all $\vartheta_{i,\gamma,j}$ vanish. Hence $\mathbb S\eta_{j,i}=\eta_{j,i}$, and in the same way $\mathcal C\eta_{j,i}=\eta_{j,i}$. By Lemma~\ref{lem:grid-invariants}, $\eta_{j,i}$ is a combination of circle combs $e_{r'}$ with radii $r'=r_ik/d_i$, $k\mid d_i^2$. Therefore \[ T=\sum_{r'\in\mathcal R'}p_{r'}(\mathcal K)\,e_{r'} \] for a finite set $\mathcal R'\supset\mathcal R\cup\{1\}$ and polynomials $p_{r'}$. Let $r'\in\mathcal R'\setminus\mathcal R$ and suppose $p_{r'}\neq0$. Choose a private point $x$ of $r'$ relative to $\mathcal R'$ that does not lie in the finite set $F$. Near $x$ we have $T=p_{r'}(\mathcal K)\delta_x\neq0$ by \eqref{eq:rig-K-nonzero}, so $x\in\supp T$; but $x\notin F$, and $x\notin\Lambda_r$ for $r\in\mathcal R$ because $\mathcal R\subset\mathcal R'\setminus\{r'\}$. This contradicts the hypothesis on the support, so $p_{r'}=0$ for $r'\notin\mathcal R$, which proves (i). \emph{The even sector.} Let $\mathfrak r$ be the reflection $Q\mapsto-Q$. It maps $e_r$ to $e_{1/r}$ and conjugates $\mathcal K=P\partial_Q+Q\partial_P$ to $-\mathcal K$, so $\mathfrak r_*\bigl(p(\mathcal K)e_r\bigr)=p(-\mathcal K)e_{1/r}$. The reflection $X\mapsto-X$ fixes every $e_r$ and commutes with $\mathcal K$, hence fixes $T$. Thus $T$ is even if and only if $\mathfrak r_*T=T$, which by the uniqueness in (ii) means $p_{1/r}(z)=p_r(-z)$ for all $r\in\mathcal R$. In that case $p_1$ is an even polynomial and, writing $p_r(z)=\sum_jp_{r,j}z^j$, \[ T=\sum_{r\in\mathcal R,\,r>1}\ \sum_jp_{r,j}\, \mathcal K^j\bigl(e_r+(-1)^je_{1/r}\bigr) +\sum_{j\ \mathrm{even}}p_{1,j}\,\mathcal K^je_1 , \] the last sum being present only if $1\in\mathcal R$. It remains to prove \eqref{eq:rig-radius-derivative}; the uniqueness and degree statements then follow from (ii), and each radius derivative is even because $\rhoF_r$ is. For a Schwartz function $f$, $\langle e_r,f\rangle=\sum_{m,n}f(mr,n/r)$ in light-cone coordinates. Since $r\partial_r\bigl[f(mr,n/r)\bigr] =\bigl((u\partial_u-v\partial_v)f\bigr)(mr,n/r)$ and $\mathcal Kf$ is again a Schwartz function, the series may be differentiated termwise any number of times, locally uniformly in $r$, and \[ (r\partial_r)^j\langle e_r,f\rangle =\langle e_r,\mathcal K^jf\rangle =\bigl\langle(-\mathcal K)^je_r,f\bigr\rangle , \] because the transpose of $\mathcal K$ is $-\mathcal K$. Replacing $r$ by $1/r$ changes the sign of $r\partial_r$, so $(r\partial_r)^je_{1/r}=\mathcal K^je_{1/r}$. Adding the two and dividing by two gives \eqref{eq:rig-radius-derivative}, in view of $\rhoF_r=\frac12(e_r+e_{1/r})$. \end{proof} Theorem~\ref{thm:circle-jets} applies in particular to distributions supported on a rational grid. The link is the following elementary fact, which is also used in Section~\ref{subsec:rig-localization}. \begin{lemma}[Integral-spin points of a rational light-cone grid] \label{lem:grid-circles} Let $d\geq1$ be an integer. Every point with light-cone coordinates $(u,v)=(m/d,n/d)$, $m,n\in\ZZ$, and integral spin $uv\in\ZZ$ lies in \[ \bigcup_{k\mid d^2}\Lambda_{k/d}, \] the union over the positive divisors $k$ of $d^2$. The set $\mathcal R_d=\{k/d:k\mid d^2\}$ of these radii contains $1$ and is closed under $r\mapsto1/r$, and $\Lambda_r\subset d^{-1}\Lambda_1$ for $r\in\mathcal R_d$. \end{lemma} \begin{proof} Let $k=d^2/\gcd(n,d^2)$, with the convention $\gcd(0,d^2)=d^2$. Then $d^2$ divides $nk$. Moreover $d^2\mid mn$ implies that $k$ divides $m\cdot n/\gcd(n,d^2)$, and $k$ is coprime to $n/\gcd(n,d^2)$, so $k\mid m$. Hence \[ u=\frac mk\cdot\frac kd,\qquad v=\frac{nk}{d^2}\Bigm/\frac kd \] with integers $m/k$ and $nk/d^2$, that is, $(u,v)\in\Lambda_{k/d}$. The radius $k/d$ equals $1$ for $k=d$, and $(k/d)^{-1}=(d^2/k)/d$. Finally a point $(m_1k/d,\,n_1d/k)$ of $\Lambda_{k/d}$ has $v=n_1(d^2/k)/d\in d^{-1}\ZZ$. \end{proof} \begin{corollary}[Invariant distributions on a rational grid] \label{cor:rig-grid-invariants} Let $d\geq1$ and $q\geq0$ be integers, and let $\mathcal R_d$ be as in Lemma~\ref{lem:grid-circles}. Let $T$ be a tempered distribution of local order at most $q$, supported in the light-cone grid $d^{-1}\Lambda_1=\{(u,v)\in d^{-1}\ZZ^2\}$, with $\mathbb ST=T$ and $\mathcal CT=T$. Then \[ T=\sum_{r\in\mathcal R_d}p_r(\mathcal K)\,e_r \] with unique polynomials $p_r$ of degree at most $q$. If in addition $T$ is even, then $T$ is a linear combination, with unique coefficients, of the distributions \begin{equation}\label{eq:rig-grid-basis} (r\partial_r)^j\rhoF_r,\qquad r\in\mathcal R_d,\ r\geq1,\ 0\leq j\leq q,\ \ j\ \text{even if}\ r=1 . \end{equation} Conversely, each distribution in \eqref{eq:rig-grid-basis} is tempered, even, invariant under $\mathbb S$ and $\mathcal C$, supported in $d^{-1}\Lambda_1$, and of local order at most $q$. Hence the space of even tempered distributions of local order at most $q$ that are supported in $d^{-1}\Lambda_1$ and invariant under $\mathbb S$ and $\mathcal C$ has the basis \eqref{eq:rig-grid-basis}. The same description holds, with $d=2k$, for the invariant distributions supported in a rational momentum grid $(2k)^{-1}\ZZ^2$: they are the elements of this space whose support lies in that grid. \end{corollary} \begin{proof} The smooth function $e^{2\pi is}-1$ annihilates $T$, so $T$ vanishes near every point at which this function is nonzero; that is, the spin is integral on $\supp T$. By Lemma~\ref{lem:grid-circles}, $\supp T\subset\bigcup_{r\in\mathcal R_d}\Lambda_r$, and Theorem~\ref{thm:circle-jets} applies with $\mathcal R=\mathcal R_d$ and $F=\emptyset$. The converse statements follow from \eqref{eq:rig-radius-derivative}, Theorem~\ref{thm:circle-jets}(ii) and the inclusion $\Lambda_r\subset d^{-1}\Lambda_1$. For the last assertion note that $(2k)^{-1}\ZZ^2$ is contained in the light-cone grid $(2k)^{-1}\Lambda_1$, because $u=P+Q$ and $v=P-Q$. \end{proof} \subsection{A finite certificate for the origin coefficients} \label{subsec:rig-certificate} Theorem~\ref{thm:circle-union} shows that $\mathbb S$- and $\mathcal C$-invariance forbid positive-order origin coefficients. For distributions of bounded local order, finitely many test functions detect this obstruction, as we show in this subsection. The first step replaces Lemma~\ref{lem:boost-invariants} by a statement that uses the phase operator only. \begin{lemma}[Operators commuting with the spin] \label{lem:spin-centralizer} Let $\mathsf A\in\mathcal W$ commute with multiplication by the spin function $s=P^2-Q^2=uv$. Then \[ \mathsf A=\sum_{j=0}^m\mathsf q_j\,\mathcal K^j \] with polynomials $\mathsf q_j=\mathsf q_j(P,Q)$, and consequently $\mathsf A\delta_0=\mathsf q_0(0)\,\delta_0$. The same conclusions hold if $\kappa_\nu(\mathsf A)=\mathsf A$ for some nonzero integer $\nu$. \end{lemma} \begin{proof} We use light-cone coordinates and induct on the differential order $m$ of $\mathsf A$; operators of order zero are polynomials. Let $m\geq1$, write $\mathsf A=\sum_{i+k\leq m}\mathsf a_{ik}(u,v)\, \partial_u^i\partial_v^k$, and let $\mathsf a^{\rm top}=\sum_{i+k=m}\mathsf a_{ik}\,\xi_u^i\xi_v^k$ be its principal symbol. Since $[\partial_u^i\partial_v^k,uv] =iv\,\partial_u^{i-1}\partial_v^k+ku\,\partial_u^i\partial_v^{k-1} +ik\,\partial_u^{i-1}\partial_v^{k-1}$, the commutator $[\mathsf A,s]$ has order at most $m-1$, and its part of order $m-1$ has symbol $(v\partial_{\xi_u}+u\partial_{\xi_v})\mathsf a^{\rm top}$. Hence \[ (v\partial_{\xi_u}+u\partial_{\xi_v})\mathsf a^{\rm top}=0 . \] Fix $(u,v)$ with $uv\neq0$. In the linear coordinates $\ell=u\xi_u-v\xi_v$ and $\ell'=\xi_u/v$ on the $\xi$-plane the derivation $v\partial_{\xi_u}+u\partial_{\xi_v}$ is $\partial_{\ell'}$. So $\mathsf a^{\rm top}$, a homogeneous polynomial of degree $m$ in $\xi$, depends on $\ell$ only: $\mathsf a^{\rm top}=\mathsf q\,(u\xi_u-v\xi_v)^m$ with $\mathsf q=\mathsf q(u,v)$. Comparing the coefficients of $\xi_u^m$ and $\xi_v^m$ gives $\mathsf a_{m0}=\mathsf q\,u^m$ and $\mathsf a_{0m}=\mathsf q\,(-v)^m$, hence the polynomial identity $(-v)^m\mathsf a_{m0}=u^m\mathsf a_{0m}$. As $u^m$ and $v^m$ are coprime, $u^m$ divides $\mathsf a_{m0}$, so $\mathsf q=\mathsf a_{m0}/u^m$ is a polynomial, and $\mathsf a^{\rm top}=\mathsf q\,(u\xi_u-v\xi_v)^m$ holds identically. The operator $\mathsf q\,\mathcal K^m$, with $\mathcal K=u\partial_u-v\partial_v$, has principal symbol $\mathsf a^{\rm top}$, and it commutes with $s$ because $[\mathcal K,s]=\mathcal K(uv)=0$. Thus $\mathsf A-\mathsf q\,\mathcal K^m$ commutes with $s$ and has order less than $m$, and the induction hypothesis applies. The statement about $\delta_0$ follows from \eqref{eq:rig-K-facts}. Finally let $\kappa_\nu(\mathsf A)=\mathsf A$ with $\nu\neq0$. For $z\in\CC$, \[ e^{2\pi izs}\,\mathsf A\,e^{-2\pi izs} =\sum_{k=0}^m\frac{(2\pi iz)^k}{k!}\, \operatorname{ad}_s^k(\mathsf A),\qquad \operatorname{ad}_s(\mathsf A)=[s,\mathsf A], \] the sum being finite because $\operatorname{ad}_s$ lowers the order. This polynomial in $z$ takes the value $\mathsf A$ at all integer multiples of $\nu$, hence is constant, and the coefficient of $z$ gives $[s,\mathsf A]=0$. \end{proof} \begin{lemma}[Formal rigidity without growth conditions] \label{lem:formal-rigidity} Let $(\Gamma_i)_{i\in\mathsf I}$ be a transverse family of hyperbolic grids with support $S$ and phase exponent $\nu$, and let $q\geq1$. There is a finite list $\mathsf D_1,\dots,\mathsf D_{n_0}$ of translation operators \[ \mathsf D_l=\prod_{i\in\mathsf I}(\tau_{w_{i,l}}-I)^{m_l},\qquad w_{i,l}\in\Gamma_i^\vee\setminus\{0\},\qquad m_l\in\{q+1,\,2q+1\}, \] with the following property. Let $(c_\alpha(x))_{x\in S,\, \alpha\in\mathcal A_q}$ be an arbitrary array of complex numbers, subject to no growth condition, and let \[ T=\sum_{x\in S}\sum_{|\alpha|\leq q}c_\alpha(x)\, \partial^\alpha\delta_x . \] If $\mathsf D_lT=0$ for all $l$ and $\mathcal C^\nu T=T$, then $c_\alpha(0)=0$ for all $\alpha$ with $1\leq|\alpha|\leq q$. \end{lemma} \begin{proof} \emph{The list.} For each $j\in\mathsf I$ fix a basis $(\mathsf b_{j,1},\mathsf b_{j,2})$ of $\Gamma_j^\vee$. For each $j$ and $\iota\in\{1,2\}$ the list contains the operator \[ \mathsf D_{j,\iota}=(\tau_{\mathsf b_{j,\iota}}-I)^{q+1} \prod_{i\neq j}(\tau_{w_i}-I)^{q+1}, \] where the vectors $w_i=w_i^{(j,\iota)}\in\Gamma_i^\vee$ are chosen by Lemma~\ref{lem:rig-transverse-differences}(i) with $m=q+1$ and $G_i=\Gamma_i^\vee$. In addition the list contains one operator $\mathsf D_*=\prod_{i\in\mathsf I}(\tau_{w_i^*}-I)^{2q+1}$ with arbitrary nonzero $w_i^*\in\Gamma_i^\vee$. \emph{Polynomial structure.} Let $T$ be as in the statement. By Lemma~\ref{lem:rig-transverse-differences}(ii), applied to $\mathsf D_{j,1}$ and $\mathsf D_{j,2}$, for every $j$, every coset $\gamma+\Gamma_j^\vee$ and every $\alpha$ the function $(n_1,n_2)\mapsto c_\alpha(\gamma+n_1\mathsf b_{j,1}+n_2\mathsf b_{j,2})$ has finitely supported differences of order $q+1$ in both directions. Lemma~\ref{lem:difference-newton}, which requires no growth condition, shows that it agrees outside a finite set with a polynomial of degree at most $q$ in each of $n_1,n_2$. As in the proof of Lemma~\ref{lem:transverse-combs}(ii) we obtain \[ T=T_0+F,\qquad T_0=\sum_{i,\gamma}\mathsf A_{i,\gamma}e_{i,\gamma},\qquad \mathsf A_{i,\gamma}=\sum_{|\alpha|\leq q}\partial^\alpha\circ p_{i,\gamma,\alpha}, \] where $F$ has finite support and the polynomials $p_{i,\gamma,\alpha}$ have total degree at most $2q$. \emph{The finite part vanishes.