\subsection{Phase after the terminal connection} \label{sec:terminal-phase-value} A terminal exit of radius $R_0=2+2\alpha$ leads to a new core whose radius is close to $2/\alpha$. The cyclic entrance already has this scale, but its ordinary radius still depends on the auxiliary height. The stable phase removes that dependence exactly on the reference orbit. Comparing at the same height then gives the phase error for a perturbed orbit. We first record the resulting value and wall estimates. Retain the actual terminal arrival $\mathcal E(h,Y)$ from \eqref{eq:terminal-height-maps}, and write \[ Y=(2+2\alpha,u,w),\qquad h=\eta\alpha^J,\qquad y_+=\mathcal E(h,Y),\qquad \kappa=H(M_+-1,1). \] \begin{proposition}[The next core and its phase] \label{prop:terminal-phase-value} Fix $0<\varepsilon_{\rm in}\leq10^{-4}$ and integers $q\geq16$, $J\geq q+2$. Choose \begin{equation} 0<\eta\leq \min\left(\frac1{100}, \frac{\varepsilon_{\rm in}}{4(11/5)^q}\right). \label{eq:terminal-value-height} \end{equation} There are $C\geq1$ and $\varepsilon>0$ such that, whenever \begin{equation} 0<\alpha\leq1,\qquad 02$. \end{proposition} The last condition ensures that the arrival lies in the core domain for the next era. The wall estimates will carry a radius-dependent smallness condition through successive eras. \subsubsection{The reference phase} On the boundary with only the strong wall present, the stable system~\eqref{eq:stable-boundary-field} reduces to \[ \dot m=mu^2,\qquad \dot u=\frac{1-m^2+u^2}{2}u,\qquad w=0. \] Its conserved quantity is \begin{equation} I(m,u)=\frac{1+m^2+u^2}{m},\qquad \lambda_+(I)=\frac{I+\sqrt{I^2-4}}2. \label{eq:terminal-strong-invariant} \end{equation} \begin{lemma}[The strong-wall boundary limit] \label{lem:terminal-strong-limit} For $m\geq2$ and $|u|\leq1/200$, \begin{equation} P(m,u,0)=\lambda_+(I(m,u)). \label{eq:terminal-strong-projection} \end{equation} For $0<\alpha\leq1$ and $0\leq v\leq\alpha^2/400$, set \[ R_0=2+2\alpha,\qquad y_0=\bigl(1-\sqrt{R_0^2-v^2},0,v,0\bigr),\qquad z_0=\mathsf C_p y_0. \] Then \begin{equation} P((z_0)_M,(z_0)_U,0)=1+\frac2\alpha,\qquad \widehat\rho(z_0)=\frac2\alpha. \label{eq:terminal-reference-radius} \end{equation} \end{lemma} \begin{proof} The derivative of $I$ along the displayed two-dimensional system vanishes: \[ \left(1-\frac{1+u^2}{m^2}\right)mu^2 +\frac{2u}{m}\frac{1-m^2+u^2}{2}u=0. \] The same identity holds in original time, since the time change multiplies both components by the same positive factor. Proposition~\ref{prop:stable-phase-limit} keeps $m(t)>1$ and gives $(m(t),u(t))\to(P,0)$ with $P>1$. Passing to the limit in $I$ yields \[ P^2-I(m,u)P+1=0. \] Moreover, $I(m,u)-2=((m-1)^2+u^2)/m>0$. The two roots are positive, their product is one, and exactly one exceeds one. This proves \eqref{eq:terminal-strong-projection}. For the cyclic reference point, put $g_0=\sqrt{R_0^2-v^2}$ and \[ \mathcal H_0=(2-g_0)^2+v^2=R_0^2+4-4g_0. \] The cyclic formula gives \begin{equation*} m_0=\frac{R_0^2-4}{\mathcal H_0},\qquad u_0=\frac{4v}{\mathcal H_0},\qquad v_0=w_0=0. \end{equation*} Since $v\leq\alpha/100$, the endpoint algebra in the proof of Lemma~\ref{lem:terminal-cycle-entrance} gives \[ 1.99\alpha1.9/\alpha$ and $0\leq u_0\leq2v/\alpha^2\leq1/200$. Thus~\eqref{eq:terminal-strong-projection} applies. The identity $g_0^2+v^2=R_0^2$ gives \[ \mathcal H_0^2+(R_0^2-4)^2+16v^2 =\bigl(2(R_0^2-4)+16\bigr)\mathcal H_0. \] Substitution into~\eqref{eq:terminal-strong-invariant} therefore gives \begin{equation} I(m_0,u_0)=2+\frac{16}{R_0^2-4},\qquad \lambda_+(I(m_0,u_0))=\frac{R_0+2}{R_0-2} =1+\frac2\alpha. \label{eq:terminal-reference-invariant} \end{equation} For