\chapter{The interpolation and the defect}\label{sec:fnd} In this section, we recall the interpolation of \cite[Section~2]{AL}, which compares the fractional moments of the partition function with the constrained scalar Parisi problem. We also fix the normalizations, the tilted law, and the observables that we use in the rest of the paper. The later sections build on two results. The first is the defect identity \eqref{eq:in-envelope} of \cref{cor:fnd-defect}. It states that four times the fractional-moment error $e_{N,\beta}(\lambda)$ is the integral over the interpolation of a defect $\calD_N(\rho)=\beta(A+2J+V)$, whose three terms are overlap observables at a minimizing profile. The second is \cref{prop:fnd-mean-bias}, where we show that $(P_\beta-p_{N,\beta})/\beta$ is at most $2e_{N,\beta}(\lambda)$ plus a term of order $\lambda^5$. Along the way, we record the martingale and contact identities in \cref{prop:fnd-contact}, the integrated variance bound in \cref{prop:fnd-variance}, the decomposition of the overlap error in \cref{lem:fnd-decomp}, the interpolation identity in \cref{prop:fnd-interpolation}, and the trial budget in \cref{lem:fnd-trial}. Most of these facts are proved in \cite{AL}. We state each of them in full, with its location in \cite{AL}. Where the argument is short, we also sketch the proof, so that this section can be read without \cite{AL} at hand. Besides \cite{AL}, this section uses only the scalar Parisi functional \eqref{eq:intro-parisi} and the notation of \cref{sec:intro-background}, together with the support theorem \cite[Theorem~1.1]{Lopatto}. Its results are used throughout the paper. \Cref{prop:fnd-contact,prop:fnd-variance,lem:fnd-decomp} are used in \cref{sec:wi,sec:th,sec:c7,sec:c7-closure}; the energy normalization and the trial budget in \cref{sec:lz,sec:lz-root,sec:sc}; and \eqref{eq:in-envelope}, \eqref{eq:fnd-moving}, and \cref{prop:fnd-mean-bias} in \cref{sec:c7-closure,sec:b7}. We treat the laws with anisotropic fields in \cref{sec:gauss}, where we also prove the two Gaussian tools that we need for profiles that do not minimize the functional. Throughout this section, we fix $\beta>1$ and $N\ge1$, and we assume no relation between the tilt $\lambda$ and $N$. The completion, the interpolating functional, and the identities of \cref{subsec:fnd-law,sec:fnd-contact,sec:fnd-variance,sec:fnd-defect} hold for every $\beta>0$. We use the hypothesis $\beta>1$ for the support of the Parisi measure in \cref{sec:fnd-completion} and for the cost of the scalar floor in \cref{sec:fnd-trial}. The interpolation of \cite[Section~2]{AL} is a quantitative form of the Guerra interpolation that Talagrand used for the positive fractional moments of the partition function, whose limits he determined in \cite{Talagrand2007FractionalMoments}; see \cite[Section~1.2]{AL}. For fixed $00$, the normalized logarithmic moment of the completed partition function is \cite[(1.3)]{AL} \[ \phi^c_{N,\beta}(s) =\frac1{Ns}\log\E_{\rm ref}e^{sF^c_{N,\beta}} =\frac1{Ns}\log\E_{\rm ref}e^{sF_{N,\beta}}+\frac{\beta^2s}{4N}, \] where we used $\log\E_{\rm ref}e^{s\beta D_N}=\beta^2s^2/4$. As $s\downarrow0$, we have $\phi^c_{N,\beta}(s)\to p_{N,\beta}$, since $F_{N,\beta}$ has exponential moments of every order. Recall the scalar Parisi functional $\mathcal P_\beta$ of \eqref{eq:intro-parisi}, which we evaluate at the distribution function of a probability measure on $[0,1]$. For $0\le s\le1$ and $0\le\lambda\le\beta$, we define \[ P_\beta(s)=\min_{\mu\in\mathcal P([0,1]):\,\mu(\{0\})\ge s} \mathcal P_\beta\bigl(\mu([0,\cdot\,])\bigr), \qquad E_\beta(\lambda)=\beta^{-1}P_\beta(\lambda/\beta). \] The minimum is attained \cite[Section~1.1]{AL}, and $P_\beta(0)=P_\beta$. The function $E_\beta$ is the constrained value in the energy normalization of \cite[Section~7.1]{AL}, in which the order $s$ of the moment is replaced by the tilt $\lambda=\beta s$. Note that $E_\beta$ is nondecreasing, because the admissible class shrinks as $s$ grows; in particular, $E_\beta(\lambda)\ge E_\beta(0)$. The unconstrained minimizer $\mu_\beta$ is unique \cite{AuffingerChen2015Uniqueness}. We write $\alpha_\beta(q)=\mu_\beta([0,q])$ and $\gamma_\beta=\beta\alpha_\beta$. Since $\beta>1$, we have $\supp\mu_\beta=[0,q_\beta]$ with $00$. An \emph{admissible profile} is a deterministic probability measure $\mu=s\delta_0+\nu$ on $[0,1]$, where $\nu\ge0$ has mass $1-s$ and may charge $0$. Equivalently, $\mu$ is a deterministic probability measure such that $\mu(\{0\})\ge s$. We call $s\delta_0$ the prescribed root mass and $\nu$ the free measure of $\mu$. We write $a(q)=\mu([0,q])$ for the cumulative function. It is nondecreasing and right-continuous, with $a\ge s$ and $a(1)=1$. Conditional on $W$, let $U=U_{\mu,t}$ solve \begin{equation}\label{eq:fnd-vector-pde} \partial_qU=-\frac c2\bigl(\Delta U+a(q)|\nabla U|^2\bigr), \qquad U(1,x;W)=\log\sum_{\sigma\in\{-1,1\}^N} e^{\beta\sqrt t\,\sigma^TW\sigma/2+x\cdot\sigma}. \end{equation} This is the Parisi equation in $\R^N$; its terminal value is the logarithm of the completed partition function at inverse temperature $\beta\sqrt t$ in the external field $x$. We define the interpolating functional and its minimum over admissible profiles by \begin{equation}\label{eq:fnd-functional} \mathcal F_{t,s}(\mu) =\frac1{Ns}\log\E_{\rm ref}e^{sU(0,0;W)} -\frac c2\int_0^1qa(q)\dd q, \qquad f_{N,s}(t)=\min_{\mu}\mathcal F_{t,s}(\mu). \end{equation} By \cite[Section~2.6 and Proposition~2.3]{AL}, the equation \eqref{eq:fnd-vector-pde} has a solution for every admissible profile, and $\mathcal F_{t,s}$ is continuous under weak convergence of profiles. For a step profile, the solution is given by the Hopf--Cole recursion that we recall in \cref{subsec:fnd-law}. For a general profile, it is the uniform limit of the solutions for step profiles whose cumulative functions converge in $L^1([0,1])$. Indeed, if $U_a$ and $U_{\tilde a}$ are the solutions for the cumulative functions $a$ and $\tilde a$, then \cite[Section~2.6, (2.19)]{AL} \[ \sup_{q,x,W}\bigl|U_a(q,x;W)-U_{\tilde a}(q,x;W)\bigr| \le\frac{cN}2\int_0^1|a(u)-\tilde a(u)|\dd u . \] The admissible profiles form a weakly compact set, since they are the image of the compact set of measures of mass $1-s$ under $\nu\mapsto s\delta_0+\nu$, and weak convergence of profiles implies $L^1$ convergence of their cumulative functions. We conclude that the minimum in \eqref{eq:fnd-functional} is attained. We note that minimizers are deterministic. The Gaussian expectation is taken inside the functional, which means that $\mathcal F_{t,s}(\mu)$ is a number for each profile. A minimizer may depend on $N$, $\rho$, and $\lambda$ but not on the couplings. This matters below, because the tilted law of \cref{subsec:fnd-law} is constructed from a deterministic profile, and the estimates at a minimizer combine that law with the variational inequality that the same profile satisfies. A minimizer need not be unique; at each use, we say which minimizer is meant. The prescribed root mass $s\delta_0$ matches the order $s$ of the moment. In the derivative of the interpolation, which we compute in \cref{prop:fnd-interpolation}, the outer logarithmic moment contributes a term that cancels the root mass exactly, so that only the free measure $\nu$ remains. In the posterior densities of \cref{sec:gauss}, the outer tilt cancels it in the same way. The two endpoints of the interpolation are explicit. At $t=0$, the terminal value in \eqref{eq:fnd-vector-pde} is $\sum_i\log(2\cosh x_i)$ and $c=\beta^2$. Then the equation separates into $N$ copies of the scalar Parisi equation of \eqref{eq:intro-parisi}, and we have $U(q,x;W)=\sum_iu_a(q,x_i)$, where $u_a$ is the solution of that equation with $\alpha=a$. This shows that $U(0,0;W)=Nu_a(0,0)$ is deterministic and that $\mathcal F_{0,s}(\mu)=\mathcal