\subsection{Differentiation of the terminal passage} \label{sec:terminal-variation} The auxiliary height separates two parts of a single orbit. Its choice can therefore be held fixed when differentiating the full terminal return. We first establish this local independence, including ordinary neighborhoods of the initial data. We then estimate the outgoing derivatives. Although the outgoing clock interval grows like $\log(1/\alpha)$, its integrated Jacobian is bounded. First derivatives consequently remain bounded, while second derivatives grow at most linearly in the clock length. Write $Y=(R,u,w)$ for the downward-exit parameters. Make the height dependence in Section~\ref{sec:terminal-passage} explicit by setting $z(h,Y)=\mathsf C_p y_h(Y)$ and \begin{equation} \begin{aligned} \mathcal T(h,Y)&=S_h(Y)+T_{\rm in}(z(h,Y)),\\ \mathcal E(h,Y)&=\mathcal P(z(h,Y)). \end{aligned} \label{eq:terminal-height-maps} \end{equation} All the time variables in this definition are original normalized times. \subsubsection{Local independence of the section height} \begin{lemma}[The height can be held fixed] \label{lem:terminal-height-freezing} At every positive-wall input in Proposition~\ref{prop:terminal-first-arrival}, put $Y_0=(2+2\alpha,u,w)$ and $h_0=\eta\alpha^J$. The functions $\mathcal T$ and $\mathcal E$ are jointly $C^2$ near $(h_0,Y_0)$. On a neighborhood of that point, \begin{equation} \mathcal T(h,Y)=\mathcal T(h_0,Y),\qquad \mathcal E(h,Y)=\mathcal E(h_0,Y). \label{eq:terminal-local-height-independence} \end{equation} In particular, their height derivatives vanish. For any function $a$ continuous at $Y_0$ with $a(Y_0)=h_0$, the maps $\mathcal T(a(Y),Y)$ and $\mathcal E(a(Y),Y)$ agree near $Y_0$ with their fixed-height versions and are $C^2$ there. \end{lemma} \begin{proof} Consider first the outgoing event equation $V(\phi_t x(Y))-h=0$, where $x(Y)$ is the normalized state corresponding to $y_-(Y)$. Its time derivative is strictly negative at $t=S_{h_0}(Y_0)$. The implicit function theorem, with $(h,Y)$ as parameters, gives a jointly $C^2$ event time. The chart and strict negativity of $dV/dt$ persist on the whole compact segment, including a small extension beyond its endpoints. For nearby $(h,Y)$, they therefore persist up to the moving event time. The event is still the first arrival at $V=h$. Hence this local implicit time equals $S_h(Y)$, and its state is jointly $C^2$. The cyclic denominator is positive at the endpoint. Moreover, all incoming conditions hold there with strict margins. In particular, \eqref{eq:terminal-entrance-smallness} and $k^q\geq1$ give \[ 07/4,\qquad m_e>1. \] They persist near $(h_0,Y_0)$. The rational cyclic map and the incoming arrival are thus $C^2$ throughout a smaller neighborhood, which proves joint regularity in~\eqref{eq:terminal-height-maps}. We also need to identify these nearby compositions as physical first arrivals. Along the original outgoing segment, the cyclic chart is positive and its active wall is less than one. These are open conditions on a compact segment. By continuity of the flow and of $S_h(Y)$, they continue to hold up to the nearby moving endpoint. The incoming segment then stays below its own arrival section until its first crossing. The proof of Proposition~\ref{prop:terminal-first-arrival} applies to every point of this neighborhood. Thus $\mathcal T(h,Y)$ and $\mathcal T(h_0,Y)$ are both the first positive arrival time of the same cyclic orbit at $V=1$. They are equal, and their states are equal as well. This proves~\eqref{eq:terminal-local-height-independence}. For fixed $Y_0$ the two functions are locally constant in $h$, so their height derivatives vanish. Finally, $Y\mapsto(a(Y),Y)$ is continuous at $Y_0$ and takes that point to $(h_0,Y_0)$. Equation~\eqref{eq:terminal-local-height-independence} therefore holds along this graph near $Y_0$. The fixed-height functions are $C^2$, giving the last assertion without any differentiability requirement on $a$. \end{proof} For