\section{Vertex-first cut geometry} \label{sec:vertex-geometry} At a shared endpoint, composition requires one marked cut ball and one set of collars for both incident edges. We therefore construct the complete vertex rows and their cut balls before choosing any edge map. The same vertex collars will later coordinate the local and spectator extensions. Throughout this section the protected input \(\cT\) is fixed, but no edge representative is chosen. Every object is constructed once for each \(v\in V\), directly from the row in \eqref{tab:five-active-disk-rows}. Every incident edge uses this same vertex datum. \subsection{Complete rows and relative ball identifications} For \(v\in V\), cut the active sector along its three displayed row disks: \begin{equation} K_v =U_{ijk}\mathbin{\backslash\!\backslash} (D_i^v\cup D_j^v\cup D_k^v). \label{eq:vertex-cut-ball} \end{equation} \begin{figure}[htbp] \centering \begin{tikzpicture}[ obj/.style={draw,rounded corners=5pt,minimum width=4.2cm,minimum height=2.05cm}, outputbox/.style={draw,rounded corners=5pt,minimum width=3.6cm,minimum height=1.55cm}, note/.style={draw,rounded corners=3pt,align=center,inner sep=4pt,text width=4.4cm}, arr/.style={-{Latex[length=2mm]},thick}, disk/.style={draw,thick} ] \node[obj] (U) at (0,0) {}; \node[fill=white,inner sep=1pt] at ($(U.north)+(0,-.28)$) {\(U_{ijk}\)}; \draw[disk] (-1.05,-.30) -- (-1.05,.38); \draw[disk] (0,-.30) -- (0,.38); \draw[disk] (1.05,-.30) -- (1.05,.38); \node[font=\scriptsize] at (-1.05,-.62) {\(D_i^v\)}; \node[font=\scriptsize] at (0,-.62) {\(D_j^v\)}; \node[font=\scriptsize] at (1.05,-.62) {\(D_k^v\)}; \node[outputbox] (K) at (6.5,0) {\(K_v\cong D^3\)}; \draw[arr] (U.east) -- (K.west); \node[align=center,font=\small] at (3.25,1.50) {cut along the complete\\three-disk row}; \node[note,below=8mm of K] (relative) {chosen relative ball identification:\\\(E\) and its full bicollar are fixed}; \draw[densely dashed] (K.south) -- (relative.north); \end{tikzpicture} \caption{The vertex-first cut-ball construction. Every edge incident to \(v\) uses this same complete row and the same relative ball identification. The drawing records the cutting operation and fixed bicollar only; the disk shapes are schematic.} \label{fig:cut-ball-marking} \end{figure} \Needspace{4\baselineskip} \begin{proposition}[Five complete vertex rows] \label{prop:five-complete-rows} The disks in each row of \eqref{tab:five-active-disk-rows} are embedded, pairwise disjoint, oriented, and product framed. The cut manifold \(K_v\) is an oriented smooth \(3\)-ball. Moreover, the ball identification may be chosen to fix the global interface disk \(E\) and its full bicollar. After adjoining the unchanged exterior row, each active triple therefore gives a complete global row \(\mathfrak C_v\). \end{proposition} \paragraph{Band separation and relative ball gluing.} The height and band separations first make the composite disks embedded and product framed. Cutting the central co-cores then reduces each row to the same three elementary handles, while the prescribed cancellation order keeps the terminal overlapping lobes distinct. Because every move misses the interface disk and its bicollar, the relative ball identifications glue to one complete global row. \begin{proof} The height separations \eqref{eq:height-separation}, band separations \eqref{eq:band-separation}, and disjoint smoothing boxes show directly that every band sum in \eqref{eq:four-descendant-disks} is embedded. The band orientations are the positive band-sum orientations, and the simultaneous quadrant rounding makes the product normals on disk pieces and bands agree. Thus each composite disk has one global product-normal collar. This proves embeddedness, disjointness, orientation, and framing without using homology. Let \begin{equation} C=\operatorname{Round}\bigl(\chi(Q\times[1-\tau,1])\bigr). \label{eq:central-three-ball} \end{equation} It is a ball, and \(U_{ijk}\) is obtained from it by attaching the three product \(1\)-handles. Cutting a handle along its middle co-core leaves two half-handles, each a ball attached to the current ball along a disk; absorbing the half-handle is a