P_\beta(a)$. At $t=1$, we have $c=0$, which implies that $U(0,0;W)=U(1,0;W)=F^c_{N,\beta}$ and that $\mathcal F_{1,s}(\mu)=\phi^c_{N,\beta}(s)$ for every profile. Minimizing over admissible profiles, we obtain \cite[Proposition~2.3]{AL} \begin{equation}\label{eq:fnd-endpoints} f_{N,s}(0)=P_\beta(s),\qquad f_{N,s}(1)=\phi^c_{N,\beta}(s). \end{equation} For a fixed profile, the map $t\mapsto\mathcal F_{t,s}(\mu)$ is nonincreasing (\cref{prop:fnd-interpolation}). By \eqref{eq:fnd-error-definition}, the fractional-moment error is $(f_{N,s}(0)-f_{N,s}(1))/\beta$, which is the decrease of $f_{N,s}/\beta$ along the interpolation. The defect of \cref{sec:fnd-defect} is four times the rate of this decrease. \paragraph{The energy normalization.} We vary profiles in the energy normalization of \cite[Section~7.1]{AL}. For an admissible profile $\mu$ with cumulative function $a$, we set \[ \gamma=\beta a,\qquad \nu_\gamma=\beta\nu,\qquad F_\rho(\gamma)=\beta^{-1}\mathcal F_{1-\rho,\lambda/\beta}(\mu). \] Then $\dd\gamma$ is a measure of mass $\beta$ with $\dd\gamma\ge\lambda\delta_0$; we also call $\gamma$ admissible. We have $\min_\gamma F_\rho(\gamma)=\beta^{-1}f_{N,s}(1-\rho)$, where the minimum is over admissible $\gamma$. The name refers to the following rescaling of the spatial variable. The function $\widetilde U(q,y;W)=\beta^{-1}U(q,\beta y;W)$ solves \[ \partial_q\widetilde U =-\frac\rho2\bigl(\Delta\widetilde U+\gamma(q)|\nabla\widetilde U|^2\bigr), \] with terminal value $\beta^{-1}$ times the logarithm of the completed partition function in the field $\beta y$, and we have \[ F_\rho(\gamma)=\frac1{N\lambda}\log\E_{\rm ref} e^{\lambda\widetilde U(0,0;W)} -\frac\rho2\int_0^1q\gamma(q)\dd q . \] This is the functional of \cite[(7.2)]{AL} with $r=\rho$, in which the diagonal of $W$ has been integrated out explicitly \cite[Section~7.1]{AL}. Note that the rescaling leaves the gradient unchanged, $\nabla\widetilde U(q,y;W)=\nabla U(q,\beta y;W)$, and that it multiplies the Hessian by $\beta$. We define the \emph{scalar trial profile} by $\gamma^{\rm tr}_\lambda(q)=\max\{\lambda,\gamma_\beta(q)\}$. It is nondecreasing and right-continuous, and it satisfies $\lambda\le\gamma^{\rm tr}_\lambda\le\beta$ and $\gamma^{\rm tr}_\lambda(1)=\beta$. In other words, $\gamma^{\rm tr}_\lambda/\beta$ is the cumulative function of an admissible profile. When $\lambda$ is fixed, we write $\gamma^{\rm tr}=\gamma^{\rm tr}_\lambda$. We discuss its cost and its use as a comparison profile in \cref{sec:fnd-trial}. \section{The tilted joint law and overlap observables} \label{subsec:fnd-law} Fix $0<\rho\le1$ and an admissible profile $\mu$. We recall the joint law of \cite[Section~2]{AL}, under which all later expectations are taken. It is built in three stages. \begin{enumerate}[label=(\roman*)] \item The Gaussian law of $W$ is tilted by the density $e^{sU(0,0;W)}/\E_{\rm ref}e^{sU(0,0;W)}$. \item Given $W$, the auxiliary field solves \begin{equation}\label{eq:fnd-diffusion} \dd X_q=ca(q)\nabla U(q,X_q;W)\dd q+\sqrt c\dd B_q, \qquad X_0=0, \end{equation} where $B$ is a standard Brownian motion in $\R^N$ under the conditional law given $W$. \item Given $W$ and the path $X$, a terminal spin $\sigma\in\{-1,1\}^N$ is drawn with probabilities proportional to $\exp\{\beta\sqrt t\,\sigma^TW\sigma/2+X_1\cdot\sigma\}$. \end{enumerate} We write $\Pp$ and $\E$ for this joint law, and $\calG_q=\sigma(W,X_r:0\le r\le q)$ for the information revealed up to level $q$; note that it does not contain the terminal spin. At fixed $N$, the drift in \eqref{eq:fnd-diffusion} is bounded and Lipschitz in $x$ \cite[Section~2.6.1]{AL}, and the equation has a unique strong solution. The tilt in (i) changes the law of $W$, which is no longer Gaussian under $\Pp$, but it does not change the conditional law of $B$ given $W$. For a step profile, the law has a discrete description, which explains the construction. The