\documentclass{amsart} % options include 12pt or 11pt or 10pt % classes include article, report, book, letter, thesis \usepackage{setspace} \usepackage{a4} \usepackage{amsthm} \usepackage{latexsym} \usepackage{amsfonts} \usepackage{graphicx} \usepackage{textcomp} \usepackage{cite} \usepackage{enumerate} \usepackage{amssymb} \usepackage{hyperref} \usepackage{amsmath} \usepackage{tikz} \usepackage[mathscr]{euscript} \usepackage{mathtools} \newtheorem{theorem}{Theorem}[section] \newtheorem{acknowledgement}[theorem]{Acknowledgement} \newtheorem{conjecture}[theorem]{Conjecture} \newtheorem{corollary}[theorem] {Corollary} \newtheorem{definition}[theorem]{Definition} \newtheorem{example}[theorem]{Example} \newtheorem{lemma} [theorem]{Lemma} \newtheorem{notation}[theorem]{Notation} \newtheorem{observation}[theorem]{Observation} \newtheorem{problem}[theorem]{Problem} \newtheorem{proposition}[theorem]{Proposition} \newtheorem{remark}[theorem]{Remark} \newtheorem{question}[theorem]{Question} \setlength{\parindent}{0pt} \setlength{\evensidemargin}{0.3cm} \setlength{\oddsidemargin}{0.3cm} \setlength{\topmargin}{-1cm} \textwidth 16cm \textheight 23cm \onehalfspacing \title{This is the title} \newcommand{\Cross}{\mathbin{\tikz [x=1.4ex,y=1.4ex,line width=.2ex] \draw (0,0) -- (1,1) (0,1) -- (1,0);}}% \raggedbottom \newcommand{\abs}[1]{\lvert#1\rvert} \newcommand{\blankbox}[2]{% \parbox{\columnwidth}{\centering \setlength{\fboxsep}{0pt}% \fbox{\raisebox{0pt}[#2]{\hspace{#1}}}% }% } \usepackage{fancyhdr} %\pagestyle{fancy} \pagestyle{fancy} %\thispagestyle{empty} \fancyhead[LO]{\textbf{NONCOMMUTATIVE BUZANO-DRAGOMIR INEQUALITY AND APPLICATIONS}} \fancyhead[RE]{\textbf{K. MAHESH KRISHNA}} \begin{document} \vspace{0.9cm} \hrule\hrule\hrule\hrule\hrule \vspace{0.3cm} \begin{center} {\bf{Noncommutative Buzano-Dragomir Inequality and Applications}}\\ \vspace{0.3cm} \hrule\hrule\hrule \vspace{0.3cm} \textbf{K. Mahesh Krishna}\\ School of Mathematics and Natural Sciences\\ Chanakya University Global Campus\\ NH-648, Haraluru Village\\ Devanahalli Taluk, Bengaluru North District\\ Karnataka State 562 110 India \\ Email: kmaheshak@gmail.com\\ Date: \today \hrule\hrule \end{center} \vspace{0.5cm} %-------------------------------------- \textbf{Abstract}: Dragomir [\textit{Bull. Aust. Math. Soc., 2016}] showed that the Buzano inequality holds for orthogonal projections on Hilbert spaces. Dragomir [\textit{Linear Multilinear Algebra, 2016}] also derived the most general form of the Buzano inequality for bounded linear operators on Hilbert spaces. We show that Dragomir result extends to adjointable morphisms on Hilbert C*-modules. Using this generalization, we derive bounds for the roots of polynomials over commutative unital C*-algebras. We formulate the notion of noncommutative numerical range and derive numerical radius bounds for self-adjoint morphisms on Hilbert C*-modules over unital C*-algebras. We formulate several open problems, including the noncommutative Toeplitz-Hausdorff, von Neumann inequality, Ando inequality, Berger power dilation, Kittaneh inequality, Crouzeix problems. \textbf{Keywords}: Buzano Inequality, Numerical radius, Polynomial roots, Hilbert C*-modules, Crouzeix inequality. \textbf{Mathematics Subject Classification (2020)}: 47A12, 46L08.\\ \hrule \tableofcontents \hrule \section{Introduction} More than half-century ago, Buzano derived the following generalization of the \textit{Cauchy-Schwarz inequality} \cite{BUZANO}. \begin{theorem} \cite{FUJII, BUZANO, STEELE} \label{BT} (\textbf{Buzano Inequality}) Let $\mathcal{H}$ be a complex Hilbert space (with the inner product linear in the first variable and conjugate linear in the second variable). Then \begin{align}\label{BI} |\langle \tau, h\rangle \langle h, \omega\rangle |\leq \frac{\|h\|^2(|\langle \tau, \omega \rangle|+\|\tau\|\|\omega\|)}{2}\leq \|h\|^2\|\tau\|\|\omega\|, \quad \forall h, \tau, \omega \in \mathcal{H}. \end{align} In other words, \begin{align*} \left|\left\langle \tau, \frac{h}{\|h\|}\right\rangle \left \langle \frac{h}{\|h\|}, \omega \right\rangle\right|\leq \frac{|\langle \tau, \omega \rangle|+\|\tau\|\|\omega\|}{2}\leq \|\tau\|\|\omega\|, \quad \forall \tau, \omega \in \mathcal{H}, \forall h \in \mathcal{H}\setminus \{0\}. \end{align*} Further, we have following. \begin{enumerate}[\upshape(i)] \item Let $\tau, \omega \in \mathcal{H}\setminus\{0\}$ be such that $\langle \tau, \omega \rangle =0$. Choose $\alpha, \beta \in \mathbb{C}$ with $|\beta|=1$. Define \begin{align*} h_{\alpha, \beta}\coloneqq \alpha \left(\frac{\tau}{\|\tau\|}+\beta\frac{\omega}{\|\omega\|}\right). \end{align*} Then \begin{align*} |\langle \tau, h_{\alpha, \beta}\rangle \langle h_{\alpha, \beta}, \omega\rangle |= \frac{\| h_{\alpha, \beta}\|^2(|\langle \tau, \omega \rangle|+\|\tau\|\|\omega\|)}{2}. \end{align*} \item Let $\tau, \omega \in \mathcal{H}\setminus\{0\}$ be such that $\langle \tau, \omega \rangle \neq 0$. For $\alpha \in \mathbb{C}$, define \begin{align*} h_{\alpha}\coloneqq \alpha \left(\frac{\tau}{\|\tau\|}+\frac{\langle \tau, \omega \rangle}{|\langle \tau, \omega \rangle |}\frac{\omega}{\|\omega\|}\right). \end{align*} Then \begin{align*} |\langle \tau, h_{\alpha}\rangle \langle h_{\alpha}, \omega\rangle |= \frac{\| h_{\alpha}\|^2(|\langle \tau, \omega \rangle|+\|\tau\|\|\omega\|)}{2}. \end{align*} \end{enumerate} \end{theorem} Ten years ago, Dragomir made the following far reaching generalization of Theorem \ref{BT} \cite{DRAGOMIR2}. \begin{theorem} \cite{DRAGOMIR2} \label{DT} (\textbf{Buzano-Dragomir Inequality}) Let $\mathcal{H}$ be a complex Hilbert space and $P:\mathcal{H}\to \mathcal{H}$ be an orthogonal projection. Then \begin{align}\label{DI} |\langle P\tau, \omega\rangle |\leq \frac{|\langle \tau, \omega \rangle|+\|\tau\|\|\omega\|}{2}, \quad \forall \tau, \omega \in \mathcal{H}. \end{align} \end{theorem} Now note that for any nonzero $h\in \mathcal{H}$, the map \begin{align*} \mathcal{H} \ni \tau \mapsto \left\langle \tau, \frac{h}{\|h\|} \right \rangle \frac{h}{\|h\|} \in \mathcal{H} \end{align*} is a rank one orthogonal projection. Thus