} For $w\in\Gamma_i^\vee$ translation by $w$ preserves $e_{i,\gamma}$, so $(\tau_w-I)^{2q+1}\bigl(\partial^\alpha(p\,e_{i,\gamma})\bigr) =\partial^\alpha\bigl(((\tau_w-I)^{2q+1}p)\,e_{i,\gamma}\bigr)=0$ for every polynomial $p$ of degree at most $2q$. Since translations commute, $\mathsf D_*T_0=0$, and therefore $\mathsf D_*F=\mathsf D_*T-\mathsf D_*T_0=0$. The distribution $F$ is tempered, and by \eqref{eq:rig-intertwine} $\omega_*\,\mathbb S^{-1}F=0$ with $\omega_*=\prod_i(\chi_{w_i^*}-1)^{2q+1}$. Since $F$ has finite support, $\mathbb S^{-1}F$ is a real-analytic function, and $\omega_*$ vanishes only on the locally finite family of lines $B(w_i^*,X)\in\ZZ$. Hence $\mathbb S^{-1}F$ vanishes on a dense open set, so $\mathbb S^{-1}F=0$ and $F=0$. \emph{Conclusion.} Thus $T=T_0$ is a polynomial comb. Since $\mathcal C^\nu$ fixes $T$ and every $e_{i,\gamma}$, $\sum_{i,\gamma}\mathsf A_{i,\gamma}e_{i,\gamma} =\sum_{i,\gamma}\kappa_\nu(\mathsf A_{i,\gamma})e_{i,\gamma}$, and Lemma~\ref{lem:transverse-combs}(i) gives $\kappa_\nu(\mathsf A_{i,\gamma})=\mathsf A_{i,\gamma}$. Near the origin $T=\sum_i\mathsf A_{i,0}\delta_0$, and by Lemma~\ref{lem:spin-centralizer} each term is a multiple of $\delta_0$. \end{proof} \begin{lemma}[A finite consequence of finitely supported equations] \label{lem:finite-rows} Let $\mathcal I$ be a set. Call an element $\mathsf r$ of the space $\CC^{(\mathcal I)}$ of finitely supported functions on $\mathcal I$ a \emph{row}, and let it act on arbitrary arrays $c\in\CC^{\mathcal I}$ by $\mathsf r(c)=\sum_{\imath\in\mathcal I}\mathsf r_\imath c_\imath$. Let $\mathsf R$ be a family of rows and $\lambda$ a row. If $\lambda(c)=0$ for every $c\in\CC^{\mathcal I}$ such that $\mathsf r(c)=0$ for all $\mathsf r\in\mathsf R$, then $\lambda$ is a finite linear combination of elements of $\mathsf R$. \end{lemma} \begin{proof} Let $U\subset\CC^{(\mathcal I)}$ be the linear span of $\mathsf R$. If $\lambda\notin U$, there is a linear functional $\Lambda$ on $\CC^{(\mathcal I)}$ that vanishes on $U$ and satisfies $\Lambda(\lambda)=1$. Let $c_\imath$ be the value of $\Lambda$ on the indicator function of $\{\imath\}$. Then $\mathsf r(c)=\Lambda(\mathsf r)$ for every row $\mathsf r$, so $c$ satisfies all equations of $\mathsf R$ while $\lambda(c)=1$, a contradiction. Hence $\lambda\in U$. \end{proof} The array $c$ produced in this proof satisfies no growth condition. This is the reason for stating Lemma~\ref{lem:formal-rigidity} for arbitrary arrays: a rigidity statement for tempered arrays only would not yield a finite combination of rows. \paragraph{Uniform families of Gaussian mixtures.} To control the test functions, also in families, we fix the following notation. Let $n\geq0$ be an integer; for $n=0$ the cube $[-1,1]^n$ is a point of unit mass. For a continuous map $z:[-1,1]^n\to\CC^2$ and a polynomial $p(X,\xi)=\sum_{|\gamma|\leq n'}p_\gamma(\xi)X^\gamma$ whose coefficients are continuous functions of $\xi\in[-1,1]^n$, put \begin{gather*} \mathfrak m[p,z](X)=\int_{[-1,1]^n}p(X,\xi)\, e^{-2\pi|X|^2+z(\xi)\cdot X}\dd\xi,\\ \|p\|=\max_\gamma\sup_\xi|p_\gamma(\xi)|,\qquad \|z\|=\sup_\xi|z(\xi)| . \end{gather*} \begin{lemma}\label{lem:rig-mixture-family} Let $n,n'\geq0$ be integers and $\mathsf z_0<\infty$, and let $p,z$ be as above, with $p$ of degree at most $n'$ in $X$ and $\|z\|\leq\mathsf z_0$. \begin{enumerate}[(i)] \item $\mathfrak m[p,z]\in\mathcal G_{2\pi}$, and $e^{w\cdot X}\mathfrak m[p,z]=\mathfrak m[p,z+w]$ for $w\in\CC^2$. \item $\mathbb S\,\mathfrak m[p,z]=\mathfrak m[\tilde p,iJz]$, where $J=\operatorname{diag}(1,-1)$ and $\tilde p$ is a polynomial of degree at most $n'$ in $X$ with $\|\tilde p\|\leq C\|p\|$, $C=C(n',\mathsf z_0)$. \item For every integer $k_0\geq0$, every $\varrho<\infty$ and every $00$ put \[ \Sigma(t)=\Sigma_0\cup\Lambda_t\cup\Lambda_{1/t}. \] Fix $t_0>0$ and an integer $q\geq1$. There exist $\varepsilon_0\in(0,t_0)$, integers $n\geq1$ and $K\geq0$, and, for every $t$ with $0<|t-t_0|<\varepsilon_0$, functions $f_{1,t},\dots,f_{n,t}$ on $\CC^2$ such that the following hold. \begin{enumerate}[(i)] \item $f_{l,t}\in\mathcal G_{2\pi}$ and $\mathbb Sf_{l,t}\in\mathcal G_{2\pi}$ for all $l$ and $t$. \item For every $t$ with $0<|t-t_0|<\varepsilon_0$, every even tempered distribution $T$ with $\supp T\subset\Sigma(t)$, of local order at most $q$ and with $\mathcal CT=T$, satisfies \begin{equation}\label{eq:rig-moving-certificate} \max_{1\leq|\alpha|\leq q}|c_\alpha(0)|\leq\sum_{l=1}^n \bigl|\langle(\mathbb S-I)T,f_{l,t}\rangle\bigr| . \end{equation} \item For every integer $k_0\geq0$, every $\varrho<\infty$ and every $00$ \[ \Gamma_+(t)=\Lambda_t,\qquad\Gamma_-(t)=\Lambda_{1/t},\qquad \Gamma_i(t)=\Gamma_i\ \ (i\in\mathsf I),\qquad S(t)=\bigcup_{i\in\mathsf I^\pm}\Gamma_i(t)\supset\Sigma(t). \] For each $i\in\mathsf I^\pm$ let $\ell^t_{i,1},\ell^t_{i,2}$ be the linear forms \[ \Bigl(\frac{d_iu}{r_i},\,d_ir_iv\Bigr)\ \ (i\in\mathsf I),\qquad \Bigl(\frac ut,\,tv\Bigr)\ \ (i=+),\qquad \Bigl(tu,\,\frac vt\Bigr)\ \ (i=-), \] so that $\Gamma_i(t)$ is the set where both forms are integral, and let $x_{i,m,n}(t)$ be the point of $\Gamma_i(t)$ at which they take the values $(m,n)\in\ZZ^2$. The dual lattice $\Gamma_i(t)^\vee$ consists of the points $x_{i,m,n}(t)$ with $m,n\in d_i^2\ZZ$, and $\nu s\in\ZZ$ on $S(t)$, for every $t>0$. Let $\mathbb F=\QQ(\pi i,\,r_i:i\in\mathsf I)\subset\CC$, a countable field. A \emph{Laurent vector} is a map $y:(0,\infty)\to\RR^2$ whose coordinates are given by elements of $\mathbb F[t,t^{-1}]$ (real-valued for $t>0$). The maps $t\mapsto x_{i,m,n}(t)$ are Laurent vectors, Laurent vectors form a group under addition, and $t\mapsto\ell^t_{i,\iota}(y(t))$ is given by an element of $\mathbb F[t,t^{-1}]$ for every Laurent vector $y$ and $\iota\in\{1,2\}$. Fix a number $t_*>0$ that is transcendental over $\mathbb F$. Evaluation at $t_*$ is an injective ring homomorphism $\mathbb F[t,t^{-1}]\to\CC$ and extends to an embedding of the field $\mathbb F(t)$ of rational functions. Hence: \begin{equation}\label{eq:rig-generic} \parbox{0.8\linewidth}{two elements of $\mathbb F[t,t^{-1}]$, or two Laurent vectors, that agree at $t_*$ agree identically.} \end{equation} The radii $r_i$ $(i\in\mathsf I)$, $t_*$ and $1/t_*$ are pairwise incommensurable. Thus $(\Gamma_i(t_*))_{i\in\mathsf I^\pm}$ is a transverse family of hyperbolic grids with phase exponent $\nu$, to which Lemma~\ref{lem:formal-rigidity} and the constructions of Section~\ref{subsec:rig-certificate} apply. For other values of $t$ the lattices $\Gamma_i(t)$ may be commensurable and may share nonzero points. \emph{Step 2: labels.} Let $\Xi=\{0\}\sqcup\bigl(\mathsf I^\pm\times(\ZZ^2\setminus\{0\})\bigr)$ and put $x_0(t)=0$, $x_\lambda(t)=x_{i,m,n}(t)$ for $\lambda=(i,m,n)$. The label $0$ is regarded as the label $(i,0,0)$ of every class $i$. For each $t$ the map $\lambda\mapsto x_\lambda(t)$ maps $\Xi$ onto $S(t)$ and is injective on the labels of any one class; at $t=t_*$ it is a bijection. A \emph{label array} is an element $\hat c\in\CC^{\Xi\times\mathcal A_q}$, and we put \[ T^t[\hat c]=\sum_{\lambda\in\Xi}\sum_{|\alpha|\leq q} \hat c_\alpha(\lambda)\,\partial^\alpha\delta_{x_\lambda(t)} , \] a locally finite sum. Conversely, let $T$ be a distribution supported in $S(t)$ of local order at most $q$, with coefficients $c_\alpha(x)$. For each $x\in S(t)$ choose one label $\lambda(x)$ with $x_{\lambda(x)}(t)=x$, and define \begin{equation}\label{eq:rig-label-array} \hat c_\alpha(\lambda(x))=c_\alpha(x)\quad(x\in S(t)),\qquad \hat c_\alpha(\lambda)=0\quad \text{if }\lambda\neq\lambda(x_\lambda(t)). \end{equation} Then $T^t[\hat c]=T$ and $\hat c_\alpha(0)=c_\alpha(0)$. When several labels are mapped to the same point, the coefficients of $T$ at that point are thus attributed to one of them and the others receive zero. \emph{Step 3: rows depending on the parameter.} Apply Lemma~\ref{lem:formal-rigidity} to the family $(\Gamma_i(t_*))_{i\in\mathsf I^\pm}$ and the order $q$. Its translation vectors are $w_{i,l}(t_*)$ for Laurent vectors $w_{i,l}=x_{i,m_{i,l},n_{i,l}}$ with $(m_{i,l},n_{i,l})\in d_i^2\ZZ^2\setminus\{0\}$. For every $t>0$ we have $w_{i,l}(t)\in\Gamma_i(t)^\vee\setminus\{0\}$, and we define $\mathsf D_l(t)$, $\omega_l(t)$, $\varkappa_{l,\mathbf k}$ and the Laurent vectors $\mathsf w_{l,\mathbf k}$ as in \eqref{eq:rig-D-expansion}. For a Laurent vector $y$, $\beta\in\mathcal A_q$ and $t>0$ define the functional on label arrays \[ \mathsf r^t_{l,y,\beta}(\hat c)=\sum_{\mathbf k} \varkappa_{l,\mathbf k} \sum_{\substack{\lambda\in\Xi\\ x_\lambda(t)=y(t)+\mathsf w_{l,\mathbf k}(t)}}\hat c_\beta(\lambda) . \] The inner sum has at most one term from each class. Since $\tau_w\delta_x=\delta_{x-w}$, \begin{equation}\label{eq:rig-moving-row-meaning} \mathsf r^t_{l,y,\beta}(\hat c)=\text{the coefficient of } \partial^\beta\delta_{y(t)}\text{ in }\mathsf D_l(t)\,T^t[\hat c] \end{equation} for every $t>0$ and every label array, whether or not labels coincide at $t$. For $\lambda\in\Xi$ and $\beta\in\mathcal A_q$ define \[ \mathsf p^t_{\lambda,\beta}(\hat c)=\sum_{\substack{\alpha\in \mathcal A_q\\ \alpha\geq\beta,\ \alpha\neq\beta}} (-1)^{|\alpha-\beta|}\binom\alpha\beta\, \mathsf h_{\alpha-\beta}(x_\lambda(t))\,\hat c_\alpha(\lambda), \] with $\mathsf h_\gamma$ as in \eqref{eq:rig-phase-row}. Its coefficients are elements of $\mathbb F[t,t^{-1}]$. If $T$ is supported in $S(t)$, has local order at most $q$ and satisfies $\mathcal C^\nu T=T$, and $\hat c$ is a label array of $T$ as in \eqref{eq:rig-label-array}, then \begin{equation}\label{eq:rig-moving-phase-rows} \mathsf p^t_{\lambda,\beta}(\hat c)=0\qquad \text{for all }\lambda\in\Xi,\ \beta\in\mathcal A_q . \end{equation} Indeed, for $\lambda=\lambda(x)$ the left side is the coefficient of $\partial^\beta\delta_x$ in $\mathcal C^\nu T-T$, because $e^{2\pi i\nu s(x)}=1$; for all other labels $\hat c_\alpha(\lambda)=0$. Finally let the \emph{generic row} be \[ \mathsf r^{\rm gen}_{l,y,\beta}(\hat c)=\sum_{\mathbf k} \varkappa_{l,\mathbf k} \sum_{\substack{\lambda\in\Xi\\ x_\lambda\equiv y+\mathsf w_{l,\mathbf k}}}\hat c_\beta(\lambda), \] where $\equiv$ denotes equality of Laurent vectors; the inner sum has at most one term. Its coefficients are integers that do not depend on $t$, and $\mathsf r^{t_*}_{l,y,\beta}=\mathsf r^{\rm gen}_{l,y,\beta}$ by \eqref{eq:rig-generic}. \emph{Step 4: the row identity at $t_*$.