\documentclass[11pt,a4paper]{article} \usepackage[T1]{fontenc} \usepackage[utf8]{inputenc} \usepackage{lmodern} \usepackage[margin=27mm]{geometry} \usepackage{amsmath,amssymb,amsthm,mathtools} \usepackage{booktabs} \usepackage{microtype} \usepackage[numbers,sort&compress]{natbib} \setlength{\bibsep}{2pt} \usepackage{xcolor} \definecolor{paperlink}{RGB}{0,0,114} \usepackage[colorlinks=true,allcolors=paperlink]{hyperref} \newcommand{\doi}[1]{\href{https://doi.org/#1}{\nolinkurl{doi:#1}}} \hypersetup{ pdftitle={Inertia and Elementary Theories of Hermitian Nilpotent Operators}, pdfauthor={Zhenyu Sun and Jilin Wang}, pdfsubject={Hermitian algebra and model theory}, pdfkeywords={Hermitian form, inertia, nilpotent operator, real closed field, model completeness} } \usepackage{enumitem} \setlist{itemsep=3pt,topsep=5pt} \setlength{\parindent}{1.2em} \setlength{\parskip}{2pt} \setlength{\emergencystretch}{2em} \numberwithin{equation}{section} \theoremstyle{plain} \newtheorem{theorem}{Theorem}[section] \newtheorem{proposition}[theorem]{Proposition} \newtheorem{lemma}[theorem]{Lemma} \newtheorem{corollary}[theorem]{Corollary} \theoremstyle{definition} \newtheorem{definition}[theorem]{Definition} \newtheorem{example}[theorem]{Example} \theoremstyle{remark} \newtheorem{remark}[theorem]{Remark} \DeclareMathOperator{\rank}{rank} \DeclareMathOperator{\im}{im} \DeclareMathOperator{\tr}{tr} \DeclareMathOperator{\End}{End} \DeclareMathOperator{\Fix}{Fix} \DeclareMathOperator{\In}{In} \DeclareMathOperator{\Spec}{Spec} \DeclareMathOperator{\diag}{diag} \DeclareMathOperator{\Span}{span} \DeclareMathOperator{\Aut}{Aut} \DeclareMathOperator{\tp}{tp} \newcommand{\RCF}{\mathrm{RCF}} \newcommand{\Qstr}{\mathcal Q} \newcommand{\LQ}{L_{\mathrm Q,n}} \newcommand{\Tstr}{T_n^{\mathrm{str}}} \newcommand{\Tinv}{T_n^{\mathrm{inv}}} \newcommand{\Tnil}{T_{n,\mathrm{nil}}^{p,q}} \newcommand{\Pos}{\operatorname{Pos}} \newcommand{\Rep}{\operatorname{Rep}} \newcommand{\Herm}{\operatorname{Herm}} \newcommand{\HSZ}{\operatorname{HSZ}} \newcommand{\Frame}{\operatorname{Frame}} \newcommand{\ev}{\operatorname{ev}} \newcommand{\Id}{\operatorname{id}} \newcommand{\op}{\mathrm{op}} \newcommand{\bP}{\mathbf P} \newcommand{\bR}{\mathbb R} \newcommand{\bC}{\mathbb C} \newcommand{\bQ}{\mathbb Q} \newcommand{\bN}{\mathbb N} \title{Inertia and Elementary Theories\\of Hermitian Nilpotent Operators} \author{Zhenyu Sun \and Jilin Wang} \date{} \begin{document} \maketitle \begin{abstract} Let \(V\) be a finite-dimensional Hermitian space over an algebraically closed field with a nonidentity involution, and suppose its form \(h\) is nondegenerate. For a self-adjoint nilpotent operator \(N\), we recover the multiplicity of each signed Jordan block from finite differences of the ranks and signature differences of the forms \(h(x,N^j y)\). On a fixed Hermitian space these inertias classify unitary conjugacy. Across scalar fields they classify elementary equivalence in the four-sorted language of scalars, vectors, endomorphisms, and projective points with \(N\) named. At fixed dimension each admissible inertia sequence isolates a complete theory. These theories are model complete and decidable, and none has the independence property. A bivariate generating function counts them by ambient signature. For two self-adjoint square-zero operators with a common image of fixed positive dimension and positive definite quotient forms, simultaneous unitary conjugacy on a fixed Hermitian space is classified by the ordered generalized eigenvalues. The associated Hermitian pencil recovers these eigenvalues even when all operator words have constant ranks and inertias. At fixed signature and rank the family theory is model complete and decidable. Its completions correspond to the ordered-field types of the spectrum, and each completion has the Turing degree of its type. We also characterize the Witt index by square-zero ranks over arbitrary fields with involution. For positive definite spaces we prove that finite-measurement sentences at fixed dimensions and outcome count have the same truth value over \(R(\sqrt{-1})\) as over \(\mathbb C\) for every real closed field \(R\). The least Naimark dilation dimension of a measurement is the sum of its effect ranks. \end{abstract} \noindent\textbf{Keywords.} Hermitian form, inertia, self-adjoint nilpotent operator, model completeness, real closed field, quantum measurement. \section{Introduction}\label{sec:introduction} The ranks of the powers of a nilpotent operator determine the lengths of its Jordan blocks. If the operator is self-adjoint for an indefinite Hermitian form, each block also has a sign. Even on a hyperbolic plane, two rank-one nilpotent operators can have the same Jordan form and opposite signs. We ask how to read these signs from the operator and the form, and which first-order sentences distinguish the resulting structures. Let \(K\) be an algebraically closed field with a nonidentity involution \(\sigma\), and let \((V,h)\) be a nondegenerate Hermitian space of dimension \(n\) over \(K\). The fixed field \(R=K^\sigma\) is real closed, and \(K=R(u)\) with \(u^2=-1\). We write \((p,q)\) for the ordered signature of \(h\). The four sorts of our language are the field \(K\), the space \(V\), its full endomorphism algebra, and its projective space. It names neither a basis of \(V\) nor a square root of \(-1\). \subsection{One operator and two operators} For a self-adjoint nilpotent operator \(N\), consider the Hermitian forms \[ B_j^N(x,y)=h(x,N^j y),\qquad 0\leq jb\) and \(a\geq b\), for \(a,b\in R\), abbreviate \(\Pos(a-b)\) and \(\Pos(a-b)\vee a=b\). If \(z=a+ub\), then \[ \sigma(z)z=a^2+b^2, \] which is positive for \(z\neq0\). For a possibly degenerate Hermitian form \(b\), its inertia is the triple \(\In(b)=(p(b),q(b),z(b))\) of positive, negative, and zero indices. We often write only the positive and negative indices, since \(z(b)=n-p(b)-q(b)\) for a form on \(V\). The rank is \(p(b)+q(b)\), and the signature difference is \(p(b)-q(b)\). \begin{proposition}\label{prop:inertia} Over \(K=R(u)\), every Hermitian form is congruent to \(\diag(I_p,-I_q,0_z)\), and \((p,q,z)\) is unique. For a nondegenerate form of signature \((p,q)\), \[ w(h)=\min(p,q). \] \end{proposition} \begin{proof} If a Hermitian form \(b\) is nonzero, polarization shows that \(b(v,v)\neq0\) for some \(v\). Indeed, the equalities \(b(x+y,x+y)=0\) and \(b(x+uy,x+uy)=0\), together