Inequality (\ref{DI}) recovers Inequality (\ref{BI}). Inequality (\ref{BI}) has various applications, we describe few. Recall that \cite{GUSTAFSONRAO, HALMOS, HORNJOHNSON, GAUWUBOOK, STONEBOOK} the \textbf{numerical range} of a bounded linear operator $T:\mathcal{H} \to \mathcal{H} $ is defined as \begin{align*} W_\mathbb{C}(T)\coloneqq \{\langle Th, h\rangle: h \in \mathcal{H}, \|h\|=1\} \end{align*} and the \textbf{numerical radius} of $T$ is defined as \begin{align*} w_\mathbb{C}(T)\coloneqq \sup_{h \in \mathcal{H}, \|h\|=1}|\langle Th, h\rangle|. \end{align*} For $ \tau, \omega \in \mathcal{H}$, define the rank one operator \begin{align*} \tau \otimes \omega : \mathcal{H} \ni h \mapsto (\tau \otimes \omega)h \coloneqq \langle h, \omega \rangle \tau \in \mathcal{H}. \end{align*} In 1993, Fujii and Kubo derived following result, using Inequality (\ref{BI}) \cite{FUJII}. \begin{theorem} \cite{FUJII} \label{FKR} Let $\mathcal{H}$ be a complex Hilbert space and $ \tau, \omega \in \mathcal{H}$. Then \begin{align*} w_\mathbb{C}(\tau \otimes \omega)=\frac{|\langle \tau, \omega \rangle|+\|\tau\|\|\omega\|}{2}. \end{align*} \end{theorem} Let $p(z)\coloneqq a_0+a_1z+\cdots +a_{n-1}z^{n-1}+z^n \in \mathbb{C}[z]$. A direct observation reveals that the zeros of $p$ are the eigenvalues of the \textbf{Frobenius companion matrix} \begin{align*} C_p\coloneqq \begin{pmatrix} -a_{n-1}&-a_{n-2}&-a_{n-3}&\cdots &-a_2 &-a_1&-a_0\\ 1&0&0&\cdots &0 &0&0\\ 0&1&0&\cdots &0 &0&0\\ \vdots &\vdots &\vdots & & \vdots &\vdots &\vdots\\ 0&0&0&\cdots &0 &0&0\\ 0&0&0&\cdots &1 &0&0\\ 0&0&0&\cdots &0 &1&0\\ \end{pmatrix} \in \mathbb{M}_n(\mathbb{C}) \end{align*} and the eigenvalues of $C_p$ are the same as the zeros of $p$. Let $R$ be the right shift matrix defined by \begin{align*} R\coloneqq \begin{pmatrix} 0&0&0&\cdots &0 &0&0\\ 1&0&0&\cdots &0 &0&0\\ 0&1&0&\cdots &0 &0&0\\ \vdots &\vdots &\vdots & & \vdots &\vdots &\vdots\\ 0&0&0&\cdots &0 &0&0\\ 0&0&0&\cdots &1 &0&0\\ 0&0&0&\cdots &0 &1&0\\ \end{pmatrix} \in \mathbb{M}_n(\mathbb{C}). \end{align*} Define \begin{align*} {\bf{a}}\coloneqq \begin{pmatrix} \overline{a_{n-1}}\\ \overline{a_{n-2}}\\ \overline{a_{n-3}}\\ \vdots \\ \overline{a_{2}}\\ \overline{a_{1}}\\ \overline{a_{0}}\\ \end{pmatrix}, \quad {\bf{e_1}} \coloneqq \begin{pmatrix} 1\\ 0\\ 0\\ \vdots \\ 0\\ 0\\ 0\\ \end{pmatrix}. \end{align*} Then \begin{align}\label{FK} C_p=R- {\bf{e_1}}\otimes {\bf{a}}. \end{align} Fujii and Kubo derived following bound for the zeros of $p$ using Inequality \ref{BI} and the representation (\ref{FK}) \cite{FUJII}. \begin{theorem} \cite{FUJII} \label{FKT} (\textbf{Fujii-Kubo polynomial root upper bound}) Let $p(z)\coloneqq a_0+a_1z+\cdots +a_{n-1}z^{n-1}+z^n \in \mathbb{C}[z]$. If $\lambda$ is a zero of $p$, then \begin{align}\label{FKRB} |\lambda|&\leq w_\mathbb{C}(R)+\frac{\sqrt{\sum_{j=0}^{n-1}|a_j|^2}+|a_{n-1}|}{2}=\cos\left(\frac{\pi}{n+1}\right)+\frac{\sqrt{\sum_{j=0}^{n-1}|a_j|^2}+|a_{n-1}|}{2}. \end{align} \end{theorem} Let $p(z)\coloneqq a_0+a_1z+\cdots +a_{n-1}z^{n-1}+z^n \in \mathbb{C}[z]$ with $a_0\neq 0$. Define \begin{align*} q(z)\coloneqq \frac{1}{a_0}z^np\left(\frac{1}{z}\right)=\frac{1}{a_0}+\frac{a_{n-1}}{a_0}z+\cdots +\frac{a_{1}}{a_0}z^{n-1}+z^n \in \mathbb{C}[z]. \end{align*} We note that $\lambda \in \mathbb{C}\setminus \{0\}$ satisfies $p(\lambda)=0$ if and only if $q(1/\lambda)=0$ \cite{HORNJOHNSON}. Frobenius companion matrix of $q$ is \begin{align*} C_q\coloneqq \begin{pmatrix} -\frac{a_1}{a_0}&-\frac{a_2}{a_0}&-\frac{a_3}{a_0}&\cdots &-\frac{a_{n-1}}{a_0} &-\frac{a_{n-1}}{a_0}&-\frac{1}{a_0}\\ 1&0&0&\cdots &0 &0&0\\ 0&1&0&\cdots &0 &0&0\\ \vdots &\vdots &\vdots & & \vdots &\vdots &\vdots\\ 0&0&0&\cdots &0 &0&0\\ 0&0&0&\cdots &1 &0&0\\ 0&0&0&\cdots &0 &1&0\\ \end{pmatrix} \in \mathbb{M}_n(\mathbb{C}) \end{align*} By applying Theorem \ref{FKT} to $q$, we get following result. \begin{theorem} \cite{FUJII} (\textbf{Fujii-Kubo polynomial root lower bound}) Let $p(z)\coloneqq a_0+a_1z+\cdots +a_{n-1}z^{n-1}+z^n \in \mathbb{C}[z]$ with $a_0 \neq 0$. If $\lambda$ is a zero of $p$, then \begin{align*} |\lambda| \geq \frac{2|a_0|}{2|a_0|\cos\left(\frac{\pi}{n+1}\right)+\sqrt{1+\sum_{j=1}^{n-1}|a_j|^2}+|a_{1}|}. \end{align*} \end{theorem} For any bounded linear operator $T:\mathcal{H} \to \mathcal{H} $, the Cauchy-Schwarz inequality gives \begin{align}\label{NR} w_\mathbb{C}(T)\leq \|T\|. \end{align} In 2007, Dragomir strengthened Inequality (\ref{NR}) using Buzano inequality \cite{DRAGOMIR}. \begin{theorem} \cite{DRAGOMIR} \label{DIT} (\textbf{Dragomir Numerical Radius Inequality}) Let $T:\mathcal{H} \to \mathcal{H} $ be a bounded linear operator. Then \begin{align*} w_\mathbb{C}(T) \leq \frac{1}{\sqrt{2}}\sqrt{w_\mathbb{C}(T^2)+\|T\|^2}\leq \|T\|. \end{align*} \end{theorem} Our fundamental motivation comes from the following question: What is the noncommutative analogue of Theorem \ref{DT}? This is then naturally connected with the notion of Hilbert C*-modules which are first introduced by Kaplansky \cite{KAPLANSKY} for modules over commutative C*-algebras and later developed for modules over arbitrary C*-algebras by Paschke \cite{PASCHKE} and Rieffel \cite{RIEFFEL}. \begin{definition} \cite{KAPLANSKY, PASCHKE, RIEFFEL} Let $\mathcal{A}$ be a unital C*-algebra. A right module $\mathcal{E}$ over $\mathcal{A}$ is said to be a \textbf{semi-inner product C*-module} if there exists a map $ \langle \cdot, \cdot \rangle: \mathcal{E}\times \mathcal{E} \to \mathcal{A}$ such that the following hold. \begin{enumerate}[\upshape(i)] \item $\langle x, x \rangle \geq 0$, $\forall x \in \mathcal{E}$. \item $\langle x+y, z \rangle =\langle x, z \rangle+\langle y, z \rangle$, $\forall x,y,z \in \mathcal{E}$. \item $\langle x, ya \rangle =\langle x, y \rangle a$, $\forall x,y \in \mathcal{E}$, $\forall a \in \mathcal{A}$. \item $\langle x, y \rangle=\langle y,x \rangle^*$, $\forall x,y \in \mathcal{E}$. \end{enumerate} \end{definition} Semi-inner product C*-modules satisfy noncommutative Cauchy-Schwarz inequality. \begin{theorem} \cite{LANCE} \label{NCS} (\textbf{Kaplansky-Paschke-Rieffel