% Compile with pdfLaTeX at least twice for cross-references. \documentclass[11pt,a4paper]{article} \usepackage[T1]{fontenc} \usepackage[utf8]{inputenc} \usepackage{lmodern} \usepackage{amsmath,amssymb,amsthm,mathtools,mathrsfs} \usepackage[margin=25mm,footskip=12mm]{geometry} \usepackage{microtype,booktabs,array,tabularx,enumitem,needspace} \makeatletter \renewcommand\section{\@startsection{section}{1}{\z@} {-18pt plus -4pt minus -2pt}{7pt}{\normalfont\large\bfseries}} \renewcommand\subsection{\@startsection{subsection}{2}{\z@} {-12pt plus -3pt minus -2pt}{5pt}{\normalfont\normalsize\bfseries}} \renewcommand\subsubsection{\@startsection{subsubsection}{3}{\z@} {-9pt plus -2pt minus -1pt}{4pt}{\normalfont\normalsize\itshape}} \renewcommand\@seccntformat[1]{\csname the#1\endcsname\hspace{0.6em}} \makeatother \usepackage[unicode,hidelinks]{hyperref} \hypersetup{ pdftitle={Seven Research Directions in Differential Geometry and Differential Topology Enabled by AI}, pdfauthor={GPT 6 Astra},bookmarksnumbered=true,bookmarksdepth=2 } \setlength{\parindent}{1.5em} \setlength{\parskip}{2pt plus 1pt minus 1pt} \setlength{\emergencystretch}{2em} \setlist[enumerate]{label=\textup{(\roman*)},leftmargin=1.8em,itemsep=2pt,topsep=4pt} \setlist[itemize]{leftmargin=1.5em,itemsep=2pt,topsep=4pt} \setcounter{secnumdepth}{2} \setcounter{tocdepth}{1} \newtheoremstyle{paper}{7pt}{5pt}{\itshape}{}{\bfseries}{.}{0.5em}{} \theoremstyle{paper} \newtheorem{theorem}{Theorem}[section] \newtheorem{proposition}[theorem]{Proposition} \newtheorem{lemma}[theorem]{Lemma} \newtheorem{corollary}[theorem]{Corollary} \theoremstyle{definition} \newtheorem{definition}[theorem]{Definition} \newtheorem{example}[theorem]{Example} \theoremstyle{remark} \newtheorem{remark}[theorem]{Remark} \newtheorem*{remark*}{Remark} \numberwithin{equation}{section} \pagestyle{plain} \raggedbottom \clubpenalty=10000 \widowpenalty=10000 \makeatletter \renewenvironment{thebibliography}[1] {\section*{References}\phantomsection\addcontentsline{toc}{section}{References}\small\raggedright \list{\@biblabel{\@arabic\c@enumiv}} {\settowidth\labelwidth{\@biblabel{#1}}\leftmargin\labelwidth \advance\leftmargin\labelsep\@openbib@code\usecounter{enumiv} \let\p@enumiv\@empty\renewcommand\theenumiv{\@arabic\c@enumiv} \setlength{\itemsep}{4pt}\setlength{\parsep}{0pt}} \sloppy\clubpenalty4000\widowpenalty4000\sfcode`\.=1000\relax} {\def\@noitemerr{\@latex@warning{Empty bibliography}}\endlist} \makeatother \begin{document} \begin{center} {\Large\bfseries Seven Research Directions in Differential Geometry\\[3pt] and Differential Topology Enabled by AI\par} \vspace{14pt} {\normalsize GPT 6 Astra\par} \vspace{4pt} {\normalsize prompted be Jianqiao Shang\par} \end{center} \begin{abstract} \phantomsection \pdfbookmark[1]{Abstract}{paper-abstract} This article presents seven AI-generated research directions in differential geometry and differential topology, each centered on a proposed research object or formulation. For each direction, we provide basic definitions and theorems, discuss connections with existing mathematical problems and theories, and outline questions for further study. The definitions introduced in these seven directions are relatively new. The article is intended as a collection of AI-generated research guides rather than a conventional research paper. \end{abstract} \vspace{10pt} \tableofcontents \clearpage \section{Introduction} \label{sec:introduction} \subsection{Background} \label{intro:background} The idea behind this article was to let AI explore geometry and topology freely and see what conclusions it could reach by focusing on ``heuristic'' mathematics. Using the chat interface of GPT 6 Astra Pro, the prompter started fifteen separate conversations and asked the AI to propose new mathematical objects worth studying. The prompter then merged related topics, discarded problems that did not seem worth pursuing, and collected the directions he himself found interesting into this research guide. These questions are relatively new overall, but they are closely tied to existing human mathematical research. According to the prompter, further work has shown clear mathematical structure in some of these theories and has even solved open problems in other areas. This gives the prompter reason to believe that at least some of these directions are promising. The prompter will discuss further work on these directions in later papers. The prompter claims no credit for any of these theories and welcomes human-led mathematical discussion with anyone interested in them. The hope is that AI will create more interesting mathematical problems, rather than just kill existing ones. References may be incomplete, since the prompter has limited knowledge of each of these areas and AI may have missed relevant works. The prompter apologizes for any omissions of works that should have been cited as sources of the ideas presented here and will correct them as soon as they are reported. \subsection{Critical kernels} Section~\ref{ck:chapter} studies symmetric kernels whose Morse slice functions define finite critical equivalence classes. The associated coverings give strong topological restrictions when the Euler characteristic is nonzero. First-level Morse--Bott attachments yield quadratic cohomology extensions, and additional generation hypotheses lead to recognition by reflection groups. This connects the construction with invariant theory and rational homotopy theory. Further questions concern geometric realizability and what remains true without the generation hypotheses. \subsection{Uniformly Morse linear systems} Section~\ref{um:chapter} studies finite-dimensional spaces of functions modulo constants whose nonzero elements are Morse. On a closed connected $n$-manifold, the rank is at most $n+1$, with equality possible precisely on the standard smooth sphere. Critical coverings, Hessian bundles, and critical-point configurations furnish extension obstructions. A rank-two system on $S^3$ with linked minima admits an odd nonlinear extension but no rank-three linear extension. Connections with parametrized Morse theory and round fold maps motivate further questions about existence, deformation classes, and maximal systems. \subsection{Presymplectic dependency algebras} Section~\ref{pd:chapter} studies positive systems of closed two-forms of constant rank zero or two and their finite wedge algebras. Restriction to characteristic foliations realizes matroid contraction. The algebras distinguish systems on a fixed torus with identical cohomology classes, matroids, and volume polynomials. These constructions relate multilinear matroid representations to symplectic pairs and polysymplectic geometry. Further questions concern local moduli and the extent to which the algebra captures the geometry and deformation behavior of the chosen system. \subsection{Diffusion transport defects} Section~\ref{dt:chapter} studies rank defects of connection heat kernels and coverings by their invertibility domains. Characteristic classes give lower bounds for the covering number. Flat torus constructions exhibit arbitrarily many distinct covering levels as time varies, keeping the metric and connection fixed in each example while allowing dimension to grow. The framework relates vector diffusion methods, characteristic-class obstructions, and theta-function geometry. Further questions concern transversality and the possible time profiles of the covering number. \subsection{Tangent shapes and knots} Section~\ref{ts:chapter} studies families of compact shapes embedded in punctured tangent spaces and oriented knots in spheres of tangent directions. Euler-class and holonomy arguments yield obstructions and rigidity results for shape fields. For a prescribed positive nontrivial torus-knot type on a closed, connected, oriented smooth four-manifold, existence is characterized by a weighted circle reduction of the tangent bundle and explicit characteristic-class conditions. These results connect embedding spaces, classical $G$-structures, and four-manifold topology. Further questions concern deformation classes, additional differential conditions, and the geometry of linear incidence among tangent directions. \Needspace{11\baselineskip} \subsection{Finite-scale bundle comparisons} Section~\ref{fs:chapter} organizes smooth fiber identifications by their distance from the diagonal, using an extension radius and a system of restriction maps. We establish metric stability and line-bundle criteria, including an exact half-systole formula for nontrivial real line bundles and computations on flat tori. For closed negatively curved oriented surfaces, the complete family of labelled radii on finite covers recovers the marked length spectrum. This links direct connections with systolic geometry. Further questions concern higher-rank obstructions, critical radii, and information retained by the full comparison system. \subsection{Harmonic closure of differential forms} Section~\ref{hc:chapter} considers the algebra generated by harmonic forms under wedge product, exterior differentiation, and Hodge star on a closed oriented Riemannian manifold. Finite closure produces a finite de Rham model and a canonical Lie algebra. For compact nilmanifolds with descended left-invariant metrics, the construction recovers the metric Lie algebra. Other results include conformal rigidity in the presence of intermediate cohomology and a three-dimensional classification. Connections with geometric formality motivate further study of higher-dimensional finite-closure metrics and their associated Lie algebra actions. \section{Critical kernels} \label{ck:chapter} A critical kernel is a symmetric two-point function whose slice critical points form finite equivalence classes. The resulting covering structure imposes restrictions on the topology of the underlying manifold. Throughout this section, manifolds are smooth, closed (compact without boundary), connected, and of positive dimension. Cohomology is singular cohomology. Put $P_M(t)=\sum_j\dim H^j(M;\mathbb Q)t^j$. A rational homotopy equivalence is denoted by $\simeq_{\mathbb Q}$. For a left action on $M$, the left action on cohomology is $g\cdot a=(g^{-1})^*a$; formulas involving $g^*$ use ordinary pullback. \subsection{Definition and covering geometry} \label{ck:sec:definition} \begin{definition}[Critical kernel] \label{ck:def:kernel} A \emph{critical kernel} on $M$ is a smooth function $F:M\times M\to[0,\infty)$ such that: \begin{enumerate}[label=\textup{(\roman*)}] \item $F(x,y)=F(y,x)$, and $F(x,y)=0$ if and only if $x=y$; \item for every $x\in M$, the slice $F_x(y)=F(x,y)$ is Morse; \item the relation $x\sim_F y\Longleftrightarrow d_2F(x,y)=0$ is an equivalence relation. \end{enumerate} Write $C_F=\{(x,y):d_2F(x,y)=0\}$ and $B_F=M/{\sim_F}$. An isomorphism of kernels is a diffeomorphism $\phi:M\to N$ satisfying $F_N(\phi x,\phi y)=F_M(x,y)$. \end{definition} \begin{proposition}[Critical covering] \label{ck:prop:covering} Let $n=\dim M$. Then $C_F$ is a closed embedded $n$-manifold; both projections $C_F\to M$ are finite coverings of the same degree $r\ge2$. The quotient $B_F$ has a natural closed smooth manifold structure, and \[ q:M\longrightarrow B_F,\qquad C_F=M\times_{B_F}M, \] is an $r$-sheeted smooth covering. In particular every slice has exactly $r$ critical points. We call $r$ the \emph{critical degree}. \end{proposition} \begin{proof} The section $d_2F$ of $\pi_2^*T^*M$ is transverse to zero: its vertical derivative at a zero is the nondegenerate Hessian of $F_x$. The implicit function theorem makes $C_F$ locally a graph $y=\phi(x)$. Thus its first projection is a proper local diffeomorphism, hence a finite covering. The diagonal makes it surjective. Reciprocity of the equivalence relation allows coordinate interchange, proving the same assertion for the second projection; each local branch $\phi$ is a local diffeomorphism. For a class $[x]=\{x_1,\ldots,x_r\}$, shrink a neighborhood $U$ of $x=x_1$ so that all branches are diffeomorphisms $\phi_i:U\to U_i$, with $\phi_1=\operatorname{id}$ and the $U_i$ disjoint. Transitivity gives $[\phi_i(u)]=\{\phi_1(u),\ldots,\phi_r(u)\}$. Therefore $\bigcup_iU_i$ is saturated, and each $q|_{U_i}$ is a homeomorphism onto the same open subset of $B_F$. These are quotient charts, with smooth branch maps as transitions. The quotient is Hausdorff because the equivalence relation is closed on a compact Hausdorff space, and second countable because $q$ is open. Finally, a Morse function on a positive-dimensional closed manifold has a minimum and a distinct maximum, so $r\ge2$. \end{proof} \Needspace{8\baselineskip} \begin{proposition}[Morse--Bott structure and metric] \label{ck:prop:metric} The full function $F$ is Morse--Bott with critical manifold $C_F$. Its normal index at $(x,y)$ equals the index of $y$ for $F_x$. Also \[ g_x(u,v)=\operatorname{Hess}_{y=x}F_x(u,v) \] defines a Riemannian metric, natural under kernel isomorphisms. \end{proposition} \begin{proof} If $d_2F(x,y)=0$, reciprocity and symmetry imply $d_1F(x,y)=0$, so $\operatorname{Crit}(F)=C_F$. On a local branch $y=\phi(x)$, set $A=D\phi_x$ and $H=D^2_{yy}F(x,\phi(x))$. Differentiating the critical equations along the branch gives \[ D^2F=\begin{pmatrix}A^{\mathsf T}HA&-A^{\mathsf T}H\\-HA&H\end{pmatrix}, \qquad D^2F((v,w),(v,w))=H(w-Av,w-Av). \] Its kernel is exactly the tangent space to the graph, and its normal inertia is that of $H$. On the diagonal, $x$ is a nondegenerate minimum of $F_x$, so $g_x$ is positive definite. Smoothness and naturality follow from the intrinsic Hessian at a critical point. \end{proof} \begin{proposition}[Products] \label{ck:prop:products} If $F$ and $K$ are critical kernels on $M$ and $N$, then \[ (F\oplus K)((x,u),(y,v))=F(x,y)+K(u,v) \] is a critical kernel on $M\times N$. Critical relations and quotient coverings are products, degrees multiply, indices add, and the induced metric is the product metric. \end{proposition} \begin{proof} Slice gradients and Hessians split, and criticality is the product of the two equivalence relations. The other axioms follow directly. \end{proof} \subsection{Euler rigidity} \label{ck:sec:euler} \begin{theorem}[Euler rigidity] \label{ck:thm:euler} If $\chi(M)\ne0$, then \[ \chi(M)=r>0,\qquad \chi(B_F)=1. \] Every slice has only even-index critical points and is perfect over $\mathbb Z$. The manifold $M$ is simply connected, of even dimension, and its integral homology and cohomology are free and concentrated in even degrees. The covering $q$ is universal; its deck group $G\cong\pi_1(B_F)$ acts freely and satisfies \begin{equation} |G|=\chi(M)=\dim_{\mathbb Q}H^*(M;\mathbb Q),\qquad H^*(M;\mathbb Q)^G=\mathbb Q. \label{ck:eq:invariants} \end{equation} The quotient $B_F$ is rationally acyclic and nonorientable, and \begin{equation} p_i(TM)=0\in H^{4i}(M;\mathbb Z)\qquad(i>0). \label{ck:eq:pontryagin} \end{equation} \end{theorem} \begin{proof} The covering formula gives $\chi(M)=r\chi(B_F)$. For any slice, the Morse formula gives $\chi(M)=\sum_{j=1}^r(-1)^{\lambda_j}$. The diagonal contributes a minimum, so $-r<\chi(M)\le r$. A nonzero integer multiple of $r$ in this interval is $r$. Hence every $\lambda_j$ is even. The Morse CW decomposition has only even cells. Connectedness forces one zero-cell; there are no one-cells, so $M$ is simply connected. Every cellular boundary map vanishes. This proves integral perfection and freeness, and also orientability and even dimension. The universal covering has $|G|=r$. Transfer injects $H^*(B_F;\mathbb Q)$ into $H^*(M;\mathbb Q)$ and identifies it with the invariants. Thus the quotient has no odd rational cohomology. Its Euler characteristic is $1$, so its only rational cohomology is $H^0=\mathbb Q$. Since it has positive dimension, it is nonorientable. Finally $TM\cong q^*TB_F$; naturality gives rational vanishing of all positive Pontryagin classes of $TM$. Torsion-freeness upgrades this to integral vanishing. \end{proof} \begin{remark} \label{ck:rem:euler} Until the end of Subsection~\ref{ck:sec:recognition}, assume $\chi(M)\ne0$ and put $A=H^*(M;\mathbb Q)$. The critical set decomposes as \[ C_F=\bigsqcup_{g\in G}\Gamma_g,\qquad \Gamma_g=\{(x,gx):x\in M\}. \] Write $c_g$ and $\lambda_g$ for its constant critical value and index. Then \[ c_1=0,\quad\lambda_1=0,\quad c_g>0\ (g\ne1),\quad c_g=c_{g^{-1}},\quad\lambda_g=\lambda_{g^{-1}}. \] The last two equalities follow from coordinate interchange. Integral perfection gives \begin{equation} P_M(t)=\sum_{g\in G}t^{\lambda_g}. \label{ck:eq:poincare} \end{equation} In particular, there is one index-zero branch and one index-$n$ branch. Vanishing Pontryagin classes alone does not imply stable parallelizability or spin. \end{remark} \subsection{Examples} \label{ck:sec:examples} The