Gaussian Hopf--Cole recursion in the Parisi setting is described in \cite[Section~3, (10)--(13)]{Guerra2003}, and the finite-dimensional tilted law used here is the formulation of \cite[Section~2.1]{AL}. Suppose that the profile has grid points $0=q_0\min_{[0,1]}G$ is relatively open in $[0,1]$ and $\nu$-null, and we conclude that $\supp\nu$ is contained in the set of minimum points of $G$. By Step 1, $G$ is twice continuously differentiable, with \[ G'(q)=q-\E S_q,\qquad G''(q)=1-\frac cN\E\Tr H_q^2 . \] If $q\in\supp\nu\cap(0,1)$, then $q$ is an interior minimum point of $G$, and therefore $G'(q)=0$ and $G''(q)\ge0$. These are the last two relations in \eqref{eq:in-contact}. At $q=0$, we have $G'(0)=-\E S_0=0$, because $m_0=0$. If $0\in\supp\nu$, then $0$ is a minimum point of $G$, and $G''(0)\ge0$, since otherwise $G''<0$ near $0$ and $G(h)0$. At $q=1$, the terminal Gibbs measure gives positive probability to every spin configuration. Then $|m_{1,i}|<1$ for all $i$, and $G'(1)=1-\E S_1>0$, which implies that $G(1-h)0$ and that $1$ is not a minimum point of $G$. This proves $\supp\nu\subset[0,1)$ and \eqref{eq:in-contact}, which is \cite[(2.9)]{AL}. \paragraph{Step 4: general profiles.} Let $\mu$ be an arbitrary admissible profile. Following \cite[Section~2.6]{AL}, we approximate $\nu$ by its pushforwards $\nu_j$ onto finite meshes that contain $0$, $1$, and any prescribed finite set of levels, with mesh size tending to zero. These pushforwards are taken under the map that sends each point to the smallest mesh point greater than or equal to it. Let $\mu_j=s\delta_0+\nu_j$. Then $\mu_j\Rightarrow\mu$, the cumulative functions converge in $L^1([0,1])$, and they agree with $a$ at the mesh points. The spatial derivatives of fixed order are bounded uniformly over step profiles at fixed $N$. We apply the $L^1$ estimate recalled in \cref{sec:fnd-functional} to the solutions, and the same comparison argument to their differentiated equations. Using also the uniform bound on the derivatives and Gr\"onwall's inequality, we find that the solutions and their first and second spatial derivatives converge uniformly. We couple the laws for $\mu_j$ and $\mu$ through the same matrix $W$ under its Gaussian reference law and the same Brownian motion $B$. We also use the same uniform variable to sample the terminal spin. Since the drifts are bounded and Lipschitz, Gr\"onwall's inequality implies that $X$, $m$, and $H$ for $\mu_j$ converge to those for $\mu$ uniformly in $q$, in probability. The conditional second moments of the terminal spin, which solve linear backward equations with drift $ca\nabla U$, converge in the same way, and so does $C_q$. The ratios of the tilt densities for $\mu_j$ to the density for $\mu$ converge uniformly to one, since these ratios lie between $e^{-2sd_j}$ and $e^{2sd_j}$, where $d_j=(cN/2)\|a_j-a\|_{L^1}\to0$. Then the densities converge in $L^1$ of the Gaussian reference law. Since the conditional moments and spatial derivatives used here are bounded at fixed $N$, their convergence in probability, uniformly in the level, implies that they also converge in every finite $L^p$ norm needed below. Using these convergences, we pass \eqref{eq:in-martingale}, the formula for the derivative of $\E S_q$, its continuity in $q$, and \eqref{eq:fnd-first-variation} to the limit \cite[Section~2.6.2]{AL}. If $\mu$ is a minimizer, we apply the limiting first variation directly to $\mu$; the approximating step profiles need not be minimizers. Step 3 then applies to $\mu$ without change. \end{proof} \section{The integrated variance bound and the overlap error} \label{sec:fnd-variance} At a minimizer, we use the contact identities to turn the posterior variance bound of \cite[Proposition~2.2]{AL} into bounds that depend only on the cumulative function $a$. \begin{proposition}[Integrated variance and trace bounds] \label{prop:fnd-variance} Let $0<\rho\le1$, and