Inequality}) Let $\mathcal{E}$ be a semi-inner product C*-module. Then \begin{align*} \langle y, x \rangle \langle x, y \rangle \leq \|\langle x, x \rangle\| \langle y, y \rangle, \quad \forall x, y \in \mathcal{E}. \end{align*} In particular, \begin{align*} \|\langle y, x \rangle\|^2 \leq \|\langle x, x \rangle\| \|\langle y, y \rangle\|, \quad \forall x, y \in \mathcal{E}. \end{align*} \end{theorem} \begin{definition} \cite{LANCE} A semi-inner product C*-module $\mathcal{E}$ is said to be an \textbf{inner product C*-module} if $ x \in \mathcal{E}$ satisfies $\langle x, x \rangle = 0$, then $x=0$. \end{definition} \begin{definition} \cite{LANCE} A inner product C*-module $\mathcal{E}$ is said to be \textbf{Hilbert C*-module} if $\mathcal{E}$ is complete w.r.t. the norm $\|x\|\coloneqq \sqrt{\|\langle x, x \rangle\|}$, $\forall x \in \mathcal{E}$. \end{definition} In 2012, Khosravi, Drnovsek and Moslehian derived noncommutative version of Inequality (\ref{BI}) \cite{KHOSRAVI}. \begin{theorem} \cite{KHOSRAVI} \label{KDMT} (\textbf{Buzano-Khosravi-Drnovsek-Moslehian Inequality}) Let $\mathcal{E}$ be a Hilbert C*-module. Then \begin{align}\label{KI} \|\langle \omega, x\rangle \langle x, \tau\rangle \|\leq \frac{\|\langle \tau, \omega \rangle\|+\|\tau\|\|\omega\|}{2}\leq \|\tau\|\|\omega\|, \quad \forall \tau, \omega \in \mathcal{E}, \forall x \in \mathcal{E} \text{ with } \langle x, x \rangle =1. \end{align} \end{theorem} In this article, we show that Theorem \ref{DT} extends to orthogonal projections on Hilbert C*-modules (which will also generalize Theorem \ref{KDMT}). We also derive modular analogue of Theorems \ref{FKT} and \ref{DIT}. \section{Noncommutative Buzano-Dragomir Inequality} We start by deriving noncommutative analogue of Theorem \ref{DT}. \begin{theorem}\label{PC}(\textbf{Noncommutative Buzano-Dragomir Inequality}) Let $\mathcal{E}$ be a Hilbert C*-module over a unital C*-algebra $\mathcal{A}$ and $P:\mathcal{E}\to \mathcal{E}$ be an orthogonal projection. Then \begin{align*} \|\langle \tau, P\omega\rangle \|\leq \frac{\|\langle \tau, \omega \rangle\|+\|\tau\|\|\omega\|}{2}, \quad \forall \tau, \omega \in \mathcal{E}. \end{align*} \end{theorem} \begin{proof} We find \begin{align*} \|2\langle \tau, P\omega\rangle-\langle \tau, \omega \rangle\|&=\| \langle \tau, 2P\omega-\omega\rangle\|\leq \|\tau\|\|2P\omega-\omega\|. \end{align*} We now find \begin{align*} \|2P\omega-\omega\|^2&=\|\langle 2P\omega-\omega, 2P\omega-\omega\rangle \|\\ &=\|4\langle P \omega, P\omega\rangle-2\langle P \omega, \omega\rangle-2\langle \omega, P\omega\rangle+\langle \omega, \omega\rangle\|\\ &=\|\langle \omega, \omega\rangle\|\\ &=\|\omega\|^2. \end{align*} Therefore \begin{align*} 2\|\langle \tau, P\omega\rangle\|-\|\langle \tau, \omega \rangle\| &\leq \|2\langle \tau, P\omega\rangle-\langle \tau, \omega \rangle\|\leq \|\tau\|\|\omega\|. \end{align*} \end{proof} \begin{corollary} Theorem \ref{KDMT} follows from Theorem \ref{PC}. \end{corollary} \begin{proof} Let $\mathcal{E}$ be a Hilbert C*-module and $ x \in \mathcal{E}$ with $\langle x, x \rangle =1$. Define \begin{align*} P: \mathcal{E} \ni y \mapsto Py\coloneqq x \langle x, y \rangle \in \mathcal{E}. \end{align*} Then $P$ is an orthogonal projection. Theorem \ref{PC} gives \begin{align*} \|\langle \tau, x\rangle \langle x, \omega\rangle \|&=\|\langle \tau, x \langle x, \omega \rangle \rangle \|=\|\langle \tau, P\omega \rangle\| \\ &\leq \frac{\|\langle \tau, \omega \rangle\|+\|\tau\|\|\omega\|}{2}, \quad \forall \tau, \omega \in \mathcal{E}. \end{align*} \end{proof} In 2016, Dragomir further improved Theorem \ref{DT} for bounded linear operators \cite{DRAGOMIR3}. \begin{theorem} \cite{DRAGOMIR3} \label{DIG} (\textbf{Buzano-Dragomir Inequality}) Let $\mathcal{H}$ be a complex Hilbert space and $T:\mathcal{H}\to \mathcal{H}$ be a bounded linear operator. Then \begin{align*} |\langle T\tau, T\omega\rangle |\leq \frac{\|T\|^2(|\langle \tau, \omega \rangle|+\|\tau\|\|\omega\|)}{2}, \quad \forall \tau, \omega \in \mathcal{H}. \end{align*} \end{theorem} We now derive following noncommutative version of Theorem \ref{DIG}. \begin{theorem} \label{NDI} (\textbf{Noncommutative Buzano-Dragomir Inequality}) Let $\mathcal{E}$ be a Hilbert C*-module over a unital C*-algebra $\mathcal{A}$ and $T:\mathcal{E}\to \mathcal{E}$ be an adjointable morphism. Then \begin{align*} \|\langle T\tau, T\omega\rangle \|\leq \|T\|^2\|\langle \tau, \omega \rangle\|+\bigg\|\langle \tau, \tau \rangle\|T\|^2-\langle T\tau, T\tau \rangle\bigg\|^\frac{1}{2}\bigg\|\langle \omega, \omega \rangle\|T\|^2-\langle T\omega, T\omega \rangle\bigg\|^\frac{1}{2}, \quad \forall \tau, \omega \in \mathcal{E}. \end{align*} \end{theorem} \begin{proof} Our proof is motivated by the Hilbert space argument due to Dragomir \cite{DRAGOMIR3}. Let $T:\mathcal{E}\to \mathcal{E}$ be an adjointable morphism and $\tau, \omega \in \mathcal{E}$. Define \begin{align*} [\cdot, \cdot]: \mathcal{E} \times \mathcal{E} \ni (x,y)\mapsto [x,y]\coloneqq \langle x, y \rangle \|T\|^2-\langle Tx, Ty \rangle \in \mathcal{A}. \end{align*} Then $ [\cdot, \cdot]$ is a semi-inner product. By applying Theorem \ref{NCS} to this semi-inner product, we get \begin{align*} \big\|[x,y] \big\|^2\leq \|[x, x]\|\|[y,y]\|, \quad \forall x, y \in \mathcal{E}. \end{align*} In particular, \begin{align*} \left\|[\tau, \omega]\right\|^2\leq \|[\tau, \tau]\|\|[\omega, \omega]\|. \end{align*} Previous inequality gives \begin{align*} \bigg\|\langle \tau, \omega \rangle \|T\|^2-\langle T\tau, T\omega \rangle\bigg\|^2 \leq \bigg\|\langle \tau, \tau \rangle\|T\|^2-\langle T\tau, T\tau \rangle\bigg\|\bigg\|\langle \omega, \omega \rangle\|T\|^2-\langle T\omega, T\omega \rangle\bigg\|. \end{align*} Therefore \begin{align*} \|\langle T\tau, T\omega\rangle\| - \|T\|^2\|\langle \tau, \omega \rangle\|&\leq \bigg\|\langle \tau, \omega \rangle \|T\|^2-\langle T\tau, T\omega \rangle\bigg\|\\ &\leq \bigg\|\langle \tau, \tau \rangle\|T\|^2-\langle T\tau, T\tau \rangle\bigg\|^\frac{1}{2}\bigg\|\langle \omega, \omega \rangle\|T\|^2-\langle T\omega, T\omega \rangle\bigg\|^\frac{1}{2}. \end{align*} \end{proof} We are unable to simplify Theorem \ref{NDI}. We therefore ask following problem. \begin{problem} Let $\mathcal{E}$ be a Hilbert C*-module over a unital C*-algebra $\mathcal{A}$ and $T:\mathcal{E}\to \mathcal{E}$ be an adjointable morphism. Whether \begin{align*} \|\langle T\tau, T\omega\rangle \|\leq \frac{\|T\|^2(\|\langle \tau, \omega \rangle\|+\|\tau\|\|\omega\|)}{2}, \quad \forall \tau, \omega \in \mathcal{E}? \end{align*} \end{problem} Let $\mathcal{E}$ be a Hilbert C*-module over a unital C*-algebra $\mathcal{A}$. Similar to Hilbert space case, we define the \textbf{noncommutative numerical range} of an adjointable morphism $T:\mathcal{E}\to \mathcal{E}$ is defined as \begin{align*} W_\mathcal{A}(T)\coloneqq \{\langle x, Tx\rangle: x \in \mathcal{E}, \langle x, x \rangle =1\}\subseteq \mathcal{A} \end{align*} and the \textbf{noncommutative numerical radius} $T$ is defined as \begin{align*} w_\mathcal{A}(T)\coloneqq \sup_{x \in \mathcal{E}, \langle x, x \rangle =1}\|\langle x, Tx\rangle\|\geq 0. \end{align*} Note that our definition of numerical range and radius on Hilbert C*-modules differ from the existing same notion on Hilbert C*-modules \cite{ZAMANI, MEHRAZINAMYARIOMIDVAR, RAJIC} We give various examples. In all following examples, $\mathcal{A}$ is a unital C*-algebra. \begin{example} Let $b \in \mathcal{A}$. Then \begin{align*} W_\mathcal{A}(b)=\{a^*ba: a\in \mathcal{A}, a^*a=1\} \end{align*} and \begin{align*} w_\mathcal{A}(b)&=\sup\{\|a^*ba\|: a\in \mathcal{A}, a^*a=1\}\\ &= \|b\|. \end{align*} If $\mathcal{A}$ is commutative, then $ W_\mathcal{A}(b)=\{b\}$. \end{example} \begin{example} Let $d\in \mathbb{N}$ and $I_d$ be the identity matrix of size $d$ by $d$. Then we have \begin{align*} W_\mathcal{A}(I_d)=\{\langle x, x\rangle: x \in \mathcal{A}^d, \langle x, x \rangle=1\}=\left\{1\right\} \end{align*} and \begin{align*} w_\mathcal{A}(I_d)=1. \end{align*} \end{example} \begin{example} Define \begin{align*} M\coloneqq \begin{pmatrix} 0 & 1 \\ 0 & 0 \\ \end{pmatrix}. \end{align*} Then \begin{align*} W_\mathcal{A}(M)&=\{\langle x, Mx\rangle: x \in \mathcal{A}^2, \langle x, x \rangle=1\}\\ &=\left\{a^*b:a, b \in \mathcal{A}, a^*a+b^*b=1\right\} \end{align*} and \begin{align*} w_\mathcal{A}(M)&=\sup\left\{\|a^*b\|:a, b \in \mathcal{A}, a^*a+b^*b=1\right\}. \end{align*} We note that \begin{align*} a^*bb^*a\leq \frac{a^*a+b^*b}{2}, \quad \forall a, b \in \mathcal{A}. \end{align*} Therefore \begin{align*} w_\mathcal{A}(M)&=\sup\left\{\|a^*b\|:a, b \in \mathcal{A}, a^*a+b^*b=1\right\}\\ &\leq \frac{1}{\sqrt{2}}\sup\{\sqrt{\|a^*a+b^*b\|}:a, b \in \mathcal{A}, a^*a+b^*b=1\}\\ &= \frac{1}{\sqrt{2}}. \end{align*} \end{example} \begin{example} Let $d\in \mathbb{N}$ and $b_1, \dots, b_d \in \mathcal{A}$. Define $\operatorname{diag}((b_j)_{j=1}^d)$ as the diagonal matrix with diagonal entries $b_1, \dots, b_d$. Then \begin{align*} W_\mathcal{A}(\operatorname{diag}((b_j)_{j=1}^d))=\left\{\sum_{j=1}^da_j^*b_ja_j: (a_j)_{j=1}^d\in \mathcal{A}^d, \sum_{j=1}^da_j^*a_j=1\right\} \end{align*} and \begin{align*} w_\mathcal{A}(\operatorname{diag}((b_j)_{j=1}^d))&=\sup\left\{\left\|\sum_{j=1}^da_j^*b_ja_j\right\|: (a_j)_{j=1}^d\in \mathcal{A}^d, \sum_{j=1}^da_j^*a_j=1\right\}\\ &\leq \sum_{j=1}^d\|b_j\|. \end{align*} The set $ W_\mathcal{A}(\operatorname{diag}((b_j)_{j=1}^d))$ is the C*-convex hull of $\{b_j\}_{j=1}^d$ \cite{LOEBLPAULSEN}. \end{example} \begin{example} Let $R \in \mathbb{M}_{d}(\mathcal{A})$ be the right shift matrix defined by \begin{align*} R\coloneqq \begin{pmatrix} 0 & 0 & 0& \cdots & 0 & 0 & 0\\ 1 & 0 & 0& \cdots & 0 & 0 & 0\\ 0 & 1 & 0& \cdots & 0 & 0 & 0\\ \vdots &\vdots & \vdots & & \vdots &\vdots & \vdots\\ 0 & 0 & 0& \cdots & 0 & 0 & 0\\ 0 & 0 & 0& \cdots & 1 & 0 & 0\\ 0& 0 & 0& \cdots & 0 & 1 & 0\\ \end{pmatrix}. \end{align*} Thus the action of $R$ is \begin{align*} R(a_j)_{j=1}^d=(0, a_1, a_2, \dots, a_{d-1}), \quad \forall (a_j)_{j=1}^d \in \mathcal{A}^d. \end{align*} We then have \begin{align*} \langle (a_j)_{j=1}^d, R(a_j)_{j=1}^d\rangle =a_2^*a_1+\cdots+ a_d^*a_{d-1}, \quad \forall (a_j)_{j=1}^d \in \mathcal{A}^d. \end{align*} Hence \begin{align*} \|\langle (a_j)_{j=1}^d, R(a_j)_{j=1}^d\rangle\|&=\|a_2^*a_1+\cdots+ a_d^*a_{d-1}\|\\ &\leq \left\|\sum_{j=2}^da_j^*a_j\right\|^\frac{1}{2}\left\|\sum_{k=1}^{d-1}a_k^*a_k\right\|^\frac{1}{2}\\ &\leq \left\|\sum_{j=1}^da_j^*a_j\right\|^\frac{1}{2}\left\|\sum_{k=1}^{d}a_k^*a_k\right\|^\frac{1}{2}\\ &=\left\|\sum_{j=1}^da_j^*a_j\right\|, \quad \forall (a_j)_{j=1}^d \in \mathcal{A}^d. \end{align*} Therefore \begin{align*} W_\mathcal{A}(R)=\left\{a_2^*a_1+\cdots+ a_d^*a_{d-1}:(a_j)_{j=1}^d \in \mathcal{A}^d, \sum_{j=1}^{d}a_j^*a_j=1\right\} \end{align*} and \begin{align*} w_\mathcal{A}(R)&=\sup\left\{\|a_2^*a_1+\cdots+ a_d^*a_{d-1}\|:(a_j)_{j=1}^d \in \mathcal{A}^d, \sum_{j=1}^{d}a_j^*a_j=1\right\}\\ &\leq 1. \end{align*} \end{example} \begin{example} Let $\mathcal{A}$ be a unital C*-algebra and $\ell^2(\mathcal{A})$ be the standard Hilbert C*-module defined by \begin{align*} \ell^2(\mathcal{A})\coloneqq \left\{\{a_n\}_{n=1}^\infty: a_n \in \mathcal{A}, \forall n \in \mathbb{N}, \sum_{n=1}^{\infty}a_n^*a_n\in \mathcal{A}\right\} \end{align*} equipped with inner product \begin{align*} \langle \{a_n\}_{n=1}^\infty, \{b_n\}_{n=1}^\infty\rangle \coloneqq \sum_{n=1}^{\infty}a_n^*b_n , \quad \forall \{a_n\}_{n=1}^\infty, \{b_n\}_{n=1}^\infty \in \ell^2(\mathcal{A}) \end{align*} and norm \begin{align*} \|\{a_n\}_{n=1}^\infty\|=\left\|\sum_{n=1}^{\infty}a_n^*a_n\right\|^\frac{1}{2}, \quad \forall \{a_n\}_{n=1}^\infty \in \ell^2(\mathcal{A}). \end{align*} Let $L$ be the left shift morphism defined by \begin{align*} L: \ell^2(\mathcal{A}) \ni \{a_n\}_{n=1}^\infty \mapsto L \{a_n\}_{n=1}^\infty\coloneqq \{a_{n+1}\}_{n=1}^\infty\in \ell^2(\mathcal{A}). \end{align*} Then \begin{align*} W_\mathcal{A}(L)=\left\{\sum_{n=1}^{\infty}a_n^*a_{n+1}:\{a_n\}_{n=1}^\infty \in \ell^2(\mathcal{A}), \sum_{n=1}^{\infty}a_n^*a_{n}=1\right\} \end{align*} and \begin{align*} w_\mathcal{A}(L)&=\sup\left\{\left\|\sum_{n=1}^{\infty}a_n^*a_{n+1}\right\|:\{a_n\}_{n=1}^\infty \in \ell^2(\mathcal{A}), \sum_{n=1}^{\infty}a_n^*a_{n}=1\right\}\\ &\leq 1. \end{align*} \end{example} \begin{example} Define \begin{align*} A\coloneqq \begin{pmatrix} a & b \\ c & d \\ \end{pmatrix}. \end{align*} Then \begin{align*} W_\mathcal{A}(A)&=\{x^*ax+x^*by+y^*cx+y^*dy: x, y \in \mathcal{A}, x^*x+y^*y=1\} \end{align*} and \begin{align*} w_\mathcal{A}(A)&=\sup\{\|x^*ax+x^*by+y^*cx+y^*dy\|: x, y \in \mathcal{A}, x^*x+y^*y=1\}\\ &\leq\|a\|+\|b\|+\|c\|+\|d\|. \end{align*} \end{example} Given $r>0$ and $v \in \mathcal{A}$, the closed disc centered at $v \in \mathcal{A}$ of radius $ r$ is defined as \begin{align*} \mathbb{D}_{ \mathcal{A}}[v, r]\coloneqq \{z \in \mathcal{A}: \|z-v\|\leq r\}. \end{align*} Following are basic properties of noncommutative numerical range and radius. \begin{proposition} Let $\mathcal{E}$ be a Hilbert C*-module over a unital C*-algebra $\mathcal{A}$. Let $\mathcal{A}^+$ be the set of all positive elements in $\mathcal{A}$. Let $T, S :\mathcal{E}\to \mathcal{E}$ be adjointable morphisms and $a,b \in \mathcal{A}$. Let $I$ be the identity morphism on $\mathcal{E}$. \begin{enumerate}[\upshape(i)] \item $W_\mathcal{A}(T)\subseteq \mathbb{D}_{\mathcal{A}}[0, \|T\|]$. \item $0\leq w_\mathcal{A}(T)\leq \|T\|$. \item $W_\mathcal{A}(T+S)\subseteq W_\mathcal{A}(T)+W_\mathcal{A}(S)$. \item $w_\mathcal{A}(S+T)\leq w_\mathcal{A}(S)+w_\mathcal{A}(T)$. \item $W_\mathcal{A}(Ta)=W_\mathcal{A}(T)a$. \item $w_\mathcal{A}(Ta)\leq \|a\|w_\mathcal{A}(T)$. \item $W_\mathcal{A}(T^*)=(W_\mathcal{A}(T))^*$. \item $w_\mathcal{A}(T^*)=w_\mathcal{A}(T)$. \item $W_\mathcal{A}(Ta+bI)=W_\mathcal{A}(T)a+b$. \item $W_\mathcal{A}(\operatorname{Re}(T))=\operatorname{Re}(W_\mathcal{A}(T))$ and $W_\mathcal{A}(\operatorname{Im}(T))=\operatorname{Im}(W_\mathcal{A}(T))$. \item If $T\geq0$, then $W_\mathcal{A}(T)\subseteq \mathcal{A}^+$. \item Let $\mathcal{E}_0$ be a Hilbert C*-module over a unital C*-algebra $\mathcal{A}$ such that $\mathcal{E}$ is orthogonally complementable in $\mathcal{E}_0$. If an adjointable morphism $V:\mathcal{E}_0\to \mathcal{E}_0$ is a dilation of $T$, then $W_\mathcal{A}(T)\subseteq W_\mathcal{A}(V)$. \item Let $\mathcal{E}_1$ be an orthogonally complementable closed submodule in $\mathcal{E}$. Let $P:\mathcal{E}\to \mathcal{E}_1$ be an onto orthogonal projection. Then $W_\mathcal{A}(PT_{|\mathcal{E}_1})\subseteq W_\mathcal{A}(T)$. \item $W_\mathcal{A}(U^*TU)=W_\mathcal{A}(T)$ for every unitary morphism $U:\mathcal{E}\to \mathcal{E}$. \item Let $a \in \mathcal{A}$ be such that there exists a $x \in \mathcal{E}$ with $Tx=xa$ and $\langle x, x \rangle=1$. Then $a \in W_\mathcal{A}(T)$. In other words, \begin{align*} \sigma_1(T)\coloneqq \{a \in \mathcal{A}: \exists x \in \mathcal{E}, Tx=xa, \langle x, x \rangle=1\} \subseteq W_\mathcal{A}(T) \end{align*} and \begin{align*} \|a\|\leq w_\mathcal{A}(T), \quad \forall a \in \sigma_1(T). \end{align*} \item \begin{align*} w_\mathcal{A}(ST+TS)\leq\frac{w_\mathcal{A}((S+T)^2)+w_\mathcal{A}((S-T)^2)}{2}. \end{align*} In particular, if $ST=TS$, then \begin{align*} w_\mathcal{A}(ST)\leq\frac{w_\mathcal{A}((S+T)^2)+w_\mathcal{A}((S-T)^2)}{4}. \end{align*} \item If a sequence $\{T_n\}_{n=1}^\infty $ of adjointable morphisms on $\mathcal{E}$ converges to an adjointable morphism $T $ on $\mathcal{E}$ in the morphism norm, then the sequence $\{w_\mathcal{A}(T_n)\}_{n=1}^\infty$ converges to $w_\mathcal{A}(T)$ in the norm. \end{enumerate} \end{proposition} Using generalized polarization identity, it is known that $w_\mathbb{C}(T)\geq \|T\|/2$ \cite{GUSTAFSONRAO}. We are unable to derive noncommutative version of this result. For $ \tau, \omega \in \mathcal{E}$, define the morphism \begin{align*} \tau \otimes \omega : \mathcal{E} \ni x \mapsto (\tau \otimes \omega)x \coloneqq \tau \langle \omega, x \rangle \in \mathcal{E}. \end{align*} Following is modular version of Theorem \ref{FKR}. \begin{theorem} Let $\mathcal{E}$ be a Hilbert C*-module over a commutative unital C*-algebra $\mathcal{A}$ and $ \tau, \omega \in \mathcal{E}$. Then \begin{align}\label{RE} w_\mathcal{A}(\tau \otimes \omega)\leq \frac{\|\langle \tau, \omega \rangle\|+\|\tau\|\|\omega\|}{2}\leq \|\tau\|\|\omega\|. \end{align} In particular, \begin{align*} w_\mathcal{A}(\tau \otimes \tau)\leq \|\tau\|^2. \end{align*} \end{theorem} \begin{proof} Let $ \tau, \omega \in \mathcal{E}$. Let $x \in \mathcal{E}$ with $\langle x, x \rangle=1$. Then using commutativity of C*-algebra, \begin{align*} \|\langle x, (\tau \otimes \omega)x \rangle\| &=\|\langle x, \tau \langle \omega, x \rangle\rangle \|=\|\langle x, \tau \rangle \langle \omega, x \rangle \|\\ &=\|\langle \omega, x \rangle \langle x, \omega\rangle\|\leq \frac{\|\langle \tau, \omega \rangle\|+\|\tau\|\|\omega\|}{2}. \end{align*} Therefore \begin{align*} w_\mathcal{A}(\tau \otimes \omega)\leq \frac{\|\langle \tau, \omega \rangle\|+\|\tau\|\|\omega\|}{2}. \end{align*} \end{proof} Unlike the Hilbert space case, we are unable to derive equality in Inequality (\ref{RE}). Let $\mathcal{A}$ be a unital C*-algebra and $p(z)\coloneqq a_0+a_1z+\cdots +a_{n-1}z^{n-1}+z^n \in \mathcal{A}[z]$. Define the \textbf{modular Frobenius companion matrix} \begin{align*} C_p\coloneqq \begin{pmatrix} -a_{n-1}&-a_{n-2}&-a_{n-3}&\cdots &-a_2 &-a_1&-a_0\\ 1&0&0&\cdots &0 &0&0\\ 0&1&0&\cdots &0 &0&0\\ \vdots &\vdots &\vdots & & \vdots &\vdots &\vdots\\ 0&0&0&\cdots &0 &0&0\\ 0&0&0&\cdots &1 &0&0\\ 0&0&0&\cdots &0 &1&0\\ \end{pmatrix} \in \mathbb{M}_n(\mathcal{A}). \end{align*} Given $ n \in \mathbb{N}$, we consider $\mathcal{A}^n$ with the standard inner product \begin{align*} \langle (a_j)_{j=1}^n, (b_j)_{j=1}^n\rangle \coloneqq \sum_{j=1}^{n}a_j^*b_j, \quad \forall (a_j)_{j=1}^n, (b_j)_{j=1}^n \in \mathcal{A}^n. \end{align*} Hence the norm on $\mathcal{A}^n$ is \begin{align*} \|(a_j)_{j=1}^n\|=\left\|\sum_{j=1}^{n}a_j^*a_j\right\|^\frac{1}{2}, \quad \forall (a_j)_{j=1}^n \in \mathcal{A}^n. \end{align*} We then have the following result. \begin{theorem} Let $\mathcal{A}$ be a commutative unital