first two examples also cover $\chi(M)=0$; the restriction in Remark~\ref{ck:rem:euler} is not imposed in this subsection. \begin{example}[Spheres and their products] \label{ck:ex:spheres} On the unit sphere $S^n\subset\mathbb R^{n+1}$, $n\ge1$, set $F(x,y)=1-x\cdot y$. Its critical partners are $x$ and $-x$, with indices $0$ and $n$. The quotient is $S^n\to\mathbb{RP}^n$, of degree $2$. Products give \[ F(x,y)=\sum_{i=1}^k(1-x_i\cdot y_i)\qquad\text{on}\qquad\prod_{i=1}^kS^{n_i}. \] The critical group is $(\mathbb Z/2)^k$ acting by coordinate antipodes, and a branch has index $\sum_{i\in I}n_i$ when exactly the coordinates in $I$ are reversed. If all $n_i=d$ are even, cohomology is generated in degree $d$, and the first positive critical branches generate the entire group. \end{example} \begin{example}[Tori] \label{ck:ex:tori} On $T^m=(\mathbb R/2\pi\mathbb Z)^m$, set \[ F(x,y)=\sum_{i=1}^m\bigl(1-\cos(y_i-x_i)\bigr). \] Critical partners differ by $0$ or $\pi$ in each coordinate. The quotient covering is $x\mapsto2x$, of degree $2^m$, and the number of index-$j$ points is $\binom mj$. Here $\chi(T^m)=0$. \end{example} \begin{example}[Complex full flags] \label{ck:ex:flags} Fix $m\ge2$ and $a_1<\cdots0$ even and $k>0$, then $k=2$. In particular, $\#_k(S^{2m}\times S^{2m})$ admits no critical kernel for $m\ge1$ and $k\ge2$. \item If $G$ has exactly one nonidentity involution, then $G\cong\mathbb Z/2$ and $M$ is a homotopy sphere. Thus cyclic groups of order greater than two and generalized quaternion groups cannot occur in this sector. \end{enumerate} \end{corollary} \begin{proof} For (i), the first positive index is $d$ or $2d$. If it were $2d$, Theorem~\ref{ck:thm:quadratic} would force $P_M=1+t^{2d}$. Hence it is $d$, and $1+t^d$ divides $1+kt^d+t^{2d}$, forcing $k=2$. For the stated connected sum, the middle Betti number is $2k$. For (ii), the unique index-$n$ branch is an involution because inversion preserves index. Every first-level branch is also an involution, so it must be that same branch. Now $\lambda=n$, and~\eqref{ck:eq:quadratic} gives $P_M=1+t^n$ and $|G|=2$. Simple connectivity and integral perfection make $M$ an integral homology sphere, hence a homotopy sphere by Hurewicz and Whitehead. Odd-order groups have no involution at all and are already excluded by Theorem~\ref{ck:thm:quadratic}. \end{proof} \subsection{Reflection groups and the \texorpdfstring{$2,4,8$}{2,4,8} restriction} \label{ck:sec:recognition} \begin{theorem}[Conditional recognition] \label{ck:thm:recognition} Assume, in addition to $\chi(M)\ne0$, that \begin{enumerate}[label=\textup{(\alph*)}] \item $A=H^*(M;\mathbb Q)$ is generated as an algebra by $V=H^d(M;\mathbb Q)$ for some $d>0$; \item $S$, the transformations at the first positive critical level, generates $G$. \end{enumerate} Set $\ell=\dim_{\mathbb Q}V$. Then $d$ is even, $G$ acts faithfully on $V$ as an essential crystallographic reflection group, and \begin{equation} A\cong\operatorname{Sym}_{\mathbb Q}(V)/\langle\operatorname{Sym}_{\mathbb Q}(V)^G_+\rangle,\qquad |V|=d. \label{ck:eq:coinvariants} \end{equation} The manifold is formal. If $m_1,\ldots,m_\ell$ are the ordinary polynomial degrees of basic invariants, then \begin{equation} P_M(t)=\prod_{i=1}^\ell(1+t^d+\cdots+t^{d(m_i-1)}),\qquad \dim M=d\sum_{i=1}^\ell(m_i-1). \label{ck:eq:hilbert} \end{equation} \par\Needspace{6\baselineskip} Furthermore:\nopagebreak \begin{enumerate}[label=\textup{(\roman*)}] \item If $G$ is nonabelian, then $d\in\{2,4,8\}$. \item If $d\notin\{2,4,8\}$, then $G\cong(\mathbb Z/2)^\ell$ and $M\simeq_{\mathbb Q}(S^d)^\ell$. \item If $d=2$, then $M\simeq_{\mathbb Q}K/T$ for a compact connected semisimple Lie group $K$ with Weyl group $G$ and maximal torus $T$. \end{enumerate} \end{theorem} \begin{proof} \emph{Reflections.} If a deck transformation fixes $V$, it fixes the generated algebra $A$. Its Lefschetz number is then $\chi(M)>0$, which contradicts freeness unless the transformation is the identity. Thus the action on $V$ is faithful. By integral perfection there are no positive indices below $d$. If $s\in S$ had $\lambda_s>d$, \eqref{ck:eq:divisibility} would make it fix $V$. Therefore $\lambda_s=d$. In degree $d$, the integral version of~\eqref{ck:eq:divisibility} gives \begin{equation} a-s^*a=e_sD_s(a),\qquad D_s:H^d(M;\mathbb Z)\longrightarrow\mathbb Z. \label{ck:eq:integral} \end{equation} The integer coefficient is unique because $e_s\ne0$ and $H^d(M;\mathbb Z)$ is free, and is additive in $a$. Thus $1-s^*$ has rank one on $V$; finite order makes $s^*$ a reflection. It preserves the integral lattice. The generation hypothesis makes $G$ a finite crystallographic reflection group, hence a Weyl group~\cite{ck:humphreys}. It is essential because $V^G=0$ by~\eqref{ck:eq:invariants}. \emph{The spherical Euler obstruction.} Choose a $G$-invariant positive inner product on $V_{\mathbb R}$. Since $e_s$ spans the negative eigenspace, \[ D_s(e_s)=2,\qquad D_s(v)=\frac{2\langle v,e_s\rangle}{\langle e_s,e_s\rangle}. \] If $G$ is nonabelian, some $s,t\in S$ do not commute. The integers $a=D_s(e_t)$ and $b=D_t(e_s)$ obey \[ ab=\frac{4\langle e_s,e_t\rangle^2}{\langle e_s,e_s\rangle\langle e_t,e_t\rangle}\in\{1,2,3\}. \] Indeed, noncommuting reflection normals are neither parallel nor perpendicular, so $00, \] where $\sigma_{\min}$ is the smallest singular value. Positivity follows because a zero differential has a nonsingular Hessian. The minimum is positive and stays positive under a sufficiently small $C^2$ perturbation of the tuple. \end{proof} \subsection{Critical incidence and the rank bound} \label{um:sec:critical} Define \[ C(V)=\{(a,x)\in S^{r-1}\times M:df_a(x)=0\}, \qquad C_i(V)=\{(a,x)\in C(V):\operatorname{ind}_x(f_a)=i\}. \] Let $\pi(a,x)=a$ and $\operatorname{ev}(a,x)=x$. \Needspace{9\baselineskip} \begin{proposition}[Critical covering] \label{um:prop:covering} The space $C(V)$ is a compact smooth $(r-1)$-manifold, and $\pi$ is a finite covering. Each $C_i(V)$ is a union of covering components. If $r\geq2$, the numbers $m_i$ of index-$i$ critical points are independent of $a$ and satisfy \[ m_i=m_{n-i},\qquad \chi(M)=\sum_{i=0}^{n}(-1)^im_i. \] If $r\geq3$, every covering component is a copy of $S^{r-1}$. \end{proposition} \begin{proof} At a zero of $df_a$, its derivative in the $M$ direction is the invertible Hessian. The implicit function theorem makes $\pi$ a local diffeomorphism. Its domain is closed in a compact product, so $\pi$ is a finite covering. The index is locally constant. For $r\geq2$, connectedness of the sphere makes the counts constant, while $f_{-a}=-f_a$ exchanges indices $i$ and $n-i$. The Euler formula is the Morse equality. Finally $S^{r-1}$ is simply connected when $r\geq3$. \end{proof} In rank two, monodromy can permute critical points: a covering of $S^1$ need not split into globally labeled branches. Whenever a branch $c:S^{r-1}\to M$ is available, its Hessians define negative and positive eigenspace bundles \[ E_c^-\oplus E_c^+\cong c^*TM,\qquad \operatorname{rank}E_c^-=\operatorname{ind}(c). \] More generally these bundles are defined over $C_i(V)$. A metric chooses the eigenspaces, but their bundle isomorphism classes do not depend on that choice. Critical coverings and Hessian bundles are standard constructions in parametrized Morse theory~\cite[\S4.1]{um:igusa}. \begin{lemma}[Minimum embedding] \label{um:lem:minimum} The map $\operatorname{ev}:C_0(V)\to M$ is an embedding. At a minimum $x$ of $f_a$, \begin{equation} \ker(dF_x^*)=\mathbb R a,\qquad \operatorname{rank}dF_x=r-1. \label{um:eq:minimum} \end{equation} \end{lemma} \begin{proof} Put $K_x=\ker(dF_x^*)$ and $H_b=\operatorname{Hess}_x f_b$ for $b\in K_x$. The form $H_a$ is positive definite. If $b\in K_x$ is independent of $a$, the real symmetric matrix $H_a^{-1/2}H_bH_a^{-1/2}$ has a real eigenvalue $\lambda$. Thus $H_b-\lambda H_a$ is singular, making the nonzero function class $[f_{b-\lambda a}]$ non-Morse. This proves~\eqref{um:eq:minimum}. Two minimum directions at the same point must now be proportional, hence equal: opposite directions exchange minima and maxima. Therefore $\operatorname{ev}$ is injective. A tangent vector $(b,v)$ to $C_0(V)$ satisfies \begin{equation} b\perp a,\qquad H_a(v,\cdot)+dF_x^*b=0. \label{um:eq:tangent} \end{equation} If $d\operatorname{ev}(b,v)=v=0$, then $b\in\mathbb Ra\cap a^\perp=0$. Thus $\operatorname{ev}$ is an immersion; compactness makes it an embedding. \end{proof} The lemma applies to all \emph{local} minima. The maximum locus has the same image in $M$, via $(a,x)\mapsto(-a,x)$. Intermediate-index incidence need not embed. \begin{theorem}[Sharp bound and sphere rigidity] \label{um:thm:bound} For every closed connected $n$-manifold, \[ 1\leq\mu_{\mathrm{lin}}(M)\leq n+1, \qquad \mu_{\mathrm{lin}}(M)=n+1\quad\Longleftrightarrow\quad M\cong S^n \] where $\cong$ denotes diffeomorphism. If $n\geq2$ and a system has rank $n+1$, every nonzero member has exactly two critical points, and its representing map is a strictly convex hypersurface embedding in $\mathbb R^{n+1}$. \end{theorem} \begin{proof} A Morse function gives rank one. At a minimum, \eqref{um:eq:minimum} gives $r-1\leq n$. If $r=n+1$, the embedding $C_0(V)\to M$ has equal dimensions. Every component has open and closed image. Since $M$ is connected and the images are disjoint, there is exactly one component, and the embedding is a diffeomorphism onto $M$. This component is a connected finite cover of $S^n$: it is $S^n$ for $n\geq2$, and a circle for $n=1$. Conversely, coordinate heights on $S^n\subset\mathbb R^{n+1}$ give rank $n+1$. For $n\geq2$, the minimum covering has one sheet; so does the maximum covering. Every point of $M$ lies in the minimum image. Equation~\eqref{um:eq:minimum} then implies that any critical height at that point is a multiple of a definite one. There are no saddle points. Also $dF$ has rank $n$ everywhere. If $F(x)=F(y)$, choose a height uniquely minimized at $x$; then $y=x$. Thus $F$ is an embedding. Every point is a unique support point, and every support direction has one such point; hence $F(M)$ is the boundary of its convex hull. Its second fundamental form is definite, giving the asserted strict convexity. \end{proof} \begin{remark} The final assertion requires $n\geq2$. On $S^1$, the rank-two system generated by $\cos(k\theta),\sin(k\theta)$ has $k$ minima and $k$ maxima per nonzero member and may multiply cover a circle. \end{remark} \subsection{Obstructions to linear extension} \label{um:sec:extension} A \emph{linear extension} of $V$ is a uniformly Morse system $W\supset V$ of rank $r+1$. Choose compatible representatives. Then the sphere family \[ \alpha_V:S^{r-1}\longrightarrow\mathcal M(M),\qquad a\longmapsto f_a, \] is the equatorial restriction of $\alpha_W:S^r\to\mathcal M(M)$. These maps are odd: $\alpha(-a)=-\alpha(a)$. \begin{proposition}[Family obstructions] \label{um:prop:family} If a rank-$r$ system extends linearly, $\alpha_V$ extends over $D^r$. If $r\geq2$, its critical covering is trivial, every labeled critical branch $S^{r-1}\to M$ is nullhomotopic, and both its Hessian bundles are trivial. Moreover the joint ordered critical-point map \[ S^{r-1}\longrightarrow\operatorname{Conf}_N(M), \qquad a\longmapsto(c_1(a),\ldots,c_N(a)), \] extends over $D^r$, where $\operatorname{Conf}_N(M)$ is the space of ordered $N$-tuples of distinct points. \end{proposition} \begin{proof} Restrict the extended family to a closed hemisphere. For $r\geq2$, the critical cover over $S^r$ is trivial. Its labeled branches and their Hessian bundles restrict to the given ones. On a hemisphere, each branch extends to a disk, each vector bundle is trivial, and critical points remain distinct. These give all the conclusions. \end{proof} These necessary conditions do not suffice for linear extension, even when a smooth odd nonlinear extension exists, as Theorem~\ref{um:thm:linked} shows. \begin{proposition}[An unlink obstruction on $S^3$] \label{um:prop:unlink} For a rank-two system on $S^3$, the image \[ L_0(V)=\operatorname{ev}(C_0(V))\subset S^3 \] is a smooth link. If $V$ extends to rank three, the minimum covering of $S^1$ has trivial monodromy and $L_0(V)$ is an unlink: its components bound pairwise disjoint embedded disks in $S^3$. \end{proposition} \begin{proof} Lemma~\ref{um:lem:minimum} embeds the finite union of covering circles. In an extension, minimum incidence is a disjoint union of copies of $S^2$. The lemma embeds these as pairwise disjoint spheres in $S^3$. Their equators are the original minimum circles, and images of hemispheres give the required disjoint disks. \end{proof} \subsection{Examples and Hessian bundles} \label{um:sec:examples} \subsubsection{Spheres and tori} On $S^n$, coordinate heights give $\mu_{\mathrm{lin}}(S^n)=n+1$. On the torus $T^n=(\mathbb R/2\pi\mathbb Z)^n$, fix $c_j>0$ and let \[ F(\theta_1,\ldots,\theta_n)=\sum_{j=1}^{n}c_je^{i\theta_j}\in\mathbb C. \] The height $\operatorname{Re}(e^{-i\phi}F)=\sum_jc_j\cos(\theta_j-\phi)$ has $2^n$ critical points, a diagonal nonsingular Hessian, and $m_i=\binom ni$. Thus it defines rank two. In particular $\mu_{\mathrm{lin}}(T^2)=2$, by Theorem~\ref{um:thm:bound}. No value of $\mu_{\mathrm{lin}}(T^n)$ for $n>2$ is asserted here. \subsubsection[A maximal-rank system on CP2]{A maximal-rank system on $\mathbb{CP}^2$} For $a=(a_1,a_2)\in\mathbb C^2\cong\mathbb R^4$, set \begin{equation} A(a)=\begin{pmatrix}0&0&a_1\\0&0&a_2\\\bar a_1&\bar a_2&0\end{pmatrix}, \qquad f_a([z])=\frac{z^*A(a)z}{z^*z}. \label{um:eq:projective} \end{equation} For $a\neq0$, the eigenvalues are $-\|a\|,0,\|a\|$. A projective Rayleigh function with simple eigenvalues has precisely the eigenlines as critical points. In an eigenbasis, its quadratic term near the $j$th eigenline is \[ \sum_{\ell\neq j}(\lambda_\ell-\lambda_j)|w_\ell|^2. \] Hence~\eqref{um:eq:projective} is a rank-four system with indices $0,2,4$. Since $\mathbb{CP}^2$ is not diffeomorphic to $S^4$, Theorem~\ref{um:thm:bound} gives \begin{equation} \mu_{\mathrm{lin}}(\mathbb{CP}^2)=4. \label{um:eq:cp-rank} \end{equation} Its representing map is, up to a constant factor, the first four coordinates of the smooth collapse $\mathbb{CP}^2\to S^4$: \[ [z:w]\longmapsto\frac{(2z\bar w,\ |z|^2-|w|^2)}{|z|^2+|w|^2}, \qquad z\in\mathbb C^2,\ w\in\mathbb C. \] This collapses the hyperplane $w=0$; see~\cite[\S16]{um:derdzinski} for this construction. \subsubsection[Infinitely many Hessian-bundle types on S2 times S2]{Infinitely many Hessian-bundle types on $S^2\times S^2$} Let $h:S^2\to S^2$ be smooth of degree $d$, choose $0<\varepsilon<1$, and define \begin{equation} F_h(x,y)=(1+\varepsilon\langle h(x),y\rangle)x\in\mathbb R^3. \label{um:eq:hessian-map} \end{equation} For a unit vector $u$, the four critical points of $u\cdot F_h$ are \[ x=su,\qquad y=\tau h(su),\qquad s,\tau\in\{1,-1\}. \] Indeed $u\cdot x=0$ cannot be critical, since the $x$-derivative there is a positive multiple of $d(u\cdot x)$. Otherwise the $y$-equation forces $y=\tau h(x)$, after which the $x$-equation forces $x=su$. Use local fiber coordinates centered on $y=\tau h(x)$. In the resulting splitting $T_xS^2\oplus T_{h(x)}S^2$, the Hessian is \begin{equation} -s(1+\varepsilon\tau)g_{S^2}\oplus(-s\varepsilon\tau)g_{S^2}. \label{um:eq:hessian-splitting} \end{equation} Thus~\eqref{um:eq:hessian-map} gives a rank-three system with indices $0,2,2,4$. On the two index-two branches, the negative bundles have absolute Euler numbers \begin{equation} \{2,\ 2|d|\}. \label{um:eq:euler-pair} \end{equation} For $(s,\tau)=(1,-1)$ the negative bundle is $TS^2$ over $u$; for $(-1,-1)$ it is $(h\circ(-\mathrm{id}))^*TS^2$, whose Euler number has absolute value $2|d|$. In any smooth deformation through admissible triples, critical branches continue and their Hessian bundles extend over $S^2\times[0,1]$. Hence the unordered pair~\eqref{um:eq:euler-pair} is invariant. Taking $d=0,1,2,\ldots$ produces infinitely many deformation classes with the same critical-point counts. These maps lie in the round-fold setting of~\cite[Theorem~5.7(3), Remark~5.8]{um:kitazawa-n}, where the associated self-intersection data also appear. \subsection{Joint critical-point configurations} \label{um:sec:configurations} For the unit-parameter $S^3$ family~\eqref{um:eq:projective}, the maximum and minimum branches are \[ c_+(a)=[a_1:a_2:1],\qquad c_-(a)=[-a_1:-a_2:1]. \] The middle branch is $[-\bar a_2:\bar a_1:0]$. Every individual branch is nullhomotopic, since the Hopf fibration $S^1\to S^5\to\mathbb{CP}^2$ gives $\pi_3(\mathbb{CP}^2)=0$. All positive and negative Hessian bundles over $S^3$ are trivial: the middle ones are oriented real two-plane bundles, classified by $H^2(S^3;\mathbb Z)=0$, and the nonzero extreme bundles are pullbacks of $T\mathbb{CP}^2$ along nullhomotopic maps. \begin{proposition} \label{um:prop:configuration} Nevertheless the joint extrema map $(c_+,c_-):S^3\to\operatorname{Conf}_2(\mathbb{CP}^2)$ represents a generator, up to sign, of $\pi_3\operatorname{Conf}_2(\mathbb{CP}^2)\cong\mathbb Z$. The family~\eqref{um:eq:projective} has no disk filling through Morse functions. \end{proposition} \begin{proof} Use the affine chart $[z_1:z_2:1]\leftrightarrow(z_1,z_2)$. The pair $(a,-a)$ is homotopic through distinct pairs to $(0,-a)$ by \[ (a,t)\longmapsto((1-t)a,-a),\qquad 0\leq t\leq1. \] The Fadell--Neuwirth fibration~\cite{um:fadell} is \[ \mathbb{CP}^2\setminus\{p\}\longrightarrow\operatorname{Conf}_2(\mathbb{CP}^2) \xrightarrow{\operatorname{pr}_1}\mathbb{CP}^2, \qquad p=[0:0:1]. \] Its fiber deformation retracts to $\mathbb{CP}^1$ by $[z_1:z_2:w]\mapsto[z_1:z_2:0]$. Since $\pi_4(\mathbb{CP}^2)=\pi_3(\mathbb{CP}^2)=0$, fiber inclusion induces an isomorphism on $\pi_3$. Under the retraction, $a\mapsto(0,-a)$ becomes $a\mapsto[a_1:a_2]$, the Hopf map, which generates $\pi_3(S^2)$. A Morse disk filling would retain exactly one minimum and one maximum and would extend their joint configuration, a contradiction. \end{proof} The preceding obstruction concerns fillings by general Morse families. The next result separates nonlinear extension from linear extension. \subsection{Linear and nonlinear extensions} \label{um:sec:linked} \begin{theorem}[Linked minima] \label{um:thm:linked} There is a rank-two uniformly Morse system $V$ on $S^3$ such that its normalized circle extends to a smooth odd family of Morse functions on a parameter $S^2$ (indeed $S^3$), but $V$ has no linear extension to rank three. Every nonzero member has Morse numbers $(2,3,3,2)$. \end{theorem} \begin{proof} Write $S^3=\{(z_1,z_2)\in\mathbb C^2:|z_1|^2+|z_2|^2=1\}$ and put \begin{equation} F(z_1,z_2)=z_1\left[1+|z_2|^2+\frac1{10}\operatorname{Re}\bigl((z_1\bar z_2)^2\bigr)\right], \qquad f=\operatorname{Re}F,\quad g=\operatorname{Im}F. \label{um:eq:linked-map} \end{equation} On $z_2=0$, $F=z_1$, so $f,g$ are independent modulo constants. The bracket is positive and invariant under simultaneous phase multiplication. Hence \begin{equation} F(e^{i\theta}z_1,e^{i\theta}z_2)=e^{i\theta}F(z_1,z_2), \qquad f_\theta:=\cos\theta f+\sin\theta g=f\circ R_{-\theta}, \label{um:eq:equivariance} \end{equation} where $R_\theta(z_1,z_2)=(e^{i\theta}z_1,e^{i\theta}z_2)$. \emph{Step 1: the Morse calculation.