boundary-collar compression. The row \(v=0\) is therefore a complete co-core system. For the four composite rows, after the carrier co-core has been cut, each band lobe is boundary parallel in its supplied product box. Sliding it through the cleared half-handle retracts the composite disk to its root while preserving the entire normal germ. Applying this elementary cancellation in the exact orders printed in \cref{tab:five-cut-schedules} reduces every row to the three elementary co-cores. At the terminal vertex the \(k_\varepsilon\)-lobe of \(J\) is nearer and is removed first; only then may the \(k_{2\varepsilon}\)-lobe of \(I_\star\) pass through the cleared region. No simultaneous cancellation or disjoint corridor for those two lobes is assumed. All isotopies are supported in the supplied handle, band, and smoothing reserves, which miss \(E\), its bicollar, the old region, and the unused handles. This proves the relative ball assertion. Finally cut the frozen exterior disks first. The active remainder meets the exterior cut product only along \(E\), and the five relative identifications agree there. Replacing one \(K_v\) by another therefore does not alter the exterior cut product, proving completeness of the global row. \end{proof} \subsection{Direct dual longitudes} The dual curves must be constructed geometrically; their homology classes alone do not supply embedded product-framed representatives. \begin{lemma}[Direct dual-track update] \label{lem:direct-dual-update} Suppose a positive product-zero-framed slide replaces a moving disk \(D_a\) by \(D_a'=D_a\#D_b^+\) and fixes the carrier \(D_b\). If \(\lambda_a,\lambda_b\) are disjoint product-framed duals before the slide, then in a boundary-parallel track beside the meridian band one may take \begin{equation} \lambda_a'=\lambda_a,\qquad \lambda_b'=\lambda_b\natural(-\lambda_a)^+. \label{eq:direct-dual-update} \end{equation} After a product-germ-preserving bigon push, these are embedded disjoint duals for \(D_a',D_b\). \end{lemma} \begin{proof} Before the bigon push, \(D_a'\) meets \(\lambda_b'\) in two points. The carrier lobe \(D_b^+\) meets the \(\lambda_b\)-piece positively, while the \(D_a\)-piece meets \((-\lambda_a)^+\) negatively. Their joining arcs bound the plumbing rectangle, whose interior misses all four objects. Push the longitude side across this bigon while keeping the ambient normal coordinate fixed. The two intersections cancel; the positive diagonal intersections \(D_a'\cdot\lambda_a'=D_b\cdot\lambda_b'=1\) remain, and all spectator germs are unchanged. \end{proof} Choose the three joining rectangles in distinct reserved tracks and set \begin{equation} \begin{aligned} L_{ji}&=\ell_j\natural_{\alpha^\vee}(-\ell_i)^+,\\ K_{ki}&=\ell_k\natural_{\beta_{ki}^\vee}(-\ell_i)^+,\\ K_{kj}&=\ell_k\natural_{\beta_{kj}^\vee}(-\ell_j)^+. \end{aligned} \label{eq:three-direct-longitudes} \end{equation} Repeated application of \cref{lem:direct-dual-update}, still before any edge, gives \begin{equation} \begin{array}{c|ccc} v&\lambda_i^v&\lambda_j^v&\lambda_k^v\\ \hline 0&\ell_i&\ell_j&\ell_k\\ B&\ell_i&\ell_j&K_{kj}\\ A&\ell_i&L_{ji}&\ell_k\\ AC&\ell_i&L_{ji}&K_{ki}\\ \starv&\ell_i&L_{ji}&K_{kj}. \end{array} \label{tab:five-direct-dual-rows} \end{equation} The rectangles and their bigon boxes are disjoint, so the simultaneous rows are embedded and product framed. Put \(m_s^v:=\partial D_s^v\) on the outgoing boundary. More strongly, \begin{equation} m_s^v\mathbin{\cdot}\lambda_r^v=\delta_{sr},\qquad m_s^v\cap\lambda_r^v=\varnothing\quad(s\neq r), \label{eq:geometric-dual-intersections} \end{equation} where the diagonal intersection is one positive transverse point in the original handle chart. The identities \begin{equation} [L_{ji}]=[\ell_j]-[\ell_i],\quad [K_{ki}]=[\ell_k]-[\ell_i],\quad [K_{kj}]=[\ell_k]-[\ell_j] \label{eq:dual-homology-check} \end{equation} are checks on these already constructed curves, not substitutes for the track construction. After cutting, the diagonal intersection opens each \(\lambda_r^v\) into an oriented arc \begin{equation} c_{r,v}:D_{r,v}^-\longrightarrow D_{r,v}^+. \label{eq:cut-dual-ribbon-core} \end{equation} Its