C*-algebra and $p(z)\coloneqq a_0+a_1z+\cdots +a_{n-1}z^{n-1}+z^n \in \mathcal{A}[z]$. If $b \in \mathcal{A}$ satisfies $p(b)=0$, then $b \in W_\mathcal{A}(C_p)$. \end{theorem} \begin{proof} Define \begin{align*} x \coloneqq \begin{pmatrix} b^{n-1}\\ b^{n-2}\\ b^{n-3}\\ \vdots\\ b^2\\ b\\ 1 \end{pmatrix} \left(\sum_{j=0}^{n-1}(b^*)^jb^j\right)^\frac{-1}{2}. \end{align*} Then $\langle x, x \rangle =1$. Using commutativity of C*-algebra, we have \begin{align*} &\langle x, C_p x\rangle=\\ &\left\langle \begin{pmatrix} b^{n-1}\\ b^{n-2}\\ b^{n-3}\\ \vdots\\ b^2\\ b\\ 1 \end{pmatrix}\left(\sum_{j=0}^{n-1}(b^*)^jb^j\right)^\frac{-1}{2}, \begin{pmatrix} -a_{n-1}&-a_{n-2}&-a_{n-3}&\cdots &-a_2 &-a_1&-a_0\\ 1&0&0&\cdots &0 &0&0\\ 0&1&0&\cdots &0 &0&0\\ \vdots &\vdots &\vdots & & \vdots &\vdots &\vdots\\ 0&0&0&\cdots &0 &0&0\\ 0&0&0&\cdots &1 &0&0\\ 0&0&0&\cdots &0 &1&0\\ \end{pmatrix} \begin{pmatrix} b^{n-1}\\ b^{n-2}\\ b^{n-3}\\ \vdots\\ b^2\\ b\\ 1 \end{pmatrix} \left(\sum_{j=0}^{n-1}(b^*)^jb^j\right)^\frac{-1}{2} \right\rangle\\ &=\left(\sum_{j=0}^{n-1}(b^*)^jb^j\right)^\frac{-1}{2} \left\langle \begin{pmatrix} b^{n-1}\\ b^{n-2}\\ b^{n-3}\\ \vdots\\ b^2\\ b\\ 1 \end{pmatrix}, \begin{pmatrix} -a_{n-1}&-a_{n-2}&-a_{n-3}&\cdots &-a_2 &-a_1&-a_0\\ 1&0&0&\cdots &0 &0&0\\ 0&1&0&\cdots &0 &0&0\\ \vdots &\vdots &\vdots & & \vdots &\vdots &\vdots\\ 0&0&0&\cdots &0 &0&0\\ 0&0&0&\cdots &1 &0&0\\ 0&0&0&\cdots &0 &1&0\\ \end{pmatrix} \begin{pmatrix} b^{n-1}\\ b^{n-2}\\ b^{n-3}\\ \vdots\\ b^2\\ b\\ 1 \end{pmatrix} \right\rangle\left(\sum_{j=0}^{n-1}(b^*)^jb^j\right)^\frac{-1}{2} \\ &=\left(\sum_{j=0}^{n-1}(b^*)^jb^j\right)^\frac{-1}{2} \left\langle \begin{pmatrix} b^{n-1}\\ b^{n-2}\\ b^{n-3}\\ \vdots\\ b^2\\ b\\ 1 \end{pmatrix}, \begin{pmatrix} -\sum_{j=0}^{n-1}a_{j}b^j\\\ b^{n-1}\\ b^{n-2}\\ \vdots\\ b^3\\ b^2\\ b \end{pmatrix} \right\rangle\left(\sum_{j=0}^{n-1}(b^*)^jb^j\right)^\frac{-1}{2}\\ &=\left(\sum_{j=0}^{n-1}(b^*)^jb^j\right)^\frac{-1}{2} \left\langle \begin{pmatrix} b^{n-1}\\ b^{n-2}\\ b^{n-3}\\ \vdots\\ b^2\\ b\\ 1 \end{pmatrix}, \begin{pmatrix} b^n\\\ b^{n-1}\\ b^{n-2}\\ \vdots\\ b^3\\ b^2\\ b \end{pmatrix} \right\rangle\left(\sum_{j=0}^{n-1}(b^*)^jb^j\right)^\frac{-1}{2}\\ &=\left(\sum_{j=0}^{n-1}(b^*)^jb^j\right)^\frac{-1}{2} \left\langle \begin{pmatrix} b^{n-1}\\ b^{n-2}\\ b^{n-3}\\ \vdots\\ b^2\\ b\\ 1 \end{pmatrix}, \begin{pmatrix} b^{n-1}\\\ b^{n-2}\\ b^{n-3}\\ \vdots\\ b^2\\ b\\ 1 \end{pmatrix} \right\rangle b \left(\sum_{j=0}^{n-1}(b^*)^jb^j\right)^\frac{-1}{2}\\ &=\left(\sum_{j=0}^{n-1}(b^*)^jb^j\right)^\frac{-1}{2}\left(\sum_{j=0}^{n-1}(b^*)^jb^j\right)b \left(\sum_{j=0}^{n-1}(b^*)^jb^j\right)^\frac{-1}{2}\\ &=\left(\sum_{j=0}^{n-1}(b^*)^jb^j\right)^\frac{-1}{2}\left(\sum_{j=0}^{n-1}(b^*)^jb^j\right) \left(\sum_{j=0}^{n-1}(b^*)^jb^j\right)^\frac{-1}{2}b\\ &=b. \end{align*} Therefore $b=\langle x, C_p x\rangle \in W_\mathcal{A}(C_p)$. \end{proof} We now derive modular analogue of Theorem \ref{FKT}. \begin{theorem} Let $\mathcal{A}$ be a commutative unital C*-algebra and $p(z)\coloneqq a_0+a_1z+\cdots +a_{n-1}z^{n-1}+z^n \in \mathcal{A}[z]$. If $b \in \mathcal{A}$ satisfies $p(b)=0$, then \begin{align*} \|b\|&\leq w_\mathcal{A}(R)+\frac{\sqrt{\left\|\sum_{j=0}^{n-1}a_j^*a_j\right\|}+\|a_{n-1}\|}{2}\\ &\leq w_\mathcal{A}(R)+\frac{\sqrt{\sum_{j=0}^{n-1}\|a_j\|^2}+\|a_{n-1}\|}{2}, \end{align*} where $R$ is the right shift matrix defined by \begin{align*} R\coloneqq \begin{pmatrix} 0&0&0&\cdots &0 &0&0\\ 1&0&0&\cdots &0 &0&0\\ 0&1&0&\cdots &0 &0&0\\ \vdots &\vdots &\vdots & & \vdots &\vdots &\vdots\\ 0&0&0&\cdots &0 &0&0\\ 0&0&0&\cdots &1 &0&0\\ 0&0&0&\cdots &0 &1&0\\ \end{pmatrix} \in \mathbb{M}_n(\mathcal{A}). \end{align*} \end{theorem} \begin{proof} Define \begin{align*} {\bf{a}}\coloneqq \begin{pmatrix} (a_{n-1})^*\\ (a_{n-2})^*\\ (a_{n-3})^*\\ \vdots \\ (a_2)^*\\ (a_1)^*\\ (a_0)^*\\ \end{pmatrix} \in \mathcal{A}^n, \quad {\bf{e_1}} \coloneqq \begin{pmatrix} 1\\ 0\\ 0\\ \vdots \\ 0\\ 0\\ 0\\ \end{pmatrix} \in \mathcal{A}^n. \end{align*} Then \begin{align}\label{QFK} C_p=R-{\bf{e_1}}\otimes {\bf{a}}. \end{align} Using (\ref{QFK}) and Inequality (\ref{RE}), we get \begin{align*} \|b\|&\leq w_\mathcal{A}(C_p)\\ &=w_\mathcal{A}(R-{\bf{e_1}}\otimes {\bf{a}}) \\ &\leq w_\mathcal{A}(R)+w_\mathcal{A}({\bf{e_1}}\otimes {\bf{a}})\\ &\leq w_\mathcal{A}(R)+\frac{\sqrt{\left\|\sum_{j=0}^{n-1}a_j^*a_j\right\|}+\|a_{n-1}\|}{2}\\ &\leq w_\mathcal{A}(R)+\frac{\sqrt{\sum_{j=0}^{n-1}\|a_j\|^2}+\|a_{n-1}\|}{2}. \end{align*} \end{proof} Let $\mathcal{A}$ be a commutative unital C*-algebra. Let $p(z)\coloneqq a_0+a_1z+\cdots +a_{n-1}z^{n-1}+z^n \in \mathcal{A}[z]$ with $a_0$ invertible. Define \begin{align*} q(z)\coloneqq \frac{1}{a_0}z^np\left(\frac{1}{z}\right)=\frac{1}{a_0}+\frac{a_{n-1}}{a_0}z+\cdots +\frac{a_{1}}{a_0}z^{n-1}+z^n \in \mathcal{A}[z]. \end{align*} We note that an invertible element $b \in \mathcal{A}$ satisfies $p(b)=0$ if and only if $q(1/b)=0$. Frobenius companion matrix of $q$ is \begin{align*} C_q\coloneqq \begin{pmatrix} -\frac{a_1}{a_0}&-\frac{a_2}{a_0}&-\frac{a_3}{a_0}&\cdots &-\frac{a_{n-1}}{a_0} &-\frac{a_{n-1}}{a_0}&-\frac{1}{a_0}\\ 1&0&0&\cdots &0 &0&0\\ 0&1&0&\cdots &0 &0&0\\ \vdots &\vdots &\vdots & & \vdots &\vdots &\vdots\\ 0&0&0&\cdots &0 &0&0\\ 0&0&0&\cdots &1 &0&0\\ 0&0&0&\cdots &0 &1&0\\ \end{pmatrix} \in \mathbb{M}_n(\mathcal{A}). \end{align*} By applying Theorem \ref{FKRB} to $q$, we get following result. \begin{theorem} Let $\mathcal{A}$ be a commutative unital C*-algebra and $p(z)\coloneqq a_0+a_1z+\cdots +a_{n-1}z^{n-1}+z^n \in \mathcal{A}[z]$ with $a_0$ invertible. If an invertible element $b \in \mathcal{A}$ satisfies $p(b)=0$, then \begin{align*} \frac{1}{\|b^{-1}\|} \geq \frac{2}{2w_\mathcal{A}(R)+\sqrt{\left\|(a^{-1}_0)^*a^{-1}_0+\sum_{j=1}^{n-1}(a_ja_0^{-1})^*a_ja_0^{-1}\right\|^2}+\|a_{1}a_0^{-1}\|}. \end{align*} \end{theorem} Equality term in (\ref{FKRB}) comes from the numerical radius of right shift matrix obtained by Davidson and Holbrook \cite{DAVIDSONHOLBROOK} (also see \cite{HAAGERUPHARPE, KARAEV}). We are unable to do this for the right shift matrix over