} Away from the coordinate circles use $t=|z_1|^2$, $\psi=\arg(z_1\bar z_2)$, and $\phi=\arg z_1$. With $\varepsilon=1/10$, \[ f=\rho(t,\psi)\cos\phi,\qquad \rho=\sqrt t\,[2-t+\varepsilon t(1-t)\cos2\psi]>0. \] Interior critical points have $\phi=0,\pi$ and $d\rho=0$. The angular equation gives $s=\cos2\psi\in\{1,-1\}$; the radial equation is \[ P_s(t)=2-3t+\varepsilon s(3t-5t^2)=0. \] For both signs, $P_s$ is strictly decreasing on $[0,1]$, positive at zero and negative at one. Let $t_s$ denote its unique root. There, \[ \rho_{tt}=\frac{P_s'(t_s)}{2\sqrt{t_s}}<0, \qquad\rho_{\psi\psi}=-4\varepsilon s t_s^{3/2}(1-t_s), \qquad\rho_{t\psi}=0. \] Thus the base amplitude has two nondegenerate maxima ($\psi=0,\pi$) and two saddles ($\psi=\pi/2,3\pi/2$). Near $z_2=0$, with $\zeta=z_2/z_1=x+iy$, \[ \rho=1+(1/2+\varepsilon)x^2+(1/2-\varepsilon)y^2+O(|\zeta|^4), \] giving one base minimum. At $z_1=0$, $dF=2\,dz_1$, so no height is critical there. At $\phi=0,\pi$, respectively, the Hessians are \[ \operatorname{Hess}\rho\oplus(-\rho),\qquad -\operatorname{Hess}\rho\oplus\rho. \] All are nonsingular. The base maxima give indices $3,0$, the saddles $2,1$, and the minimum $1,2$, yielding $(2,3,3,2)$. Equation~\eqref{um:eq:equivariance} proves uniform Morseness. \emph{Step 2: an odd nonlinear extension.} Identify $S^3$ with unit quaternions $q=z_1+z_2j$. The function $f$ is odd. For $a=(a_1,a_2,a_3)\in S^2$, define \begin{equation} u(a)=a_1+ia_2+ja_3,\qquad\Phi_a(q)=f\bigl(u(a)^{-1}q\bigr). \label{um:eq:quaternion} \end{equation} Every $\Phi_a$ is an isometric pullback of $f$, so is Morse, and $\Phi_{-a}=-\Phi_a$. On the equator $a=(\cos\theta,\sin\theta,0)$, it is $f_\theta$. The same formula works for every $u\in\mathrm{Sp}(1)=S^3$. In particular, a hemisphere gives a disk filling through Morse functions. \emph{Step 3: the linear obstruction.} The two local minima of $f_\theta$ trace the circles \[ L_\pm=\left\{e^{i\theta}\bigl(\sqrt{t_+},\ \pm\sqrt{1-t_+}\bigr):\theta\in\mathbb R/2\pi\mathbb Z\right\}. \] These are two distinct Hopf fibers, so $|\operatorname{lk}(L_+,L_-)|=1$. Directly, their spanning complex lines are independent; an invertible complex-linear transformation followed by radial normalization sends the pair to the two coordinate circles, the standard Hopf link. Proposition~\ref{um:prop:unlink} would force a zero linking number if a rank-three linear extension existed. This contradiction proves the theorem. \end{proof} \begin{corollary}[Maximality and affine unavoidability] \label{um:cor:maximal} The system in Theorem~\ref{um:thm:linked} is maximal by inclusion although $\mu_{\mathrm{lin}}(S^3)=4$. For every $h\in C^\infty(S^3)$ there are $a,b\in\mathbb R$ such that $h+af+bg$ is not Morse. \end{corollary} \begin{proof} Any larger containing system would contain a rank-three extension. If $[h]\in V$, some $h+af+bg$ is constant. Otherwise failure of uniform Morseness for $\operatorname{span}\{[f],[g],[h]\}$ supplies a non-Morse nonzero combination. Its $h$-coefficient cannot vanish, so divide by it. \end{proof} \begin{corollary}[Deformation obstruction and an infinite family] \label{um:cor:deformation} The system of Theorem~\ref{um:thm:linked} cannot be deformed through admissible ordered pairs to a linearly extendible system. Moreover, for every $k\geq2$ there is such a nonextendible system with Morse numbers $(k,k+1,k+1,k)$, still admitting an odd nonlinear extension. \end{corollary} \begin{proof} In a smooth deformation of admissible pairs, the minimum covering extends over $S^1\times[0,1]$. Its initially trivial monodromy stays trivial. Lemma~\ref{um:lem:minimum} gives a smooth isotopy of the minimum link, preserving its linking numbers. For the infinite family replace the square in~\eqref{um:eq:linked-map} by the $k$th power, with a sufficiently small positive coefficient $\varepsilon_k$. The unperturbed amplitude $\rho_0(t)=\sqrt t(2-t)$ has a nondegenerate radial maximum at $t=2/3$ and is independent of $\psi$. The perturbation is \[ \varepsilon_k t^{(k+1)/2}(1-t)^{k/2}\cos(k\psi). \] Its angular critical equation is $\sin(k\psi)=0$. The radial equation has one root near $2/3$ for each angular solution, with negative radial second derivative; for small $\varepsilon_k$ it has no other interior roots. The angular second derivative alternates sign, producing $k$ maxima and $k$ saddles. The north minimum persists, and the south fiber remains regular. Hence the stated Morse counts hold. The $k$ minimum circles are distinct Hopf fibers, so every pair links nontrivially. The same quaternionic formula gives an odd nonlinear extension, while Proposition~\ref{um:prop:unlink} prohibits a linear one. \end{proof} A general Morse-family filling gives critical-point maps of disks into $M$; their images may intersect at different parameter values. A linear extension forces the \emph{entire} minimum incidence to embed in $M$. The linked-minima example detects precisely this stronger geometric requirement, even though the original loop is nullhomotopic in $\mathcal M(S^3)$. \subsection{Related work} \label{um:sec:related} The basic language belongs to parametrized Morse theory: critical coverings and Hessian bundles are explicit in Igusa's framing principle~\cite{um:igusa}. Product maps of two functions and their discriminants are studied by Takao~\cite{um:takao}. The sphere-bundle examples and the circular singular-value geometry are closely related to round fold maps~\cite{um:kitazawa-3,um:kitazawa-n}; the degree data in Subsection~\ref{um:sec:examples} already have precedents in that classification. The projective collapse used above is described in~\cite[\S16]{um:derdzinski}, and Proposition~\ref{um:prop:configuration} uses the classical configuration-space fibration~\cite{um:fadell}. Linking also has established roles in Morse theory, including Usher's results for a single Morse function~\cite{um:usher}. These results do not provide a general classification or existence theory for uniformly Morse linear systems. \section{Presymplectic dependency algebras} \label{pd:chapter} We study positive families of closed rank-two forms through their finite wedge algebras and geometric deletion and contraction. \subsection{Definitions} Throughout this section, manifolds are nonempty, smooth, connected and without boundary. A \emph{closed manifold} is compact without boundary. Kernels of two-forms are taken as kernels of the maps $v\mapsto\iota_v\omega$; products of forms mean wedge products. \begin{definition}[Positive rank-two system]\label{pd:definition} Let $E$ be a finite label set. A positive rank-two system on $M$ is a tuple $\boldsymbol\omega=(\omega_e)_{e\in E}$ of closed two-forms such that: \begin{enumerate}[label=\textup{(\roman*)}] \item each $\omega_e$ has constant rank zero or two; \item $K_S:=\bigcap_{e\in S}\ker\omega_e$ has constant rank for every $S\subseteq E$, with $K_\varnothing=TM$; \item positive sums introduce no additional kernel directions: \begin{equation}\label{pd:nc} \ker\left(\sum_{e\in S}t_e\omega_e\right)=K_S\qquad(t_e>0). \end{equation} \end{enumerate} \end{definition} The system is \emph{effective} if $K_E=0$. Its \emph{dependency algebra} is the unital graded real algebra \begin{equation}\label{pd:algebra} A_\omega:=\mathbb R[\omega_e:e\in E]\subseteq\Omega^{\mathrm{even}}(M),\qquad\deg\omega_e=2. \end{equation} The coefficients in $A_\omega$ are constant real numbers, not arbitrary smooth functions. The full structured object retains the labelled generators and their realization as forms. An isomorphism of labelled systems is a diffeomorphism pulling back each labelled form to its counterpart. Each rank-two form is pointwise decomposable, so $\omega_e^2=0$. Hence $A_\omega$ is finite-dimensional, spanned by the squarefree monomials \[ \omega_S:=\bigwedge_{e\in S}\omega_e,\qquad\omega_\varnothing=1,\qquad\dim_{\mathbb R}A_\omega\leq2^{|E|}. \] If the system is effective, $\sum_e\omega_e$ is symplectic; in particular $\dim M$ is even. Zero generators are retained because restriction can create them. \subsection{Matroid structure and foliations} \begin{proposition}[Matroid rank]\label{pd:matroid} The function \[r(S)=\tfrac12\operatorname{codim}K_S\] is the rank function of an ordinary matroid on $E$. Furthermore, \begin{equation}\label{pd:independent} r(S)=|S|\quad\Longleftrightarrow\quad\omega_S(p)\neq0\text{ for every }p\in M. \end{equation} \end{proposition} \begin{proof} At $p$, put $U_e=(\ker\omega_e(p))^\circ\subseteq T_p^*M$ and $U_S=\sum_{e\in S}U_e$. Then $U_S=K_S(p)^\circ$. By \eqref{pd:nc}, $\dim U_S$ is the rank of a skew form and is even. Thus $r(S)$ is an integer, independent of $p$. Normalization and monotonicity are immediate; adding one $U_e$ increases dimension by at most two. Also \[ \dim U_A+\dim U_B=\dim U_{A\cup B}+\dim(U_A\cap U_B)\geq\dim U_{A\cup B}+\dim U_{A\cap B}. \] After division by two these are the matroid rank axioms. Finally, a squarefree wedge is nonzero exactly when its two-dimensional support planes sum directly, equivalently when $r(S)=|S|$. \end{proof} A subset satisfying \eqref{pd:independent} is \emph{independent}; a \emph{basis} of $S$ is an independent subset of $S$ of size $r(S)$. Pointwise, the $U_e$ form a multilinear representation of the matroid; this linear-algebraic notion is established in the literature~\cite{pd:kuehne}. \begin{lemma}[Coherent orientation of bases]\label{pd:orientation} For any $U\subseteq E$, orient $T_pM/K_U(p)$ by the symplectic form $\Omega_U=\sum_{e\in U}\omega_e$. For every basis $B$ of $U$, $\omega_B$ is positive in this orientation. \end{lemma} \begin{proof} The path $\Omega_B+s\sum_{e\in U\setminus B}\omega_e$, $0\leq s\leq1$, is nondegenerate on $T_pM/K_U(p)$ by \eqref{pd:nc}, since $K_B=K_U$. Its orientation is constant, and $\Omega_B^{r(U)}=r(U)!\omega_B$. \end{proof} \begin{proposition}[Foliations and basis coordinates]\label{pd:foliations} Every $K_S$ is integrable. If the system is effective on a $2n$-manifold and $B=\{b_1,\ldots,b_n\}$ is a basis, then locally there are coordinates $(p_1,q_1,\ldots,p_n,q_n)$ such that \[\omega_{b_i}=dp_i\wedge dq_i\qquad(1\leq i\leq n).\] \end{proposition} \begin{proof} The closed form $\Omega_S$ has constant-rank kernel $K_S$. For $X,Y\in\Gamma(K_S)$, Cartan's formula gives $\mathcal L_X\Omega_S=0$ and then $\iota_{[X,Y]}\Omega_S=0$. Frobenius applies. Each nonzero $\omega_{b_i}$ descends locally to an area form on a surface transverse to its kernel: it annihilates the kernel and is invariant along it. Choose area coordinates $p_i,q_i$ on that surface. By independence, the resulting $2n$ differentials form a coframe, so the combined functions are coordinates. \end{proof} \subsection{Deletion and contraction} Deleting labels preserves Definition~\ref{pd:definition}; algebraically it takes the subalgebra generated by the retained forms. Contraction uses characteristic leaves, rather than an arbitrary submanifold. \begin{theorem}[Hereditary compatibility and geometric contraction]\label{pd:contraction} For $S,T\subseteq E$ and $t_e>0$, \begin{equation}\label{pd:hereditary} \ker\left(\left.\sum_{e\in T}t_e\omega_e\right|_{K_S}\right)=K_{S\cup T}. \end{equation} Consequently, on every connected leaf $L$ of $K_S$, the forms $\omega_e|_L$, $e\in E\setminus S$, form a positive rank-two system with rank function \begin{equation}\label{pd:rank-contraction} r/S(T)=r(S\cup T)-r(S),\qquad T\subseteq E\setminus S. \end{equation} This is matroid contraction. \end{theorem} \begin{proof} Put $U=S\cup T$, $s=r(S)$ and $q=r(U)-s$, and choose a basis $B$ of $S$. Write $\beta=\omega_B$ and $\eta=\sum_{e\in T}t_e\omega_e$. All these forms descend to $TM/K_U$. If $q>0$, expand $\beta\wedge\eta^q$. Its nonzero terms are positive multiples of basis wedges for $U$, by Lemma~\ref{pd:orientation}. At least one term is nonzero because $B$ extends to a basis of $U$ using labels in $T$. Hence $\beta\wedge\eta^q\neq0$. Since $\beta$ is a nonzero top form on the annihilator of $K_S$, this implies $(\eta|_{K_S})^q\neq0$. Meanwhile $K_U$ is contained in the kernel of $\eta|_{K_S}$ and has codimension $2q$ there. Equality follows. For $q=0$, $K_U=K_S$ and the restriction is zero. Taking $T$ to be a singleton proves that each restricted generator has constant rank zero or two and kernel $K_{S\cup\{e\}}$. The general case proves positive compatibility and the common-kernel rank formula. Closedness is preserved by restriction to a leaf. \end{proof} \begin{theorem}[Algebraic contraction]\label{pd:algebraic-contraction} Choose a basis $B_S$ of $S$ and set $\beta_S=\omega_{B_S}$. The image of $A_\omega$ under restriction to the distribution $K_S$ is canonically isomorphic to \begin{equation}\label{pd:quotient} A_{\omega/S}:=A_\omega/\operatorname{Ann}_{A_\omega}(\beta_S),\qquad \operatorname{Ann}_{A_\omega}(\beta_S)=\{a\in A_\omega:\beta_S\wedge a=0\}. \end{equation} The ideal in \eqref{pd:quotient} is independent of the chosen basis $B_S$. \end{theorem} \begin{proof} Pointwise, for any exterior form $\alpha$, \[\beta_S\wedge\alpha=0\quad\Longleftrightarrow\quad\alpha|_{K_S}=0.\] Indeed, choose a cotangent splitting with $K_S^\circ$ as one summand. Wedging by its top form kills exactly the components containing a factor in $K_S^\circ$; the remaining component is the restriction to $K_S$. Thus the kernel of the algebra homomorphism \[A_\omega\longrightarrow\Gamma(\Lambda^{\mathrm{even}}K_S^*)\] is $\operatorname{Ann}_{A_\omega}(\beta_S)$. Different basis wedges are sections of the same line bundle and differ by a nowhere-zero smooth function, so they have the same annihilator. \end{proof} \begin{remark} The quotient describes the \emph{image along the whole foliation}, not the full algebra of leafwise forms. Restriction to a single leaf can have additional kernel. The rank formula \eqref{pd:rank-contraction}, however, holds on every leaf. Multiplication by $\beta_S$ identifies the quotient with $\beta_S A_\omega$ only as a shifted vector space, not as an algebra. \end{remark} Products supply a second elementary construction. On $M\times N$, combine pullbacks of two systems. Their kernels split, so \eqref{pd:nc} holds, ranks add, and the matroid is the direct sum. Their algebras satisfy \[A_{M\times N}\cong A_M\otimes_{\mathbb R}A_N.