with vanishing diagonal values, force both the real and imaginary parts of \(b(x,y)\) to vanish. Split off the nondegenerate line \(Kv\) and proceed by induction. Each nonzero diagonal entry lies in \(R\) and can be rescaled to \(1\) or \(-1\). The remaining subspace is the radical. In the resulting diagonal representation, projection of a positive definite subspace onto the \(p\) positive coordinates is injective. Thus its dimension is at most \(p\), and the coordinate subspace attains this bound. It follows that \(p\) is intrinsic. The same argument applies to \(q\), and the radical determines \(z\). For \(h=\diag(I_p,-I_q)\), the vectors \(e_i+f_i\), for \(1\leq i\leq\min(p,q)\), span a totally isotropic subspace. Projection of any totally isotropic subspace onto either the positive or the negative coordinates is injective, proving the reverse bound. These are the usual Hermitian inertia and Witt arguments \cite{Scharlau1985}. \end{proof} We write \(H_{p,q}=\diag(I_p,-I_q)\) for the standard matrix of signature \((p,q)\). \subsection{The four sorts} The language \(\LQ\) has sorts \(K,V,M,P\). The scalar sort carries \(0,1,+,-,\cdot,\sigma\). The vector and operator sorts carry their additive and scalar-multiplication operations. The language also includes the maps \[ M\times M\longrightarrow M,\quad (S,T)\longmapsto ST, \qquad \ev:M\times V\longrightarrow V, \qquad h:V\times V\longrightarrow K, \] and a relation \(\Rep\subseteq V\times P\). We write \(Tv\) for \(\ev(T,v)\). No basis is named in \(\LQ\). \begin{definition}\label{def:structure} The Hermitian structure associated with \((K,\sigma,V,h)\) is \[ \Qstr(K,V,h) =\bigl(K,V,\End_K(V),\bP(V);\,\sigma,h,\ev,\Rep\bigr), \] with the natural operations, where \(\dim_KV=n\) and \[ \Rep(v,p)\quad\Longleftrightarrow\quad v\neq0,\ p=Kv. \] The theory \(\Tstr\) describes these structures over arbitrary fields with involution. The theory \(\Tinv\) adds algebraic closedness of \(K\) and \(\sigma\neq\Id\). Its signature-\((p,q)\) extension, for \(p+q=n\), is denoted \(T_n^{p,q}\). \end{definition} \begin{proposition}\label{prop:axiomatization} The class in Definition~\ref{def:structure} is elementary. In particular, \(\Tstr\) has an effective finite axiomatization. \end{proposition} \begin{proof} Use the field and involution axioms, the vector-space axioms, and the Hermitian identities and nondegeneracy. The assertion that \(V\) has a basis of length \(n\) is first-order. On \(M\), impose the vector-space axioms, linearity of evaluation in its vector argument, and \[ (S+T)v=Sv+Tv,\qquad (aT)v=a(Tv),\qquad (-_M T)v=-_V(Tv),\qquad (ST)v=S(Tv). \] Add extensionality, \[ \forall S\,\forall T\, \bigl((\forall v\ Sv=Tv)\longrightarrow S=T\bigr), \] and the assertion that for some basis \(e_1,\ldots,e_n\), every list of images \(v_1,\ldots,v_n\) is realized by an operator, as expressed by \[ \exists\bar e\left(\operatorname{Basis}_n(\bar e)\wedge \forall v_1\cdots v_n\ \exists T\ \bigwedge_i Te_i=v_i\right). \] These axioms identify \(M\) with all of \(\End_K(V)\). For \(P\), require each nonzero vector to represent a unique point, every point to have a representative, no zero vector to represent a point, and \[ \Rep(v,p)\wedge a\neq0\ \longrightarrow\ \Rep(av,p), \] \[ \Rep(v,p)\wedge\Rep(w,p)\ \longrightarrow\ \exists a\,(a\neq0\wedge w=av). \] Thus the fibers are exactly the nonzero parts of the one-dimensional subspaces. For fixed \(n\) these conditions are a finite, effectively given list of axioms. Evaluation identifies the operator sort with \(\End_K(V)\), and the representative relation identifies the point sort with \(\mathbf P(V)\). \end{proof} We use \(I\) for the unique operator satisfying \(\forall v\ Iv=v\). For each \(T\in M\), the nondegeneracy of \(h\) gives a unique adjoint satisfying \[ h(Tx,y)=h(x,T^\dagger y). \] In a basis with Gram matrix \(H\), it is \[ T^\dagger=H^{-1}\sigma(T)^{\mathrm t}H. \] Consequently the relations \(S=T^\dagger\), \(T=T^\dagger\), and \(T^\dagger T=TT^\dagger=I\) are first-order. They define adjunction, self-adjointness, and unitarity, respectively. \subsection{Inertia as an intrinsic first-order predicate} Let \(g(x,y;\bar c)\) be a term defining a Hermitian form on \(V\). For nonnegative integers \(a,b\) with \(a+b\leq n\), let \(\operatorname{In}_{a,b}(g)\) assert that some basis \(v_1,\ldots,v_n\) has Gram matrix \[ \diag(I_a,-I_b,0_{n-a-b}) \] for \(g\). The basis condition itself has an existential definition over \(\Tstr\). It asks for vectors \(w_1,\ldots,w_n\) satisfying \[ h(w_i,v_j)=\delta_{ij}\qquad(1\leq i,j\leq n). \] Pairing a linear relation among the \(v_j\) with each \(w_i\) shows that all its coefficients vanish. Conversely, nondegeneracy of \(h\) gives such a dual basis for every basis of \(V\). \begin{lemma}\label{lem:inertia-definable} In \(\Tinv\), the formula \(\operatorname{In}_{a,b}(g)\) defines exactly the forms of inertia \((a,b,n-a-b)\). It has an existential definition using vector and scalar variables. In particular the signature sentences \(\operatorname{Sig}_{p,q}:=\operatorname{In}_{p,q}(h)\) are existential, mutually exclusive, and exhaustive. \end{lemma} \begin{proof} Proposition~\ref{prop:inertia} identifies the three indices from the Gram matrix. The dual-basis condition above uses only existential quantifiers, and the prescribed entries are the scalar terms \(0,1,-1\). \end{proof} When a fixed finite-dimensional quotient is used below, its linear independence, basis, and form conditions can likewise be expressed on representatives. Appendix~\ref{app:formulas} records the translations. \section{Coordinate interpretations and semialgebraic reduction} \label{sec:interpretations} An orthogonal coordinate system need not be definable from the form. Once a frame and a square root of \(-1\) are named, all four sorts have coordinates in the ordered fixed field. For a named operator, the only additional data needed are its matrix entries in that frame. \subsection{Frames and projective representatives} Fix a symmetric matrix \(H\in GL_n(\mathbb Z)\). Its entries are scalar terms, and its inverse also has integer entries. An \(H\)-frame is a basis \(\bar e=(e_1,\ldots,e_n)\) satisfying \(h(e_i,e_j)=H_{ij}\). In the language expanded by \(\bar e\), the coordinate relations are \begin{align} v=\sum_i x_i e_i,\qquad Te_j=\sum_i a_{ij}e_i. \label{eq:coordinates} \end{align} Their solutions are unique. In