} At $t=t_*$ label arrays are the same as arrays on $S(t_*)\times\mathcal A_q$, the functionals $\mathsf p^{t_*}_{\lambda,\beta}$ are the phase rows \eqref{eq:rig-phase-row}, and the translation row \eqref{eq:rig-translation-row} at a point of $\RR^2$ is either zero or equal to $\mathsf r^{t_*}_{l,y,\beta}$ for a Laurent vector $y$ whose value at $t_*$ is that point: if the row is nonzero, the point is $x_\lambda(t_*)-\mathsf w_{l,\mathbf k}(t_*)$ for some $\lambda$ and $\mathbf k$. Exactly as for \eqref{eq:rig-row-identity}, Lemmas~\ref{lem:formal-rigidity} and~\ref{lem:finite-rows} give, for each $\alpha$ with $1\leq|\alpha|\leq q$, finitely many triples $\mu=(l_\mu,y_\mu,\beta_\mu)$, $\mu\in\mathsf M_\alpha$, with Laurent vectors $y_\mu$, finitely many pairs $\mu'=(\lambda_{\mu'},\beta_{\mu'})$, $\mu'\in\mathsf M'_\alpha$, and complex numbers $\vartheta^*_\mu$, $\vartheta^*_{\mu'}$ such that for all label arrays \[ \hat c_\alpha(0)=\sum_{\mu\in\mathsf M_\alpha}\vartheta^*_\mu\, \mathsf r^{\rm gen}_\mu(\hat c) +\sum_{\mu'\in\mathsf M'_\alpha}\vartheta^*_{\mu'}\, \mathsf p^{t_*}_{\mu'}(\hat c), \] where $\mathsf r^{\rm gen}_\mu=\mathsf r^{\rm gen}_{l_\mu,y_\mu, \beta_\mu}$ and $\mathsf p^t_{\mu'}=\mathsf p^t_{\lambda_{\mu'}, \beta_{\mu'}}$. \emph{Step 5: the row identity for all parameters.} All the rows in the last identity, and the coordinate functional $\hat c\mapsto\hat c_\alpha(0)$, are supported in one finite subset of $\Xi\times\mathcal A_q$ that does not depend on $t$. Restricted to these columns, the rows $\mathsf r^{\rm gen}_\mu$ and $\mathsf p^t_{\mu'}$ form a matrix with entries in $\mathbb F[t,t^{-1}]$. The identity says that, after evaluation at $t_*$, a coordinate vector lies in the row space of this matrix. Evaluation at $t_*$ is an embedding of the field $\mathbb F(t)$ into $\CC$, and the solvability of a linear system is not affected by an extension of the field of scalars. Hence there are rational functions $\vartheta_\mu,\vartheta_{\mu'}\in\mathbb F(t)$ with \begin{equation}\label{eq:rig-moving-row-identity} \hat c_\alpha(0)=\sum_{\mu\in\mathsf M_\alpha}\vartheta_\mu(t)\, \mathsf r^{\rm gen}_\mu(\hat c) +\sum_{\mu'\in\mathsf M'_\alpha}\vartheta_{\mu'}(t)\, \mathsf p^t_{\mu'}(\hat c) \end{equation} as an identity over $\mathbb F(t)$, and therefore for all label arrays and all real $t>0$ outside the finite set $\mathsf E'$ of poles of the functions $\vartheta_\mu,\vartheta_{\mu'}$, $\mu\in\mathsf M_\alpha$, $\mu'\in\mathsf M'_\alpha$, $1\leq|\alpha|\leq q$. \emph{Step 6: incidences and denominators.} Fix $\mu\in\mathsf M_\alpha$ and write $(l,y,\beta)=(l_\mu,y_\mu, \beta_\mu)$. For $i\in\mathsf I^\pm$, $\mathbf k\in\{0,\dots,m_l\}^{\mathsf I^\pm}$ and $\iota\in\{1,2\}$ let \[ \mathsf v_{i,\mathbf k,\iota}(t)=\ell^t_{i,\iota}\bigl(y(t) +\mathsf w_{l,\mathbf k}(t)\bigr)\in\mathbb F[t,t^{-1}], \] so that $y(t)$ lies in the coset $\Gamma_i(t)-\mathsf w_{l,\mathbf k}(t)$ if and only if $\mathsf v_{i,\mathbf k,1}(t)$ and $\mathsf v_{i,\mathbf k,2}(t)$ are integers. Call the pair $(i,\mathbf k)$ of \emph{type one} if both functions are constant with integer values, and of \emph{type two} otherwise. For a pair of type two choose $\iota=\iota(i,\mathbf k)$ such that $\mathsf v^\star_{i,\mathbf k}:=\mathsf v_{i,\mathbf k,\iota}$ is not an integer constant. By \eqref{eq:rig-generic}, $\mathsf v^\star_{i,\mathbf k}(t_*)\notin\ZZ$. Consequently the function \[ \mathfrak d_\mu(t)=\prod_{(i,\mathbf k)\ \text{of type two}} \bigl(e^{2\pi i\mathsf v^\star_{i,\mathbf k}(t)}-1\bigr) \] is real-analytic on $(0,\infty)$ and does not vanish at $t_*$. Its zeros, and the zeros of the finitely many functions $\mathfrak d_\mu$ together, form a closed discrete subset $\mathsf E''$ of $(0,\infty)$. We claim that \begin{equation}\label{eq:rig-no-extra-incidence} \mathsf r^t_\mu=\mathsf r^{\rm gen}_\mu\qquad \text{for all }t\in(0,\infty)\setminus\mathsf E'' . \end{equation} Every term of $\mathsf r^{\rm gen}_\mu$ occurs in $\mathsf r^t_\mu$, and the two functionals differ only by terms $\hat c_\beta(\lambda)$ with $x_\lambda(t)=y(t)+\mathsf w_{l,\mathbf k}(t)$ for some $\mathbf k$. Let $\lambda$ and $\mathbf k$ satisfy this equation at some $t\notin\mathsf E''$, and let $i$ be a class of $\lambda$. Then $y(t)$ lies in $\Gamma_i(t)-\mathsf w_{l,\mathbf k}(t)$, so both $\mathsf v_{i,\mathbf k,\iota}(t)$ are integers. Since $t\notin\mathsf E''$, the pair $(i,\mathbf k)$ is of type one: $\mathsf v_{i,\mathbf k,1}\equiv m$ and $\mathsf v_{i,\mathbf k,2}\equiv n$ with integers $m,n$. Hence $y+\mathsf w_{l,\mathbf k}\equiv x_{i,m,n}$ as Laurent vectors, and $x_\lambda(t)=x_{i,m,n}(t)$. As the labels of the class $i$ are mapped injectively, $\lambda=(i,m,n)$, and the term $\hat c_\beta(\lambda)$ occurs in $\mathsf r^{\rm gen}_\mu$ as well. This proves \eqref{eq:rig-no-extra-incidence}. \emph{Step 7: the tests.} Choose $\varepsilon_0\in(0,t_0)$ so small that the set $\{t:0<|t-t_0|\leq\varepsilon_0\}$ contains no point of $\mathsf E'\cup\mathsf E''$; this is possible because both sets are closed and discrete in $(0,\infty)$. For $0<|t-t_0|<\varepsilon_0$ and $\mu\in\mathsf M_\alpha$, $1\leq|\alpha|\leq q$, let $\psi_{\mu,t}$ be the function $\psi$ of Lemma~\ref{lem:rig-cardinal-tests} for the cosets $\Gamma_i(t)-\mathsf w_{l_\mu,\mathbf k}(t)$, written with the forms $\ell^t_{i,1},\ell^t_{i,2}$ and the points $-\mathsf w_{l_\mu,\mathbf k}(t)$, for the point $y_\mu(t)$, the order $q$, the index $\beta_\mu$, and the choices $\ell^\star=\ell^t_{i,\iota(i,\mathbf k)}$ of Step~6. These choices are legitimate: for a pair of type one, $y_\mu(t)$ lies in the coset for every $t$; for a pair of type two and $t\notin\mathsf E''$, the chosen form is not integral at $y_\mu(t)+\mathsf w_{l_\mu,\mathbf k}(t)$, so $y_\mu(t)$ does not lie in the coset. The quantity $\mathfrak d$ of Lemma~\ref{lem:rig-cardinal-tests}(ii) is $|\mathfrak d_\mu(t)|$. Define \[ f_{\mu,t}=\vartheta_\mu(t)\,\omega_{l_\mu}(t)\,\mathbb S\psi_{\mu,t} . \] The functions $f_{l,t}$ of the proposition are the $f_{\mu,t}$, $\mu\in\mathsf M_\alpha$, $1\leq|\alpha|\leq q$, in some enumeration. Assertion (i) follows as in the proof of Theorem~\ref{thm:origin-certificate}, from Lemmas~\ref{lem:rig-cardinal-tests}(ii) and~\ref{lem:rig-mixture-family}. \emph{Step 8: proof of (ii).