\] The external-product map is injective: evaluations of forms on tangent multivectors separate any finite-dimensional space of forms, so applying such evaluations on one factor detects every coefficient on the other. \subsection{Cohomology and volume} Throughout this subsection assume that $M$ is closed and the system is effective, with $\dim M=2n$. Orient $M$ by $\sum_e\omega_e$. \begin{theorem}[Nonvanishing of independent monomials]\label{pd:nonvanishing} For every $S\subseteq E$, \begin{equation}\label{pd:cohomology} \prod_{e\in S}[\omega_e]\neq0\quad\Longleftrightarrow\quad S\text{ is independent}. \end{equation} The classes are in real de Rham cohomology. \end{theorem} \begin{proof} For dependent $S$, $\omega_S=0$ by Proposition~\ref{pd:matroid}. For independent $S$, extend it to a basis $B$ of $E$. Lemma~\ref{pd:orientation} gives $\int_M\omega_B>0$. If $\omega_S=d\alpha$, the remaining generators are closed, so $\omega_B=d(\alpha\wedge\omega_{B\setminus S})$, contradicting Stokes' theorem. \end{proof} \begin{corollary}[Obstructions]\label{pd:obstructions} The following assertions hold. \begin{enumerate}[label=\textup{(\roman*)}] \item $b_{2k}(M)\geq\binom nk$ for $0\leq k\leq n$. In particular $b_2(M)\geq n$, and each nonzero generator determines a nonzero square-zero class in $H^2(M;\mathbb R)$. \item If $n>1$, $\mathbb{CP}^n$ admits no effective system. \item A system of three pairwise independent generators on a closed four-manifold requires $b_2(M)\geq3$. In particular, $S^2\times S^2$ admits no such triple. \end{enumerate} \end{corollary} \begin{proof} For (i), fix a basis $B$. In a relation among $[\omega_S]$ with $S\subseteq B$ and $|S|=k$, wedge with $\omega_{B\setminus S_0}$. Every term except that indexed by $S_0$ contains a squared generator and vanishes. The positive top integral forces the remaining coefficient to be zero. For (ii), every nonzero class in $H^2(\mathbb{CP}^n;\mathbb R)$ has nonzero square. For (iii), the intersection matrix of the three classes is \[\begin{pmatrix}0&a&b\\a&0&c\\b&c&0\end{pmatrix},\qquad a,b,c>0,\] whose determinant is $2abc>0$. Their classes are linearly independent. \end{proof} The associated volume polynomial is \begin{equation}\label{pd:volume} P_\omega(t)=\frac1{n!}\int_M\left(\sum_e t_e\omega_e\right)^n =\sum_{B\text{ a basis}}c_B\prod_{e\in B}t_e,\qquad c_B=\int_M\omega_B>0. \end{equation} Thus it is multiaffine, with support exactly the matroid bases. Theorem~\ref{pd:nonvanishing} is a statement about monomials; the algebra map $A_\omega\to H^{\mathrm{even}}(M;\mathbb R)$ need not be injective on their linear combinations. \subsection{Examples and separation} \subsubsection{Product and linear models} \begin{example}[Products of surfaces]\label{pd:surfaces} Let $M=\Sigma_1\times\cdots\times\Sigma_n$, with oriented surfaces carrying area forms $\sigma_i$. The forms $\omega_i=\pi_i^*\sigma_i$ give an effective system with every subset independent and \[A_\omega\cong\mathbb R[x_1,\ldots,x_n]/(x_1^2,\ldots,x_n^2),\qquad\deg x_i=2.\] The squarefree products are linearly independent by their distinct degrees in the individual factors. \end{example} \begin{example}[Compact realizations of complex-representable matroids]\label{pd:complex} Let $(c_e)_{e\in E}$ be a rank-$n$ vector configuration in $\mathbb C^n$. On $\mathbb T^{2n}$ define constant complex one-forms and real two-forms by \[\alpha_e=\sum_{j=1}^n c_{ej}(dx_j+i\,dy_j),\qquad\omega_e=\frac i2\alpha_e\wedge\overline{\alpha_e}.\] The system is effective and its matroid is that of the vectors $c_e$. Indeed, for the standard complex structure $J$, \[\left(\sum_e t_e\omega_e\right)(v,Jv)=\sum_e t_e|\alpha_e(v)|^2,\] so \eqref{pd:nc} holds; common complex kernels have the required real codimensions. Thus every complex-representable matroid has a compact model. No rationality assumption on the coefficients is required. \end{example} \subsubsection{A four-generator torus family} On $\mathbb T^4=(\mathbb R/\mathbb Z)^4$, use coordinates $x,y,u,v$ and their globally defined angular one-forms. Set \[V=dx\wedge dy\wedge du\wedge dv,\qquad a_\varepsilon(u)=2+\varepsilon\sin(2\pi u),\qquad0\leq\varepsilon<1,\] and define \begin{equation}\label{pd:family} \begin{aligned} \omega_1&=dx\wedge dy,&\omega_2&=du\wedge dv,\\ \omega_3&=(dx+du)\wedge(dy+dv),&\omega_4&=(dx+a_\varepsilon du)\wedge(dy+4\,dv). \end{aligned} \end{equation} All four forms are closed and of rank two. Writing $a=a_\varepsilon$, their products are \[ \begin{array}{c|cccccc} (i,j)&(1,2)&(1,3)&(1,4)&(2,3)&(2,4)&(3,4)\\\hline (\omega_i\wedge\omega_j)/V&1&1&4a&1&1&3(a-1) \end{array} \] Every coefficient is positive. Hence every positive sum involving at least two labels is symplectic, while a singleton has rank two. The system is effective and has matroid $U_{2,4}$: precisely the subsets of size at most two are independent. \begin{theorem}[Same cohomology data, different finite algebras]\label{pd:separation} For the family \eqref{pd:family}, all labelled de Rham classes, the matroid, and the volume polynomial are independent of $\varepsilon$. Nevertheless, the algebra dimensions in form degrees $0,2,4$ are \[ \begin{array}{c|ccc} &\dim A^0&\dim A^2&\dim A^4\\\hline \varepsilon=0&1&4&1\\ 0<\varepsilon<1&1&4&2 \end{array}. \] Consequently the constant system is not isomorphic to any nonconstant member, even after relabelling. \end{theorem} \begin{proof} Only $\omega_4$ changes. For $F(u)=-\varepsilon\cos(2\pi u)/(2\pi)$, \[\omega_4^\varepsilon-\omega_4^0=(a_\varepsilon-2)du\wedge(dy+4\,dv)=d\bigl(F(u)(dy+4\,dv)\bigr).\] Thus the labelled classes agree, and \eqref{pd:volume} gives the same volume polynomial. The four degree-two generators are linearly independent: the coefficients of $dx\wedge dv$ and $du\wedge dy$ in a relation give $c_3+4c_4=0$ and $c_3+ac_4=0$. Since $a\neq4$, $c_3=c_4=0$, followed by $c_1=c_2=0$. The product table gives \[A^4=\operatorname{span}_{\mathbb R}\{V,aV\},\] which has dimension one exactly when $a$ is constant. There are no higher nonzero degrees. Any isomorphism of systems induces an isomorphism of these algebras. \end{proof} \begin{proposition}[Local moduli and absence of a common complex structure]\label{pd:local-moduli} For \eqref{pd:family}: \begin{enumerate}[label=\textup{(\roman*)}] \item where $da\neq0$, no coordinates make all four forms constant simultaneously; \item no almost complex structure preserves all four kernels. In particular the forms cannot all be of type $(1,1)$ for a common almost complex structure. \end{enumerate} \end{proposition} \begin{proof} For (i), the intrinsic ratio of top forms is \[\frac{\omega_1\wedge\omega_4}{\omega_1\wedge\omega_2}=4a(u).\] It would be constant in any simultaneous constant-coefficient model. For (ii), write $P=\ker\omega_2=\operatorname{span}_{\mathbb R}\{\partial_x,\partial_y\}$ and $Q=\ker\omega_1=\operatorname{span}_{\mathbb R}\{\partial_u,\partial_v\}$. The remaining kernels are graphs $Q\to P$ of $-I$ and $-D$, where $D=\operatorname{diag}(a,4)$. A complex structure preserving $P,Q$ is block diagonal. Preservation of the graph of $-I$ identifies its two blocks; preservation of the graph of $-D$ forces the common block to commute with $D$. Since $a\neq4$, that block is real diagonal, so it cannot square to $-I$. A $(1,1)$-form has a complex-invariant kernel. \end{proof} \begin{remark}[Scope of the separation] Theorem~\ref{pd:separation} distinguishes chosen structures on the same manifold; it does not yet distinguish underlying manifolds with the same homotopy type. The abstract algebra also does not classify all local moduli: for nonconstant $a$ the displayed multiplication table, expressed using $V,aV$, does not record the full function $a$. \end{remark} \subsection{Related work}\label{pd:related} The pointwise support planes form $2$-arrangements, hence multilinear matroid representations~\cite{pd:kuehne}. Complementary two-form examples in dimension four are symplectic pairs~\cite{pd:bande}. An effective tuple, viewed as an $\mathbb R^E$-valued two-form, is polysymplectic~\cite{pd:blacker}; its kernel foliations also connect it to symplectic webs~\cite{pd:boyom}. The finite wedge algebra is retained before passage to cohomology; positive compatibility supplies hereditary restriction and annihilator contraction along characteristic foliations. The raw algebra is an invariant of the structured manifold and may jump under small deformations, as Theorem~\ref{pd:separation} shows. \section{Diffusion transport defects} \label{dt:chapter} We study the rank defects of connection heat kernels and coverings by the open sets on which these kernels trivialize a bundle. \subsection{Heat kernels and defects} Throughout this section, $(M^n,g)$ is a smooth, closed, connected Riemannian manifold, and $E\to M$ is a smooth bundle of rank $r\geq1$ over $\mathbb F=\mathbb R$ or $\mathbb C$, equipped with a Euclidean or Hermitian metric and a compatible connection $\nabla$. The connection Laplacian is \[L=\nabla^*\nabla\geq0.\] Its heat kernel, normalized against Riemannian volume, is \[ H_t(x,p)\in\operatorname{Hom}(E_p,E_x),\qquad (e^{-tL}s)(x)=\int_M H_t(x,p)s(p)\,d\operatorname{vol}_g(p),\qquad t>0. \] Thus a source vector $v\in E_p$ produces the smooth section $x\mapsto H_t(x,p)v$. \begin{definition}[Defect correspondence]\label{dt:defect} For $1\leq k\leq r$, define \[\mathcal D^{(k)}=\{(t,x,p)\in(0,\infty)\times M\times M:\dim_{\mathbb F}\ker H_t(x,p)\geq k\}.\] Write $\mathcal D_t^{(k)}=\{(x,p):(t,x,p)\in \mathcal D^{(k)}\}$ and $D_t(p)=\{x:(x,p)\in \mathcal D_t^{(1)}\}$. The associated lost-direction incidence is \[\mathcal I=\{(t,x,p,[v]):[v]\in\mathbb P(E_p),\ H_t(x,p)v=0\}.\] Here $\mathbb P$ denotes real or complex projectivization as appropriate. \end{definition} \begin{definition}[Heat covering number]\label{dt:cover-definition} Set \[U_t(p)=M\setminus D_t(p)=\{x:H_t(x,p)\text{ is invertible}\},\] and define \begin{equation}\label{dt:cover-number} \mathfrak h_t(M,g,E,\nabla)=\min\left\{q\geq1:\exists p_1,\ldots,p_q\in M,\quad M=\bigcup_{j=1}^q U_t(p_j)\right\}. \end{equation} When the data are fixed, write simply $\mathfrak h_t$. \end{definition} Finiteness is proved below. The sets $U_t(p)$ are domains of bundle trivializations, not necessarily coordinate neighborhoods. The loci $\mathcal D^{(k)}$ are closed in positive time; no smoothness or Whitney stratification is assumed. On any smooth submanifold on which the rank is constant, the kernels form a smooth vector bundle, and $\mathcal I$ restricts to its projectivization. \subsection{Basic properties} \begin{proposition}[Symmetry, positivity, and invariance]\label{dt:positivity} For every $t>0$, \[H_t(x,p)^*=H_t(p,x),\qquad H_t(p,p)>0.\] Consequently, $\mathcal D_t^{(k)}$ is invariant under $(x,p)\mapsto(p,x)$ and is disjoint from the diagonal. These loci and $\mathfrak h_t$ are invariant under metric-preserving bundle isomorphisms intertwining the connections and covering isometries of the base. \end{proposition} \begin{proof} Let $(\phi_j)$ be an orthonormal eigenbasis of $L$, with eigenvalues $\lambda_j\geq0$. The smooth spectral expansion is \[H_t(x,p)=\sum_j e^{-t\lambda_j}\phi_j(x)\phi_j(p)^*.\] It gives symmetry and \[\langle H_t(p,p)v,v\rangle=\sum_j e^{-t\lambda_j}|\langle\phi_j(p),v\rangle|^2.\] If this vanishes, $v$ is orthogonal to every $\phi_j(p)$ and hence to every smooth section evaluated at $p$, since smooth spectral expansions converge in $C^\infty$. Thus $v=0$. Covariance of $L$ gives covariance of its heat kernel, so ranks and covering numbers are preserved. \end{proof} \begin{proposition}[Trivialization and topological obstruction]\label{dt:trivialization} For all $t>0$, $1\leq\mathfrak h_t<\infty$. Each $U_t(p)$ trivializes $E$. In particular, if $E$ is nontrivial, then $D_t(p)\neq\varnothing$ for every $p$ and $t$. More generally, let $\gamma_1(E),\ldots,\gamma_q(E)$ be positive-degree characteristic classes, with coefficients in a fixed commutative ring, each vanishing on a trivial bundle. If \[\gamma_1(E)\smile\cdots\smile\gamma_q(E)\neq0,\qquad\text{then}\qquad\mathfrak h_t\geq q+1.\] \end{proposition} \begin{proof} The map $(x,v)\mapsto H_t(x,p)v$ identifies $U_t(p)\times E_p$ with $E|_{U_t(p)}$. By Proposition~\ref{dt:positivity}, $p\in U_t(p)$; these open sets cover $M$, and compactness gives a finite subcover. A cover by one such set would trivialize $E$ globally. If $q$ heat domains covered $M$, each $\gamma_i(E)$ would restrict to zero on the $i$th domain and would lift to relative cohomology for that domain. Their relative cup product lies in $H^*(M,M)=0$, contradicting the displayed nonzero product. A cover by fewer domains can be padded by repetitions. This is the usual cup-product obstruction to trivializing covers; see~\cite{ref:hatcher-vb}. \end{proof} \begin{proposition}[Stability and rescaling]\label{dt:stability} The integer-valued function $t\mapsto\mathfrak h_t$ is upper semicontinuous on $(0,\infty)$. The same assertion holds along smooth families of metrics and compatible connections on a fixed bundle. For a constant $s>0$, \begin{equation}\label{dt:rescaling} H_t^{\nabla,sg}(x,p)=s^{-n/2}H_{t/s}^{\nabla,g}(x,p),\qquad \mathfrak h_t(M,sg,E,\nabla)=\mathfrak h_{t/s}(M,g,E,\nabla). \end{equation} \end{proposition} \begin{proof} Choose a covering tuple $p_1,\ldots,p_q$ at $t_0$. Compactness gives \[\min_{x\in M}\max_{1\leq i\leq q}\sigma_{\min}(H_{t_0}(x,p_i))>0.\] Continuity of the heat kernel preserves this inequality nearby, so $\mathfrak h_t\leq\mathfrak h_{t_0}$. Smooth parameter dependence of heat kernels gives the family statement by the same argument. Finally, $L_{sg}=s^{-1}L_g$ and $d\operatorname{vol}_{sg}=s^{n/2}d\operatorname{vol}_g$, which prove \eqref{dt:rescaling}. \end{proof} \begin{theorem}[Small-time localization]\label{dt:localization} Fix $p\in M$. For every open neighborhood $V$ of $\operatorname{Cut}(p)$, there is $\varepsilon>0$ such that \[D_t(p)\subset V\qquad(00$ and $P_{x\leftarrow p}$ is parallel transport along the unique minimizing geodesic. The leading map is uniformly invertible on $K$. Thus $H_t(x,p)$ is invertible there for sufficiently small $t$. Apply this to $K=M\setminus V$. \end{proof} This is a one-sided localization statement: it does not assert that every cut point is a limit of defects. \subsection{Examples} \begin{example}[A global parallel frame]\label{dt:parallel-frame} If $E$ admits a global parallel orthonormal frame, then \[H_t(x,p)=h_t(x,p)I_r\] in that frame, where $h_t>0$ is the scalar heat kernel. Hence $\mathcal D^{(1)}=\varnothing$ and $\mathfrak h_t=1$ for all $t>0$. \end{example} \begin{proposition}[Rectangular tori with sign holonomy]\label{dt:sign-holonomy} On $\mathbb T^m=(\mathbb R/2\pi\mathbb Z)^m$ with the product flat metric, consider the trivial complex line bundle with \[\nabla=d+\frac i2\sum_{j=1}^k d\theta_j,\qquad0\leq k\leq m.\] Then, for every $t>0$, \begin{equation}\label{dt:sign-domains} U_t(p)=\prod_{j=1}^k\bigl(S^1\setminus\{p_j+\pi\}\bigr)\times(S^1)^{m-k},\qquad\mathfrak h_t=k+1. \end{equation} \end{proposition} \begin{proof} For one twisted circle, a kernel representative on the universal cover, up to a nowhere-zero phase, is \[k_t^-(u)=\frac1{\sqrt{4\pi t}}\sum_{\ell\in\mathbb Z}(-1)^\ell e^{-(u+2\pi\ell)^2/(4t)}.\] On $(-\pi,\pi)$ this is the Dirichlet heat kernel of that interval with source $0$, by the method of images. It is strictly positive in the interior and vanishes at the endpoints. Its only zero modulo $2\pi$ is therefore the antipode. The product heat kernel gives the first formula in \eqref{dt:sign-domains}. Given $q\leq k$ sources $p^{(1)},\ldots,p^{(q)}$, choose a target with $\theta_j=p_j^{(j)}+\pi$ for $1\leq j\leq q$. It lies in none of their heat domains. Conversely, choose $k+1$ sources whose first $k$ coordinates are $(a_\ell,\ldots,a_\ell)$, with all $a_\ell$ distinct. Each coordinate excludes at most one source, so the $k$ coordinates cannot exclude all $k+1$. If $k=0$, the kernel is everywhere nonzero. \end{proof} Thus even a topologically trivial line bundle with zero curvature can have $\mathfrak h_t>1$. Holonomy affects the invariant. \begin{example}[Antipodal defects on the round sphere]\label{dt:sphere} For the Levi-Civita connection on $TS^2$, with the standard round metric, \[H_t(-p,p)=0\qquad(t>0).\] Indeed, regard the oriented tangent planes as complex lines, with $J_pv=p\times v$. The connection Laplacian commutes with $J$, so its heat kernel is complex linear. Rotations fixing $p$ and $-p$ act on these two complex tangent lines by opposite characters $e^{i\theta}$ and $e^{-i\theta}$. Equivariance forces their complex-linear intertwiner $H_t(-p,p)$ to vanish. This argument does not determine the entire zero set. \end{example} \subsection{Line bundles on surfaces} Let $\Sigma$ be a closed, connected, oriented surface, and let $L\to\Sigma$ be a Hermitian line bundle with a unitary connection. Put $d=\langle c_1(L),[\Sigma]\rangle$. \begin{proposition}[Fixed-source index formula]\label{dt:index} Fix $t>0$, $p\in\Sigma$, and $0\neq v\in L_p$. If the zeros of $s(x)=H_t(x,p)v$ are isolated, then \[\sum_{x:s(x)=0}\operatorname{ind}_x(s)=d.