\section{Normalized central configurations and curves of them}\label{sec:setup} \subsection{The system of Albouy and Kaloshin} Let $m=(m_1,\dots,m_5)$. Following \cite[p.~540]{AK12}, a \emph{normalized central configuration} is a solution $(x,y,\delta)\in\C^5\times\C^5\times\C^{10}$ of \begin{equation}\label{eq:AK4} x_k=\sum_{l\ne k}m_l\,\delta_{kl}^{3}(x_k-x_l),\quad y_k=\sum_{l\ne k}m_l\,\delta_{kl}^{3}(y_k-y_l),\quad \delta_{kl}^{2}\big((x_k-x_l)^2+(y_k-y_l)^2\big)=1,\quad y_1=y_2, \end{equation} for $k\ne l$ in $\{1,\dots,5\}$, with $\delta_{kl}=\delta_{lk}$. It is \emph{real} if $x,y\in\R^5$, and \emph{positive} if moreover all $\delta_{kl}$ are positive. Summing the first equation multiplied by $m_k$ shows that solutions have their centre of mass at the origin. The multiplier $\lambda$ of \eqref{eq:cc} is normalized to $1$. \begin{lemma}\label{lem:realpos} Let $m\in(\R_{>0})^5$. Every central configuration with masses $m$ is similar, by an orientation-preserving similarity, to exactly two positive normalized central configurations, which differ by the rotation by $\pi$. In particular, if \eqref{eq:AK4} has finitely many solutions, there are finitely many central configurations up to similarity. \end{lemma} \begin{proof} Taking the scalar product of \eqref{eq:cc} with $m_i(q_i-c)$ and summing gives $\lambda I=U$ with $I=\sum_im_i|q_i-c|^2>0$ and $U=\sum_{i0$. So $\lambda>0$. We translate $c$ to the origin, scale by $\lambda^{1/3}$, and rotate so that $q_1-q_2$ is horizontal. Exactly two rotations do this. Conversely, the translation and the scale of a positive normalized central configuration are fixed by \eqref{eq:AK4}. \end{proof} We put $z=x+iy$, $w=x-iy$ and $r_{kl}=\delta_{kl}^{-1}$, so that $r_{kl}^2=z_{kl}w_{kl}$ with $z_{kl}=z_k-z_l$. For real configurations $w=\bar z$. For complex ones $z$ and $w$ are independent. \subsection{Centred coordinates and the slice}\label{ss:slice} For $h\in\C^5$ and $p=(p_{kl})_{k0$ the map $(u,v,p)\mapsto(t^{1/3}u,t^{1/3}v,t^{-1/3}p)$ is an isomorphism $X_m\to X_{tm}$ that preserves $\{u_{12}=v_{12}\}$, and its composition with the rotation by $s=t^{-1/3}$, $(u,v,p)\mapsto(u,t^{2/3}v,t^{-1/3}p)$, is an isomorphism $Y_m\to Y_{tm}$. Relabelling the bodies together with their masses, followed by a translation and a rotation, is an isomorphism $Y_m\to Y_{m'}$ for the permuted masses $m'$. In particular finiteness of $Y_m$ is invariant under positive scaling and permutation of the masses. \item A configuration satisfies \eqref{eq:cc} for the masses $m$ with multiplier $\lambda$ if and only if it satisfies \eqref{eq:cc} for $tm$ with multiplier $t\lambda$, and relabelling the bodies together with their masses maps the central configurations for $m$ to those for the permuted masses. Both bijections preserve similarity and orientation. Hence the number of central configurations up to similarity, and up to orientation-preserving similarity, is invariant under positive scaling and permutation of the masses. \end{enumerate} \end{lemma} \begin{proof} (a) The rows $D_{kl}$ are invariant and $Z_k$, $W_k$ are multiplied by $s$, $s^{-1}$. The action is free because $u_1\ne0$ on $X_m$. The inverse of the map is $x\mapsto(u_1,u_1^{-1}\cdot x)$. The point $s\cdot x$ lies in $\{u_{12}=v_{12}\}$ if and only if $s^2=v_{12}/u_{12}$. (b) The rows for $tm$ at the image point are multiples of the rows for $m$. For a relabelling, we translate the new body $5$ to the origin and rotate to restore $u_1=1$. (c) Multiplying the masses by $t$ multiplies the right side of \eqref{eq:cc} by $t^2$ and the left side by $t$ for fixed $\lambda$. Relabelling permutes the equations. \end{proof} For $\{i,j,k,l,n\}=\{1,\dots,5\}$ the \emph{4-product} of \cite[p.~580]{AK12} is $\cP_{ij}=r_{ij}^2r_{kl}^2r_{ln}^2r_{nk}^2$. \subsection{The potential form of the rows}\label{ss:potential} Let \[ U=\sum_{k0})^5$, $U=I>0$ at the point of $Y_m$ given by a real central configuration. \end{enumerate} \end{lemma} \begin{proof} (a) In the coordinates $z,w$ of \eqref{eq:AK4} the centre of mass is at the origin and $I=\sum_km_kz_kw_k$. We multiply the equation for $z_k$ by $m_kw_k$ and sum over $k$. By antisymmetry and $p_{kl}^2z_{kl}w_{kl}=1$, $\sum_km_kz_kw_k=\sum_{k0})^5$. If $Y_m$ contains no irreducible curve on which some $r_{kl}^2$ is non-constant and $U$ is not identically zero, then the planar five-body problem with masses $m$ has finitely many central configurations up to similarity. \end{corollary} \begin{proof} Infinitely many central configurations give infinitely many points of $Y_m$ with $U>0$ (Lemmas~\ref{lem:realpos}, \ref{lem:slice} and \ref{lem:U}(c)), hence an irreducible curve $C\subseteq Y_m$ on which $U$ is a positive constant. The fibres of $(u,v,p)\mapsto(r_{kl}^2)_{k0})^5$ \emph{settled} if $Y_m$ contains no irreducible curve on which some $r_{kl}^2$ is non-constant and $U\not\equiv0$. We call such a curve \emph{nontrivial}. A settled mass vector has finitely many central configurations up to similarity. The isomorphisms of Lemma~\ref{lem:slice}(b) multiply the $r_{kl}^2$ and $U$ by nonzero constants or permute them. Thus settledness is invariant under positive scaling and permutation of the masses. \subsection{Places and balancing}\label{ss:balancing} Let $C\subseteq Y_m$ be a nontrivial curve. The functions $u_k$, $v_k$, $u_{kl}$, $v_{kl}$, $p_{kl}$, $r_{kl}^2$ and $\cP_{ij}$ are units of the coordinate ring $\C[C]$: for instance $1/p_{kl}=p_{kl}u_{kl}v_{kl}$. A non-constant unit has a zero and a pole on the smooth projective model $\bar C$ of $C$. All of them lie at the finitely many \emph{places at infinity}, the points of $\bar C$ not over $C$. For a place $P$ at infinity with valuation $\val_P$ put \[ \rho(P)=\big(-\val_P(p_{kl})\big)_{k