} Let $0<|t-t_0|<\varepsilon_0$ and let $T$ be as in (ii). Then $\supp T\subset\Sigma(t)\subset S(t)$. Every point of $S(t)$ lies in some $\Gamma_i(t)$, $i\in\mathsf I^\pm$, and the factor $(\chi_{w_{i,l}(t)}-1)^{m_l}$ of $\omega_l(t)$ vanishes on $\Gamma_i(t)$ to order $m_l\geq q+1$, because $w_{i,l}(t)\in\Gamma_i(t)^\vee$. This holds for every $t$, also when the lattices $\Gamma_i(t)$ are not transverse, since it uses only a class to which the point belongs and the factor of that class. Hence $\omega_l(t)T=0$ by Lemma~\ref{lem:rig-local-pairing}(ii), and as in the proof of Theorem~\ref{thm:origin-certificate}, using that $T$ is even, \[ \mathsf D_l(t)T=\mathbb S\,\omega_l(t)\,(\mathbb S-I)T . \] Let $\hat c$ be a label array of $T$ as in \eqref{eq:rig-label-array}. By \eqref{eq:rig-no-extra-incidence}, \eqref{eq:rig-moving-row-meaning} and Lemma~\ref{lem:rig-cardinal-tests}(i), \[ \mathsf r^{\rm gen}_\mu(\hat c)=\mathsf r^t_\mu(\hat c) =\langle\mathsf D_{l_\mu}(t)T,\psi_{\mu,t}\rangle =\bigl\langle(\mathbb S-I)T,\, \omega_{l_\mu}(t)\,\mathbb S\psi_{\mu,t}\bigr\rangle . \] Since $\mathcal C^\nu T=T$, the phase rows vanish on $\hat c$ by \eqref{eq:rig-moving-phase-rows}. Inserting this into \eqref{eq:rig-moving-row-identity}, which is valid because $t\notin\mathsf E'$, and using $\hat c_\alpha(0)=c_\alpha(0)$, \[ c_\alpha(0)=\sum_{\mu\in\mathsf M_\alpha} \langle(\mathbb S-I)T,f_{\mu,t}\rangle , \] which implies \eqref{eq:rig-moving-certificate}. \emph{Step 9: proof of (iii).} For $|t-t_0|\leq\varepsilon_0$ the points $y_\mu(t)$, the vectors $\mathsf w_{l,\mathbf k}(t)$ and the forms $\ell^t_{i,\iota}$ are bounded, since $t$ stays in a compact subset of $(0,\infty)$. By Lemma~\ref{lem:rig-cardinal-tests}(ii), each $\psi_{\mu,t}$ is a sum of a bounded number of functions $\mathfrak m[p,z]$ with fixed $n$ and $n'$, with $\|z\|$ bounded uniformly in $t$, and with $\|p\|\leq C|\mathfrak d_\mu(t)|^{-(q+1)^2}$. By Lemma~\ref{lem:rig-mixture-family}(i) and (ii) the same holds for $\mathbb S\psi_{\mu,t}$, for $f_{\mu,t}=\vartheta_\mu(t)\omega_{l_\mu}(t)\mathbb S\psi_{\mu,t}$ and for $\mathbb Sf_{\mu,t}$, with \[ \|p\|\leq C\,|\vartheta_\mu(t)|\,|\mathfrak d_\mu(t)|^{-(q+1)^2}; \] here we use that $\omega_l(t)$ is a sum of exponentials $e^{2\pi iB(\mathsf w_{l,\mathbf k}(t),X)}$ with fixed integer coefficients and bounded $\mathsf w_{l,\mathbf k}(t)$. The function $\mathfrak d_\mu$ is real-analytic near $t_0$ and not identically zero, so it vanishes at $t_0$ to some finite order $k_\mu\geq0$. Since it has no other zero in $[t_0-\varepsilon_0,t_0+\varepsilon_0]$, the quotient $\mathfrak d_\mu(t)/(t-t_0)^{k_\mu}$ is continuous and nonvanishing on this interval, and $|\mathfrak d_\mu(t)|\geq C^{-1}|t-t_0|^{k_\mu}$ there. Similarly the rational function $\vartheta_\mu$ has at most a pole of finite order $k'_\mu$ at $t_0$ and no other pole in the interval, so $|\vartheta_\mu(t)|\leq C|t-t_0|^{-k'_\mu}$. With $K=\max_\mu\bigl((q+1)^2k_\mu+k'_\mu\bigr)$ we obtain $\|p\|\leq C|t-t_0|^{-K}$, and Lemma~\ref{lem:rig-mixture-family}(iii) gives \eqref{eq:rig-moving-envelope}. The exponent $K$ is determined by the chosen row identities and the denominators, which were fixed in terms of $\mathcal R_0$, $t_0$ and $q$ alone; the numbers $k_0$, $\varrho$ and $b$ affect only $C$. \end{proof} \subsection{The localization obstruction} \label{subsec:rig-localization} In this subsection the certificates are applied to the spectrum of an admissible partition function. The distribution to which they are applied is a finite Taylor expansion of the analytic evaluation \eqref{eq:analytic-evaluation} about real lattice points. \paragraph{Weight derivatives of the state measures.} For $h>0$, an integer $k\geq0$ and a smooth function $\phi$ on $\RR$, the function $h\mapsto\langle A_h,\phi\rangle =\frac12(\phi(\sqrt h)+\phi(-\sqrt h))$ is smooth on $(0,\infty)$, and by the chain rule its $k$-th derivative is a linear combination of the numbers $\phi^{(l)}(\pm\sqrt h)$, $l\leq k$. This defines a distribution $A_h^{(k)}$ on $\RR$ which is even, supported in $\{\pm\sqrt h\}$ and of order at most $k$. For $h=0$ we put \[ A_0^{(k)}=\frac{k!}{(2k)!}\,\delta_0^{(2k)} . \] If $\phi$ is entire, then $\frac12(\phi(\sqrt h)+\phi(-\sqrt h)) =\sum_k\phi^{(2k)}(0)h^k/(2k)!