\] If all zeros are transverse, there are at least $|d|$ of them. For $L=T\Sigma$ with its oriented complex-line structure and Levi-Civita connection, the sum equals $\chi(\Sigma)$. \end{proposition} \begin{proof} The local index is the winding number of the local section around a zero. The sum of these indices is the Euler number of the underlying oriented real plane bundle, which is its first Chern number~\cite{ref:hatcher-vb}. A transverse zero has index $+1$ or $-1$. For the tangent bundle, $c_1(T\Sigma)[\Sigma]=\chi(\Sigma)$. \end{proof} \begin{theorem}[The two-point defect cycle]\label{dt:cycle} Suppose, at a fixed $t>0$, that $H_t$ is transverse to the zero section as a section of \[F=\pi_1^*L\otimes\pi_2^*L^*\longrightarrow\Sigma\times\Sigma.\] Then $\mathcal D_t^{(1)}$ is a smooth closed oriented surface, possibly empty, disjoint from the diagonal. Moreover, \begin{equation}\label{dt:cycle-class} \operatorname{PD}[\mathcal D_t^{(1)}]=\pi_1^*c_1(L)-\pi_2^*c_1(L), \end{equation} \begin{equation}\label{dt:self-intersection} [\mathcal D_t^{(1)}]\cdot[\mathcal D_t^{(1)}]=-2d^2. \end{equation} Interchanging the two factors restricts to a free orientation-reversing involution on the defect surface. \end{theorem} \begin{proof} A transverse zero set of a complex line-bundle section represents its first Chern class~\cite{ref:hatcher-vb}. Since $c_1(F)=\pi_1^*c_1(L)-\pi_2^*c_1(L)$, this gives \eqref{dt:cycle-class}. Squaring and integrating over the product gives \eqref{dt:self-intersection}; the squares of classes pulled back from either surface vanish, and the mixed product integrates to $d^2$. The heat-kernel adjoint identity preserves the zero set. Factor interchange preserves the orientation of the four-dimensional ambient product but induces complex conjugation on the normal complex line, reversing its orientation. It therefore reverses the induced orientation of the zero surface. It has no fixed points there by diagonal positivity. \end{proof} Transversality is a hypothesis, not a genericity result proved here. A general smooth heat-kernel section is not holomorphic; its local indices need not be positive. \subsection{A transition on a flat torus}\label{dt:transition-section} The following example changes with $t$ while the metric, bundle, and connection remain fixed. \begin{theorem}[A two-dimensional transition]\label{dt:transition} Let \[a=(1,0),\quad b=(1/2,\sqrt3/2),\quad\Lambda=\mathbb Za+\mathbb Zb,\quad M_0=\mathbb R^2/\Lambda,\] with the Euclidean quotient metric $g_0$. Write $x=q_1a+q_2b$, with $q_j\in\mathbb R/\mathbb Z$, and equip the trivial Hermitian line bundle with \begin{equation}\label{dt:connection} \nabla_0=d+2\pi i\left(\frac5{12}\,dq_1-\frac13\,dq_2\right). \end{equation} There exists $\varepsilon\in(0,1)$ such that \[\mathfrak h_t=2\quad(00$. The error estimate follows from the positive squared-distance gap to all other lattice points and the quadratic growth of lattice distances. Since $a,b$ are independent, \eqref{dt:phase-cancel} gives the unique zero of $F$: \[e^{a\cdot z_0/2}=\frac{\sqrt3}{2},\qquad e^{b\cdot z_0/2}=\frac12,\qquad z_0=\left(\log\frac34,-\frac{\log12}{\sqrt3}\right).\] With the usual orientations of $\mathbb R^2$ and $\mathbb C$, \[\det_{\mathbb R}DF(z_0)=\frac3{32}>0.\] The implicit function theorem applied to \eqref{dt:rescaled} gives a simple zero \begin{equation}\label{dt:simple-zero} x_+(t)=v+tz_0+O(te^{-c/t}). \end{equation} The exponentially small remainder extends smoothly to $t=0$ on bounded $z$-sets, so the usual parameter version of that theorem applies. Equation~\eqref{dt:conjugate} gives a second zero $x_-(t)=-x_+(t)$ modulo $\Lambda$, with opposite index. \textbf{3. Exclusion of all other small-time zeros.} There are precisely two Voronoi-vertex classes modulo $\Lambda$, represented by $v$ and $-v$. Away from small neighborhoods of these vertices, a finite collection of neighborhoods has either one leading lattice point or two leading adjacent lattice points, with a uniform squared-distance gap to all the others. The ratios of phases for adjacent points belong to \[\{\rho(a),\rho(b),\rho(a-b),\rho(-a),\rho(-b),\rho(b-a)\}.\] None is $-1$. Therefore, for each relevant pair of unit phases $u,w$, there is $c_0>0$ such that \[|ru+sw|\geq c_0(r+s)\qquad(r,s\geq0).\] The single leading term or the sum of the two leading terms consequently dominates the exponentially smaller tail. There are no zeros in these neighborhoods for sufficiently small $t$. For completeness, uniqueness near $v$ requires control beyond bounded rescaled coordinates. In a sufficiently small fixed neighborhood of $v$, put \[w_0=e^{-|x|^2/(4t)},\quad w_a=e^{-|x-a|^2/(4t)},\quad w_b=e^{-|x-b|^2/(4t)},\quad W=w_0+w_a+w_b.\] The sum of all omitted absolute values is at most $Ce^{-c/t}W$, uniformly in that neighborhood. This again follows from a uniform distance gap, together with the convergent Gaussian tail. Hence, at any zero, \[|q_0+Aq_a+Bq_b|\leq Ce^{-c/t},\qquad(q_0,q_a,q_b)=W^{-1}(w_0,w_a,w_b).\] The affine map from $q_0+q_a+q_b=1$ to $q_0+Aq_a+Bq_b\in\mathbb C$ is an isomorphism. Its unique zero is the interior point proportional to $(1,\sqrt3/2,1/2)$. Thus $(q_0,q_a,q_b)$ is exponentially close to that point. Taking logarithms of the two weight ratios forces \[\frac{x-v}{t}=z_0+O(e^{-c/t}).\] Every zero near $v$ therefore lies in the neighborhood where the implicit-function zero is unique. The same argument applies near $-v$. This proves that there are exactly two simple zeros. \textbf{4. Large-time nonvanishing.} In the global periodic frame, the eigenfunctions are Fourier characters and the eigenvalues are \[\lambda_k=4\pi^2Q(k+\alpha),\qquad Q(u,v)=\frac43(u^2-uv+v^2),\qquad k\in\mathbb Z^2.\] Let $k_0=(-1,0)$. For $\ell=(u,v)\in\mathbb Z^2$ and $B_0=u^2-uv+v^2$, direct subtraction gives \begin{equation}\label{dt:spectral-gap} \lambda_{k_0+\ell}-\lambda_{k_0}=\frac{4\pi^2}{9}(12B_0-10u-v)\geq\frac{2\pi^2}{9}(u^2+v^2). \end{equation} Indeed, for integer $u,v$, $B_0\geq\max(|u|,|v|)$, and always $B_0\geq(u^2+v^2)/2$. For the first inequality, use $B_0\geq3u^2/4$, with the cases $|u|\leq1$ checked directly, and likewise for $v$. Thus $k_0$ is the unique ground frequency. Factoring its nonzero contribution out of the spectral expansion leaves $1+S_t(q)$, where \[\sup_q|S_t(q)|\leq\sum_{(u,v)\neq(0,0)}e^{-(2\pi^2/9)t(u^2+v^2)}.\] For $t\geq1$, put $r=e^{-2\pi^2/9}<1/8$. Since $u^2\geq|u|$ for integers $u$, \[\sup_q|S_t(q)|\leq\left(\sum_{u\in\mathbb Z}e^{-(2\pi^2/9)u^2}\right)^2-1 <\left(\frac97\right)^2-1=\frac{32}{49}<1.\] Consequently, the heat kernel is nowhere zero for every $t\geq1$. \textbf{5. Covering numbers.} At small times, let $Z_t=\{x_+(t),x_-(t)\}$. Every source has the nonempty defect set $p+Z_t$, so one source cannot cover. Choose $p_2-p_1\notin Z_t-Z_t$; then the two defect sets are disjoint, and their complementary heat domains cover $M_0$. Thus $\mathfrak h_t=2$. Large-time nonvanishing gives $\mathfrak h_t=1$. \end{proof} \subsection{Products and covering levels} \begin{lemma}[Finite defects in product factors]\label{dt:products} Consider a product of flat tori, trivial Hermitian line bundles with constant unitary connections, and the product connection and metric. Fix a time. Suppose that exactly $k$ factors have nonempty finite fixed-source zero sets, and every other factor has a nowhere-zero kernel. Then the product satisfies $\mathfrak h_t=k+1$. \end{lemma} \begin{proof} The product heat kernel is the product of the factor kernels. For each of $q\leq k$ proposed sources, assign a different defective factor and choose that target coordinate to be a zero for the assigned source. The resulting target is missed by all $q$ heat domains. For the upper bound, choose $k+1$ source coordinates in each defective factor so that the corresponding translates of its finite zero set are pairwise disjoint. This is possible by successively avoiding finitely many differences. A given target coordinate then blocks at most one source in each defective factor. The $k$ factors cannot block all $k+1$ sources. For $k=0$, one source suffices. \end{proof} \begin{theorem}[Arbitrarily many distinct levels]\label{dt:many-levels} For each $N\geq1$, there is a fixed flat torus of dimension $2N$, with a fixed flat unitary connection on a trivial complex line bundle, and nonempty ordered open intervals \[I_00$ and \[s_{j+1}>s_j/\varepsilon\qquad(1\leq j0$ that is invariant under reflection \[ (a,b)\longmapsto(a,-b). \] Such a model is a disk centred on the positive horizontal axis with $b-1$ disjoint smaller open disks removed, all centred on that axis. In a local unit frame $(V,W)$ of $\R V\oplus L$, define \[ \cS_x = \{aV_x+bW_x:(a,b)\in A\}. \] Replacing $W$ by $-W$ leaves this set unchanged. The local definitions therefore glue. Since $a>0$, every fibre avoids zero. \end{proof} \begin{center} \small \begin{tabular}{@{}lccc@{}} \toprule Base & Disk & Annulus & Pair of pants\\ \midrule $S^2$ & No & Yes & No\\ $\R P^2$ & No & Yes & No\\ Orientable surface of genus $\geq 2$ & No & Yes & No\\ $T^2$ & Yes & Yes & Yes\\ Klein bottle & Yes & Yes & Yes\\ \bottomrule \end{tabular} \end{center} Equation~\eqref{ts:eq:original-4} classifies \emph{existence}. It does not classify deformation classes or the embeddings of the individual fibres. \subsection{Three-dimensional knot fields} Throughout this subsection, $\dim M=3$ and $F=S^1$. Knot type means ordinary unparametrized ambient-isotopy type in $\R^3$. The distinguished origin is not part of this knot-type classification. A knot type $K$ is \emph{chiral} if it is not isotopic to its mirror image, even after forgetting the orientation of the knot. A field of \emph{unoriented ambient type $K$} means that, in arbitrary linear coordinates on each tangent space, its type is $K$ or its mirror. \begin{theorem}[Chirality detects orientability] \label{ts:thm:chiral} Fix a chiral knot type $K$. A closed connected smooth three-manifold admits a tangent knot field of unoriented ambient type $K$ if and only if it is orientable. \end{theorem} \begin{proof} Fix a handedness of $K$. For each $x$, exactly one orientation of $T_xM$ makes $\cK_x$ have that handedness. Knot type is locally constant in a smooth family of compact embeddings: nearby embeddings are isotopic, and isotopy extension supplies an ambient isotopy. Hence the selected orientations vary continuously and orient $M$. Conversely, a closed orientable three-manifold is parallelizable \cite{ts:BL}. Choose a trivialization \[ TM\cong M\times\R^3 \] and place a representative \[ K\subset\R^3\setminus\{0\} \] in every fibre. \end{proof} \subsubsection{Tangent trefoils} Every closed orientable three-manifold admits tangent trefoils. In a framing of $T^3$ or $S^3$, one may use the standard $(2,3)$-torus-knot parametrization \begin{equation} \kappa(t) = \bigl( (2+\cos 3t)\cos 2t,\, (2+\cos 3t)\sin 2t,\, \sin 3t \bigr), \qquad t\in\R/2\pi\Z. \label{ts:eq:original-5} \end{equation} Its distance from the vertical axis is at least $1$, so it avoids the origin. \subsubsection{Holonomy rigidity} \begin{definition}[Parallel field] On a Riemannian manifold $(M,g)$, a shape field is \emph{parallel} if Levi--Civita parallel transport satisfies \[ P_\gamma(\cS_{\gamma(0)}) = \cS_{\gamma(1)} \] for every piecewise smooth path $\gamma$. \end{definition} \begin{lemma} For every nontrivial smooth knot $K\subset\R^3$, the orthogonal stabilizer \[ \Stab_{O(3)}(K) = \{A\in O(3):A(K)=K\} \] is finite. \end{lemma} \begin{proof} The stabilizer is a closed subgroup of the compact Lie group $O(3)$. If its identity component had positive dimension, it would contain a circle of rotations about an axis. The knot cannot lie entirely in that axis, so it contains the circular orbit of an off-axis point. This orbit is an embedded circle in the connected one-manifold $K$. Its inclusion is locally a diffeomorphism, so it is open in $K$; compactness makes it closed. It therefore equals $K$. Thus $K$ would be a round circle and hence an unknot, contrary to hypothesis. The stabilizer is consequently a zero-dimensional compact Lie group, and is finite. \end{proof} \begin{theorem}[Parallel-knot rigidity] \label{ts:thm:flat} If a connected Riemannian three-manifold admits a parallel field whose fibres are nontrivial knots, then \[ \Rm_g\equiv 0. \] \end{theorem} \begin{proof} At every $x\in M$, \[ \Hol_x(g) \subset \Stab_{O(T_xM,g_x)}(\cK_x). \] The right-hand side is finite by the lemma. The restricted holonomy group is connected, hence trivial. By the Ambrose--Singer theorem, curvature endomorphisms belong to the restricted holonomy Lie algebra. That Lie algebra is zero, so the curvature vanishes \cite{ts:AS}. \end{proof} The same argument works in any dimension when a parallel shape has finite orthogonal stabilizer. The standard flat three-torus has parallel knot fields. Although $S^3$ has tangent trefoils, no such field can be parallel for any Riemannian metric: a compact simply connected flat manifold of positive dimension cannot exist, because a complete simply connected flat manifold is Euclidean space. \subsection{Deformation and normal variation} \subsubsection{Parametrized deformation classes} \begin{theorem}[Infinitely many parametrized deformation classes] \label{ts:thm:hopf} For every smooth knot type $K$, there are infinitely many deformation classes of parametrized tangent knot fields of type $K$ on $S^3$. \end{theorem} \begin{proof} Fix a framing \[ \tau_x:\R^3\longrightarrow T_xS^3, \] an orientation of $S^3$, and an embedding \[ \kappa:S^1\longrightarrow\R^3\setminus\{0\} \] of type $K$. Choose smooth maps \[ R_k:S^3\longrightarrow\SO(3), \qquad k\in\Z, \] representing the elements of \[ \pi_3(\SO(3))\cong\Z. \] Define \begin{equation} \gamma_k(x,t) = \tau_x\bigl(R_k(x)\kappa(t)\bigr). \label{ts:eq:original-6} \end{equation} For any parametrized field $\gamma$, differentiation at a fixed $t_0\in S^1$ defines a map \begin{equation} u_\gamma(x) = \frac{ \tau_x^{-1}\bigl(\partial_t\gamma(x,t_0)\bigr) }{ \left| \tau_x^{-1}\bigl(\partial_t\gamma(x,t_0)\bigr) \right| } \in S^2. \label{ts:eq:original-7} \end{equation} The denominator is nonzero because each fibre map is an embedding. A deformation of parametrized fields induces a homotopy of these maps. For~\eqref{ts:eq:original-6}, \[ u_{\gamma_k}(x)=R_k(x)a, \qquad a=\frac{\kappa'(t_0)}{|\kappa'(t_0)|}. \] The fibration \[ \SO(2)\longrightarrow\SO(3) \xrightarrow{\;R\mapsto Ra\;}S^2 \] induces an isomorphism on $\pi_3$, because \[ \pi_3(\SO(2))=\pi_2(\SO(2))=0. \] Therefore the maps $u_{\gamma_k}$ represent distinct elements of \[ \pi_3(S^2)\cong\Z. \] They are detected by the Hopf invariant \cite{ts:H}. With compatible choices of generators, \[ H(u_{\gamma_k})=k. \] Thus the fields $\gamma_k$ are pairwise inequivalent under deformation through parametrized fields. \end{proof} The integer labels use the chosen framing. This proves neither a classification of \emph{all} parametrized fields nor a classification after forgetting parametrizations or quotienting by diffeomorphisms of the base. \subsubsection{Normal variation} Fix a Riemannian metric $g$ and assume now that \[ \partial F=\varnothing. \] Let \[ \iota:U\times F\longrightarrow TM \] be a local parametrization of a shape field. For $v=\iota_x(u)$ and $X\in T_xM$, define \begin{equation} \mathcal B_v(X) = \left( \nabla_X\iota(\,\cdot\,,u) \right)^{\perp_{T_v\cS_x}}. \label{ts:eq:original-8} \end{equation} Here $\nabla$ is the Levi--Civita connection. The tangent space $T_v\cS_x$ is viewed as a subspace of $T_xM$ using the canonical identification \[ T_v(T_xM)\cong T_xM, \] and the orthogonal projection uses $g_x$. Thus $\mathcal B$ is a section of \[ p^*T^*M\otimes\nu_{\mathrm{vert}}\cS, \] where $\nu_{\mathrm{vert}}\cS$ is the normal bundle of the shapes inside the tangent fibres. \begin{proposition} For compact boundaryless fibres,~\eqref{ts:eq:original-8} is independent of local parametrization, and \[ \mathcal B=0 \quad\Longleftrightarrow\quad \text{the shape field is parallel}. \] \end{proposition} \begin{proof} An $x$-dependent reparametrization changes $\nabla_X\iota$ by a vector tangent to $\cS_x$. Its normal projection is therefore unchanged. Parallel fields plainly give $\mathcal B=0$. Conversely, consider a smooth path in the base and trivialize $TM$ along that path by parallel transport. The shape bundle over the path is also trivial, so it can be represented by a smooth family of embeddings $\iota_t$ of $F$ into a fixed vector space. If $\mathcal B=0$, then \[ \partial_t\iota_t=d\iota_t(Z_t) \] for