let $\mu=s\delta_0+\nu$ minimize $\mathcal F_{t,s}$. For every deterministic $k\in L^2(\nu)$, \begin{equation}\label{eq:in-Lvar} \Var\left(\int k(q)L_q\,\nu(\dd q)\right) \le\frac1M\int\frac{k(q)^2}{a(q)}\,\nu(\dd q), \qquad A\le\frac1{Ms}. \end{equation} \end{proposition} The first bound is \cite[Proposition~2.2, (2.16)]{AL}, and the second is \cite[Section~2.5, (2.18)]{AL}. We briefly recall the argument. We fix the terminal spin and apply the Brascamp--Lieb inequality to the law of the independent Gaussian coordinates that generate $W$ and the field. For a fixed spin, this law is uniformly log-concave, although the marginal law of $W$ under $\Pp$ is not Gaussian. \begin{proof}[Proof of \cref{prop:fnd-variance}] We first show that, for every admissible profile and every deterministic $k\in L^2(\nu)$, \begin{equation}\label{eq:fnd-L-general} \Var\left(\int k(q)L_q\,\nu(\dd q)\right) \le\frac1{N^2}\int k(q)^2\,\E\Tr(H_qC_q)\,\nu(\dd q), \end{equation} which is \cite[(2.15)]{AL}. Let $\mu$ be a step profile. For $\varepsilon>0$, we start the field at $X_0=\sqrt\varepsilon z_0$, where $z_0$ is a standard Gaussian vector included in the outer tilt. We collect the independent standard Gaussian coordinates that generate $W$, $z_0$, and the field increments in one vector $Z$. With the terminal spin fixed, $Z$ has a density proportional to $e^{-\Phi_\sigma(Z)}$, and the Hessian of $\Phi_\sigma$ is $\mathcal Q=I+\int\mathcal A_q\,\nu(\dd q)\succeq I$, where $\mathcal A_q=\nabla_Z^2U(q,X_q;W)\succeq0$ \cite[(2.1)--(2.3)]{AL}. We derive this density for more general laws in the proof of \cref{lem:fnd-posterior}. We work in these Gaussian reference coordinates, in which, at the grid points $q_\ell$ of the profile, \[ X_{q_\ell}=\sqrt\varepsilon z_0 +\sum_{h=1}^{\ell}\sqrt{c(q_h-q_{h-1})}\,z_h ; \] the tilted law is obtained by reweighting these coordinates. In this representation, the field depends on $z_0$ only through the term $\sqrt\varepsilon z_0$, which gives $\nabla_{z_0}U(q,X_q;W)=\sqrt\varepsilon m_q$ and shows that the block of $\mathcal A_q$ for the coordinates of $z_0$ is $\varepsilon H_q$. Let $v_q$ be the vector whose $z_0$ block is $(\sigma-m_q)/\sqrt\varepsilon$ and whose other blocks vanish. Differentiating $L_q$ with the spin fixed, we find \[ \nabla_ZL_q=\frac1N\mathcal A_qv_q,\qquad v_q^T\mathcal A_qv_q=(\sigma-m_q)^TH_q(\sigma-m_q). \] For $Y_k=\int kL_q\,\dd\nu$ and $b=\int k(q)\mathcal A_qv_q\,\nu(\dd q)$, we have $\nabla_ZY_k=b/N$. For every vector $w$, using the Cauchy--Schwarz inequality for the forms $\mathcal A_q$ and for the integral against $\nu$, together with $\int\mathcal A_q\,\dd\nu=\mathcal Q-I\preceq\mathcal Q$, we have \[ |w^Tb|^2\le\Bigl(\int w^T\mathcal A_qw\,\nu(\dd q)\Bigr) \int k(q)^2v_q^T\mathcal A_qv_q\,\nu(\dd q) \le(w^T\mathcal Qw)\int k(q)^2v_q^T\mathcal A_qv_q\,\nu(\dd q). \] The choice $w=\mathcal Q^{-1}b$ yields $b^T\mathcal Q^{-1}b\le\int k^2v_q^T\mathcal A_qv_q\,\dd\nu$. Then the Brascamp--Lieb inequality \cite{BrascampLieb1976}, in the form \cite[Proposition~2.2, (2.14)]{AL}, implies that the conditional variance of $Y_k$ given $\sigma$ is at most $N^{-2}\E[b^T\mathcal Q^{-1}b\mid\sigma]$. By the spin-gauge symmetry of \cite[Section~2.1]{AL}, the conditional law of $Y_k$ given $\sigma$ does not depend on $\sigma$. Using the law of total variance, we obtain the same bound for $\Var(Y_k)$. Conditioning on $\calG_q$, we have $\E[(\sigma-m_q)^TH_q(\sigma-m_q)\mid\calG_q]=\Tr(H_qC_q)$. We remove the regularization by dominated convergence as $\varepsilon\downarrow0$, using $|L_q|\le3/2$, $\Tr(H_qC_q)\le N^2$, and the Gaussian domination of the outer tilt. The approximation of Step~4 in the proof of \cref{prop:fnd-contact} then extends \eqref{eq:fnd-L-general} to all profiles, first for continuous $k$ and then by density for $k\in L^2(\nu)$ \cite[Section~2.6.2]{AL}. Now suppose that $\mu$ is a minimizer. Using the fact that