$ is an entire function of $h$, and $\langle A_h^{(k)},\phi\rangle$ is its $k$-th derivative for every $h\geq0$. Applying this in each variable, for every entire function $f$ on $\CC^2$ and all $h,\bar h\geq0$, \begin{equation}\label{eq:rig-jet-pairing} \bigl\langle A_h^{(i)}\otimes A_{\bar h}^{(l)},f\bigr\rangle =\partial_h^i\partial_{\bar h}^l\,\ev f(h,\bar h). \end{equation} For a real point $X=(P,Q)$ and $k\geq0$ let \begin{equation}\label{eq:rig-fixed-spin-jet} \Upsilon_X^{(k)}=2^{-k}\sum_{i+l=k}\binom ki\, A_{P^2}^{(i)}\otimes A_{Q^2}^{(l)} . \end{equation} By \eqref{eq:rig-jet-pairing}, for entire $f$, \begin{equation}\label{eq:rig-jet-derivative} \bigl\langle\Upsilon_X^{(k)},f\bigr\rangle =\frac{d^k}{d\zeta^k}\Big|_{\zeta=0} \ev f\bigl(P^2+\tfrac\zeta2,\,Q^2+\tfrac\zeta2\bigr). \end{equation} Thus $\Upsilon_X^{(k)}$ is the $k$-th derivative of the state measure $A_h\otimes A_{\bar h}$ along the curve of constant spin through $(h,\bar h)=(P^2,Q^2)$, parametrized by the dimension; the variable $\zeta$ is the displacement called $d$ in the remark following Lemma~\ref{lem:weight-derivative-bound}. It is an even distribution supported in $\{(\pm P,\pm Q)\}$ and of local order at most $2k$. \begin{lemma}[The Taylor distribution]\label{lem:rig-taylor-distribution} Let $Z$ be an admissible partition function of gap $g$ at $c=1+12a$ with $00$ and $0\leq\varepsilon0$, let $b>0$ and $M<\infty$, and suppose that \begin{equation}\label{eq:rig-test-envelope} |\partial^\alpha F(X)|\leq M\,e^{-b|\operatorname{Re}X|^2}\qquad \text{for }F\in\{f,\mathbb Sf\},\ |\alpha|\leq2N+2,\ |\operatorname{Im}P|,|\operatorname{Im}Q|\leq1 . \end{equation} Then, with a constant $C_N$ depending only on $N$, \begin{equation}\label{eq:rig-defect-bound} \begin{split} \bigl|\langle(\mathbb S-I)T_a,f\rangle\bigr|\leq C_N\,e^{5b}M \Bigl[&\#\{j:\Delta_j\leq E_*\}\,(\varepsilon+a)^{N+1}+a^{N+1}\\ &+\sum_{j:\,\Delta_j>E_*}e^{-b\Delta_j}\Bigr]. \end{split} \end{equation} \end{enumerate} \end{lemma} \begin{proof} (i) Finitely many states have $\Delta_j\leq E_*$, so the sum is finite. Each $\Upsilon^{(n)}_X$ with $n\leq N$ is even, of local order at most $2N$, and supported in $\{(\pm P,\pm Q)\}$, which is contained in $\Sigma$ for $X=X_j$ and for the vacuum points. For the phase, let $X=(P,Q)$ be real with $P^2-Q^2\in\ZZ$ and let $f$ be entire. The function $e^{2\pi i(P^2-Q^2)}f$ has the even evaluation $e^{2\pi i(h-\bar h)}\ev f(h,\bar h)$, and along the curve $(h,\bar h)=(P^2+\frac\zeta2,Q^2+\frac\zeta2)$ the factor $e^{2\pi i(h-\bar h)}$ is identically one. By \eqref{eq:rig-jet-derivative}, $\langle\mathcal C\Upsilon^{(n)}_X,f\rangle =\langle\Upsilon^{(n)}_X,f\rangle$ for all entire $f$. Both sides are distributions of finite order with support in the same finite set, and polynomials realize arbitrary jets at finitely many points; hence $\mathcal C\Upsilon^{(n)}_X=\Upsilon^{(n)}_X$. This applies to $X_j$, because $P_j^2-Q_j^2=s_j\in\ZZ$, and to the vacuum points. (ii) For a state, $|X_j|^2\geq\Delta_j-\varepsilon\geq g-\varepsilon>0$, so none of the points $(\pm P_j,\pm Q_j)$ is the origin. The vacuum terms with $(k,l)\neq(0,0)$ are supported away from the origin. For $(k,l)=(0,0)$, by the definition of $A_0^{(i)}$, \[ \Upsilon^{(n)}_{(0,0)}=2^{-n}\sum_{i+l=n}\binom ni \frac{i!\,l!}{(2i)!\,(2l)!}\, \partial_P^{2i}\partial_Q^{2l}\delta_0 , \] which is $\delta_0$ for $n=0$, equals $\frac14(\partial_P^2+\partial_Q^2)\delta_0$ for $n=1$, and has order $2n\geq4$ for $n\geq2$. The term $n=1$ carries the factor $-a$. (iii) Let $F\in\{f,\mathbb Sf\}$; recall that $\mathbb Sf\in\mathcal G_{4\pi^2/b_0}$. For a state with $\Delta_j\leq E_*$ put $\Phi_j(\zeta)=\ev F(P_j^2+\frac\zeta2,Q_j^2+\frac\zeta2)$, and for $k,l\in\{0,1\}$ put $\Psi_{k,l}(\zeta)=\ev F(k+\frac\zeta2,l+\frac\zeta2)$. These are entire functions of $\zeta$. Since $P_j^2=\frac12(|X_j|^2+s_j)$ and $h_j=\frac12(\Delta_j+s_j)$, and similarly for $Q_j^2$ and $\bar h_j$, \[ \Phi_j(\zeta_j)=\ev F\bigl(h_j-\tfrac a2,\bar h_j-\tfrac a2\bigr), \qquad \Psi_{k,l}(-a)=\ev F\bigl(k-\tfrac a2,l-\tfrac a2\bigr), \] which are the shifted evaluations in \eqref{eq:analytic-evaluation}. By \eqref{eq:rig-jet-derivative} and \eqref{eq:rig-taylor-distribution}, $\langle T_a,F\rangle$ is the sum of the Taylor polynomials of degree $N$ at $\zeta=0$ of these functions, evaluated at $\zeta_j$ and at $-a$ respectively. Therefore \begin{equation}\label{eq:rig-taylor-split} \begin{split} \mathcal L_a(F)-\langle T_a,F\rangle ={}&\sum_{k,l\in\{0,1\}}(-1)^{k+l}\,\mathrm{Rem}_N[\Psi_{k,l}](-a) +\sum_{j:\,\Delta_j\leq E_*}\mathrm{Rem}_N[\Phi_j](\zeta_j)\\ &+\sum_{j:\,\Delta_j>E_*} \ev F\bigl(h_j-\tfrac a2,\bar h_j-\tfrac a2\bigr), \end{split} \end{equation} where $\mathrm{Rem}_N[\Phi](\zeta)$ denotes the Taylor remainder of order $N$, and where the sums defining $\mathcal L_a(F)$ converge absolutely by Lemma~\ref{lem:gaussian-identity}. For real $\zeta$, \[ \bigl|\mathrm{Rem}_N[\Phi](\zeta)\bigr|\leq \frac{|\zeta|^{N+1}}{(N+1)!}\, \max_{\zeta'\ \text{between}\ 0\ \text{and}\ \zeta} |\Phi^{(N+1)}(\zeta')| , \] and $\Phi_j^{(N+1)}(\zeta')$ is the average, with weights $2^{-N-1}\binom{N+1}i$, of the derivatives $\partial_h^i\partial_{\bar h}^{N+1-i}\ev F$ at the point $(P_j^2+\frac{\zeta'}2,Q_j^2+\frac{\zeta'}2)$. For $\zeta'$ between $0$ and $\zeta_j$, the first coordinate of this point lies between $P_j^2\geq0$ and $h_j-\frac a2\geq-\frac a2$, the second between $Q_j^2\geq0$ and $\bar h_j-\frac a2\geq-\frac a2$, and their sum $|X_j|^2+\zeta'$ is at least $-a$. Thus both arguments are real and at least $-1$, whatever their size, and Lemma~\ref{lem:weight-derivative-bound} applies with $k=N+1$ and $\beta=b$, by \eqref{eq:rig-test-envelope}. That lemma is uniform over all real arguments $h,\bar h\geq-1$. Hence no separate treatment is needed for paths along which a squared momentum is small, vanishes, becomes slightly negative, or passes from the range in which the proof of that lemma uses the integral formula \eqref{eq:sq-momentum-derivative} to the range in which it uses the endpoint formula. We obtain $|\Phi_j^{(N+1)}(\zeta')|\leq