a smooth time-dependent vector field $Z_t$ on $F$. Let $\phi_t$ solve \[ \partial_t\phi_t=-Z_t\circ\phi_t, \qquad \phi_0=\id. \] Compactness and absence of boundary ensure that this flow exists throughout each compact time interval. The chain rule gives \[ \frac{d}{dt}(\iota_t\circ\phi_t)=0. \] Hence the images of the $\iota_t$ are constant in the parallel trivialization. The same conclusion holds along piecewise smooth paths by concatenation. Thus parallel transport preserves the shape field. \end{proof} For fibres with boundary,~\eqref{ts:eq:original-8} alone is insufficient: it does not detect boundary motion tangent to the fibre. For example, an expanding interval in a one-dimensional vector space has identically zero normal variation. No corresponding equivalence is asserted in that case. \subsection{Four-dimensional direction knots}\label{tk:sec:directions} In Subsections~\ref{tk:sec:directions}--\ref{tk:sec:incidence}, unless otherwise specified, $M$ is connected, oriented, four-dimensional, and without boundary. Integral cohomology is used unless coefficients are displayed; $\bar a$ denotes reduction of $a\in H^2(M;\Z)$ modulo $2$. The \emph{oriented direction bundle} is \[ S(TM)=(TM\setminus 0)/\R_{>0}, \qquad \pi:S(TM)\longrightarrow M. \] Its fiber is an oriented $3$-sphere. A Riemannian metric identifies it with the unit tangent sphere bundle by radial normalization, but no metric is part of the definition. \begin{definition}[Tangent-knot field] An \emph{oriented tangent-knot field} is a smooth embedded submanifold $\K\subset S(TM)$ such that $\pi|_{\K}$ is a proper surjective submersion with circle fibers, together with an orientation of its vertical tangent line bundle. A field has \emph{type $K$} if each fiber $\K_x\subset S(T_xM)$ has the oriented ambient isotopy type of a fixed oriented knot $K\subset S^3$. \end{definition} The fibers are \emph{unparametrized}: the data do not include a map $M\times S^1\to S(TM)$. Two fields are equivalent if an orientation-preserving diffeomorphism of their base manifolds carries one to the other under its derivative on directions, preserving fiber orientations. A deformation is a smooth one-parameter family of fields of the fixed type. \begin{proposition}[Basic properties] The total space $\K$ has dimension $5$. The map $\K\to M$ is an oriented circle bundle, and its fiber knot type is locally constant. Fields exist locally for every knot type; every parallelizable oriented four-manifold admits a field of every type. \end{proposition} \begin{proof} Ehresmann's theorem makes the proper submersion a smooth circle bundle. Local trivializations and isotopy extension identify nearby embedded fibers by ambient isotopies. An oriented frame on an open set identifies its direction bundle with $U\times S^3$, where $U\times K$ defines a field. A global frame gives the final assertion. \end{proof} Define the \emph{charge} of a field by \[ a(\K)=e(\K\to M)\in H^2(M;\Z). \] Here the Euler class of an oriented circle bundle is defined using $\Diff^+(S^1)\simeq\SO(2)$, with the convention $e(S(L))=c_1(L)$ for the unit circle bundle of a complex line bundle $L$. The charge is preserved by deformation and is natural under equivalences. For a chosen metric, let $P\to M$ be the oriented orthonormal frame bundle. Write $\CK$ for the component containing $K$ in \[ \Emb(S^1,S^3)/\Diff^+(S^1), \] with its smooth topology. A field is equivalently a smooth family of points in the associated bundle \[ P\times_{\SO(4)}\CK\longrightarrow M. \] This description is the bridge to obstruction theory. \subsubsection{Relation to tangent shapes} The direction construction is a restricted variant of the tangent-shape construction. A metric identifies each positive ray with its unit vector, so a direction-knot field lifts to a tangent $S^1$-shape field, with the given fiber orientation. Conversely, a tangent circle field with a chosen fiber orientation determines a direction-knot field only when its radial projection is an embedding on each fiber. An arbitrary embedded circle in $T_xM\setminus\{0\}$ need not satisfy this condition. Positive radial lengths are additional data and are forgotten in the direction description. The orientation of the circle fibers does not specify a global parametrization. The latter would trivialize the circle bundle. Also, the Euler obstruction in Theorem~\ref{ts:thm:euler} is vacuous for $F=S^1$; the four-dimensional restrictions below use the topology of the space of knots in $S^3$. \subsection{Torus knots and existence} Fix relatively prime integers $p,q\geq2$, and put \[ K_{p,q} = \left\{ 2^{-1/2}(z^p,z^q): |z|=1 \right\} \subset S^3\subset\C^2, \] \[ H_{p,q} = \left\{ \operatorname{diag}(u^p,u^q):|u|=1 \right\} \subset\SO(4). \] The knot has the orientation induced by $z=e^{it}$. Its orientation-preserving rotational stabilizer is $H_{p,q}\cong S^1$. Assertions concerning these torus knots use the positive type and the specified ambient orientation. \begin{lemma}[External knot-space input: Hatcher] \label{tk:lem:hatcher} The natural rotation-orbit inclusion \begin{equation} \label{tk:eq:orbit} \SO(4)/H_{p,q} \longrightarrow \mathscr C_{K_{p,q}} \end{equation} is an $\SO(4)$-equivariant map and an underlying homotopy equivalence. \end{lemma} This is the oriented version of Hatcher's theorem~\cite{tk:hatcher}: the unoriented stabilizer is a weighted copy of $O(2)$; passing to the orientation double cover gives~\eqref{tk:eq:orbit}. The map, not just the abstract homotopy type of its target, is important. \begin{theorem}[Weighted circle reduction] \label{tk:thm:reduction} A field of type $K_{p,q}$ and charge $a$ exists on $M$ if and only if there is a complex line bundle $L$ with $c_1(L)=a$ and an oriented real bundle isomorphism \begin{equation} \label{tk:eq:splitting} TM \cong \bigl(L^{\otimes p}\oplus L^{\otimes q}\bigr)_{\R}. \end{equation} Moreover, every such field is homotopic through sections of the knot-space bundle to one arising from an $H_{p,q}$-reduction. \end{theorem} \begin{proof} The equivariant map~\eqref{tk:eq:orbit} induces a fiberwise homotopy equivalence \[ P/H_{p,q} \longrightarrow P\times_{\SO(4)}\mathscr C_{K_{p,q}}. \] Thus a section on the right determines, up to homotopy, a section on the left; this is the standard homotopy lifting argument over a CW base. Such a section is an $H_{p,q}$-reduction of $P$, which gives~\eqref{tk:eq:splitting}. Its associated circle bundle is $S(L)$, since $u\in H_{p,q}$ acts on the knot parameter by $z\mapsto uz$. The universal fiber-circle bundle shows that the homotopy preserves $a$. Conversely, choose a Hermitian metric on $L$. In the bundle on the right of~\eqref{tk:eq:splitting}, the map \[ S(L) \longrightarrow S\bigl((L^{\otimes p}\oplus L^{\otimes q})_{\R}\bigr), \qquad v\longmapsto [\,v^{\otimes p}\oplus v^{\otimes q}\,] \] is fiberwise an embedded $K_{p,q}$ because $\gcd(p,q)=1$. Transport it by the bundle isomorphism. Continuous reductions can be smoothed, so this constructs a smooth field of charge $a$. \end{proof} \begin{remark} The theorem is a statement about existence and homotopy, not a linear normal form for every given fiber and not a classification up to diffeomorphism. The class $a$ alone need not classify fields. A global fiber parametrization would force $a=0$, hence~\eqref{tk:eq:splitting} would force $TM$ to be trivial. \end{remark} For any such field, the characteristic-class identities are \begin{equation} \label{tk:eq:classes} \begin{aligned} e(TM)&=pq\,a^2,\\ p_1(TM)&=(p^2+q^2)a^2,\\ w_2(TM)&=(p+q)\bar a. \end{aligned} \end{equation} They follow directly from the Chern classes of the two line summands. In particular, the reduction induces an almost complex structure with $c_1=(p+q)a$. \begin{theorem}[Existence on a closed four-manifold] \label{tk:thm:criterion} Let $M$ be closed and $a\in H^2(M;\Z)$. A field of type $K_{p,q}$ with charge $a$ exists if and only if, writing $N=\langle a^2,[M]\rangle$, one has \begin{equation} \label{tk:eq:criterion} \begin{aligned} (p+q)\bar a&=w_2(TM),\\ pqN&=\chi(M),\\ (p^2+q^2)N&=3\sigma(M). \end{aligned} \end{equation} \end{theorem} \begin{proof} Necessity follows from~\eqref{tk:eq:classes}, the Euler formula and the signature theorem. For sufficiency, choose $L$ with $c_1(L)=a$, and set \[ E=(L^{\otimes p}\oplus L^{\otimes q})_{\R}. \] Equations~\eqref{tk:eq:criterion} give equal $w_2,e,p_1$ for $E$ and $TM$; equality of the degree-four numbers is equality of classes because $H^4(M;\Z)\cong\Z$. Oriented real rank-four bundles over this base are determined by these classes, by Dold--Whitney~\cite{tk:doldwhitney}. Hence $E\cong TM$ as oriented bundles, and Theorem~\ref{tk:thm:reduction} applies. \end{proof} The same argument can be expressed through the Hirzebruch--Hopf criterion~\cite{tk:hirzebruchhopf}: $c=(p+q)a$ satisfies $\bar c=w_2$ and \[ c^2[M]=2\chi+3\sigma. \] \subsection{Topology and arithmetic} \begin{corollary}[Slope identity] \label{tk:cor:slope} A closed manifold carrying a $K_{p,q}$-field satisfies \begin{equation} \label{tk:eq:slope} \begin{aligned} 3pq\,\sigma&=(p^2+q^2)\chi,\\ 2\chi-3\sigma&=-(p-q)^2N. \end{aligned} \end{equation} If $M$ is simply connected, then $N>0$, $\sigma>0$, and \[ b_2=pqN-2, \qquad \sigma=\frac{p^2+q^2}{3}N. \] If $p$ and $q$ are both odd, every such $M$ is spin. \end{corollary} \begin{proof} Use~\eqref{tk:eq:criterion}, $\chi=2+b_2$ in the simply connected case, and $p+q\equiv0\pmod2$ in the odd--odd case. \end{proof} \begin{corollary}[Trefoil divisibility] \label{tk:cor:trefoil} For a closed manifold with a $K_{2,3}$-field, \[ N\in12\Z, \qquad (\chi,\sigma)=(72k,52k) \quad\text{for some }k\in\Z. \] If it is simply connected, $\chi\ge72$. If it is also spin, then $N\in48\Z$ and $\chi\ge288$. Both simply connected lower bounds are attained by the examples in Subsection~\ref{tk:sec:examples}. \end{corollary} \begin{proof} The identities are $\chi=6N$, $3\sigma=13N$, and $\bar a=w_2$. Thus $N=3m$ and $\sigma=13m$. The class $a$ is characteristic for the unimodular intersection form on $H^2(M;\Z)/\mathrm{torsion}$, so van der Blij's congruence~\cite{tk:vanderblij} gives $N\equiv\sigma\pmod8$. Hence \[ 3m\equiv13m\pmod8, \] so $4\mid m$. In the spin case, Rokhlin's theorem gives $16\mid\sigma$ (see~\cite{tk:furuta}, introduction), whence $16\mid m$. Simply connectedness gives $N>0$. \end{proof} The slope identity already excludes $S^4$, $\CP^2$, and $S^2\times S^2$ from carrying a trefoil field in their standard orientations: their respective pairs $(\chi,\sigma)$ are $(2,0)$, $(3,1)$, and $(4,0)$. \begin{proposition}[Asymmetric hyperbolic type] \label{tk:prop:hyperbolic} Let $K\subset S^3$ be a hyperbolic knot whose complement has trivial orientation-preserving isometry group. An oriented four-manifold admits a field of this type if and only if it is parallelizable. Consequently, in the closed case, $\chi=\sigma=0$ and all positive-degree characteristic classes of $TM$ vanish. \end{proposition} \begin{proof} For this asymmetric case Hatcher's orbit theorem~\cite{tk:hatcher} gives a homotopy equivalence \[ \SO(4)\longrightarrow\CK. \] The associated bundle map identifies the existence of a section with that of a section of \[ P\times_{\SO(4)}\SO(4)\cong P. \] This is a framing. The converse follows by placing a fixed copy of $K$ in every framed fiber. \end{proof} \subsection{Einstein metrics} Let $g$ be a smooth Riemannian metric on a closed oriented four-manifold. Write \[ E=\Ric_g-\tfrac14s_g g \] for traceless Ricci curvature, and $W^\pm$ for the self-dual and anti-self-dual Weyl curvature operators. Put \[ \norm{T}_2^2=\int_M|T|^2\,d\mu_g. \] We use the Hilbert--Schmidt Weyl norm convention \[ |W|^2=\tfrac14W_{ijkl}W^{ijkl}, \qquad |E|^2=E_{ij}E^{ij}. \] \begin{theorem}[Curvature identity and Einstein rigidity] \label{tk:thm:einstein} If $M$ carries a $K_{p,q}$-field of charge square $N$, then every metric $g$ satisfies \begin{equation} \label{tk:eq:curvature} \norm{E}_2^2 = 8\pi^2(p-q)^2N +4\norm{W^-}_2^2 +\frac1{12}\norm{s_g}_2^2. \end{equation} For $N>0$, this gives the strictly positive lower bound \[ \norm{E}_2^2\ge8\pi^2(p-q)^2N. \] Every Einstein metric on $M$, if one exists, is flat. \end{theorem} \begin{proof} The Chern--Gauss--Bonnet and signature formulas, with these conventions, give \begin{align*} 8\pi^2\chi &= \norm{W^+}_2^2+\norm{W^-}_2^2 +\frac1{24}\norm{s_g}_2^2 -\frac12\norm{E}_2^2,\\ 12\pi^2\sigma &= \norm{W^+}_2^2-\norm{W^-}_2^2 \end{align*} (see~\cite{tk:atiyahlebrun}, Section~2, in the smooth case). Subtracting yields \[ 4\pi^2(2\chi-3\sigma) = 2\norm{W^-}_2^2 +\frac1{24}\norm{s_g}_2^2 -\frac12\norm{E}_2^2. \] Substitute~\eqref{tk:eq:slope}. Since $p\ne q$, $N>0$ excludes $E=0$. If $N<0$, then $\chi=pqN<0$, also impossible for an Einstein metric by the first formula. If $N=0$ and $E=0$, that formula forces $W^+=W^-=0$ and $s_g=0$, so the full curvature vanishes. \end{proof} This is a consequence of classical four-dimensional curvature identities, not a new curvature tensor attached to the knot field. The metric need not be compatible with the field. \subsection{Four-dimensional examples} \label{tk:sec:examples} In a hyperbolic summand of an intersection form, use generators $u,v$ with \[ u^2=v^2=0, \qquad u\cdot v=1. \] Then \[ (ru+sv)^2[M]=2rs. \] We write $\overline{K3}$ for a K3 surface with reversed complex orientation; it is spin and has \[ b_2=22, \qquad \chi=24, \qquad \sigma=16, \] with hyperbolic summands in its intersection form (cf.~\cite{tk:furuta,tk:hopkins}). \begin{example}[A field of every knot type] A global frame on $T^4$ gives \[ S(TT^4)\cong T^4\times S^3. \] For every knot $K$, the product $T^4\times K$ is a field. For $K_{2,3}$ this is the explicit family \[ t\longmapsto2^{-1/2}(e^{2it},e^{3it}), \] with $a=0$. \end{example} \begin{example}[Nonparallelizable with zero characteristic numbers] Let \[ M_0 = (\CP^2\mathbin{\#}\overline{\CP}^{\,2}) \mathbin{\#}\,2(S^1\times S^3). \] Its form is $\langle1\rangle\oplus\langle-1\rangle$ and $\chi=\sigma=0$. For diagonal generators $h,e$, set $a=h+e$. Then \[ a^2[M_0]=0, \qquad \bar a=w_2(TM_0)\ne0. \] The criterion gives a trefoil field, although $M_0$ is not parallelizable. \end{example} \begin{example}[Sharp simply connected trefoil bound] The manifold \[ M_1 = \#^{61}\CP^2 \ \#\ \#^{9}\overline{\CP}^{\,2} \] has $(\chi,\sigma)=(72,52)$. Choose $a$ with coefficient $1$ on every positive generator, coefficient $3$ on five negative generators, and coefficient $1$ on the remaining four. Then \[ a^2[M_1]=61-5\cdot9-4=12, \qquad \bar a=w_2(TM_1). \] Theorem~\ref{tk:thm:criterion} gives a trefoil field, attaining $\chi=72$. \end{example} \begin{example}[Sharp simply connected spin trefoil bound] Let \[ M_2=\#^{13}\overline{K3}. \] Then $(\chi,\sigma)=(288,208)$. In one hyperbolic summand take $a=2u+12v$, so \[ a^2[M_2]=48, \qquad \bar a=0. \] The trefoil criterion holds, attaining the spin bound $\chi=288$. \end{example} \begin{example}[An odd--odd torus-knot field] Let \[ M_3 = \#^{74}\overline{K3} \ \#\ \#^{25}(S^2\times S^2). \] It is spin, with $(\chi,\sigma)=(1680,1184)$. Choose $a=u+24v$, so $a^2[M_3]=48$. For $(p,q)=(5,7)$, one has \[ pq\cdot48=1680 \] and \[ (p^2+q^2)48=3552=3\cdot1184. \] Thus $M_3$ admits a $K_{5,7}$-field. \end{example} All connected-sum numbers follow from \[ \chi(X\mathbin{\#}Y)=\chi(X)+\chi(Y)-2 \] and \[ \sigma(X\mathbin{\#}Y)=\sigma(X)+\sigma(Y). \] The last three examples admit no Einstein metric by Theorem~\ref{tk:thm:einstein}. \subsection{Spin geography and the 11/8 conjecture} Here $p,q\ge3$ are coprime and odd. Abbreviate \[ A=p^2+q^2, \qquad B=pq, \qquad \rho_{p,q}=\frac{A}{3B}. \] Let $\mathsf C_{11/8}$ be the assertion that every closed, smooth, simply connected spin four-manifold $X$ satisfies \[ b_2(X)\ge\frac{11}{8}|\sigma(X)|. \] This is the simply connected form of the $11/8$ conjecture discussed in~\cite{tk:furuta,tk:hopkins}; the reformulation below does not prove or disprove it. \begin{proposition}[Existence and nonexistence regions] \label{tk:prop:geography} If $\rho_{p,q}<8/11$, some closed simply connected spin four-manifold admits a $K_{p,q}$-field. If $\rho_{p,q}\ge4/5$, none does. More precisely, any such field on a closed simply connected manifold obeys \begin{equation} \label{tk:eq:furuta} (12B-5A)N\ge48. \end{equation} \end{proposition} \begin{proof} For existence, put \[ \Delta=24B-11A>0. \] Choose an integer $t\ge1$ with $m=\Delta t-1\ge1$, and set $n=At$. On \[ M = \#^n\overline{K3} \ \#\ \#^m(S^2\times S^2) \] one has \[ \chi=48Bt, \qquad \sigma=16At, \] and a hyperbolic-summand class $a=u+24tv$ with \[ a^2[M]=48t. \] Since $p+q$ is even, the criterion applies. For nonexistence, any candidate is spin and has nonzero $b_2$ and positive signature. Donaldson's theorem excludes a nonzero