the trace of the product of two positive semidefinite matrices is nonnegative, together with $H_q-a(q)C_q\succeq0$, we have \[ \Tr H_q^2=\Tr\bigl(H_q(H_q-a(q)C_q)\bigr)+a(q)\Tr(H_qC_q) \ge a(q)\Tr(H_qC_q), \] and similarly \[ \Tr(H_qC_q)=\Tr\bigl((H_q-a(q)C_q)C_q\bigr)+a(q)\Tr C_q^2 \ge a(q)\Tr C_q^2 . \] By \eqref{eq:in-contact}, $\E\Tr H_q^2\le N/c$ at every contact level, and $\nu$ is carried by its support. Dividing by $a(q)\ge s>0$, we find that $\E\Tr(H_qC_q)\le N/(ca(q))$ and $\E\Tr C_q^2\le N/(ca(q)^2)$ for $\nu$-almost every $q$. Inserting the first bound into \eqref{eq:fnd-L-general} and using $M=Nc$, we obtain the first bound in \eqref{eq:in-Lvar}. For the second, the quantile function \eqref{eq:fnd-quantile} and $a(Q(v))\ge s+v$ give \[ A\le\frac1M\int\frac{\nu(\dd q)}{a(q)^2} =\frac1M\int_0^{1-s}\frac{\dd v}{a(Q(v))^2} \le\frac1M\int_0^{1-s}\frac{\dd v}{(s+v)^2} =\frac1M\Bigl(\frac1s-1\Bigr)\le\frac1{Ms}. \qedhere \] \end{proof} \begin{remark}\label{rem:fnd-partial-atoms} Since $k$ in \eqref{eq:in-Lvar} is arbitrary, the bound applies to sub-measures of $\nu$, such as the image of Lebesgue measure on an interval of quantiles that contains only part of an atom. If $h$ is a Borel function with $0\le h\le1$, then applying \eqref{eq:in-Lvar} with $kh$ in place of $k$ and using $h^2\le h$, we obtain \[ \Var\Bigl(\int k(q)h(q)L_q\,\nu(\dd q)\Bigr) \le\frac1M\int\frac{k(q)^2h(q)}{a(q)}\,\nu(\dd q). \] \end{remark} We now show that the overlap error splits into the three terms of the defect. \begin{lemma}[Decomposition of the overlap error]\label{lem:fnd-decomp} Let $0<\rho\le1$. For every admissible profile and every $q\in[0,1]$, we have $\Var(L_q)=j_q+\Var(S_q)/4$. If $q$ is a contact level of a minimizer, then \begin{equation}\label{eq:in-decomp} \E(R_q-q)^2=a_q^{\rm th}+2j_q+\Var(S_q). \end{equation} \end{lemma} \begin{proof} Both identities are displayed in \cite[Section~2.5]{AL} before (2.17). Let $\xi^1=\sigma^1-m_q$ and $\xi^2=\sigma^2-m_q$. Conditionally on $\calG_q$, these vectors are independent and centered, with covariance $C_q$, and \[ R_q=S_q+\frac1N\bigl(m_q\cdot\xi^1+m_q\cdot\xi^2+\xi^1\cdot\xi^2\bigr). \] The three terms in parentheses have conditional mean zero, they are pairwise orthogonal given $\calG_q$, and their conditional second moments are $m_q^TC_qm_q$, $m_q^TC_qm_q$, and $\Tr C_q^2$. Taking expectations, we find that for every admissible profile and every $q$, \begin{equation}\label{eq:fnd-RS} \E(R_q-S_q)^2=a_q^{\rm th}+2j_q . \end{equation} Since $\E[R_q-S_q\mid\calG_q]=0$, this implies that \[ \E(R_q-q)^2=a_q^{\rm th}+2j_q+\E(S_q-q)^2 =a_q^{\rm th}+2j_q+\Var(S_q)+(\E S_q-q)^2 . \] At a contact level of a minimizer, $\E S_q=q$ by \eqref{eq:in-contact}, which proves \eqref{eq:in-decomp}. Similarly, $L_q=S_q/2+N^{-1}(\sigma-m_q)\cdot m_q$, where the second term has conditional mean zero and conditional variance $N^{-2}m_q^TC_qm_q$ given $\calG_q$. By the law of total variance, we have $\Var(L_q)=j_q+\Var(S_q)/4$. \end{proof} \section{The optimized interpolation and the defect} \label{sec:fnd-defect} We next recall from \cite[Proposition~2.3]{AL} that the derivative of the interpolating functional in $t$ is an integral of squared overlap deviations. \begin{proposition}[Interpolation identity]\label{prop:fnd-interpolation} Let $N\ge1$ and $00$ and letting $h\downarrow0$, we find $f_{N,s}'(t)\le\partial_t\mathcal F_{t,s}(\mu)$; dividing by $h<0$ gives the reverse inequality. This is \cite[(2.20)]{AL}. \end{proof} In particular, $t\mapsto\mathcal F_{t,s}(\mu)$ and $f_{N,s}$ are nonincreasing. We define the \emph{defect} \[ \calD_N(\rho)=-\frac4\beta f_{N,s}'(1-\rho) \] at every $\rho\in(0,1)$ such that $f_{N,s}$ is differentiable at $1-\rho$. Since $f_{N,s}$ is Lipschitz, Rademacher's theorem implies that this holds for almost every $\rho$, and $\calD_N$ is a measurable function defined almost everywhere. All pointwise statements