fact vector coordinates are given by terms, \[ x_i=\sum_j(H^{-1})_{ij}h(e_j,v), \] and the same expression applied to \(Te_j\) gives the operator entries. For projective points, put \[ C_i=\{(x_1,\ldots,x_n)\in K^n: x_1=\cdots=x_{i-1}=0,\ x_i=1\}, \qquad C^{\mathrm{proj}}=\bigsqcup_{i=1}^n C_i. \] Each one-dimensional subspace has a unique representative in \(C^{\mathrm{proj}}\), obtained by dividing by the first nonzero coordinate. The formula \[ \operatorname{Can}(p,\bar x):\ \bar x\in C^{\mathrm{proj}}\ \wedge\ \Rep\left(\sum_i x_i e_i,p\right) \] therefore specifies a definable bijection between \(P\) and this definable subset of \(K^n\). \begin{theorem}[Coordinate reduction]\label{thm:coordinate-reduction} Expand a model of \(\Tinv\) by an \(H\)-frame and by an element \(u\) satisfying \(u^2=-1\) and \(\sigma(u)=-u\). Every formula in this expanded language admits an effective translation to an ordered-field formula over \(R=\Fix(\sigma)\). The translation uses two real coordinates for each scalar variable, \(2n\) for each vector or projective variable, and \(2n^2\) for each operator variable. With both the frame and \(u\) named, the structure is parameter-free bi-interpretable with \(R\). If finitely many operators are also named, the corresponding expansion of \(R\) names the real and imaginary parts of their matrix entries. The same assertion holds uniformly when those matrices are specified by polynomial or rational expressions in real parameters named on both sides, with nonzero denominators. \end{theorem} \begin{proof} First replace \(V\), \(M\), and \(P\) by \(K^n\), \(K^{n^2}\), and \(C^{\mathrm{proj}}\), respectively, using \eqref{eq:coordinates}. Vector operations, matrix multiplication, and evaluation are polynomial. The form is \[ h(x,y)=\sigma(x)^{\mathrm t}Hy. \] The representative relation becomes proportionality between a nonzero vector and a canonical representative. Restricted projective quantifiers are handled by the defining formula for \(C^{\mathrm{proj}}\). Next write each scalar \(x\) as \(a+ub\), where \(a,b\in R\), using \[ a=\frac{x+\sigma(x)}2,\qquad b=-\frac{u(x-\sigma(x))}2. \] Multiplication and conjugation become \[ (a,b)(c,d)=(ac-bd,ad+bc),\qquad \sigma(a,b)=(a,-b). \] Translate atomic formulas by these rules and proceed through Boolean operations and quantifiers. This gives the claimed effective translation and coordinate counts. Conversely, the real field is interpreted on the definable fixed-field subset of \(K\), with the order from \eqref{eq:positive}. Starting from an ordered real closed field, form \(R^2\) with the displayed operations and \(u=(0,1)\), then the vector, operator, and canonical projective sorts. The coordinate maps and the scalar decomposition give definable isomorphisms between each structure and the corresponding double interpretation. Named operator matrices are transported by the same maps, including in the parameterized case. \end{proof} Real closed fields have effective quantifier elimination in the ordered field language \cite{Marker2002,vandenDries1998}. Hence every formula in Theorem~\ref{thm:coordinate-reduction} has a semialgebraic description in the resulting real coordinates. If an operator is fixed in a canonical matrix form with entries in \(\{0,1,-1\}\), it introduces no scalar parameters. In particular, the signed Jordan matrices used in Section~\ref{sec:model-theory} require no expansion of the fixed field. \subsection{Descent and the original language} \begin{proposition}\label{prop:frame-descent} Work in the class of models admitting an \(H\)-frame. Let \(\varphi(\bar x;\bar e)\) be a formula using such a frame. Suppose its truth on a tuple \(\bar x\) is independent of the chosen \(H\)-frame. Then the relation it defines is definable in the original language by \[ \exists\bar e\, \bigl(\Frame_H(\bar e)\wedge\varphi(\bar x;\bar e)\bigr). \] \end{proposition} \begin{proof} An \(H\)-frame exists in every structure under consideration. The assumed independence makes the existential choice equivalent to any particular choice. \end{proof} The inertia predicates of Lemma~\ref{lem:inertia-definable} are already formulas of \(\LQ\). Proposition~\ref{prop:no-quantifier-elimination} and Remark~\ref{rem:frame-and-biinterpretation} describe which conclusions about coordinates depend on the named constants. \section{Inertia of powers and nilpotent unitary orbits}\label{sec:nilpotent} Let $K$ be an algebraically closed field with a nonidentity involution $\sigma$, let $R=K^\sigma$, and let $(V,h)$ be a nondegenerate Hermitian space of dimension $n$ and signature $(p,q)$. Throughout this section, $N$ is an $h$-self-adjoint nilpotent endomorphism of $V$. For $0\leq j\leq n$, define the Hermitian form on $V$ by \begin{equation}\label{eq:power-forms} B_j^N(x,y)=h(x,N^j y),\qquad B_0^N=h. \end{equation} Write $(p_j,q_j)$ for its positive and negative indices, and put \begin{equation}\label{eq:power-inertia-data} r_j=p_j+q_j,\qquad d_j=p_j-q_j. \end{equation} The zero index is $n-r_j$. Self-adjointness and nondegeneracy give \begin{equation}\label{eq:power-radical} \operatorname{rad} B_j^N=\ker N^j,\qquad r_j=\operatorname{rank}N^j. \end{equation} In particular, $r_0=n$, $d_0=p-q$, and $r_n=d_n=0$. We also set $r_{n+1}=d_{n+1}=0$. The signed Jordan form over the complex numbers is classical \cite{Mehl2006}. We construct its nilpotent blocks over \(K=R(u)\), then compute the contribution of one block to each \(B_j^N\). This calculation recovers the signs in any basis. \subsection{Signed cyclic decompositions}\label{subsec:signed-cyclic} Let $J_m=J_m(0)$ be the nilpotent Jordan matrix with ones immediately above the diagonal, and let \[ F_m=(\delta_{a+b,m+1})_{1\leq a,b\leq m} \] be the reversal matrix. Thus $F_mJ_m=J_m^{\mathrm t}F_m$. The inertia of $F_m$ is $(\lceil m/2\rceil,\lfloor m/2\rfloor)$. Each pair of coordinate vectors interchanged by $F_m$ contributes one positive and one negative square, and the middle coordinate contributes a positive square when $m$ is odd. \begin{lemma}\label{lem:signed-cyclic} Suppose that $N^m=0$ and $N^{m-1}\neq0$. There is an $N$-invariant nondegenerate subspace $W$ of dimension $m$ and a basis of $W$ in which \[ [N|_W]=J_m,\qquad [h|_W]=\varepsilon F_m, \qquad \varepsilon\in\{1,-1\}. \] The orthogonal complement $W^\perp$ is also $N$-invariant. \end{lemma} \begin{proof} Since $N^{m-1}\ne0$ and $h$ is nondegenerate, $B_{m-1}^N$ is nonzero. By Proposition~\ref{prop:inertia} it has a nonzero diagonal value. Choose $v$ with \[ c=h(v,N^{m-1}v)\neq0. \] Every moment $\beta_j=h(v,N^jv)$ belongs to $R$, because $N^j$ is self-adjoint. Replacing $v$ by $|c|^{-1/2}v$ gives $\beta_{m-1}=\varepsilon\in\{1,-1\}$. The vectors $v,Nv,\ldots,N^{m-1}v$ are linearly independent. To make the Gram matrix a signed reversal matrix, we change the cyclic generator so that its moments of orders $0,\ldots,m-2$ vanish. In the truncated polynomial ring $R[t]/(t^m)$, put \[ C(t)=\varepsilon^{-1} \sum_{a=0}^{m-1}\beta_{m-1-a}t^a. \] Its constant term is $1$. Consequently there is a polynomial $P(t)$ with constant term $1$ such that \begin{equation}\label{eq:moment-normalization} P(t)^2C(t)\equiv1\pmod{t^m}. \end{equation} For example, take the truncated binomial expansion \[ P(t)=\sum_{\ell=0}^{m-1} \binom{-1/2}{\ell}\bigl(C(t)-1\bigr)^\ell \pmod{t^m}. \] All its coefficients lie in $R$. Set $w=P(N)v$. Since $P(N)$ commutes with $N$, is self-adjoint, and is invertible on $V$, the vector $w$ generates the same cyclic subspace as $v$. Writing $P(t)^2=\sum_a\gamma_at^a$ modulo $t^m$ gives \[ h(w,N^jw) =\sum_{a=0}^{m-1-j}\gamma_a\beta_{j+a} =\varepsilon\,[t^{m-1-j}]\bigl(P(t)^2C(t)\bigr) =\varepsilon\,\delta_{j,m-1} \quad(0\leq j1$. Moreover, \[ h(e_a,e_b)=h(w,N^{2m-a-b}w) =\varepsilon\,\delta_{a+b,m+1}, \] where moments of index at least $m$ vanish. This proves the two matrix identities and nondegeneracy of the cyclic subspace $W$. Finally, if $x\in W^\perp$ and $y\in W$, then $h(Nx,y)=h(x,Ny)=0$, so $Nx\in W^\perp$. \end{proof} \begin{theorem}[Signed Jordan decomposition]\label{thm:signed-jordan} There is an orthogonal decomposition of $(V,h,N)$ into blocks \begin{equation}\label{eq:signed-blocks} (K^m,\,\varepsilon F_m,\,J_m),\qquad 1\leq m\leq n,\quad \varepsilon\in\{1,-1\}. \end{equation} If $c_m^+$ and $c_m^-$ count the blocks of length $m$ with the indicated sign, respectively, then \begin{align} n&=\sum_{m=1}^n m(c_m^++c_m^-),\label{eq:signed-dimension}\\ p&=\sum_{m=1}^n \left(\left\lceil\frac m2\right\rceil c_m^+ +\left\lfloor\frac m2\right\rfloor c_m^-\right),\label{eq:signed-positive}\\ q&=\sum_{m=1}^n \left(\left\lfloor\frac m2\right\rfloor c_m^+ +\left\lceil\frac m2\right\rceil c_m^-\right).\label{eq:signed-negative} \end{align} Conversely, any nonnegative integral block multiplicities satisfying \eqref{eq:signed-positive}--\eqref{eq:signed-negative} are realized by an $h$-self-adjoint nilpotent endomorphism of $V$. \end{theorem} \begin{proof} Apply Lemma~\ref{lem:signed-cyclic} with $m$ equal to the nilpotency index, then repeat on the nondegenerate invariant orthogonal complement. The process terminates because the dimension decreases at each step. The signature formulas follow from the inertia of $F_m$. For the converse, form the indicated orthogonal direct sum. Its form has signature $(p,q)$, so an isometry to $(V,h)$ transports its direct sum of Jordan blocks to the required endomorphism. \end{proof} \subsection{Recovery and realization of inertia profiles}\label{subsec:inertia-recovery} On a single signed block, taking a power of $N$ shortens the nondegenerate part of the form by one coordinate at each step. Its rank records the remaining length. Its signature difference records the sign whenever that length is odd. \begin{theorem}[Recovery from the inertia of powers]\label{thm:inertia-recovery} For a self-adjoint nilpotent endomorphism $N$ with signed block multiplicities $c_m^\pm$, one has \begin{align} r_j&=\sum_{m>j}(m-j)(c_m^++c_m^-),\label{eq:rank-from-blocks}\\ d_j&=\sum_{\substack{m>j\\m-j\text{ odd}}} (c_m^+-c_m^-) \qquad(0\leq j\leq n).\label{eq:imbalance-from-blocks} \end{align} These relations are invertible. More precisely, for $1\leq m\leq n$, \begin{equation}\label{eq:inertia-inversion} c_m^\pm=\frac12\left[ r_{m-1}-2r_m+r_{m+1} \ \pm\ (d_{m-1}-d_{m+1})\right]. \end{equation} Consequently the sequence $\bigl((p_j,q_j)\bigr)_{j=0}^{n-1}$ determines the signed Jordan multiplicities uniquely. \end{theorem} \begin{proof} On a block of length $m$ and sign $\varepsilon$, the Gram matrix of $B_j^N$ is $\varepsilon F_mJ_m^j$. If $jj$, and contributes $\varepsilon$ to the difference of positive and negative indices exactly when $m-j$ is odd. Additivity of inertia under orthogonal sums proves \eqref{eq:rank-from-blocks}--\eqref{eq:imbalance-from-blocks}. Set $t_m=c_m^++c_m^-$ and $e_m=c_m^+-c_m^-$. Taking successive differences in \eqref{eq:rank-from-blocks} yields \[ r_{m-1}-r_m=\sum_{\ell\geq m}t_\ell, \qquad t_m=r_{m-1}-2r_m+r_{m+1}. \] Similarly, the summands in $d_{m+1}$ are exactly those in $d_{m-1}$ except for $e_m$, so \[ e_m=d_{m-1}-d_{m+1}. \] The equalities $c_m^\pm=(t_m\pm e_m)/2$ give \eqref{eq:inertia-inversion}. The specified zero boundary values cover $m=n$ and $m=n-1$ as well. \end{proof} \begin{corollary}[Admissible inertia profiles]\label{cor:admissible-inertia} Let $(p_j,q_j)$, $0\leq jj}(m-j)t_m,\qquad d_j=\sum_{\substack{m>j\\m-j\text{ odd}}}e_m. \] At $j=0$ these identities show that the direct sum of the associated signed blocks has dimension $n$ and signature $(p,q)$. Theorem~\ref{thm:signed-jordan} realizes it on $(V,h)$. The same identities at every $j$ recover the prescribed ranks and index differences, hence the prescribed inertias. \end{proof} \begin{corollary}[Admissible Jordan partitions]\label{cor:admissible-partitions} A partition $\lambda=(\lambda_1,\ldots,\lambda_a)$ of $n$ occurs as the ordinary Jordan type of an $h$-self-adjoint nilpotent endomorphism if and only if \begin{equation}\label{eq:partition-admissibility} \sum_{i=1}^a\left\lfloor\frac{\lambda_i}{2}\right\rfloor \leq\min(p,q). \end{equation} Equivalently, the number $o(\lambda)$ of odd parts of $\lambda$ satisfies $o(\lambda)\geq|p-q|$. \end{corollary} \begin{proof} Each block contributes at least $\lfloor\lambda_i/2\rfloor$ to both indices. This proves necessity. Write $b=\sum_i\lfloor\lambda_i/2\rfloor=(n-o(\lambda))/2$. Every even block has equal positive and negative indices, whereas each odd block contributes one additional index of the sign assigned to that block. If \eqref{eq:partition-admissibility} holds, assign positive signs to $p-b$ odd blocks and negative signs to $q-b$ odd blocks. Both numbers are nonnegative and their sum is $o(\lambda)$. The signs of even blocks may be chosen arbitrarily. The resulting signed direct sum has signature $(p,q)$. \end{proof} \subsection{First-order definitions of the unitary orbits}\label{subsec:nilpotent-definability} Write $\operatorname{U}(h)$ for the group of invertible endomorphisms preserving $h$. Its action on endomorphisms is conjugation. \begin{theorem}\label{thm:nilpotent-orbits} Two $h$-self-adjoint nilpotent endomorphisms $N$ and $N'$ are conjugate under $\operatorname{U}(h)$ if and only if \[ \operatorname{inertia}B_j^N= \operatorname{inertia}B_j^{N'}\qquad(0\leq jq$, use one block $(F_{2q+1},J_{2q+1})$ and $p-q-1$ positive length-$1$ blocks. If $q>p$, use $(-F_{2p+1},J_{2p+1})$ and $q-p-1$ negative length-$1$ blocks. These constructions include $w=0$ and, by an isometry, give operators on the prescribed space $(V,h)$. \end{proof} \section{Elementary classification and definable sets} \label{sec:model-theory} We use the original multisorted language $\LQ$, without a named basis or imaginary unit, and the theories $\Tinv$ and $T_n^{p,q}$ from Definition~\ref{def:structure}. In the language $\LQ(N)$, where $N$ is a constant of the operator sort, put \[ T_{n,\mathrm{nil}} =\Tinv+\{N=N^\dagger,\ N^n=0\}. \] Here the adjoint notation abbreviates its defining relation. Adding the signature sentence $\operatorname{Sig}_{p,q}$ gives $T_{n,\mathrm{nil}}^{p,q}$, where $p+q=n$. \subsection{Defining the signed Jordan branches} Write \[ \Gamma_n=\left\{\gamma=(c_m^+,c_m^-)_{m=1}^n: c_m^\pm\in\mathbb Z_{\geq0},\quad \sum_{m=1}^n m(c_m^++c_m^-)=n\right\}. \] For $\gamma\in\Gamma_n$, form the canonical pair $(J_\gamma,H_\gamma)$ by taking $c_m^+$ copies of $(J_m,F_m)$ and $c_m^-$ copies of $(J_m,-F_m)$, in a fixed order, using the reversal matrix $F_m$ of Section~\ref{subsec:signed-cyclic}. Thus $H_\gamma$ is symmetric, integral, and has determinant $\pm1$. Let $(p_\gamma,q_\gamma)$ be its signature. Define \begin{align*} \operatorname{Can}_\gamma(\bar e,N):={}& \bigwedge_{a,b=1}^n h(e_a,e_b)=(H_\gamma)_{ab} \\ &\wedge\bigwedge_{b=1}^n Ne_b=\sum_{a=1}^n(J_\gamma)_{ab}e_a, \qquad \chi_\gamma:=\exists\bar e\, \operatorname{Can}_\gamma(\bar e,N). \end{align*} The invertible Gram matrix makes the $n$ vectors in $\bar e$ a basis. Set \[ T_{n,\mathrm{nil}}^{\gamma}=T_{n,\mathrm{nil}}+\{\chi_\gamma\}. \] Equivalently, one can specify a branch by the power forms $B_j^N(x,y)=h(x,N^j y)$, using the inertia predicates from Lemma~\ref{lem:inertia-definable}. If $(p_j^\gamma,q_j^\gamma)$ are the inertias of $H_\gamma J_\gamma^j$, Theorems~\ref{thm:signed-jordan} and~\ref{thm:inertia-recovery} give \begin{equation}\label{eq:inertia-branch} T_{n,\mathrm{nil}}\models \chi_\gamma\ \longleftrightarrow\ \bigwedge_{j=0}^{n-1} \operatorname{In}_{p_j^\gamma,q_j^\gamma}(B_j^N). \end{equation} Thus $\chi_\gamma$ can be read either as a condition on a single Jordan basis or as a list of basis-independent inertia conditions. \begin{theorem}[Elementary classification of nilpotent expansions] \label{thm:nilpotent-elementary-classification} For fixed $n$, the following statements hold. \begin{enumerate} \item The theories $T_{n,\mathrm{nil}}^{\gamma}$, for $\gamma\in\Gamma_n$, are exactly the complete extensions of $T_{n,\mathrm{nil}}$. Two models are elementarily equivalent if and only if the inertias of $h(x,N^j y)$ agree for $0\leq j0}=\{x:\sigma(x)=x\ \wedge\ \exists z\,(\sigma(z)=z\wedge z\ne0\wedge z^2=x)\}. \] In the framed language, every atomic formula with one free scalar variable, restricted to $x\in R$, becomes a finite system of one-variable polynomial equalities over $R(u)$. To see this, apply induction on terms. The field operations, vector operations, evaluation, composition, and the Hermitian form are polynomial in coordinates, while the named frame and $N$ have fixed integral coordinates. There is no closed term of projective sort, so the representative relation produces no additional atomic condition in this one-variable situation. Each such polynomial equality defines a finite set or all of $R$. Every quantifier-free formula therefore defines a finite or cofinite subset of $R$. The set $R_{>0}$ and its complement in $R$ are both infinite, proving the assertion. The same positive cone is definable in the reduct, whose quantifier-free formulas are also quantifier-free in the expansion. Taking $N=0$ gives the assertion for $T_n^{p,q}$. \end{proof} \begin{remark}\label{rem:frame-and-biinterpretation} A frame chosen in the smaller model remains a frame under any embedding, which is enough for model completeness. Bi-interpretability imposes a further constraint because it preserves automorphism groups. In an unframed model, $v\mapsto-v$ on $V$, acting identically on $K,M,P$, is an automorphism of order two, also when $N$ is named. An automorphism of an ordered field has no nontrivial finite orbit. Indeed, if it moves an element upwards or downwards, its successive iterates form a strictly monotone sequence. Thus the unframed model cannot be parameter-free bi-interpretable with a real closed field. In the standard complex model, even after a canonical frame is named, complex conjugation in that frame gives an automorphism of order two. Naming $u$ distinguishes it from $-u$, as required by the coordinate interpretation. \end{remark} \section{Pairs of square-zero operators and Hermitian pencils} \label{sec:pairs} Two self-adjoint square-zero operators with the same image induce two forms on a common quotient. When both forms are positive definite, their generalized eigenvalues can vary even though the word ranks and inertias remain fixed. Throughout this section, fix \(p+q=n\) and \(1\leq s\leq\min(p,q)\). \begin{definition}\label{def:positive-pair} A positive pair of rank \(s\) consists of two named operators \(N_1,N_2\) in a model of \(T_n^{p,q}\) such that \[ N_i=N_i^\dagger,\qquad N_i^2=0,\qquad \rank N_i=s,\qquad \im N_1=\im N_2, \] and \begin{equation}\label{eq:positive-quotient-condition} N_i x\neq0\quad\Longrightarrow\quad \Pos\bigl(h(x,N_i x)\bigr) \qquad(i=1,2). \end{equation} The resulting first-order theory is denoted \(T_{\mathrm{pair}}^{p,q;s}\). \end{definition} Set \(W=\im N_1=\im N_2\). Self-adjointness gives \(\ker N_i=(\im N_i)^\perp=W^\perp\), and \(N_i^2=0\) gives \(W\subseteq W^\perp\). Thus \[ N_1N_2=N_2N_1=0. \] On the \(s\)-dimensional quotient \(E=V/W^\perp\), define \begin{equation}\label{eq:pair-quotient-forms} q_i([x],[y])=h(x,N_i y). \end{equation} Changing either representative by an element of \(W^\perp\) does not change