\section{The half-plane coboundary} \label{sec:coboundary} \begin{theorem}[Exact reverse-complement defect] \label{thm:coboundary} For every length-$k$ word $w$, \begin{equation} m_0(\RC w)-m_0(w) =\chi(\tail(w))-\chi(\head(w)) =(\nabla\chi)(w). \label{eq:coboundary} \end{equation} Equivalently, $\ind_{\RC(M_0)}-\ind_{M_0}=\nabla\chi$. \end{theorem} \begin{proof} Put $A=\operatorname{Im}P_s(w)$ and $B=\operatorname{Im}P_s(Rw)$. Lemma~\ref{lem:covariance} sends the ordered imaginary coordinates of $\RC(w)$ to $(B,A)$. If $A$ and $B$ are nonzero, the selector rule gives \[ m_0(\RC w)-m_0(w) =\ind[B<00]-\ind[B>0]. \] The ray cases fix the sign convention. If $A=0$, write $P_s(w)=r\in\mathbb R$. Then $B=-r\sin(2\pi/k)$: for $r<0$ both sides are $-1$, and for $r>0$ both are zero. If $B=0$, write $P_s(Rw)=r\in\mathbb R$: for $r>0$ both sides are $+1$, and for $r<0$ both are zero. When $k>2$, simultaneous vanishing of $A$ and $B$ with $P_s(w)\neq0$ is impossible. In the zero sector, the chosen ties are equivariant, while both lower imaginary coordinates vanish. Finally, Lemma~\ref{lem:covariance} identifies the sign difference with $\chi(\tail(w))-\chi(\head(w))$ under convention~\eqref{eq:gradient}. \end{proof} The open upper half-plane and the negative-real-axis convention are load-bearing. Equation~\eqref{eq:coboundary} is a literal edgewise identity, not an averaged symmetry statement.