product neighborhood is the framed dual ribbon used in the cut-sphere marking. \subsection{The marked cut sphere} Let \(S=S^2_{Q0}\) denote the abstract sphere cellulated in \cref{app:cut-schedules}. It has seven core faces \begin{equation} E,\quad i^-,i^+,\quad j^-,j^+,\quad k^-,k^+, \label{eq:seven-cut-faces} \end{equation} three spoke--dual branches \(E\to r^-\to r^+\), one complementary \(24\)-gon \(Z_{\mathrm{mod}}\), and cell count \begin{equation} (V_{\mathrm{cell}},E_{\mathrm{cell}},F_{\mathrm{cell}}) =(48,84,38). \label{eq:q0-cell-census} \end{equation} \Needspace{4\baselineskip} \begin{proposition}[Five direct smooth realizations] \label{prop:five-sphere-realizations} For each \(v\in V\) there is an orientation-preserving diffeomorphism \begin{equation} b_v:S\overset{\cong}{\longrightarrow}\partial K_v \label{eq:five-boundary-realizations} \end{equation} which sends every indexed face, ribbon, spoke, detector, and attachment sector to its directly constructed counterpart on \(\partial K_v\). The five maps are chosen independently from the vertex rows and obey one common signed-face convention. \end{proposition} \paragraph{The fat-tree disk and its complementary disk.} The seven cut faces and three dual arcs first form a realized fat tree on each cut sphere. The prescribed spoke slots make its regular neighbourhood a disk, leaving one complementary disk; product charts identify the common ribbon data, and an endpoint-flat boundary interpolation extends that identification over the complement. The common detector and face convention are therefore part of the smooth realization, not consequences of the cell count. \begin{proof} On \(\partial K_v\), begin with the seven realized cut faces and the three disjoint dual arcs \eqref{eq:cut-dual-ribbon-core}. They form four forest components. Choose one spoke \(s_{r,v}:E\to D_{r,v}^-\) at a time, attaching on \(E\) in the cyclic slots \begin{equation} p_i=1,\qquad p_j=5,\qquad p_k=3. \label{eq:spoke-attachment-slots} \end{equation} Each spoke joins two distinct components in the connected complement, so no cycle is created. The resulting regular neighborhood of the connected fat tree is a disk; its complement in the sphere \(\partial K_v\) is a second disk \(Z_v\). Thickening the six tree edges gives the spoke and dual-ribbon rectangles. The supplied \(E\)-collar also carries one common detector with zero turning in both frame directions. Product-coordinate maps identify the regular neighborhood of the abstract fat tree with the realized one and agree on complete overlap strips. To extend over the complementary disk, choose polar charts in which the boundary germ has the form \begin{equation} (r,[\theta])\longmapsto(r,[f_v(\theta)]),\qquad f_v(\theta+1)=f_v(\theta)+1,\quad f_v'(\theta)>0. \label{eq:complementary-disk-boundary-germ} \end{equation} With \(f_{v,s}=(1-s)\operatorname{id}+sf_v\) and an endpoint-flat radial cutoff \(\eta\), use \begin{equation} (r,[\theta])\longmapsto \bigl(r,[f_{v,\eta(r)}(\theta)]\bigr). \label{eq:positive-polar-fill} \end{equation} It is the identity near the polar center, hence smooth there, and for \(r>0\) its angular derivative is \((1-\eta(r))+\eta(r)f_v'(\theta)>0\). It is therefore a positive disk diffeomorphism agreeing to all orders with the boundary map on a full annulus. Gluing gives \(b_v\). The explicit face list in \cref{app:cut-schedules} proves the full incidence statement; a cell count alone would not. \end{proof} For each \(r\), fix an orientation-reversing \(\jmath_r:D^2\to D^2\) and positive face charts \(\kappa_{r,v}^{\sigma,\partial}:D^2\to D_{r,v}^{\sigma}\) so that \begin{equation} \kappa_{r,v}^{+,\partial} =\gamma_{r,v}\kappa_{r,v}^{-,\partial}\jmath_r^{-1}, \label{eq:positive-face-chart} \end{equation} where \(\gamma_{r,v}\) is the canonical identification of the two cut copies. The surface pairings are \begin{equation} \begin{aligned} \pi_{r,v}^{-+,\partial} \kappa_{r,v}^{-,\partial}(z) &=\kappa_{r,v}^{+,\partial}(\jmath_rz),\\ \pi_{r,v}^{+-,\partial} &=(\pi_{r,v}^{-+,\partial})^{-1}. \end{aligned} \label{eq:surface-face-pairings} \end{equation} They are smooth orientation-reversing surface