this expression. The forms are Hermitian and nondegenerate. Condition~\eqref{eq:positive-quotient-condition} says exactly that both are positive definite. \subsection{A simultaneous normal form} \begin{theorem}\label{thm:pair-classification} Every positive pair of rank \(s\) admits a basis in which \begin{equation}\label{eq:pair-canonical} H= \begin{pmatrix} 0&I_s&0\\ I_s&0&0\\0&0&H_{p-s,q-s} \end{pmatrix}, \quad N_1= \begin{pmatrix} 0&I_s&0\\0&0&0\\0&0&0 \end{pmatrix}, \quad N_2= \begin{pmatrix} 0&D_{\boldsymbol\lambda}&0\\0&0&0\\0&0&0 \end{pmatrix}, \end{equation} where \[ D_{\boldsymbol\lambda}=\diag(\lambda_1,\ldots,\lambda_s), \qquad 0<\lambda_1\leq\cdots\leq\lambda_s,\quad \lambda_i\in R. \] The ordered tuple \(\boldsymbol\lambda\), with repetitions, is unique. Over the same scalar field, it is a complete invariant for simultaneous unitary conjugacy. \end{theorem} \begin{proof} Let \(A\in\End_K(E)\) be defined by \[ q_1(x,Ay)=q_2(x,y). \] The Hermitian symmetry of \(q_2\) makes \(A\) self-adjoint for \(q_1\). Algebraic closedness gives an eigenvector \(v\ne0\). Its eigenvalue is \(q_2(v,v)/q_1(v,v)>0\). The \(q_1\)-orthogonal complement of \(Kv\) is invariant under \(A\). Induction, with normalization in the real closed field, gives a \(q_1\)-orthonormal eigenbasis with positive eigenvalues. Order them as \(\lambda_1,\ldots,\lambda_s\). Choose representatives \(f_i\in V\) of this basis and put \(e_i=N_1f_i\). Then \[ h(f_i,e_j)=\delta_{ij},\qquad h(e_i,e_j)=0,\qquad N_2f_j=\lambda_j e_j. \] Indeed, both sides of the last identity lie in \(W\) and have the same pairings with every \(f_i\). These pairings determine a vector in \(W\) because the \(e_j\) are a basis of \(W\) dual to the \(f_i\) under \(h\). Replace each \(f_j\) by \[ f'_j=f_j-\frac12\sum_{\ell=1}^s e_\ell h(f_\ell,f_j). \] The pairings \(h(e_i,f'_j)=\delta_{ij}\) are unchanged, and direct expansion gives \(h(f'_i,f'_j)=0\). Since both operators kill \(W\), their values on the \(f'_j\) are also unchanged. Thus the span of the \(e_i,f'_i\) is a nondegenerate hyperbolic subspace. Its orthogonal complement has signature \((p-s,q-s)\) and lies in \(W^\perp\), so both operators vanish there. This proves \eqref{eq:pair-canonical}. A simultaneous isometry induces an isometry of the pair \((q_1,q_2)\), and hence preserves the spectrum of \(A=q_1^{-1}q_2\) with multiplicities. Conversely, equality of the ordered spectra identifies the canonical bases in \eqref{eq:pair-canonical} and produces a simultaneous isometry. \end{proof} The simultaneous reduction of two forms with one positive definite form is the usual definite Hermitian pencil construction \cite{HornJohnson2013,GohbergLancasterRodman2005}. Theorem \ref{thm:pair-classification} realizes that construction inside the square-zero operator geometry, including the common radical and the ambient orthogonal complement. \begin{proposition}\label{prop:pair-definable-spectrum} The ordered spectrum \(\boldsymbol\lambda\) is a uniquely definable tuple in the original language with \(N_1,N_2\). For every \(t\in R\), the Hermitian pencil \[ B_t(x,y)=h\bigl(x,(N_2-tN_1)y\bigr) \] has inertia \begin{equation}\label{eq:pencil-inertia} \In(B_t)= \left( \#\{i:\lambda_i>t\}, \#\{i:\lambda_i1. \] Here an operator word means a monomial in \(N_1,N_2\). Since \(t>1\), the operators \(N_1,N_2\) are linearly independent. The empty word gives \(I\) and hence the ambient form \(h\). Every operator word of length at least two is zero. Both words of length one have rank \(2\), and both forms \(h(x,N_i y)\) have inertia \((2,0,2)\). Thus the ranks and inertias of all words in the two operators are independent of \(t\). The generalized spectrum is \((1,t)\). As \(t\) ranges over \((1,\infty)\subset\mathbb R\), the structures have pairwise different complete theories by Theorem~\ref{thm:pair-elementary}. The second jump in the pencil inertia \eqref{eq:pencil-inertia} occurs at \(t\). \end{example} \section{Witt index and orthogonal spectral decompositions} \label{sec:spectral} A square-zero self-adjoint operator has totally isotropic image. Conversely, a basis of any totally isotropic subspace gives an explicit operator with that image. Neither direction requires an assumption on the scalar field or its characteristic. \begin{theorem}\label{thm:general-witt} Let \(h\) be a nondegenerate Hermitian form on a finite-dimensional vector space over any field with involution. For each integer \(s\geq0\), there exists a self-adjoint operator \(N\) with \[ N^2=0,\qquad \rank N=s \] if and only if \(s\leq w(h)\). Every totally isotropic \(s\)-dimensional subspace occurs as the image of such an operator. \end{theorem} \begin{proof} If \(N=N^\dagger\) and \(N^2=0\), then \[ h(Nx,Ny)=h(x,N^2y)=0, \] so \(\im N\) is totally isotropic. Conversely, let \(W=\Span(e_1,\ldots,e_s)\) be totally isotropic and put \[ N(x)=\sum_{i=1}^s e_i h(e_i,x). \] This map is linear, and \[ h(Nx,y)=\sum_i h(x,e_i)h(e_i,y)=h(x,Ny). \] Since \(h(e_i,e_j)=0\), one has \(N^2=0\). To see that the image is all of \(W\), observe that a relation \(\sum_i a_i h(e_i,x)=0\) for all \(x\) gives \(h(\sum_i\sigma(a_i)e_i,x)=0\), hence all \(a_i=0\). Thus the coordinate functionals \(h(e_i,\cdot)\) are linearly independent. Their joint map has rank \(s\), so \(\im N=W\). For \(s=0\), take \(N=0\). \end{proof} For fixed \(n\), this theorem gives first-order sentences \[ \HSZ_s:\ \exists N\,\bigl(N=N^\dagger\wedge N^2=0\wedge\rank N=s\bigr). \] In \(T_n^{p,q}\), they hold precisely for \(s\leq\min(p,q)\). Thus the entire list of square-zero ranks records the Witt index. The proof applies in characteristic \(2\) as well, with the definition of \(w(h)\) used in Section~\ref{sec:structures}. \subsection{The spectral criterion} An operator has a complete orthogonal eigenbasis if there are a basis \(v_1,\ldots,v_n\) and scalars \(\lambda_1,\ldots,\lambda_n\) such that \[ Tv_i=\lambda_i v_i,\qquad h(v_i,v_j)=0\quad(i\neq j). \] For fixed \(n\), this is a first-order predicate \(\operatorname{COEB}(T)\). \begin{theorem}\label{thm:individual-spectral} In a model of \(\Tinv\), a self-adjoint operator \(T\) has a complete orthogonal eigenbasis if and only if it is diagonalizable and all its eigenvalues belong to \(R=\Fix(\sigma)\). \end{theorem} \begin{proof} For eigenvectors \(v,w\) with eigenvalues \(\lambda,\mu\), self-adjointness gives \[ \bigl(\sigma(\lambda)-\mu\bigr)h(v,w)=0. \] If an orthogonal