C_{N+1}Me^{4b}e^{b}$ and, since $|\zeta_j|\leq\varepsilon+a$, \[ \bigl|\mathrm{Rem}_N[\Phi_j](\zeta_j)\bigr| \leq C_{N+1}Me^{5b}(\varepsilon+a)^{N+1}. \] The same argument for $\Psi_{k,l}$ on $[-a,0]$, where the arguments are at least $-\frac a2$ and their sum is at least $-a$, gives $|\mathrm{Rem}_N[\Psi_{k,l}](-a)|\leq C_{N+1}Me^{5b}a^{N+1}$. For the states with $\Delta_j>E_*$, Lemma~\ref{lem:weight-derivative-bound} without derivatives gives \[ \bigl|\ev F\bigl(h_j-\tfrac a2,\bar h_j-\tfrac a2\bigr)\bigr| \leq C_{N+1}Me^{4b}e^{-b(\Delta_j-a)}\leq C_{N+1}Me^{5b}e^{-b\Delta_j}. \] Hence $|\mathcal L_a(F)-\langle T_a,F\rangle|$ is bounded by $4C_{N+1}e^{5b}M$ times the bracket in \eqref{eq:rig-defect-bound}. Finally, by Lemma~\ref{lem:gaussian-identity}, $\mathcal L_a(\mathbb Sf)=\mathcal L_a(f)$, so \[ \langle(\mathbb S-I)T_a,f\rangle =\langle T_a,\mathbb Sf\rangle-\langle T_a,f\rangle =\bigl[\mathcal L_a(f)-\langle T_a,f\rangle\bigr] -\bigl[\mathcal L_a(\mathbb Sf)-\langle T_a,\mathbb Sf\rangle\bigr], \] and \eqref{eq:rig-defect-bound} follows with $C_N=8C_{N+1}$. \end{proof} The individual coefficients of $T_a$ in \eqref{eq:rig-local-form} need not be bounded: they can be large when a nonzero squared momentum $P_j^2$ or $Q_j^2$ is small. The proof does not use them; Lemma~\ref{lem:weight-derivative-bound} controls their combined action on entire test functions. \begin{theorem}[No localization on a fixed union of circle lattices] \label{thm:fixed-localization} Let $00$, $C<\infty$, $A<\infty$ and $u_*>1/(2\pi)$. There is no admissible sequence of gap $g$, with parameters $a\to0$ and $L=\log(1/a)$, such that for every $a$ in the sequence every state $j$ with $\Delta_j\leq u_*L$ has a real point $X_j=(P_j,Q_j)\in\Sigma_0$ with \begin{equation}\label{eq:rig-localization-hypothesis} P_j^2-Q_j^2=s_j\qquad\text{and}\qquad \bigl|\Delta_j-|X_j|^2\bigr|\leq C\,a^pL^A . \end{equation} The assignment $j\mapsto X_j$ is not required to be injective, and no relation between the number of states assigned to a point and any multiplicity is assumed. \end{theorem} \begin{proof} Suppose that such a sequence exists. Fix $b$ with $1/u_*1$, and put $q=2N$. Let $f_1,\dots,f_n$ and $C_{\Sigma_0,q}$ be given by Theorem~\ref{thm:origin-certificate} for $\Sigma=\Sigma_0$. Since $f_l$ and $\mathbb Sf_l$ lie in $\mathcal G_{2\pi}$, the bound \eqref{eq:mixture-envelope} with $b'=b$ provides a constant $M$ such that \eqref{eq:rig-test-envelope} holds for every $f=f_l$. Let $a$ be an element of the sequence, so small that $a\leq g^2/4$, $2\pi au_*L}e^{-b\Delta_j}\leq A_gb\Bigl( \frac{u_*L}{b-2\pi a}+\frac1{(b-2\pi a)^2}\Bigr) e^{-(b-2\pi a)u_*L}=O\bigl(L\,a^{bu_*}\bigr), \] because $e^{2\pi au_*L}\to1$. Altogether \begin{equation}\label{eq:rig-fixed-defect} \max_l\bigl|\langle(\mathbb S-I)T_a,f_l\rangle\bigr| \leq C'\Bigl[L^{1+(N+1)A_+}\,a^{(N+1)\min(p,1)}+a^{N+1} +L\,a^{bu_*}\Bigr] \end{equation} with $C'$ independent of $a$. Since $(N+1)\min(p,1)>1$, $N+1>1$ and $bu_*>1$, the right side is $o(a)$. This contradicts the lower bound $a/4$ for small $a$. \end{proof} \begin{theorem}[No localization with one moving radius] \label{thm:moving-localization} Let $00$, $C<\infty$, $A<\infty$ and $u_*>1/(2\pi)$. There is no admissible sequence of gap $g$, with parameters $a\to0$ and $L=\log(1/a)$, together with radii $t_a\in I$, such that for every $a$ in the sequence every state $j$ with $\Delta_j\leq u_*L$ has a real point \[ X_j=(P_j,Q_j)\in\Sigma_0\cup\Lambda_{t_a}\cup\Lambda_{1/t_a} \] with \[ P_j^2-Q_j^2=s_j\qquad\text{and}\qquad \bigl|\Delta_j-|X_j|^2\bigr|\leq C\,a^pL^A . \] The assignment $j\mapsto X_j$ is not required to be injective, no relation between the number of states assigned to a point and any multiplicity is assumed, and $\Sigma_0\cup\Lambda_{t_a}\cup\Lambda_{1/t_a}$ is not required to be the support of an element of $\mathcal B_g$. \end{theorem} \begin{proof} Suppose that such a sequence exists. Passing to a subsequence we may assume $t_a\to t_0\in I$. We use the notation $\Sigma(t)$ of Proposition~\ref{prop:moving-certificate}. \emph{Choice of parameters.} Fix $b$ with $1/u_*1$, and put $q=2N$. Apply Proposition~\ref{prop:moving-certificate} to $\mathcal R_0$, $t_0$ and $q$; this provides $\varepsilon_0$, $n$, the exponent $K$ and the tests $f_{l,t}$. Then apply part (iii) of the proposition with $k_0=2N+2$, the strip $|\operatorname{Im}X|\leq\sqrt2$ and the chosen $b$; this provides the constant $C_1$ in \eqref{eq:rig-moving-envelope}. Finally fix $\eta>0$ so small that \begin{equation}\label{eq:rig-eta} K\eta<\tfrac12\min\bigl\{(N+1)\min(p,1)-1,\ bu_*-1\bigr\}. \end{equation} Thus $N$, $q$, the number of derivatives and $K$ are fixed before $\eta$. Either $|t_a-t_0|\geq a^\eta$ for infinitely many $a$ in the sequence, or $|t_a-t_0|0$, the constants $C_3$ and $\max(A,1)$, and the same $g$ and $u_*$. \end{proof} By Lemma~\ref{lem:grid-circles}, the hypothesis on $\mathcal R_0$ in Theorems~\ref{thm:fixed-localization} and~\ref{thm:moving-localization} is satisfied by the set $\mathcal R_d$ of radii that carries the integral-spin points of the light-cone grid $d^{-1}\Lambda_1$. The two theorems are equivalent to a statement about individual partition functions. \begin{corollary}[Uniform form]\label{cor:rig-threshold} Let $g$, $\mathcal R_0$, $\Sigma_0$, $I$, $p$, $C$, $A$ and $u_*$ be as in Theorem~\ref{thm:moving-localization}. There is $a_*>0$ with the following property. If $Z$ is an admissible partition function of gap $g$ at $c=1+12a$ with $0