maps. They are not cellular: a negative face has four sectors and a positive face has two. The inherited two-sided face collars have a uniform positive width \(d_{\mathrm{inh}}\). In their local doubles define \begin{equation} \pi_{r,v}^{-+,\mathrm{full}} \bigl(\kappa_{r,v}^{-,\partial}(z),u\bigr) =\bigl(\kappa_{r,v}^{+,\partial}(\jmath_rz),u\bigr), \qquad |u|0\), it extends to a global inward collar \[ c:\partial M\times[0,b)\longrightarrow M \] which equals \(c^{\mathrm{loc}}\) literally on \(O_0\times[0,b)\). \end{lemma} \begin{proof} Push \(\partial_u\) forward by \(c^{\mathrm{loc}}\) to a field \(X_{\mathrm{loc}}\). Choose \(O_0\Subset O_{1/2}\Subset O_1\), a smaller depth \(a_00\). Let \(d_{\mathrm{germ}}>0\) be the minimum positive depth on which the local collars agree literally with the finitely many inherited germs, decreased if necessary to lie below their common inherited depth. After restricting the inherited full-normal face collars to one common positive depth, denote that source-backed pairing depth by \(\eps_{\mathrm{pair}}^{\mathrm{src}}>0\). Choose, before every edge, \begin{equation} \begin{gathered} 00,\qquad z_v(x,t)=c_v(b_v\zeta_{\mathrm{mod}}(x),t), \quad (x,t)\in D^2\times[0,u_0]. \label{eq:vertex-only-disk-collar} \end{equation} No later edge-dependent shrink changes \(u_0\), \(z_v\), or its domain. At \(t=0\), the definitions give the correctly typed boundary identity \begin{equation} \boxed{p_v\rho_vz_v(x,0)=\bar z_v(x).} \label{eq:corrected-vertex-boundary-crosswalk} \end{equation} The factor \(\rho_v\) cannot be omitted: \(z_v(x,0)\) lies on the cut sphere, whereas \(p_v\) is defined after regluing. Collect the cellulation, pairings, collars, and quotient data into \(\cQ_v\). These choices give one common set of endpoint data for the later edge constructions. \begin{proposition}[Simultaneous pre-edge vertex package] \label{prop:simultaneous-vertex-package} For the fixed tuple \(\cT\), there is one simultaneous choice \begin{equation} \left( \mathfrak C_v,K_v,\cQ_v,q_v^P,q_v,q_v^{(3)}, \rho_v^{(3)},\rho_v,p_v,\bar z_v, z_v:D^2\times[0,u_0]\to K_v \right)_{v\in V} \label{eq:constructed-vertex-package} \end{equation} with one common \(u_0>0\). Every component is fixed before all edge footprints, endpoint atlases, and edge representatives. \end{proposition} The parameterizations in this simultaneous construction identify the supplied exterior data with one common abstract background marking \(\mathfrak C_{\mathrm{bg}}\) on \(Y\). It contains exactly the old, unused-handle, and global-\(E\) data induced by \(\mathfrak C_{\mathrm{ext}}\), and no varying active vertex row. This is the relative structure used when the two outgoing routes are compared in \cref{sec:rigidity-pentagon}. \subsection{The frozen exterior splitting} The vertex construction also fixes, independently of all edges, \begin{equation} \iota_{\mathrm{old}}:H_1(X;\Q)\hookrightarrow H_1(Y;\Q),\quad H_{\mathrm{old}}=\im\iota_{\mathrm{old}},\quad \lambda_g^Y=\iota_{\mathrm{old}}(\lambda_g). \label{eq:old-homology-inclusion} \end{equation} For \(\mathcal I_{\mathrm{unused}} =\{1,\ldots,N\}\setminus\{i,j,k\}\), put \begin{equation} \begin{aligned} H_{\mathrm{ext}} &=H_{\mathrm{old}}\oplus \bigoplus_{t\in\mathcal I_{\mathrm{unused}}} \bigl(\Q[m_t]\oplus\Q[\ell_t]\bigr),\\ I_{\mathrm{ext}}&=\id_{H_{\mathrm{ext}}},\\ \Lambda_{\mathrm{ext}} &=\lambda_g^Y\oplus \bigoplus_{t\in\mathcal I_{\mathrm{unused}}}\Q[m_t]. \end{aligned} \label{eq:frozen-exterior-splitting} \end{equation} Writing \(m_r,\lambda_r\) for the \(p_0\)-images of the active framed row, set \begin{equation} U=\Span_{\Q}\{[m_i],[m_j],[m_k]\},\qquad U^\vee=\Span_{\Q}\{[\lambda_i],[\lambda_j],[\lambda_k]\}. \label{eq:active-homology-summands} \end{equation} Then \begin{equation} H_1(Y;\Q)=H_{\mathrm{ext}}\oplus(U\oplus U^\vee), \qquad \Lambda=\Lambda_{\mathrm{ext}}\oplus U. \label{eq:pre-edge-homology-splitting} \end{equation} When \(N=3\), the unused sums in \eqref{eq:frozen-exterior-splitting} are empty, and \(\dim\Lambda=g+3=g+N\). The later edge actions are compared in this fixed homology splitting; preservation of \(\Lambda\) is proved in \cref{sec:homology}.