the choice used in the terminal passage, $a(R,u,w)=\eta((R-2)/2)^J$. The lemma identifies its derivatives with those computed at fixed numerical height. The same local identity also gives zero derivative with respect to the logarithmic height $\ell$ when $h=e^{-\ell}$. Uniform estimates over a range of heights follow by stopping one longer outgoing segment earlier. This avoids choosing a different initial neighborhood for each height. \begin{lemma}[Uniformity above a lower height] \label{lem:terminal-height-uniform} Fix $0<\eta_0\leq1/100$ and $J\geq2$. The constants $C_*$ and $\varepsilon$ in Lemma~\ref{lem:terminal-cycle-entrance} can be chosen to work simultaneously for every $\eta\in[\eta_0,1/100]$. If $q+2\leq J$ and $0<\varepsilon_{\rm in}\leq10^{-4}$ are also fixed, then one input threshold gives all the conclusions of Proposition~\ref{prop:terminal-first-arrival} for every \begin{equation} \eta_0\leq\eta\leq \min\left(\frac1{100}, \frac{\varepsilon_{\rm in}}{4(11/5)^q}\right). \label{eq:terminal-height-interval} \end{equation} The local height independence of Lemma~\ref{lem:terminal-height-freezing} holds at each such input and height. \end{lemma} \begin{proof} Construct the outgoing segment down to $h_0=\eta_0\alpha^J$. Its strictly decreasing active wall crosses each $h=\eta\alpha^J$ with $\eta\geq\eta_0$ and $\eta<1$ exactly once no later than that endpoint. The intermediate value theorem gives the crossing, and strict decrease proves its first-arrival property. Thus \begin{equation*} S_{\eta\alpha^J}(Y)\leq S_{\eta_0\alpha^J}(Y). \end{equation*} All estimates along the longer segment apply up to the earlier endpoint. Reduce $\varepsilon$ so that $C_*\varepsilon\leq1/10000$. Then, with the fixed constant $C_*$ from that segment, \[ |\rho-R_0|\leq C_*b,\qquad |U|+|W|\leq C_*b,\qquad C_*b\leq\alpha^{2J}/10000. \] At the earlier endpoint, $V=\eta\alpha^J\leq\alpha/100$. The algebra in Lemma~\ref{lem:terminal-cycle-entrance} therefore gives exactly the same denominator and radius bounds, and the same wall bounds with this value of $\eta$. For the weighted incoming walls, reduce $\varepsilon$ so that $C_*\varepsilon\leq\varepsilon_{\rm in}/[4(11/5)^q]$. The proof of~\eqref{eq:terminal-entrance-smallness} is then uniform over~\eqref{eq:terminal-height-interval}. The entire cyclic outgoing segment still has active wall at most $1/5000$, since it is a subsegment of the longer one. Composition with the incoming passage gives the actual first arrival. The strict margins used in Lemma~\ref{lem:terminal-height-freezing} hold at each input, proving its local conclusion as well. \end{proof} \subsubsection{The Jacobian along the outgoing segment} Let $Y=(\rho,U,W)$ and regard $V$ as a prescribed clock value. Write the vector field in~\eqref{eq:terminal-outgoing-field} as \[ f_V(Y)=\bigl(f,a_U U,a_W W\bigr),\qquad f=\frac{-C\rho-g(U-W)^2/\rho}{q_-}. \] All derivatives in these estimates hold $V$ fixed. Norms on $\R^3$ are maximum norms, with their induced operator norms. \begin{lemma}[An integrable Jacobian] \label{lem:terminal-jacobian} On the signed region~\eqref{eq:terminal-clock-region}, with $\beta=|U|+|W|$, \begin{equation} \|D_Y f_V\|\leq |a_U|+|a_W|+2048(V+\beta). \label{eq:terminal-jacobian-norm} \end{equation} The field and its first two state derivatives are uniformly bounded on this region, including at $V=0$. \end{lemma} \begin{proof} The small factors in the radial row and in the off-diagonal wall entries are visible before taking norms. Put $c_U=V+W-2U$. Quotient differentiation gives \begin{align*} \partial_\rho f &=\frac{-C-(1/g-g/\rho^2)(U-W)^2-f\rho/g}{q_-},\\ \partial_U f &=\frac{-c_U\rho-2g(U-W)/\rho-fc_U}{q_-},\\ \partial_W f &=\frac{-U\rho+2g(U-W)/\rho-fU}{q_-}. \end{align*} The corresponding rate derivatives are \begin{align*} \partial_\rho a_U&=\frac{\rho/g-\rho-a_U\rho/g}{q_-},& \partial_\rho a_W&=\frac{(1-a_W)\rho/g}{q_-},\\ \partial_U a_U&=\frac{U-a_Uc_U}{q_-},& \partial_U a_W&=-\frac{(1+a_W)c_U}{q_-},\\ \partial_W a_U&=\frac{V-W-a_UU}{q_-},& \partial_W a_W&=-\frac{(1+a_W)U}{q_-}. \end{align*} To bound them, use $q_-\geq1/2$, $g\geq1$, $1\leq\rho\leq5$, $g/\rho\leq1$, $\rho/g\leq5$, and \[ |c_U|\leq V+2\beta,\qquad |1/g-g/\rho^2|\leq2. \] Equation~\eqref{eq:terminal-perturbation-rates} and $\beta\leq1/50$ give $|f|\leq1$ and $|a_U|,|a_W|\leq32$. Keeping the sharper bound $|f|\leq20(|U|V+\beta^2)$ in the radial derivative gives \begin{align} |\partial_\rho f|&\leq256(|U|V+\beta^2),& |\partial_U f|&\leq32(V+\beta),& |\partial_W f|&\leq16\beta,\notag\\ |\partial_\rho a_j|&\leq512,& |\partial_U a_j|,\ |\partial_W a_j| &\leq256(V+\beta),&& j=U,W. \label{eq:terminal-gradient-bounds} \end{align} For example, the three numerator terms in $\partial_\rho f$ are bounded by $H$, $2\beta^2$ and $100H$, respectively, where $H=|U|V+\beta^2$. Division by $q_-\geq1/2$ gives the stated $256H$. The other bounds follow from the same displayed formulas: the radial $U$ numerator is at most $6V+14\beta$, and the radial $W$ numerator at most $8\beta$; the rate numerators are bounded by $256$ in the radial direction and $128(V+\beta)$ in either wall direction. The Jacobian entries in a wall row retain the factor of that wall: \[ D(a_UU)[\xi]=U\,Da_U[\xi]+a_U\xi_U,\qquad D(a_WW)[\xi]=W\,Da_W[\xi]+a_W\xi_W. \] Since $H\leq V+\beta$ and $V+\beta\leq2$, the sum of absolute values in the radial row is at most $512(V+\beta)$, while each rate gradient has row sum at most $1536$. Each wall row is consequently bounded by $|a_j|+1536\beta$. Taking the maximum of the three row sums proves \eqref{eq:terminal-jacobian-norm}. For the second derivatives, consider the compact box \[ 7/4\leq\rho\leq17/4,\qquad |U|,|W|\leq1/100,\qquad0\leq V\leq1. \] On it, $\rho^2-V^2$ is bounded away from zero, $\rho>0$, and $q_-\geq1/2$. The formulas defining $f_V$ are therefore smooth on a neighborhood of the box. Their derivatives through order two are continuous there and have a finite common bound. \end{proof} Fix $\eta_0\in(0,1)$ and $J\geq1$, and set $L_0=\log(1/\eta_0)+J\log(1/\alpha)$. For the outgoing orbit constructed at this lowest height, denote its clock state by $Y(\sigma)$ and its state Jacobian by $L_Y(\sigma)=D_Y f_{e^{-\sigma}}(Y(\sigma))$. The pointwise bounds~\eqref{eq:terminal-boundary-rate-bound} and~\eqref{eq:terminal-perturbation-rates} give, for $T\leq L_0$, \begin{align} \int_0^T |a_j|\dd\sigma &\leq\mathcal R(T),\notag\\ \mathcal R(T) &=10\alpha T+800BbT+100(Bb)^2T+100Bb+5. \label{eq:terminal-absolute-rate-integral} \end{align} Here $B$ is chosen using $\eta_0$ as in Lemma~\ref{lem:terminal-outgoing}. Integrating \eqref{eq:terminal-jacobian-norm} now yields \begin{equation} \int_0^T\|L_Y(\sigma)\|\dd\sigma \leq2\mathcal R(T)+2048(1+BbT). \label{eq:terminal-integrated-jacobian} \end{equation} With the same smallness bounds as before, $\mathcal R(T)\leq10K+6$, where $K=\log(1/\eta_0)+J/e$. Reducing the input threshold if necessary also gives $bT\leq1$. Thus the right-hand side is at most \begin{equation} B_*=2(10K+6)+2048(1+B), \label{eq:terminal-jacobian-budget} \end{equation} uniformly in $\alpha$, the signed wall inputs, and the duration $T\leq L_0$. For fixed $h$, express the outgoing state in its radius and two small walls: \begin{equation} E_h(Y)=\bigl(H(M_h-1,h),U_h,W_h\bigr). \label{eq:terminal-outgoing-radius-map} \end{equation} The active wall has the fixed value $h$ at this event. \begin{proposition}[First and second outgoing derivatives] \label{prop:terminal-outgoing-derivatives} Fix $0<\eta_0<1$ and $J\geq1$. There are $C>0$ and $\varepsilon>0$ such that, for \begin{equation} 0<\alpha\leq1,\qquad 01/\alpha$. Thus every one of these actual cyclic endpoints satisfies \eqref{eq:terminal-incoming-phase-bounds}, with one constant $A_1$. These estimates retain the growing-wall factor $v_e$. To obtain derivatives in the original exit parameters, the remaining step is to control the cyclic entrance coordinates and their stable radial phase.