definite even form; Furuta's theorem~\cite{tk:furuta} therefore applies: \[ BN-2 = b_2 \ge \frac54\sigma+2 = \frac{5A}{12}N+2. \] This is~\eqref{tk:eq:furuta}. In particular, $12B-5A>0$, or $\rho_{p,q}<4/5$. \end{proof} \begin{theorem}[$11/8$ detection by torus-knot fields] \label{tk:thm:118} The assertion $\mathsf C_{11/8}$ is false if and only if there are coprime odd $p,q\ge3$ and a closed, smooth, simply connected four-manifold carrying a $K_{p,q}$-field with \begin{equation} \label{tk:eq:forbidden} 11(p^2+q^2)>24pq, \qquad\text{or equivalently}\qquad \rho_{p,q}>\frac8{11}. \end{equation} \end{theorem} \begin{proof} Given such a field, the manifold is spin, $N>0$, and \[ \frac{b_2}{\sigma} = \frac{3B}{A}-\frac{6}{AN} < \frac{3B}{A} < \frac{11}{8}. \] Thus it violates $\mathsf C_{11/8}$. Conversely, let $X$ be a counterexample, oriented so that $s=\sigma(X)>0$, and put $b=b_2(X)$. Choose coprime odd $p,q\ge3$ such that \begin{equation} \label{tk:eq:density} \frac8{11} < \frac{A}{3B} < \frac{s}{b}. \end{equation} This is possible: ratios of coprime odd integers $q/p>1$ are dense in $(1,\infty)$, and \[ r\longmapsto\frac{r+r^{-1}}3 \] maps that interval continuously and strictly increasingly onto $(2/3,\infty)$. Set \[ D=3Bs-Ab>0. \] For an integer $t$ large enough that $\ell=Dt-1\ge1$, let $k=2At$ and form \[ M = \#^k X \ \#\ \#^\ell(S^2\times S^2). \] This manifold is smooth, simply connected and spin. Direct calculation gives \[ \chi(M)=kb+2\ell+2=6Bst, \qquad \sigma(M)=ks=2Ast. \] In a hyperbolic summand choose $a=u+3st\,v$, so that \[ a^2[M]=6st. \] These numbers satisfy~\eqref{tk:eq:criterion}, including $w_2=(p+q)\bar a=0$. Thus $M$ carries the required field, and~\eqref{tk:eq:density} gives~\eqref{tk:eq:forbidden}. \end{proof} \begin{remark}[Meaning of the equivalence] The theorem translates an existing geography problem into a geometric existence problem; it supplies no new inequality. The range \[ \frac8{11}<\rho<\frac45 \] is not decided by the arguments here. In particular, $\rho_{3,5}=34/45>8/11$, so a simply connected $K_{3,5}$ example would violate $\mathsf C_{11/8}$. Its charge square must be a positive multiple of $24$ by Rokhlin's theorem; the smallest numerical candidate is \[ (\chi,\sigma)=(360,272). \] This is not an existence claim. No integral pair has $\rho=8/11$, since the required ratio \[ q/p=(12\pm\sqrt{23})/11 \] is irrational. \end{remark} \subsection{Incidence data}\label{tk:sec:incidence} Let $\Conf_4(\K/M)$ be the bundle of ordered quadruples of pairwise distinct points in a common fiber. For $\xi_i=[v_i]\in\K_x$, choose any positively oriented volume form $\omega_x$ and positive-ray representatives $v_i$. Define \[ \mathfrak I_{\K}(x;\xi_1,\xi_2,\xi_3,\xi_4) = \sgn\bigl(\omega_x(v_1,v_2,v_3,v_4)\bigr) \in\{-1,0,1\}. \] Positive rescaling of any $v_i$ or of $\omega_x$ leaves this sign unchanged. Hence it is intrinsic to the oriented linear geometry and is natural under orientation-preserving diffeomorphisms. Its zero locus \[ \mathcal D_{\K} = \{\mathfrak I_{\K}=0\} \subset\Conf_4(\K/M) \] is the set of linearly dependent quadruples. After choosing a metric and volume form it is the zero locus of a smooth determinant function, but it need not be a smooth hypersurface. This data is not a knot-isotopy invariant: an ambient isotopy of a fiber can change linear incidence. No additional characteristic-class obstruction follows merely from writing down $\mathcal D_{\K}$. We leave the study of its singularities, differential variation, and possible refinements for future work. For torus knots, \emph{existence} is already exhausted by Theorem~\ref{tk:thm:criterion}. To obtain information beyond that criterion, one must study deformation or diffeomorphism classes, impose extra differential conditions, or pass to knot/link types with richer embedding spaces. One cannot obtain a stronger obstruction to unrestricted torus-knot-field existence while keeping the same definition and all of~\eqref{tk:eq:criterion} satisfied. \subsection{Related work} The quotient $\mathcal Q_F^n$ in~\eqref{ts:eq:original-2} is a standard type of nonlinear Grassmannian. Gay-Balmaz and Vizman study its principal-bundle and smooth-manifold foundations, including compact source manifolds with boundary \cite{ts:GV}. Fibrewise shapes therefore belong naturally to the established geometry of embedding spaces. Suppose all shapes are locally smooth linear images of a fixed model \[ A\subset\R^n\setminus\{0\}. \] Then the adapted frames form a reduction of $\Fr(TM)$ to \[ G=\Stab_{\GL(n,\R)}(A). \] This is an ordinary $G$-structure. Allowing shapes to vary outside a single linear orbit is the additional freedom in the present formulation. Riemannian unit ellipsoids are a special case; the general definition discards their convexity and radial restrictions. Theorem~\ref{ts:thm:euler} is an application of the Becker--Gottlieb transfer \cite{ts:BG} and Euler-class theory \cite{ts:MS}. Theorem~\ref{ts:thm:chiral} uses classical three-manifold parallelizability \cite{ts:BL}. Theorem~\ref{ts:thm:flat} is a finite-stabilizer application of Ambrose--Singer holonomy theory \cite{ts:AS}. Hatcher and Budney study homotopy types of spaces of knots \cite{tk:hatcher,tk:budney}. Their work is a natural starting point for analyzing the section space in~\eqref{ts:eq:original-2}. Results for long knots or knots in $S^3$ do not automatically classify fields in punctured tangent fibres: the ambient space, parametrization conventions, and twisting by $TM$ must be accounted for. Theorem~\ref{ts:thm:hopf} uses only the classical Hopf invariant \cite{ts:H}. A further problem is to compute components and obstruction classes of the section space in~\eqref{ts:eq:original-2} for a prescribed knot or higher-dimensional embedding type. The question is whether coupling the embedding space to $TM$ yields information beyond that captured by a fixed-model $G$-structure, ordinary characteristic classes, or known embedding-space invariants. The results here do not settle this question. Havens--Koytcheff~\cite{tk:havens} treat related link and solid-torus embedding spaces. The tangent-bundle reduction belongs to classical $G$-structure and characteristic-class theory: Dold--Whitney~\cite{tk:doldwhitney} and Hirzebruch--Hopf~\cite{tk:hirzebruchhopf} provide the relevant four-dimensional classification results. The arithmetic uses van der Blij~\cite{tk:vanderblij} and Rokhlin; the spin inequalities come from Furuta~\cite{tk:furuta}, with stronger related results in Hopkins--Lin--Shi--Xu~\cite{tk:hopkins}. The Einstein obstruction uses the classical Hitchin--Thorpe mechanism, with curvature conventions recorded in Atiyah--LeBrun~\cite{tk:atiyahlebrun}. \endgroup \section{Finite-scale bundle comparisons} \label{fs:chapter} A bundle comparison identifies fibers over pairs of points. We study its extension radius from the diagonal and the restriction maps between spaces of comparisons. \subsection{Definitions and basic properties} \label{fs:sec:object} Throughout this section, $M$ is a closed, connected smooth manifold, $g$ is a smooth Riemannian metric, and $E\to M$ is a smooth real or complex vector bundle of positive rank. Write $p_i:M\times M\to M$ for the projections and put \[ \Delta=\{(x,x):x\in M\},\qquad U_r(g)=\{(x,y)\in M^2:d_g(x,y)0). \] The strict inequality in this definition matters at critical radii. \begin{definition}[Comparisons and their extension radius] \label{fs:def:comparison} A \emph{comparison at scale $r$} is a smooth bundle isomorphism \[ P:p_1^*E|_{U_r(g)}\longrightarrow p_2^*E|_{U_r(g)},\qquad P_{xx}=\operatorname{id}_{E_x}. \] Thus $P_{xy}:E_x\to E_y$ is invertible and depends smoothly on $(x,y)$. Let $\mathcal C_r(E,g)$ be the space of such maps, with the compact-open $C^\infty$ topology. Define \[ R_E(g)=\sup\{r>0:\mathcal C_r(E,g)\ne\varnothing\}\in(0,\infty]. \] For $0\operatorname{rad}(M,g)$, some $x_0$ satisfies $\{x_0\}\times M\subset U_r(g)$; then $P_{x_0,y}$ trivializes $E$. Part (ii) gives the lower bound. \end{proof} For $E=TM$, infinite radius is therefore equivalent to parallelizability. For a general nontrivial bundle, existence at the supremum $r=R_E(g)$ is a separate question. \subsection{Stability and functoriality} \label{fs:sec:stability} \begin{proposition}[Metric stability] \label{fs:prop:stability} For two metrics $g,h$ on the same $M$ and a nontrivial bundle $E$, let \[ \epsilon=\sup_{x,y\in M}|d_g(x,y)-d_h(x,y)|. \] Then $|R_E(g)-R_E(h)|\le\epsilon$. For every $a>0$, one also has $R_E(a^2g)=aR_E(g)$, allowing the value $\infty$. \end{proposition} \begin{proof} For $r>\epsilon$, the inclusion $U_{r-\epsilon}(h)\subset U_r(g)$ gives a restriction map. Taking suprema yields $R_E(h)\ge R_E(g)-\epsilon$ when the right side is positive; otherwise that inequality is automatic. Interchange $g,h$. Scaling follows from $d_{a^2g}=a\,d_g$. \end{proof} \begin{proposition}[Pullback and products] \label{fs:prop:pullback} If $f:(M,g)\to(N,h)$ is smooth and $1$-Lipschitz and $F\to N$ is a bundle, then \[ R_{f^*F}(g)\ge R_F(h). \] In particular, for a product metric on $X\times Y$, \[ R_{p_X^*F}(g_X\oplus g_Y)=R_F(g_X). \] \end{proposition} \begin{proof} The map $f\times f$ carries $U_r(g)$ into $U_r(h)$, so comparisons pull back. Projection to $X$ gives one product inequality. Restriction to the isometric slice $X\times\{y_0\}$ gives the reverse inequality. \end{proof} \begin{proposition}[Relative gauge description] \label{fs:prop:gauge} If $P^0\in\mathcal C_r(E,g)$, the map $A\mapsto P^0A$ is a homeomorphism \[ \operatorname{Gau}_{\Delta}(p_1^*E|_{U_r})\cong\mathcal C_r(E,g), \] where the group on the left consists of smooth bundle automorphisms equal to the identity on $\Delta$. \end{proposition} \begin{proof} The inverse sends $P$ to $A_{xy}=(P^0_{xy})^{-1}P_{xy}$. Multiplication and inversion are continuous in the stated topology. \end{proof} Thus a nonempty comparison space is a torsor: choosing one comparison identifies it with a group. Without choosing an origin, it has the intrinsic ternary operation \[ [P,Q,R]_{xy}=P_{xy}Q_{xy}^{-1}R_{xy}, \] which is preserved by restriction. Both the spaces and the restriction maps carry information beyond the single number $R_E(g)$. \subsection{Characteristic obstructions and line bundles} \label{fs:sec:characteristic} For a natural characteristic class $c$, define \[ \delta_r c(E):=(p_2^*c(E)-p_1^*c(E))|_{U_r(g)}. \] An isomorphism of the two pullbacks implies $\delta_rc(E)=0$. This applies, with the appropriate coefficients, to Stiefel--Whitney, Pontryagin and Chern classes. In higher rank these necessary conditions need not be sufficient. \begin{theorem}[Line-bundle obstruction and topology] \label{fs:thm:lines} For a complex line bundle $L$, \[ \mathcal C_r(L,g)\ne\varnothing\quad\Longleftrightarrow\quad \delta_rc_1(L)=0\text{ in }H^2(U_r(g);\mathbb Z). \] For a real line bundle, the corresponding criterion is $\delta_rw_1(L)=0$ in $H^1(U_r(g);\mathbb F_2)$. If nonempty, $\pi_0\mathcal C_r(L,g)$ for a complex line is a torsor for $H^1(U_r(g),\Delta;\mathbb Z)$, and each path component is contractible. For a real line, the entire nonempty space $\mathcal C_r(L,g)$ is contractible. \end{theorem} \begin{proof} A comparison is a nowhere-zero section of the line bundle $p_1^*L^\vee\otimes p_2^*L$, followed by diagonal normalization. Classification of complex and real line bundles by $c_1$ and $w_1$ gives the criteria; see \cite[Proposition~3.10]{ref:hatcher-vb}. Fix $P^0$. In the complex case all other comparisons are uniquely $P^0f$, with $f:U_r\to\mathbb C^\times$ smooth and $f|_\Delta=1$. Relative homotopy classes of these maps are $H^1(U_r,\Delta;\mathbb Z)$, since $\mathbb C^\times\simeq K(\mathbb Z,1)$. Relative smooth approximation identifies smooth and continuous classes. The inclusion $\Delta\subset U_r$ is a cofibration, as it has a tubular neighborhood. The space $U_r$ is connected: join $(x,y)$ to $(x,x)$ along a minimizing geodesic and then move within $\Delta$. In the component of $f=1$, every $f$ has a unique smooth logarithm $u:U_r\to\mathbb C$ with $u|_\Delta=0$. Lifting through the exponential covering is continuous in the compact-open smooth topology. Thus this component is homeomorphic to the vector space of such $u$, and is contractible. Translation gives the other components. For real lines, a normalized ratio is positive on connected $U_r$, so the real logarithm contracts the whole space. \end{proof} \begin{remark}[What a finite range of scales can detect] \label{fs:rem:range} If a complex line has a comparison at $r_m$, choose it as origin and restrict it to $r_1<\cdots\sigma_g(\alpha)/2$, choose an $\alpha$-odd loop $c$ based at $x$ of length $\ell<2r$. Each point of $c$ has distance at most $\ell/2\ell/2$, the map \[ F:(\mathbb R/\mathbb Z)^2\longrightarrow U_r(g),\qquad F(t,s)=(t\mu,t\mu+s\lambda) \] is well defined: the two points are at distance at most $\min(s,1-s)\ell\le\ell/2$, for $0\le s\le1$. The first projection of $F$ has rank at most one and the second traces the two lattice directions. Hence \[ \bigl\langle F^*\delta_rc_1(L),[(\mathbb R/\mathbb Z)^2]\bigr\rangle=B(\mu,\lambda)\ne0. \] Theorem~\ref{fs:thm:lines} rules out a comparison. \emph{Lower bound.} Put $W=\operatorname{span}_{\mathbb R}\Lambda_0$. Since $B$ is integral, $W$ is the radical of its real extension and is rational with respect to $\Lambda$. Thus $q(\Lambda)$ is a lattice in $V/W$, and \[ q:T\longrightarrow S:=(V/W)/q(\Lambda) \] is a quotient torus. The alternating form descends to $\Lambda/\Lambda_0$, so line-bundle classification gives $L\cong q^*L'$ for a complex line $L'\to S$. Fix $r\le\ell/2$ and let $B_r^T(0)$ be the open metric ball in $T$. A point $z$ in this ball has a representative $v\in V$ with $\|v\|b/2. \end{cases} \] Each path component is contractible: the positive-definite factor in polar decomposition is contractible, and the normalized $S^1$ mapping-space components are contracted by logarithms as in Theorem~\ref{fs:thm:lines}. For completeness, the ball is a disk for $r\le a/2$ and a cylinder for $a/20$, a nonseparating degree-one lift to a finite cover in which every other simple closed geodesic has length greater than $K$. \begin{theorem}[Reconstruction from labelled radii] \label{fs:thm:reconstruction} For a primitive $\gamma\ne1$, define the metric-independent index set \[ I_\gamma=\{(H,\alpha):[\Gamma:H]<\infty,\ \gamma\in H,\ \alpha(\gamma)=1\}. \] Then \[ \ell_g(\gamma)=2\sup_{(H,\alpha)\in I_\gamma}\mathcal R_g(H,\alpha). \] The supremum is attained. Thus all the labelled radii determine the marked length spectrum. In particular, if $g,h$ have identical labelled data, there is a diffeomorphism $\phi$ isotopic to the identity such that $\phi^*h=g$. \end{theorem} \begin{proof} If $(H,\alpha)\in I_\gamma$, the lift of the geodesic representing $\gamma$ is $\alpha$-odd and has length $\ell_g(\gamma)$. By Theorem~\ref{fs:thm:half}, \[ 2\mathcal R_g(H,\alpha)=\sigma_{p_H^*g}(\alpha)\le\ell_g(\gamma). \] For the opposite inequality, first pass to a finite cover $S_1$ where $\gamma$ has a simple degree-one lift. Choose a hyperbolic metric $q$ on $S_1$ and a constant $C$ such that $\operatorname{Length}_q(c)\le C\operatorname{Length}_g(c)$ for every curve $c$; here $g$ denotes the lifted metric. The same inequality holds on every further cover. Apply Theorem~C of~\cite{fs:alvarez} to the $q$-geodesic in that simple class with $K>C\ell_g(\gamma)$. In the resulting cover there is a nonseparating degree-one lift $\widehat\gamma$. Every other simple free homotopy class has $q$-geodesic length greater than $K$, hence $g$-geodesic length greater than $K/C>\ell_g(\gamma)$. A shortest noncontractible closed geodesic is simple: splitting at a self-intersection produces a shorter noncontractible loop. It follows that $\widehat\gamma$ realizes the $g$-systole of this cover. Choose $\alpha$ with $\alpha(\widehat\gamma)=1$, possible because $\widehat\gamma$ is nonseparating. Its odd systole is then exactly $\ell_g(\gamma)$. Choose the basepoint lift so that the corresponding subgroup contains $\gamma$. This gives a pair in $I_\gamma$ attaining equality. Every nontrivial surface-group element is a power of a primitive element, and $\ell_g(\eta^k)=|k|\ell_g(\eta)$. Thus the data recover all marked lengths. The last assertion is the marked length spectrum rigidity theorem for negatively curved surfaces~\cite{fs:otal}; see also the stronger Anosov-surface result~\cite{fs:guillarmou}. \end{proof} \begin{corollary}[Exact multiplicative comparison] \label{fs:cor:multiplicative} For two such metrics on the same marked surface, \[ \sup_{H,\ \alpha\ne0}\left|\log\frac{\mathcal R_g(H,\alpha)}{\mathcal R_h(H,\alpha)}\right| =\sup_{\gamma\ne1}\left|\log\frac{\ell_g(\gamma)}{\ell_h(\gamma)}\right|. \] Both suprema