C*-algebras. We now derive Theorem \ref{DIT} for Hilbert C*-modules. \begin{theorem} (\textbf{Modular Dragomir Numerical Radius Inequality}) \label{MD} Let $\mathcal{E}$ be a Hilbert C*-module over a unital C*-algebra $\mathcal{A}$ and $T:\mathcal{E} \to \mathcal{E} $ be a self-adjoint morphism. Then \begin{align*} w_\mathcal{A}(T) \leq \frac{1}{\sqrt{2}}\sqrt{w_\mathcal{A}(T^2)+\|T\|^2}\leq \frac{1}{\sqrt{2}}\sqrt{\|T^2\|+\|T\|^2}\leq \|T\|. \end{align*} \end{theorem} \begin{proof} Let $x\in \mathcal{E}$ with $\langle x, x \rangle=1$. Then using Inequality (\ref{KI}) and the self-adjointness of $T$, we get \begin{align*} \|\langle x, Tx\rangle\|^2&=\|\langle x, Tx\rangle\langle x, Tx\rangle^*\|=\|\langle x, Tx\rangle \langle Tx, x\rangle\|\\ &=\|\langle Tx, x\rangle \langle x, Tx\rangle\|\leq \frac{\|\langle Tx, Tx \rangle\|+\|Tx\|\|Tx\|}{2}\\ &= \frac{\|\langle x, T^2x \rangle\|+\|Tx\|\|T^*x\|}{2}\leq \frac{\|\langle x, T^2x \rangle\|+\|T\|\|x\|\|T\|\|x\|}{2}\\ &=\frac{\|\langle x, T^2x \rangle\|+\|T\|^2}{2}\leq \frac{\sup_{y \in \mathcal{E}, \langle y, y \rangle =1}\|\langle y, T^2y\rangle\|+\|T\|^2}{2}\\ &=\frac{w_\mathcal{A}(T^2)+\|T\|^2}{2}. \end{align*} Therefore \begin{align*} w_\mathcal{A}(T)= \sup_{x \in \mathcal{E}, \langle x, x \rangle=1}\|\langle x, Tx\rangle\|\leq \frac{1}{\sqrt{2}}\sqrt{w_\mathcal{A}(T^2)+\|T\|^2}\leq \frac{1}{\sqrt{2}}\sqrt{\|T^2\|+\|T\|^2}\leq \|T\|. \end{align*} \end{proof} Note that we derived Theorem \ref{MD} only for self-adjoint morphisms. We are unable to derive Theorem \ref{MD} for arbitrary adjointable morphisms. We also note that in the case of self-adjoint operator $T$ on Hilbert spaces, we have $w_\mathbb{C}(T)=\|T\|$ \cite{GUSTAFSONRAO} which we can't say for self-adjoint morphisms on Hilbert C*-modules. \section{Noncommutative Toeplitz-Hausdorff Problem} Motivated from several breakthrough results in numerical range and radius, we formulate following problems. What is noncommutative \begin{enumerate}[\upshape(1)] \item Toeplitz-Hausdorff Theorem (fundamental theorem of the numerical range) \cite{TOEPLITZ, GUTKIN, HAUSDORFF, MCINTOSH, DAVIS, RAGHAVENDRAN, GUSTAFSON, GUSTAFSONRAO, NARCOWICHWARD, STONE, FEINTUCHMARKUS, HALMOS}? \item Wintner spectral inclusion theorem for numerical range \cite{BERBERIAN, GUSTAFSONRAO, WINTNER}? \item Halmos-Bernau-Smithies-Berger power inequality \cite{PEARCY, BERNAUSMITHIES}? \item Alpin-Chien-Yeh inequality\cite{ALPINCHIENYEH}? \item Kittaneh inequalities \cite{KITTANEH, KITTANEH2}? \item Yamazaki inequality \cite{YAMAZAKI}? \item Kittaneh-Moslehian-Yamazaki inequality \cite{KITTANEHMOSLEHIANYAMAZAKI}? \item Abu-Omar-Kittaneh inequality \cite{ABUOMARKITTANEH}? \item Bhunia-Bag-Paul inequality \cite{BHUNIABAGPAUL}? \item elliptical range theorem \cite{LI, BROWNSPITKOVSKY}? \item Berger power dilation for numerical contraction \cite{GUSTAFSONRAO, BERGERSTAMPFLI, BERGERSTAMPFLI2, NAGYFOIASBOOK}? \item Ando theorem for numerical contraction \cite{ANDO}? \item Furuta-Nakamoto theorem for numerical contractions \cite{FURUTANAKAMOTO2}? \item El-Haddad-Kittaneh numerical radius inequality \cite{ELHADDADKITTANEH}? \item description of numerical range of 3 $\times $ 3 matrices \cite{KEELERRODMANSPITKOVSKY}? \item description of numerical range of 4 $\times $ 4 matrices \cite{GAU}? \item Holbrook numerical radius inequalities for the product of commuting matrices \cite{HOLBROOK}? \item Okubo-Ando numerical radius inequalities for the product of commuting matrices \cite{OKUBOANDO, MULLER, HOLBROOK2}? \item Bouldin numerical radius inequalities for the product of commuting matrices \cite{BOULDIN, BOULDIN2}? \item Poncelet property for numerical ranges \cite{ADAMSCORBETTGORKIN, WU, GAUWU2}? \item Anderson theorem \cite{GAUWUBOOK, TAMYANG, DRITSCHELWOERDEMAN}? \item Kippenhahn boundary generating curve theorem \cite{KIPPENHAHN, FIEDLER}? \item Kippenhahn corner-point theorem \cite{KIPPENHAHN, FIEDLER}? \item Hildebrandt normal eigenvalue theorem \cite{BOURDONSHAPIRO, HILDEBRANDT}? \item Hildebrandt intersection theorem \cite{WILLIAMS, FURUTANAKAMOTO}? \item Marcus-Shure description for the numerical range of zero-one matrices \cite{MARCUSSHURE} and Davidson-Holbrook estimate for the numerical radius of zero-one matrices \cite{DAVIDSONHOLBROOK}? \item Johnson numerical range inclusion theorem \cite{JOHNSON2}? \item Choi-Li constrained numerical range theorem \cite{CHOILI}? \item Wang-Wu-Gau result for Crawford number \cite{WANGWUGAU}? \item Abu-Omar-Kittaneh inequality (involving generalized Aluthge transform) \cite{ABUOMARKITTANEH2}? \item Gau-Wu numerical radius equality characterizations \cite{GAUWU3}? \item Gau-Wu theorem for compact operators \cite{GAUWU4}? \item Perron-Frobenius type results on the numerical range \cite{MAROULASPSARRAKOSTSATSOMEROS}? \item Helton-Spitkovsky characterization of shapes of numerical ranges \cite{HELTONSPITKOVSKY}? \item Radjabalipour-Radjavi result on numerical ranges \cite{RADJABALIPOURRADJAVI}? \item Pollack theorem on numerical ranges \cite{POLLACK}? \item Anderson result on numerical ranges \cite{AGLER}? \item Abu-Omar-Kittaneh numerical radius inequalities for the product of matrices \cite{ABUOMARKITTANEH3}? \item Kittaneh-Moradi inequality \cite{KITTANEHMORADI}? \item Lancaster characterization for the closedness of numerical range \cite{LANCASTER}? \item Gau-Wu characterization for numerical ranges of completely non-unitary contractions \cite{GAUWU5}? \item Mees-Atherton domains containing numerical ranges \cite{MEESATHERTON}? \item Chien-Tam characterizations of circularity of numerical ranges \cite{CHIENTAM}? \item Shiu theorem on the growth of numerical range of powers of operator \cite{SHIU}? \end{enumerate} \section{Noncommutative Crouzeix Inequality, von Neumann inequality and Ando inequality Problems} Breakthrough Crouzeix theorem says following. \begin{theorem} \cite{CROUZEIX, CROUZEIX2, CROUZEIX3, BICKELGORKIN, RANSFORDSCHWENNINGER} (\textbf{Crouzeix Theorem}) For every $d \in \mathbb{N}$ and for every matrix $M\in \mathbb{M}_{d}(\mathbb{C})$, we have \begin{align*} (\textbf{Crouzeix-Palencia