eigenbasis exists, none of its vectors is isotropic, since its Gram matrix is diagonal and nondegenerate. Setting \(v=w\) therefore shows \(\lambda\in R\). Conversely, suppose that \(T\) is diagonalizable and all its eigenvalues are real. Distinct eigenspaces are orthogonal. Each eigenspace is nondegenerate, because a vector in its radical would be orthogonal to every eigenspace and hence to \(V\). Proposition~\ref{prop:inertia} provides an orthogonal basis in each eigenspace. Their union is the required basis. \end{proof} \begin{theorem}\label{thm:universal-spectral} Over an algebraically closed field with any involution, every self-adjoint operator on \((V,h)\) has a complete orthogonal eigenbasis if and only if \(h\) is anisotropic. In the nonidentity-involution case, this is equivalent to signature \((n,0)\) or \((0,n)\). \end{theorem} \begin{proof} If \(h\) is isotropic, Theorem~\ref{thm:general-witt} gives a nonzero self-adjoint square-zero operator. Such an operator is not diagonalizable. Assume \(h\) is anisotropic and let \(T=T^\dagger\). Algebraic closedness gives an eigenvector \(v\neq0\). The equality \[ \sigma(\lambda)h(v,v)=h(Tv,v)=h(v,Tv)=\lambda h(v,v) \] shows \(\sigma(\lambda)=\lambda\). The line \(Kv\) is nondegenerate, \(V=Kv\perp v^\perp\), and \(v^\perp\) is \(T\)-invariant. The restricted form is again nondegenerate and anisotropic. Induction on the dimension completes the proof. The last assertion follows from Proposition~\ref{prop:inertia}. \end{proof} For example, over an algebraically closed field of characteristic different from \(2\) with the identity involution, every nondegenerate symmetric form of dimension at least \(2\) is isotropic. In each of these dimensions a self-adjoint operator can therefore fail to have an orthogonal eigenbasis. \begin{example}\label{ex:nonreal-spectrum} Over \(K=R(u)\) with its nonidentity involution, consider the hyperbolic plane with Gram matrix \(\begin{psmallmatrix}0&1\\1&0\end{psmallmatrix}\). The matrix \(\begin{psmallmatrix}0&1\\0&0\end{psmallmatrix}\) is self-adjoint and square-zero. A different obstruction occurs with \[ H=\begin{pmatrix}1&0\\0&-1\end{pmatrix}, \qquad T=\begin{pmatrix}0&1\\-1&0\end{pmatrix}. \] Here \(T^\dagger=T\), \(T^2=-I\), and the eigenvalues are \(u,-u\). Their eigenvectors \((1,u),(1,-u)\) are isotropic and have mutual pairing \(2\). This operator is diagonalizable and has no orthogonal eigenbasis. \end{example} \begin{remark} By Lemma~\ref{lem:real-closed-field}, an algebraically closed field of positive characteristic admits no nonidentity involution. There is also a restriction inherent in Hermitian symmetry. Applying \(h(y,x)=\sigma(h(x,y))\) twice shows that \(\sigma^2\) fixes every value of \(h\). For \(v\ne0\), nondegeneracy makes the linear functional \(h(v,\cdot)\) surjective onto \(K\), so \(\sigma^2=\Id\) on all of \(K\). \end{remark} \section{Finite measurements over real closed fixed fields} \label{sec:measurements} Work in the positive definite theory \(T_n^{n,0}\), with fixed field \(R\). The transition probability between the rays of two nonzero vectors \(v,w\) is \begin{equation}\label{eq:transition-probability} \mathsf P([v],[w]) =\frac{h(v,w)h(w,v)}{h(v,v)h(w,w)}. \end{equation} The expression is independent of the representatives. Completing a square, \[ 0\leq h\left(w-v\frac{h(v,w)}{h(v,v)}, w-v\frac{h(v,w)}{h(v,v)}\right) =h(w,w)-\frac{h(w,v)h(v,w)}{h(v,v)}, \] shows \(0\leq\mathsf P\leq1\) in \(R\). Its graph is first-order, after clearing the nonzero denominator. The corresponding rank-one orthogonal projection is \[ \Pi_{[v]}x=v\,\frac{h(v,x)}{h(v,v)}. \] \subsection{States and effects} An operator \(A\) is positive semidefinite, written \(A\succeq0\), if \[ A=A^\dagger,\qquad \forall v\ \bigl(h(v,Av)=0\ \vee\ \Pos(h(v,Av))\bigr). \] A density operator satisfies \(\rho\succeq0\) and \(\tr\rho=1\). An effect satisfies \(0\preceq E\preceq I\). To define the trace of \(A\), quantify over a basis and require the scalar in question to be the sum of the diagonal entries of \(A\) in that basis. Invariance under change of basis gives a unique scalar. Fix a positive integer \(m\). An \(m\)-outcome measurement is a tuple \(E_1,\ldots,E_m\) with \begin{equation}\label{eq:povm} E_i\succeq0,\qquad \sum_{i=1}^m E_i=I. \end{equation} These are the finite-dimensional positive-operator-valued measurements (POVMs). For a density operator \(\rho\), the outcome probabilities are \[ \pi_i=\tr(\rho E_i). \] They lie in \(R_{\geq0}\) and sum to \(1\). To see nonnegativity, diagonalize \(\rho\) in an orthonormal basis. Its eigenvalues \(a_j\) are nonnegative, and \(\tr(\rho E_i)=\sum_j a_j h(e_j,E_i e_j)\geq0\). The normalization follows from \eqref{eq:povm}. Thus states, effects, measurements, and their finite probability relations are all definable in the same language. \subsection{The exact dilation dimension} For a positive definite space \(W\), a projective measurement is a tuple of self-adjoint projections \(P_1,\ldots,P_m\) satisfying \[ P_iP_j=0\ (i\neq j),\qquad \sum_iP_i=I_W. \] A dilation of \eqref{eq:povm} consists of an isometry \(J:V\to W\) and such a tuple with \[ E_i=J^\dagger P_iJ. \] Over \(\mathbb C\) this is the finite-dimensional Naimark construction \cite{BuschLahtiPellonpaaYlinen2016}. For the explicit minimal dilation of a qubit POVM, see \citet[Section~3]{PellonpaaDesignolleUola2023}. The rank formula extends to every real closed fixed field. \begin{theorem}\label{thm:naimark} Let \(K=R(u)\) for a real closed field \(R\), and let \(E_1,\ldots,E_m\) satisfy \eqref{eq:povm} on an \(n\)-dimensional positive definite space. Set \(r_i=\rank E_i\). The least possible dimension of a positive definite dilation space is \begin{equation}\label{eq:naimark-dimension} D_{\min}=\sum_{i=1}^m r_i. \end{equation} Such a dilation exists in every dimension \(d\geq D_{\min}\). \end{theorem} \begin{proof} The positive definite spectral theorem holds over \(K\) by Theorem~\ref{thm:universal-spectral}. Each \(E_i\) therefore has an orthonormal eigenbasis and nonnegative real eigenvalues. Every positive eigenvalue has a square root in \(R\). Consequently there is a surjective linear map \[ A_i:V\longrightarrow K^{r_i}, \qquad A_i^\dagger A_i=E_i. \] In an eigenbasis for \(E_i\), take the coordinates with positive eigenvalues and multiply each by the positive square root of its eigenvalue. When \(r_i=0\), the target is the zero