the second equality, the displayed fraction exceeds one and satisfies the defining quadratic, so it is the upper root. Since $v_0=0$, the stable radial phase is $P(m_0,u_0,0)-1$, which proves~\eqref{eq:terminal-reference-radius}. \end{proof} On the actual outgoing orbit with $u=w=0$, the radius is constant: the radial equation in~\eqref{eq:terminal-outgoing-field} has zero right-hand side. Thus its state at $V=h$ is exactly the point $y_0$ above with $v=h$. For $J\geq2$ and $\eta\leq1/400$, the reference stable radius is consequently $2/\alpha$ at every chosen height $h=\eta\alpha^J$. We shall use the stable phase on the signed strip \begin{equation} \mathcal S=\{(m,u,w):m\geq2,\ |u|,|w|\leq1/400\}. \label{eq:terminal-stable-strip} \end{equation} There is a constant $L\geq1$ such that \begin{equation} \|DP\|\leq L,\qquad |P(X)-P(X_0)|\leq L\|X-X_0\|,\qquad X,X_0\in\mathcal S. \label{eq:terminal-stable-lipschitz} \end{equation} Here and below the finite-dimensional norms are maximum norms. Indeed, \eqref{eq:stable-phase-differential} bounds $DP$ independently of $m$ whenever $|u|+|w|<1/100$. Integrate this bound along the line segment joining $X_0$ to $X$, which stays in $\mathcal S$. This argument also includes its zero-wall faces. \begin{lemma}[Stable radius at the cyclic entrance] \label{lem:terminal-stable-comparison} Suppose \begin{equation} \begin{gathered} 0<\alpha\leq1,\qquad 0\leq E\leq\alpha^2/10000,\qquad |\rho-(2+2\alpha)|\leq E,\\ |U|+|W|\leq E,\qquad 0\leq v\leq\alpha^2/1000. \end{gathered} \label{eq:terminal-comparison-domain} \end{equation} For $y=(1-\sqrt{\rho^2-v^2},U,v,W)$, \begin{equation} \left|\widehat\rho(\mathsf C_p y)-\frac2\alpha\right| \leq\frac{42LE}{\alpha^2}. \label{eq:terminal-stable-comparison} \end{equation} In particular, for fixed $0<\eta\leq1/1000$ and $J\geq2$, there are $C\geq1$ and $\varepsilon>0$ such that \begin{equation} \left|\widehat\rho(\mathsf C_p y_h(Y))-\frac2\alpha\right| \leq\frac{Cb}{\alpha^2} \label{eq:terminal-actual-stable-comparison} \end{equation} whenever $0<\alpha\leq1$, $00$. Indeed, $u_e+w_e\leq1$, $u_e\leq1$, $00$. The identity \begin{equation*} \frac2\kappa-\alpha =-\frac{\alpha}{\kappa}\left(\kappa-\frac2\alpha\right) \end{equation*} and $\alpha/\kappa\leq\alpha^2$ prove the bounded phase estimate in~\eqref{eq:terminal-value-bounds}. If $Cb<1-\alpha$, its upper bound gives $2/\kappa<1$, hence $\kappa>2$. For the walls, the incoming radius control and decay give \begin{equation} \frac{99}{100}k\leq\kappa\leq\frac{101}{100}k,\qquad 00$ such that, for \begin{equation} \begin{gathered} \eta_0\leq\eta\leq1/1000,\qquad0<\alpha\leq1,\\ 00$. For arbitrary signed $v$, put $r=H(\chi,v)$. Then \begin{equation*} dr=\frac{\chi\,dP+v\,dv}{r},\qquad \chi/r\leq1,\qquad |v|/r\leq1. \end{equation*} Equation~\eqref{eq:terminal-stable-lipschitz} bounds the derivative of $(m,u,v,w)\mapsto(r,u,v,w)$ by $L+1$. This map is locally $C^2$ because $P$ is $C^2$ and $r>0$. At the actual cyclic endpoint, the estimates of Lemma~\ref{lem:terminal-height-uniform} give $m_e>2$, $|u_e|\leq2\eta\leq1/400$ and $|w_e|\leq2C_*b/\alpha^2\leq1/400$, after decreasing $\varepsilon$. Thus the signed radial bound applies. Composition proves~\eqref{eq:terminal-cyclic-derivative-bounds} for $\widehat Z_h$ and its $C^2$ regularity. \end{proof} One consequence is useful when varying the phase while keeping a numerical height fixed. For $J\geq2$, choose $\eta>0$ with $2\eta\leq1/1000$ and set $h=\eta\alpha_0^J$, where $\alpha_0>0$. If \begin{equation} 0<\alpha\leq1,\qquad \left|\log\frac{\alpha}{\alpha_0}\right|<\frac{\log2}{J}, \qquad 0