% % \subsection{Constants of Section~\ref{sec:3} and Subsections~\ref{ssec:4.1} and~\ref{ssec:4.3}}\label{S:B1} We group the constants by the main-text statement in which they appear. \paragraph{Definition~\ref{def:3.1}: the scales.}\label{S:B1.scales} The screening mass satisfies $m_D/2\le\tilde m\le2m_D$, so that $\log(1/\tilde m)=\pi^2v_{\rm Cb}(0)\,\tau+O(\log\tau)$ with $\pi^2v_{\rm Cb}(0)=2.49435508\ldots$, and $\tilde m^{-1}$ is the Debye length. The scales are fixed at item~11 of the ordered list in Section~\ref{ssec:D.1}. Since $c_L\le1/308$, \eqref{eq:3.Hell} follows from $\ell\ge\tilde m^{-1}/r_0\ge L_c/c_L$. Of the conditions $L_c\ge4$ and $c_L\tilde m^{-1}\ge4r_0$ of Section~\ref{ssec:D.5}(e), the first implies $c_g':=c_g(1+1/L_c)^{-2}\ge\frac9{16}c_g$, and by the second, $L>c_L\tilde m^{-1}-2r_0\ge c_L\tilde m^{-1}/2$, that is, $\tilde mL\ge c_L/2$. \paragraph{Definition~\ref{def:3.4}: windows.} A window is the union of the blocks at block distance at most $75$ from a block. It therefore has at most $151$ blocks per direction, each of coarse side at most $2L_c-1$, and its sides are at most $151(2L_c-1)<302L_c384\vartheta L_c^3=3\cdot128\vartheta L_c^3$ since $384\vartheta=0.01152$. \item \emph{Thin sets.} $2\varepsilon_{\rm th}+12\vartheta=0.01636\le0.0164\le\frac14$, and $2/\sqrt{0.0164}=15.62\ge15.6>14$. Non-giant components are thin since $128\vartheta=0.00384<\varepsilon_{\rm th}$. \item \emph{Seal.} Lemma~\ref{lem:4.11}(b) with $\mathrm{supp}\le6(m_Q+m_{Q'})$ and $\eta_w=1/10$ gives $120(m_Q+m_{Q'})$ lines, plus $m_Q+m_{Q'}$ lines with a mark, in total $121$ per unit of $m_Q+m_{Q'}$, and $C_{\rm seal}=6\cdot121=726$. \item \emph{Interfaces.} $1+121+12=134$ non-good lines per unit of $m_Q+m_{Q'}<\vartheta L_c^2$, so $\good(I)\ge(1-134\vartheta)|F'|=0.99598|F'|\ge c_g|F'|$. \item \emph{Expansion.} For two large sides, $\varepsilon_{\rm th}-127.2\vartheta=0.004184\ge\varepsilon_{\rm th}/2$, so $\mathrm{cut}\ge\varepsilon_{\rm th}L_c^2/25.6=3.125\cdot10^{-4}L_c^2$. For adjacent in/out blocks, $\mathrm{cut}\ge(1-158\vartheta-2\varepsilon_{\rm th})L_c^2/3=0.32642L_c^2$. Both are at least $3.1\cdot10^{-4}L_c^2$, and $|A|