about $\calD_N$ are understood at these values of $\rho$. The defect depends on $N$, $\beta$, $\rho$, and $\lambda$, and not on a choice of minimizer. \begin{corollary}[The defect identity]\label{cor:fnd-defect} Let $N\ge1$ and $0<\lambda\le\beta/2$, and let $s=\lambda/\beta$. At every $\rho\in(0,1)$ at which $\calD_N(\rho)$ is defined, and for every minimizer $\mu$ of $\mathcal F_{1-\rho,s}$, \begin{equation}\label{eq:in-envelope} \calD_N(\rho)=\beta(A+2J+V),\qquad 4e_{N,\beta}(\lambda)=\int_0^1\calD_N(\rho)\dd\rho , \end{equation} where $A$, $J$, and $V$ are computed under the tilted law of $\mu$. In particular, $\calD_N\ge0$ and $e_{N,\beta}(\lambda)\ge0$. \end{corollary} \begin{proof} Let $\rho$ be as in the statement, and let $\mu$ be a minimizer at $t=1-\rho$. By \cref{prop:fnd-interpolation}(b) and \eqref{eq:fnd-fixed-derivative}, we have $\calD_N(\rho)=\beta\int\E(R_q-q)^2\,\nu(\dd q)$. Recall that the measure $\nu$ is carried by the contact levels of $\mu$, at which \eqref{eq:in-decomp} holds. Integrating \eqref{eq:in-decomp} against $\nu$, we obtain the first identity. For the second, since $f_{N,s}$ is Lipschitz, we have \[ \int_0^1\calD_N(\rho)\dd\rho=-\frac4\beta\int_0^1f_{N,s}'(t)\dd t =\frac4\beta\bigl(f_{N,s}(0)-f_{N,s}(1)\bigr) =\frac4\beta\bigl(P_\beta(s)-\phi^c_{N,\beta}(s)\bigr), \] where we used \eqref{eq:fnd-endpoints} in the last step. By \eqref{eq:fnd-error-definition}, the right side is $4e_{N,\beta}(\lambda)$; see also \cite[Proposition~2.3, (2.21)]{AL}. \end{proof} The individual terms $A$, $J$, and $V$ may depend on the choice of minimizer, but by \eqref{eq:in-envelope}, their combination $A+2J+V$ does not. In the later sections, we bound $A$, $J$, and $V$ at an arbitrary minimizer; such bounds then hold for $\calD_N(\rho)$ at almost every $\rho$. Near $\rho=0$, we use a cruder bound. For every $N\ge1$, $01$, there exist $\lambda_*>0$ and $C_*<\infty$, depending only on $\beta$, such that \[ \beta^{-1}\mathcal P_\beta(\gamma^{\rm tr}_\lambda/\beta) \le E_\beta(0)+C_*\lambda^5 \qquad(0<\lambda\le\lambda_*). \] We set $L_s=\max\{1,C_*\}$ and $\lambda_0=\min\{1,\lambda_*/2,\beta/4\}$. Recall that $E_\beta$ is nondecreasing, and note that the profile with cumulative function $\gamma^{\rm tr}_\lambda/\beta$ has mass at least $\lambda/\beta$ at zero. We obtain \begin{equation}\label{eq:fnd-scalar-trial-cost} 0\le E_\beta(\lambda)-E_\beta(0) \le\beta^{-1}\mathcal P_\beta(\gamma_\lambda^{\rm tr}/\beta) -E_\beta(0) \le L_s\lambda^5\qquad(0<\lambda\le2\lambda_0). \end{equation} The bound $\lambda_0\le\lambda_*/2$ allows us to use \eqref{eq:fnd-scalar-trial-cost} at $2\lambda$, and $\lambda_0\le\beta/4$ ensures that $2\lambda/\beta\le1/2$ for $\lambda\le\lambda_0$, so that the results above apply with $s=2\lambda/\beta$. The bound $\lambda_0\le1$ is used in \cref{sec:lz,sec:b7}. \begin{lemma}[Trial budget]\label{lem:fnd-trial} For every $N\ge1$, $0<\rho\le1$, and $0<\lambda\le\lambda_0$, \begin{equation}\label{eq:fnd-trial} 0\le F_\rho(\gamma_\lambda^{\rm tr})-\min_\gamma F_\rho(\gamma) \le e_{N,\beta}(\lambda)+L_s\lambda^5 . \end{equation} \end{lemma} \begin{proof} The lower bound holds because $\gamma^{\rm tr}_\lambda$ is admissible. Let $\mu^{\rm tr}$ be the admissible profile with cumulative function $\gamma^{\rm tr}_\lambda/\beta$. By \cref{prop:fnd-interpolation}(a), the map $t\mapsto\mathcal F_{t,s}(\mu^{\rm tr})$ is nonincreasing, and $\mathcal F_{0,s}(\mu^{\rm tr})=\mathcal P_\beta(\gamma^{\rm tr}_\lambda/\beta)$ by \cref{sec:fnd-functional}. Hence $F_\rho(\gamma^{\rm tr}_\lambda)\le \beta^{-1}\mathcal P_\beta(\gamma^{\rm tr}_\lambda/\beta)$. Recall that the optimized value $f_{N,s}$ is also nonincreasing. Using \eqref{eq:fnd-endpoints} and \eqref{eq:fnd-error-definition}, we find \[ \min_\gamma F_\rho(\gamma)=\beta^{-1}f_{N,s}(1-\rho) \ge\beta^{-1}f_{N,s}(1)=\beta^{-1}\phi^c_{N,\beta}(s) =E_\beta(\lambda)-e_{N,\beta}(\lambda). \] Subtracting