\section{Common convex parts and exact resilience frontiers} \label{sec:power-frontier} The support argument does not depend on the distance functions themselves. What it uses is a common convex part and affine differences. This gives a more general analytical theorem and an exact two-parameter consequence for coverage design. \subsection{A support theorem for lattice selectors} Let $T$ be a finite union of nondegenerate $d$-simplices. Suppose $\psi$ is continuous and convex on every supplied simplex, and define \begin{equation}\label{eq:common-convex} f_i(x)=\psi(x)+a_i\cdot x+b_i,\qquad i\in[n]. \end{equation} For a monotone rule $w$ with $w(\varnothing)=0$ and $w([n])=1$, set \begin{equation}\label{eq:lattice-selector} L_w(f)(x)=\min_{\sigma:\,w(\sigma)=1}\max_{i\in\sigma}f_i(x). \end{equation} This is a lattice polynomial without added constant arguments. Its value is one of the input values at every point. It commutes with a common additive shift of all those values. These elementary properties follow directly from the finite minimum and maximum operations. Construct $Q_T(a,b)$ by including all target vertices and, on each $s$-dimensional simplex face, the unique solutions of $s$ independent equations \begin{equation}\label{eq:affine-ties} (a_{i_j}-a_{i_0})\cdot x+b_{i_j}-b_{i_0}=0, \qquad j=1,\ldots,s, \end{equation} that lie in that face. The set depends on the affine data and target, but not on $w$ or $\psi$. \begin{theorem}[Universal support for a common convex part]\label{thm:convex-support} For every family \cref{eq:common-convex} and every nonconstant monotone rule, \begin{equation}\label{eq:convex-support} \max_{x\in T}L_w(f)(x)=\max_{q\in Q_T(a,b)}L_w(f)(q). \end{equation} The same support set works simultaneously for every continuous common convex part $\psi$, every such rule and every level threshold. Its size satisfies \cref{eq:support-count}. If the target and affine data are rational, all support points are rational. \end{theorem} \begin{proof} First suppose that $\psi$ is strictly convex on every nontrivial segment of every simplex. Let $x$ maximize $L_w(f)$ and lie in the relative interior of a target face $G$ of dimension $s$. If $s=0$, it is a supplied vertex. Otherwise let $J$ consist of the indices whose input value equals $L_w(f)(x)$, and let $I$ contain those with strictly smaller value. The prefix argument gives $w(I)=0$ and $w(I\cup J)=1$. If the affine differences in \cref{eq:affine-ties} for indices in $J$ do not span the dual tangent space of $G$, choose a nonzero tangent direction $v$ annihilated by them. Along a sufficiently short segment $x+uv$, the values for all indices in $J$ remain equal. By continuity, the smaller and larger input groups remain separated from this tied group. The selected value along that segment is therefore \[ \psi(x+uv)+a_{i_0}\cdot(x+uv)+b_{i_0}. \] It is strictly convex as a function of $u$. Its value at the middle of two distinct points is strictly smaller than their average, so at least one nearby endpoint has a greater value. Both endpoints remain in $G$, contradicting maximality. Thus $s$ independent differences occur, and $x$ is the unique solution of one of the listed systems. For merely convex $\psi$, replace it by $\psi_\varepsilon(x)=\psi(x)+\varepsilon\|x\|^2$, with $\varepsilon>0$. The affine differences and hence $Q_T(a,b)$ do not change. Common-shift commutation gives \[ L_w(f_1+\varepsilon\|x\|^2,\ldots,f_n+\varepsilon\|x\|^2) =L_w(f)(x)+\varepsilon\|x\|^2. \] The strictly convex case applies. Since $T$ is compact, these functions converge uniformly to $L_w(f)$ as $\varepsilon\downarrow0$. Their maxima on $T$ and on its finite support set converge to the respective maxima, proving \cref{eq:convex-support}. The count and rationality follow by enumerating the faces and index sets, then solving rational linear systems exactly. No differentiability of $\psi$ is required. \end{proof} \begin{remark}[The convexity boundary] The common-convex-part hypothesis is substantive. With one input $f_1(x)=-x^2$ on $[-1,1]$, the support construction contains only the endpoints, while the maximum is attained at zero. No statement for arbitrary shared nonconvex parts follows from \cref{thm:convex-support}.\footnote{Strict convexity is used only inside the proof. Adding a common positive quadratic term and taking a uniform limit removes that extra assumption without changing any tie equations.} \end{remark} The theorem identifies a finite set of places at which any one of a large family of spatial logical requirements can be hardest to meet. \subsection{Power-controlled unequal footprints} Fix rational site weights $\omega_i$ and define \begin{equation}\label{eq:power} p_i(x)=\|x-c_i\|^2-\omega_i. \end{equation} At a common power parameter $t\in\R$, contact $i$ is active when $p_i(x)\le t$. Its footprint is a disk of squared radius $t+\omega_i$ when this is nonnegative and is empty otherwise. A zero squared radius gives a point. The footprints may therefore have unequal radii. \Cref{eq:power} has common convex part $\|x\|^2$, affine coefficient $-2c_i$ and constant $\|c_i\|^2-\omega_i$. Its tie hyperplanes are the standard radical or power bisectors~\cite{aurenhammer}. The underlying power-diagram geometry is established; the theorem here uses all required support systems for simultaneous monotone-rule certification.\footnote{An additive change in squared radius is a different parameter model from an additive change in radius. The rational threshold conclusion below is for the former.} \begin{corollary}[Exact unequal-footprint power threshold]\label{cor:power-threshold} Let $Q_T^\omega$ be the support set from these power functions. For every nonconstant monotone rule $w$, the least real power parameter giving full target coverage is \begin{equation}\label{eq:power-threshold} t_w^*=\max_{q\in Q_T^\omega}\min_{\sigma:\,w(\sigma)=1}\max_{i\in\sigma}p_i(q). \end{equation} This value is rational for rational input data. If the parameter is constrained to $t\ge t_0$, the least feasible value is $\max\{t_0,t_w^*\}$. A maximizing support point fails for every $t