are finite. \end{corollary} \begin{proof} A uniform multiplicative bound for marked lengths passes to the infimum over $\alpha$-odd classes, hence to the radii by Theorem~\ref{fs:thm:half}. Conversely, the same bound for every labelled radius passes to the supremum over $I_\gamma$ in Theorem~\ref{fs:thm:reconstruction}. The metrics are bi-Lipschitz on compact $S$, which makes both bounds finite. \end{proof} \begin{remark}[Scope of the reconstruction result] \label{fs:rem:scope} The covering and rigidity mechanisms are supplied by the cited work. Indeed, the same isolation argument proves \[ \ell_g(\gamma)=\sup_{\substack{[\Gamma:H]<\infty\\\gamma\in H}}\operatorname{sys}(S_H,p_H^*g) \quad\text{for primitive }\gamma. \] Here $\operatorname{sys}$ is the length of a shortest noncontractible closed curve. The comparison-radius formulation packages these mechanisms through line bundles; it does not assert rigidity from an unordered collection of radii, or from finitely many covers. \end{remark} \subsection{Related work} \label{fs:sec:related} The individual maps $P_{xy}$ are the linear direct connections studied by Kubarski and Teleman~\cite{fs:kubarski}, formerly called quasi-connections. Discrete principal-bundle connections provide a related framework~\cite{fs:fernandez}. The organizing emphasis here is the metric family of domains $U_r$, extension obstructions, and the full restriction system. The line-bundle criteria use classical classification~\cite[Proposition~3.10]{ref:hatcher-vb}. Persistent characteristic classes of line bundles have been studied by Tinarrage~\cite{fs:tinarrage}. Homotopic distance between maps~\cite{fs:macias} is adjacent to the comparison of the two projections, although it measures a different invariant. The real-line formula translates extension into the length of loops detected by a mod-$2$ class. Subsection~\ref{fs:sec:reconstruction} combines that formula with finite-cover isolation and marked-length rigidity results. Further questions concern higher-rank unstable obstructions, behavior at critical radii, and examples where the restriction system detects geometric features missed by ordinary characteristic classes. \section{Harmonic closure of differential forms} \label{hc:chapter} We study the real algebra generated by harmonic forms under wedge product, exterior differentiation and Hodge star. All closure operations are algebraic, not topological. \subsection{Definitions and basic properties} Throughout this section, $M^n$ is a smooth, connected, closed, oriented manifold, $n\geq2$, and $g$ is a smooth Riemannian metric. Write $\Omega^\bullet(M)$ for real smooth differential forms, $\delta_g$ for the formal $L^2$-adjoint of $d$, and \[ \Delta_g=d\delta_g+\delta_gd,\qquad \mathcal H_g^k=\ker(\Delta_g|_{\Omega^k(M)}). \] Hodge theory gives $\mathcal H_g^k\cong H_{\mathrm{dR}}^k(M)$; set $b_k=\dim H_{\mathrm{dR}}^k(M)$ and $B=\sum_{k=0}^n b_k$. \begin{definition}[Harmonic closure]\label{hc:definition} The \emph{harmonic closure} of $g$ is the smallest graded real subalgebra \[ \mathcal C_g=\langle\mathcal H_g^\bullet\rangle_{\wedge,d,*_g}\subseteq\Omega^\bullet(M) \] containing every harmonic form and preserved by $d$ and $*_g$. The metric has \emph{finite harmonic closure} if $\dim_{\mathbb R}\mathcal C_g<\infty$. \end{definition} Only real scalar coefficients are allowed: $\mathcal C_g$ is not a $C^\infty(M)$-module. Equivalently, put $V_0=\mathcal H_g^\bullet$ and \[ V_{j+1}=\operatorname{span}_{\mathbb R}\bigl(V_j\cup dV_j\cup *_gV_j\cup\{\alpha\wedge\beta:\alpha,\beta\in V_j\}\bigr). \] Then each $V_j$ is finite-dimensional and $\mathcal C_g=\bigcup_{j\geq0}V_j$. In particular, $1,\operatorname{vol}_g\in\mathcal C_g$. Since $\delta_g=\pm *_gd*_g$, both $\delta_g$ and $\Delta_g$ preserve $\mathcal C_g$. For any diffeomorphism $\phi:N\to M$, $\mathcal C_{\phi^*g}=\phi^*\mathcal C_g$; orientation reversal only changes the sign of the Hodge star. Constant rescaling does not change the embedded algebra: $\mathcal C_{c^2g}=\mathcal C_g$ for $c>0$, because the harmonic spaces are unchanged and $*_{c^2g}|_{\Omega^k}=c^{n-2k}*_g$. \begin{proposition}[Scalar criterion and pointwise bounds]\label{hc:scalar} The following conditions are equivalent: \[ \dim\mathcal C_g<\infty\quad\Longleftrightarrow\quad\mathcal C_g^0=\mathbb R\cdot1. \] If they hold, same-degree elements of $\mathcal C_g$ have constant pointwise inner products, and evaluation at every $x\in M$ is injective: \[ \operatorname{ev}_x:\mathcal C_g^k\hookrightarrow\Lambda^kT_x^*M. \] Consequently, with $c_k=\dim\mathcal C_g^k$, \[ b_k\leq c_k\leq\binom nk,\qquad c_k=c_{n-k},\qquad\dim\mathcal C_g\leq2^n. \] Every nonzero element of $\mathcal C_g^k$ has constant positive norm. If $\mathcal C_g$ is infinite, it contains a nonconstant function $f$, and $1,f,f^2,\ldots$ are linearly independent. \end{proposition} \begin{proof} In a finite-dimensional algebra of functions, the powers of any $f$ satisfy a nonzero polynomial relation $P(f)=0$. Its image is finite, so connectedness makes $f$ constant. Conversely, if $\mathcal C_g^0=\mathbb R$, then \[ \langle\alpha,\beta\rangle_g=*_g(\alpha\wedge *_g\beta)\in\mathbb R\qquad(\alpha,\beta\in\mathcal C_g^k). \] A form vanishing at one point therefore vanishes everywhere. This proves evaluation injectivity and the bounds, without initially assuming finite dimensionality. Hodge star gives $c_k=c_{n-k}$. Finally, a nonconstant smooth function on connected $M$ has an interval in its image, so its powers satisfy no nonzero polynomial relation. \end{proof} \begin{proposition}[Finite Hodge model]\label{hc:hodge-model} If $\mathcal C_g$ is finite, its inclusion in $\Omega^\bullet(M)$ is a quasi-isomorphism of differential graded algebras. There is an orthogonal decomposition \[ \mathcal C_g=\mathcal H_g^\bullet\oplus d\mathcal C_g\oplus\delta_g\mathcal C_g. \] Writing $r_k=\operatorname{rank}(d:\mathcal C_g^k\to\mathcal C_g^{k+1})$, with $r_{-1}=r_n=0$, one has \[ c_k=b_k+r_{k-1}+r_k,\qquad \varepsilon(g):=\frac{\dim\mathcal C_g-B}{2}=\sum_{k=0}^{n-1}r_k\in\mathbb Z_{\geq0}. \] Moreover, $\varepsilon(g)=0$ exactly when $g$ is geometrically formal. \end{proposition} \begin{proof} The restrictions of $d$ and $\delta_g$ are adjoint and preserve this finite-dimensional space. Finite-dimensional Hodge decomposition applies. Its harmonic subspace equals $\mathcal H_g^\bullet$, since it is defined by the same equations $d\alpha=\delta_g\alpha=0$ and contains all ambient harmonic forms. Thus inclusion identifies cohomology through the same harmonic representatives. The dimension formulas follow degreewise. Finally, $\varepsilon(g)=0$ is equivalent to $\mathcal C_g=\mathcal H_g^\bullet$, equivalently to closure of harmonic forms under wedge products, the definition of geometric formality~\cite{hc:kotschick}. \end{proof} The profile $(c_0,\ldots,c_n)$ and $\varepsilon(g)$ are scale-invariant metric invariants. One may set $\varepsilon(g)=\infty$ for infinite closure. A finite real de Rham model does not by itself imply rational ellipticity or determine integral cohomology. \subsection{Examples} \begin{example}[Cohomology spheres and flat tori]\label{hc:spheres-tori} If $M$ is a rational homology sphere, then for every metric \[ \mathcal C_g=\mathcal H_g^\bullet=\operatorname{span}_{\mathbb R}\{1,\operatorname{vol}_g\},\qquad\dim\mathcal C_g=2. \] On a flat $n$-torus all harmonic forms are parallel; they are precisely the constant forms on the universal cover. Hence $\mathcal C_g=\mathcal H_g^\bullet$ has dimension $2^n$. Both examples have $\varepsilon(g)=0$. \end{example} \begin{example}[The Heisenberg three-manifold]\label{hc:heisenberg} Let $M$ be a compact Heisenberg quotient with global coframe \[d\alpha=d\beta=0,\qquad d\gamma=\alpha\wedge\beta.\] Make this coframe orthonormal and orient by $\alpha\wedge\beta\wedge\gamma$. The harmonic forms are \[ \mathcal H_g^\bullet=\operatorname{span}_{\mathbb R}\{1,\alpha,\beta,\alpha\wedge\gamma,\beta\wedge\gamma,\alpha\wedge\beta\wedge\gamma\}. \] Indeed, these forms are closed and coclosed; invariant cohomology and Nomizu's theorem~\cite{hc:nomizu} show that they account for all cohomology classes. Since $*_g(\alpha\wedge\beta)=\gamma$, \[ \mathcal C_g=\Lambda^\bullet\operatorname{span}_{\mathbb R}\{\alpha,\beta,\gamma\},\qquad\dim\mathcal C_g=8,\qquad\varepsilon(g)=1. \] This metric is not geometrically formal: $\alpha\wedge\beta=d\gamma$ is nonzero and exact. The triple Massey product $\langle[\alpha],[\alpha],[\beta]\rangle$ is represented by $\pm\alpha\wedge\gamma$, with zero indeterminacy and nonzero value. \end{example} \begin{example}[An infinite closure on the two-torus]\label{hc:infinite-torus} On $T^2=\mathbb R^2/\mathbb Z^2$, take $g=e^{2u(x,y)}(dx^2+dy^2)$ with $u$ smooth and nonconstant. Hodge star on one-forms is conformally invariant, so $dx,dy$ remain harmonic, while \[*_g(dx\wedge dy)=e^{-2u}\in\mathcal C_g^0.\] Proposition~\ref{hc:scalar} gives $\dim\mathcal C_g=\infty$. Also, an oriented surface of genus $q\geq2$ has $b_1=2q>2$, so it admits no finite-closure metric. \end{example} \begin{proposition}[Homogeneous examples]\label{hc:homogeneous} Every compact oriented Riemannian manifold admitting a connected transitive group of isometries has finite harmonic closure. \end{proposition} \begin{proof} Each group element is isotopic to the identity and hence acts trivially on cohomology. It preserves harmonic forms, so uniqueness of harmonic representatives makes them invariant. Invariant forms constitute a finite-dimensional algebra preserved by $d$ and $*_g$; it contains $\mathcal C_g$. \end{proof} \subsection{Lie algebra and reconstruction} \begin{theorem}[Canonical infinitesimal action]\label{hc:action} Suppose $\mathcal C_g$ is finite, and set \[\mathfrak l_g=\{\alpha^\sharp:\alpha\in\mathcal C_g^1\},\qquad r=\dim\mathcal C_g^1.\] Then $\mathfrak l_g$ is an $r$-dimensional Lie algebra of vector fields whose evaluation has rank $r$ at every point. Its fields preserve volume and integrate to a locally free action of a simply connected Lie group. Contraction and Lie derivative by these fields preserve $\mathcal C_g$. The action need not be isometric. \end{theorem} \begin{proof} For $\alpha\in\mathcal C_g^1$, $\delta_g\alpha$ is constant and $\langle\delta_g\alpha,1\rangle_{L^2}=\langle\alpha,d1\rangle_{L^2}=0$; thus $\delta_g\alpha=0$. For one-forms one has \[ \delta_g(\alpha\wedge\beta)=(\delta_g\alpha)\beta-(\delta_g\beta)\alpha-[\alpha^\sharp,\beta^\sharp]^\flat. \] Hence $\mathfrak l_g$ is bracket-closed. Evaluation injectivity follows from Proposition~\ref{hc:scalar}; coclosedness is equivalent to zero divergence. Compactness makes all fields complete, and the integration theorem for complete finite-dimensional Lie algebra actions gives the locally free action. Finally, $\iota_{\alpha^\sharp}\omega=\pm *_g(\alpha\wedge *_g\omega)$ preserves $\mathcal C_g$, and Cartan's formula gives the assertion for Lie derivatives. \end{proof} \begin{corollary}[Full rank]\label{hc:full-rank} If $r=n$, then $\mathcal C_g=\Lambda^\bullet(\mathcal C_g^1)$ and $(M,g)$ is isometric to $\Gamma\backslash G$ with a metric descended from a left-invariant metric on a simply connected Lie group $G$, where $\Gamma$ is discrete and cocompact. Furthermore, finite closure never has $r=n-1$. \end{corollary} \begin{proof} Constant inner products give a global orthonormal coframe $\theta^1,\ldots,\theta^n$ in $\mathcal C_g^1$. Its wedges, together with evaluation injectivity, exhaust $\mathcal C_g$; thus \[d\theta^i=\sum_{j1$ and, on smooth closed representatives of $a$, define \[E_g(\omega)=\int_M|\omega|_g^p\,dV_g.\] If $\alpha$ is harmonic with $|\alpha|_g\equiv c>0$, then for $\omega=\alpha+d\eta$, strict convexity gives \[E_g(\omega)\geq E_g(\alpha)+pc^{p-2}\int_M\langle\alpha,d\eta\rangle_g\,dV_g=E_g(\alpha),\] with equality only for $\omega=\alpha$. Thus $\alpha$ uniquely minimizes $E_g$. Since $|\omega|_h=e^{-ku}|\omega|_g$ and $dV_h=e^{nu}dV_g$, one has $E_h=E_g$. The two harmonic representatives are therefore equal. Their constant positive norms satisfy $c_h=e^{-ku}c_g$, forcing $u$ to be constant. \end{proof} \begin{corollary}[Conformal uniqueness and symmetries]\label{hc:conformal} Suppose $M$ is not a rational homology sphere. Then each conformal class contains at most one finite-closure metric up to constant scaling. Every nonconstant conformal rescaling of a finite-closure metric has infinite closure. Every conformal self-diffeomorphism of a finite-closure metric is an isometry. \end{corollary} \begin{proof} Some intermediate cohomology class is nonzero. Proposition~\ref{hc:scalar} and Theorem~\ref{hc:rigidity} apply to its harmonic representatives. For a conformal self-map $\phi$, naturality gives finite closure for $\phi^*g$, so $\phi^*g=c^2g$. Equality of total volumes, viewed as densities, gives $c=1$. \end{proof} \begin{theorem}[Closedness and generic infinitude]\label{hc:closedness} The finite-closure locus \[\mathcal F(M)=\{g\in\operatorname{Met}^\infty(M):\dim\mathcal C_g<\infty\}\] is closed in the $C^\infty$ topology. If $M$ is not a rational homology sphere, $\mathcal F(M)$ is nowhere dense and its complement is open dense. For a rational homology sphere, $\mathcal F(M)=\operatorname{Met}^\infty(M)$. \end{theorem} \begin{proof} Suppose $g_j\to g$ smoothly with $g_j\in\mathcal F(M)$. Fix a basis of cohomology. Standard elliptic dependence of harmonic projections implies that its $g_j$-harmonic representatives converge smoothly to the $g$-harmonic representatives. Every fixed finite expression in these forms using $d,\wedge,*_{g_j}$ therefore converges smoothly. If $\mathcal C_g$ were infinite, $2^n+1$ such expressions could be chosen independently. Their Gram determinant in a fixed background $L^2$ inner product stays positive for large $j$, contradicting $\dim\mathcal C_{g_j}\leq2^n$. This proves closedness; the $C^\infty$ topology here is metrizable. When intermediate cohomology is nonzero, arbitrarily small nonconstant conformal perturbations leave $\mathcal F(M)$ by Corollary~\ref{hc:conformal}, so it has empty interior. The remaining case was computed in the first example. \end{proof} \subsection{Low-dimensional consequences} \begin{proposition}[Dimension three]\label{hc:dimension-three} For a closed, connected, oriented three-manifold, the finite-closure metrics are exactly as follows. \begin{center} \begin{tabularx}{\linewidth}{@{}cXc@{}} \toprule $b_1(M)$ & Condition on $g$ & $\dim\mathcal C_g$\\ \midrule $0$ & Every metric. & $2$\\ $1$ & A nonzero harmonic one-form has constant length. & $4$\\ $2$ & A descended left-invariant metric on a compact Heisenberg quotient, up to isometry. & $8$\\ $3$ & A flat torus metric. & $8$\\ $>3$ & No such metric. & ---\\ \bottomrule \end{tabularx} \end{center} \end{proposition} \begin{proof} The bound gives $b_1\leq3$. By Hodge star, $\mathcal C_g^2=*\mathcal C_g^1$; the excluded rank $n-1$ gives $r=\dim\mathcal C_g^1\in\{0,1,3\}$. If $b_1=0$, only degrees zero and three have harmonic forms. If $b_1=1$, write its generator as $\alpha$; constant length makes $\operatorname{span}_{\mathbb R}\{1,\alpha,*\alpha,\operatorname{vol}_g\}$ an algebra, proving both directions. If $b_1=2$, choose pointwise orthonormal harmonic forms $\alpha,\beta$, and put $\gamma=*(\alpha\wedge\beta)$. Corollary~\ref{hc:full-rank} makes their structure coefficients constant. The equations $d\alpha=d\beta=0$ and $d*\alpha=d*\beta=0$ force $d\gamma=c\,\alpha\wedge\beta$. Here $c\neq0$, since otherwise all three forms would be harmonic. These are Heisenberg structure equations; the converse follows from Theorem~\ref{hc:nilmanifold}. If $b_1=3$, the harmonic orthonormal coframe is closed, giving a flat torus. Its converse is immediate. \end{proof} \begin{proposition}[A four-dimensional reduction]\label{hc:dimension-four} If $n=4$ and $\chi(M)\neq0$, then $g$ has finite harmonic closure if and only if it is geometrically formal. In particular this applies to closed simply connected four-manifolds. \end{proposition} \begin{proof} A nonzero element of $\mathcal C_g^1$ would have nowhere-zero metric dual, contradicting $\chi(M)\neq0$. Thus $\mathcal C_g^1=\mathcal C_g^3=0$. The differential vanishes on $\mathcal C_g$, and Proposition~\ref{hc:hodge-model} gives geometric formality. The converse is automatic. For a simply connected closed four-manifold, $\chi(M)=2+b_2(M)>0$. \end{proof} \subsection{Related work} Geometric formality~\cite{hc:kotschick} is exactly $\mathcal C_g=\mathcal H_g^\bullet$. Constant-length harmonic forms and nilmanifold rigidity were studied in~\cite{hc:nagy}; the high-$b_1$ conclusions above overlap that theory. Nomizu's theorem~\cite{hc:nomizu} supplies the invariant cohomology model. 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