the two bounds, we obtain \[ F_\rho(\gamma^{\rm tr}_\lambda)-\min_\gamma F_\rho(\gamma) \le e_{N,\beta}(\lambda) +\beta^{-1}\mathcal P_\beta(\gamma^{\rm tr}_\lambda/\beta)-E_\beta(\lambda) \le e_{N,\beta}(\lambda)+L_s\lambda^5, \] where in the last step we used \eqref{eq:fnd-scalar-trial-cost} and $E_\beta(\lambda)\ge E_\beta(0)$. This is \cite[Proposition~7.7, (7.44)]{AL}. \end{proof} We call a number $\eta\ge0$ that bounds the left side of \eqref{eq:fnd-trial} a \emph{trial budget}. By \cref{lem:fnd-trial}, $\eta=e_{N,\beta}(\lambda)+L_s\lambda^5$ is a trial budget simultaneously for every $\rho\in(0,1]$ and every minimizer. In \cref{sec:lz,sec:lz-root}, we use the trial budget to control the distance between a minimizer and the scalar trial profile, and in \cref{sec:b7}, it determines the cutoff between the two regimes of the proof. \section{Reduction of the mean bias}\label{sec:fnd-mean-bias} We now reduce the mean bias to the fractional-moment error by the midpoint argument of Step~1 in the proof of \cite[Theorem~7.8]{AL}. We define \[ \psi(\lambda)=\frac1{N\lambda} \log\E_{\rm ref}e^{\lambda(F_{N,\beta}/\beta+D_N)}\quad(\lambda>0), \qquad\psi(0)=\frac{p_{N,\beta}}\beta , \] so that $\psi(\lambda)=E_\beta(\lambda)-e_{N,\beta}(\lambda)$ for $0<\lambda<\beta$, by \eqref{eq:fnd-error-definition}. As a function of the $N(N+1)/2$ independent standard Gaussian coordinates $(g_{ij},z_i)$, the completed free energy $F^c_{N,\beta}/\beta$ is convex, because it is $\beta^{-1}$ times the logarithm of a sum of exponentials of linear functions. Its partial derivatives are $N^{-1/2}\langle\sigma_i\sigma_j\rangle$ in $g_{ij}$, where $\langle\cdot\rangle$ is the Gibbs average of $F^c_{N,\beta}$, and $(2N)^{-1/2}$ in $z_i$. We find that the squared norm of its gradient is at most \[ \frac1N\cdot\frac{N(N-1)}2+N\cdot\frac1{2N}=\frac N2, \] and the function is $\sqrt{N/2}$-Lipschitz. By \cite[Lemma~5.2]{AL}, which is a special case of Chen's convexity theorem \cite[Theorem~1]{ChenConvexity}, the function $\lambda\mapsto\lambda^{-1}\log\E_{\rm ref}e^{\lambda F^c_{N,\beta}/\beta}=N\psi(\lambda)$ extends to a convex function on $[0,\infty)$ whose value at zero is $\E_{\rm ref}F^c_{N,\beta}/\beta=N\psi(0)$, where we used $\E_{\rm ref}D_N=0$. In particular, $\psi$ is convex on $[0,\infty)$. \begin{proposition}[Mean bias]\label{prop:fnd-mean-bias} For every $N\ge1$ and $0<\lambda\le\lambda_0$, \begin{equation}\label{eq:fnd-mean-bias} 0\le\frac{P_\beta-p_{N,\beta}}\beta \le E_\beta(0)-2E_\beta(\lambda)+E_\beta(2\lambda) +2e_{N,\beta}(\lambda) \le 32L_s\lambda^5+2e_{N,\beta}(\lambda). \end{equation} \end{proposition} \begin{proof} The lower bound is \cite[Theorem~1.1, (1.5)]{AL}; it is also Guerra's bound \cite{Guerra2003}. Since $\psi$ is convex on $[0,\infty)$, we have $\psi(\lambda)\le(\psi(0)+\psi(2\lambda))/2$, that is, $\psi(0)\ge2\psi(\lambda)-\psi(2\lambda)$. Recall that $\psi(\lambda)=E_\beta(\lambda)-e_{N,\beta}(\lambda)$. Since $\lambda\le\lambda_0\le\beta/4$, we have $2\lambda/\beta\le1/2$. Then \cref{cor:fnd-defect} applies at the tilt $2\lambda$ and implies that $e_{N,\beta}(2\lambda)\ge0$, that is, $\psi(2\lambda)\le E_\beta(2\lambda)$. Using $E_\beta(0)=P_\beta/\beta$, we obtain \[ \frac{P_\beta-p_{N,\beta}}\beta=E_\beta(0)-\psi(0) \le E_\beta(0)-2E_\beta(\lambda)+2e_{N,\beta}(\lambda)+E_\beta(2\lambda), \] which is the middle inequality in \eqref{eq:fnd-mean-bias}. For the last inequality, we use $E_\beta(\lambda)\ge E_\beta(0)$ and \eqref{eq:fnd-scalar-trial-cost} at $2\lambda\le2\lambda_0$: \[ E_\beta(0)-2E_\beta(\lambda)+E_\beta(2\lambda) \le E_\beta(2\lambda)-E_\beta(0)\le L_s(2\lambda)^5=32L_s\lambda^5 . \qedhere \] \end{proof} In \cref{sec:b7}, we take $\lambda=N^{-7/50}$, so that $\lambda^5=N^{-7/10}$. \Cref{prop:fnd-mean-bias} then reduces \cref{thm:main} to the bound $e_{N,\beta}(N^{-7/50})\le C_\beta N^{-7/10}$ for all sufficiently large $N$.