space. Let \[ W=\bigoplus_{i=1}^m K^{r_i}, \qquad Jv=(A_1v,\ldots,A_mv). \] Since \(J^\dagger J=\sum_iE_i=I\), the map \(J\) is an isometry. Let \(P_i\) be the coordinate projection onto the \(i\)-th summand. Then \(J^\dagger P_iJ=A_i^\dagger A_i=E_i\). Conversely, let \(J:V\to W\) and \(P_i\) be any dilation. Set \(A_i=P_iJ\). Positivity of the inner product on \(W\) implies \[ \ker(A_i^\dagger A_i)=\ker A_i, \] because \(h(v,A_i^\dagger A_iv)=h(A_iv,A_iv)\). Thus \(\dim(P_iJ(V))=\rank A_i=\rank E_i=r_i\). The subspaces \(P_iJ(V)\) are mutually orthogonal, so \(\dim W\geq\sum_i r_i\). This proves minimality. To obtain a larger dimension, adjoin an orthogonal summand to \(W\), extend \(J\) by zero into that summand, and assign the new summand to one projection. \end{proof} \begin{example}\label{ex:three-dimensional-dilation} On \(K^2\), let \[ E_1=\diag(1,9/25),\qquad E_2=\diag(0,16/25). \] Their ranks are \(2\) and \(1\). A minimal dilation on \(K^3\) is \[ J=\begin{pmatrix}1&0\\0&3/5\\0&4/5\end{pmatrix}, \qquad P_1=\diag(1,1,0),\qquad P_2=\diag(0,0,1). \] The equalities \(J^\dagger J=I_2\) and \(J^\dagger P_iJ=E_i\) hold over every real closed fixed field. Theorem~\ref{thm:naimark} shows that dimension \(3\) is necessary. \end{example} \begin{corollary}[Finite-measurement transfer]\label{cor:measurement-transfer} Fix the system dimension \(n\), the number \(m\) of outcomes, and the dilation dimension \(d\). A parameter-free first-order sentence about rays and their transition probabilities, density operators, \(m\)-outcome POVMs, outcome probabilities, or dilations into dimension \(d\) has the same truth value over every \(R(u)\) as over \(\mathbb C\), with the preceding definitions and the standard positive definite forms. This truth value is decidable. \end{corollary} \begin{proof} All definitions on the \(n\)-dimensional space are formulas in \(\LQ\). Since \(d\) is fixed, the additional \(d\)-dimensional vectors and rectangular maps are encoded by fixed-length scalar tuples. Their Gram, isometry, and projection conditions are polynomial equalities together with the definable order conditions. Theorem~\ref{thm:coordinate-reduction} reduces the resulting sentence to a parameter-free sentence of \(\RCF\). Completeness and decidability of \(\RCF\), or equivalently Corollary~\ref{cor:unframed-hermitian-classification}, give the claim. \end{proof} For a particular measurement, the existence of a dilation of dimension \(d\) is the finite rank condition \(\sum_i\rank E_i\leq d\). For fixed \(n,m,d\), this condition is a finite disjunction over the rank tuples satisfying the bound. \appendix \section{Explicit formulas and finite calculations} \label{app:formulas} \subsection{Linear algebra without named bases} For a fixed nonnegative integer \(r\), membership in a finitely generated span is \[ x\in\Span(v_1,\ldots,v_r) \quad\Longleftrightarrow\quad \exists a_1\cdots a_r\ x=\sum_i a_iv_i. \] Linear dependence is \[ \exists a_1\cdots a_r \left(\bigvee_i a_i\neq0\ \wedge\ \sum_i a_iv_i=0\right), \] and independence is its negation. An \(n\)-tuple is a basis if and only if its Gram matrix for the nondegenerate ambient form \(h\) is invertible. The determinant is a fixed polynomial, so this gives a quantifier-free basis predicate in \(\LQ\). Alternatively, the dual-basis criterion of Section~\ref{sec:structures} gives an existential formula. For an operator \(A\), rank \(r>0\) is specified by independent image vectors \(Au_1,\ldots,Au_r\) spanning every \(Av\). Rank zero is \(A=0_M\). Ranks can also be expressed relative to an existentially chosen basis by the vanishing of all \((r+1)\)-minors and the nonvanishing of some \(r\)-minor. Nilpotence is \(A^n=0_M\), since the dimension is \(n\). Self-adjointness is the relation \[ \forall x\,\forall y\ h(Ax,y)=h(x,Ay). \] Equivalently, one can choose a basis \(e_1,\ldots,e_n\) and check \[ h(Ae_i,e_j)=h(e_i,Ae_j)\qquad(1\leq i,j\leq n). \] Sesquilinearity extends these finitely many identities to all vectors. Consequently each nilpotent orbit formula in \eqref{eq:nilpotent-orbit-formula} has an existential version. For every power form, existentially choose its diagonalizing basis and use the Gram determinant for the basis condition. On one of these bases impose the displayed self-adjointness identities. The condition \(A^n=0_M\) is already atomic. \subsection{Quotient forms on representatives} For a definable subspace \(C\leq V\), the cosets \([v_1],\ldots,[v_s]\) are linearly independent in \(V/C\) when \[ \forall a_1\cdots a_s\ \left(\sum_i a_iv_i\in C\ \longrightarrow\ \bigwedge_i a_i=0\right). \] They span the quotient when \[ \forall v\ \exists a_1\cdots a_s\ \left(v-\sum_i a_iv_i\in C\right). \] A form on \(V/C\) can therefore be specified and diagonalized by formulas on representatives, provided it vanishes whenever either argument lies in \(C\). No additional quotient sort is necessary. In Section~\ref{sec:pairs}, \(C=\ker N_1=\ker N_2\). The positive Gram identity \(h(f_i,N_1f_j)=\delta_{ij}\) already gives independence, and the known quotient dimension gives spanning. \subsection{Reproducible finite calculations} Table~\ref{tab:branch-counts} lists the counts through dimension \(8\). The program \texttt{anc/verify\_inertia.py} enumerates all \(3{,}131\) signed partitions in dimensions \(1\) through \(12\). For each signed block it computes the inertias of its power forms by exact rational congruence elimination. It sums these inertias over each partition and checks that \eqref{eq:inertia-inversion} recovers the original multiplicities. A separate calculation extracts coefficients of \eqref{eq:branch-generating-function} and agrees with the enumeration at every signature in this range. The script also checks the matrix examples, including the pencil at selected rational parameters and the three-dimensional dilation. Run it with Python~3 to regenerate the table and the counts by signature. \begin{table}[htbp] \centering \begin{tabular}{rll} \toprule \(n\) & \(b_{p,n-p}\) for \(0\leq p\leq\lfloor n/2\rfloor\) & \(\sum_{p=0}^n b_{p,n-p}\) \\ \midrule 1 & 1 & 2 \\ 2 & 1, 3 & 5 \\ 3 & 1, 4 & 10 \\ 4 & 1, 4, 10 & 20 \\ 5 & 1, 4, 13 & 36 \\ 6 & 1, 4, 14, 27 & 65 \\ 7 & 1, 4, 14, 36 & 110 \\ 8 & 1, 4, 14, 39, 69 & 185 \\ \bottomrule \end{tabular} \caption{Numbers of complete theories with one named self-adjoint nilpotent operator. 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