Inequality}) \quad \quad \quad \|p(M)\|\leq (1+\sqrt{2}) \sup\left\{|p(z)|: z \in W_\mathbb{C}(M)\right\}, \quad \forall p \in \mathbb{C}[z]. \end{align*} \end{theorem} We formulate following problem. \begin{problem} (\textbf{Noncommutative Crouzeix Problem}) Let $\mathcal{A}$ be a unital C*-algebra. Whether there is a universal constant $R_\mathcal{A}$ (which may depend upon $\mathcal{A}$) satisfying following: For every $d \in \mathbb{N}$ and for every matrix $M\in \mathbb{M}_{d}(\mathcal{A})$, we have \begin{align*} \|p(M)\|\leq R_\mathcal{A} \sup\left\{\|p(z)\|: z \in W_\mathcal{A}(M)\right\}, \quad \forall p \in \mathcal{A}[z]. \end{align*} \end{problem} An inequality which is very close to Crouzeix inequality is the von Neumann inequality. \begin{theorem} \label{VT} \cite{VONNEUMANN, NAGY, NAGYFOIASBOOK, DELYONDELYON, NELSON} (\textbf{von Neumann Theorem}) For every $d \in \mathbb{N}$ and for every matrix $M\in \mathbb{M}_{d}(\mathbb{C})$ with $\|M\|\leq 1$, we have \begin{align*} (\textbf{von Neumann Inequality}) \quad \quad \quad \|p(M)\|\leq \sup\left\{|p(z)|: z \in \mathbb{C}, |z|\leq 1\right\}, \quad \forall p \in \mathbb{C}[z]. \end{align*} \end{theorem} Based on Theorem \ref{VT} we formulate following problems. \begin{problem} (\textbf{Noncommutative von Neumann Inequality Problem}) Let $\mathcal{A}$ be a unital C*-algebra. Whether there is a universal constant $R_\mathcal{A}$ (which may depend upon $\mathcal{A}$) satisfying following: For every $d \in \mathbb{N}$ and for every $A\in \mathbb{M}_{d}(\mathcal{A})$ with $\|A\|\leq 1$, we have \begin{align*} \|p(A)\|\leq R_\mathcal{A} \sup\left\{\|p(z)\|: z \in \mathcal{A}, \|z\|\leq 1\right\}, \quad \forall p \in \mathcal{A}[z]. \end{align*} \end{problem} Theorem \ref{VT} has been extended by Ando for two variables. \begin{theorem} \label{AT} \cite{ANDO, NAGYFOIASBOOK} (\textbf{Ando Theorem}) For every $d \in \mathbb{N}$ and for all matrices $M, N\in \mathbb{M}_{d}(\mathbb{C})$ with $\|M\|\leq 1$, $\|N\|\leq 1$ and $MN=NM$, we have \begin{align*} (\textbf{Ando Inequality}) \quad \quad \quad \|p(M, N)\|\leq \sup\left\{|p(z, w)|: z, w \in \mathbb{C}, |z|\leq 1, |w|\leq 1\right\}, \quad \forall p \in \mathbb{C}[z, w]. \end{align*} \end{theorem} Based on Theorem \ref{AT}, we formulate following problem. \begin{problem} (\textbf{Noncommutative Ando Inequality Problem}) Let $\mathcal{A}$ be a unital C*-algebra. Whether there is a universal constant $R_\mathcal{A}$ (which may depend upon $\mathcal{A}$) satisfying following: For every $d \in \mathbb{N}$ and for all $A, B\in \mathbb{M}_{d}(\mathcal{A})$ with $\|A\|\leq 1$, $\|B\|\leq 1$ and $AB=BA$, we have \begin{align*} \quad \quad \quad \|p(A, B)\|\leq \sup\left\{\|p(z, w)\|: z, w \in \mathcal{A}, \|z\|\leq 1, \|w\|\leq 1\right\}, \quad \forall p \in \mathcal{A}[z, w]. \end{align*} \end{problem} Note that Ando theorem cannot be extended to more than two commuting matrices \cite{VAROPOULOS, CRABBDAVIE}. We observe that the Halmos dilation \cite{HALMOS2}, Egervary dilation \cite{LEVYSHALIT, EGERVARY} and Sz.-Nagy dilation (Schaffer construction) \cite{SCHAFFER} carry over to adjointable morphisms on Hilbert C*-modules. This observation will give following result. \begin{theorem} (\textbf{Noncommutative Sz.-Nagy Dilation})\label{NS} Let $\mathcal{E}$ be a Hilbert C*-module over a unital C*-algebra $\mathcal{A}$. Let $T :\mathcal{E}\to \mathcal{E}$ be an adjointable morphism such that $\|T\|\leq1$. Then there exist a Hilbert C*-module $\mathcal{E}_0$ which contains $\mathcal{E}$ isometrically, $\mathcal{E}$ is orthogonally complementable in $\mathcal{E}_0$, $P_\mathcal{E}:\mathcal{E}_0\to \mathcal{E}$ is an onto orthogonal projection and unitary morphism $U:\mathcal{E}_0\to \mathcal{E}_0$ such that \begin{align*} T^nx=P_\mathcal{E} U^nx, \quad \forall n \in \mathbb{N}, \forall x \in \mathcal{E}. \end{align*} \end{theorem} \begin{corollary} Let $\mathcal{E}$ be a Hilbert C*-module over a unital C*-algebra $\mathcal{A}$. Let $T :\mathcal{E}\to \mathcal{E}$ be an adjointable morphism such that $\|T\|\leq1$. Let $\mathcal{E}_0$, $P_\mathcal{E}$ and $U$ be as in Theorem \ref{NS}. Then \begin{align*} \|p(T)\|\leq \|p(U)\|, \quad \forall p(z)=a_0+za_1+\cdots+z^n a_n \in \mathcal{A}[z]. \end{align*} \end{corollary} \begin{corollary} Let $\mathcal{E}$ be a Hilbert C*-module over a unital C*-algebra $\mathcal{A}$. Let $T :\mathcal{E}\to \mathcal{E}$ be an adjointable morphism such that $\|T\|\leq1$. Let $x \in \mathcal{E}$ be such that $Tx=x$. Then $T^*x=x$. \end{corollary} \begin{proof} Let $x \in \mathcal{E}$ be such that $Tx=x$. Let $\mathcal{E}_0$, $P_\mathcal{E}$ and $U$ be as in Theorem \ref{NS}. We then have \begin{align*} x=Tx=P_\mathcal{E}Ux, \quad \langle Ux, Ux \rangle =\langle x, x \rangle, \quad P_\mathcal{E}x=x. \end{align*} We see that \begin{align*} \langle Ux-x, Ux-x\rangle &=2\langle x, x \rangle -\langle Ux, x \rangle-\langle x, Ux \rangle\\ &=2\langle x, x \rangle -\langle Ux, P_\mathcal{E}x \rangle-\langle P_\mathcal{E}x, Ux \rangle\\ &=2\langle x, x \rangle -\langle P_\mathcal{E}Ux, x \rangle-\langle x, P_\mathcal{E}Ux \rangle\\ &=2\langle x, x \rangle -\langle Tx, x \rangle-\langle x, Tx \rangle\\ &=2\langle x, x \rangle -\langle x, x \rangle-\langle x, x \rangle=0. \end{align*} Therefore \begin{align*} Ux=x \implies x=U^*x. \end{align*} Hence \begin{align*} x=U^*x=P_\mathcal{E}U^*x=T^*x. \end{align*} \end{proof} We also observe that the proof of Ando dilation \cite{ANDO} for commuting operators on Hilbert space will not carry over to commuting adjointable morphisms on Hilbert C*-modules (mainly because submodules need not be orthogonally complementable and C*-algebras need not have invariant basis number property). \section{Acknowledgments} AI is used for the literature survey and grammar improvement. \bibliographystyle{plain} \begin{thebibliography}{100} \bibitem{ABUOMARKITTANEH2} Amer Abu-Omar and Fuad Kittaneh. \newblock A numerical radius inequality involving the generalized {Aluthge} transform. \newblock {\em Stud. 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