\subsection{The radius at the next core} \label{sec:entrance-physical-radius} The stable radial coordinate controls the passage through a long incoming segment. At the next core, the return map is expressed in the core radius $\rho=H(M-1,V)$. The difference between these two radii is quadratic in the output walls. Retaining those walls in the chain rule makes the conversion uniform in the waiting time. Use the input coordinates and arrival map of Section~\ref{sec:entrance-variation}, and define \begin{equation} F(z)=\rho\bigl(\mathcal P(\Psi(z))\bigr),\qquad z=(r,u,v,w). \label{eq:entrance-physical-return} \end{equation} All derivatives below are in these input coordinates, with $k=H(m-1,v)$ fixed at the reference point. \begin{proposition}[Physical arrival estimates] \label{prop:entrance-physical-bounds} There are universal constants $C>0$ and $0<\varepsilon\leq10^{-4}$ such that, if \[ k\geq7/4,\qquad m\geq1,\qquad 00$. The output remains in the incoming region with reference radius $k$, so this is the same $k$ as in the input estimates. \begin{proof}[Proof of Proposition~\ref{prop:entrance-physical-bounds}] Choose a common constant $A\geq1$ for the phase and logarithmic wall estimates in Propositions~\ref{prop:entrance-three-columns} and~\ref{prop:entrance-active-column}. Decrease $\varepsilon$ to their common threshold. The regularity of the actual arrival and the positivity of its radius give the stated $C^2$ regularity. The value estimate is Proposition~\ref{prop:incoming-phase-value}. It remains to convert the four derivative columns. For the radial column, put $H=uv+(vw)^2\leq2$. Then \[ |Q_r|\leq1+2A,\qquad |(\ell_U)_r|\leq AL,\qquad |(\ell_W)_r|\leq AL/k^2. \] Using Lemma~\ref{lem:entrance-terminal-products} in \eqref{eq:entrance-terminal-correction}, we obtain \begin{align*} |E_r| &\leq\frac T{k^2} \left[2(1+2A)(uv+S)+A\{9uv+(L/k)S\}\right]\\ &\leq\frac{T(2+13A)}{k^2} \bigl[uv+(1+L/k)S\bigr]. \end{align*} Adding $|Q_r-1|\leq AH/k^2$ proves \eqref{eq:entrance-physical-radial}. For the wall columns, define \[ J_0=uv+v^2w(1+\omega),\qquad K_0=u+vw^2. \] The endpoint products imply \begin{gather*} \frac{b_+^2}{k^2}\leq4,\qquad b_+^2\leq4v,\qquad b_+^2\leq2J_0,\\ \frac{b_+U_+}{u}\leq2v,\qquad \frac{b_+W_+}{w}\leq J_0,\qquad \frac{b_+U_+}{v}\leq2u,\qquad \frac{b_+W_+}{v}\leq K_0. \end{gather*} For example, $b_+^2\leq4v^2\leq4v$ follows from $b_+\leq2v$, and $b_+^2\leq2J_0$ follows from $w^2\leq w$. The final inequality follows from $b_+W_+\leq uvw+v^2w^2\omega$ using $w,\omega\leq1$. The divisions are legitimate because $u,v,w>0$. The logarithmic estimates, with their singular initial terms retained, read \begin{align*} |(\ell_U)_u|&\leq1/u+A,& |(\ell_W)_u|&\leq A/k^2,\\ |(\ell_U)_w|&\leq A,& |(\ell_W)_w|&\leq1/w+A/k^2,\\ |(\ell_U)_v|&\leq Ak/v,& |(\ell_W)_v|&\leq A/v. \end{align*} For the strong column, the second term inside the brackets of \eqref{eq:entrance-terminal-correction} is at most \[ \frac1k\left(\frac{b_+U_+}{u}+A b_+^2\right) \leq(2+4A)\frac vk. \] For the weak column it is at most \[ \frac1k\left(\frac{b_+W_+}{w}+A b_+^2\right) \leq(1+2A)\frac{J_0}k. \] For the active column it is at most \[ A\left(\frac{b_+U_+}{v}+\frac{b_+W_+}{kv}\right) \leq A(2u+K_0)\leq3AK_0. \] The first term in the correction has the same respective scales: $|Q_u|\leq Av/k$, $|Q_w|\leq AJ_0/k$ and $|Q_v|\leq AK_0$, while $b_+^2/k^2\leq4$. Thus, with $B=T(2+8A)$, \[ |E_u|\leq Bv/k,\qquad |E_w|\leq BJ_0/k,\qquad |E_v|\leq BK_0. \] Since $DF=DQ-DE$, addition of the corresponding phase bounds proves~\eqref{eq:entrance-physical-walls}. A common enlargement of $C$ includes the value and radial bounds. \end{proof} One useful consequence expresses the estimates without a waiting factor. Since $(1+L/k)\omega\leq1$ and $u+w\leq1$, a universal constant $B$ gives \begin{equation} \begin{split} |F-r|+|F_r-1|&\leq Bv(u+v),\\ |F_u|&\leq Bv,\qquad |F_v|\leq B(u+v). \end{split} \label{eq:entrance-compact-phase-bounds} \end{equation} Indeed, $uv+v^2w^2\leq v(u+v)$, $k\geq1$ and $u+vw^2\leq u+v$. These bounds are adapted to composition with the finite outgoing segment: its new growing wall is proportional to the old weak wall.